SAT High School

What is the ratio of the concentration of potassium ions to the concentration of carbonate ions in a 0. 015 m solution of potassium carbonate?

Answers

Answer 1

The ratio of the concentration of potassium ions (K⁺) to the concentration of carbonate ions (CO₃²⁻) = 2: 1

How do you calculate concentration ratio in chemistry?The quantity of a material in a given area is referred to as concentration in chemistry. Another definition states that concentration is the ratio of the solute in a solution to either the solvent or the whole solution. Mass per unit volume is the most used unit of measurement for concentration.The proportion of a solute in the solvent is one method to express the concentration of a solution. The % can also be calculated in one of two ways: either by dividing the solute's mass by the solution's mass, or by dividing the solute's volume by the solution.For a concentration of 3mg to 5g, one value needs to be converted to the other so units are equal: 5g = 5,000mg – meaning the ratio would be 3:5,000 w/w.

Given data :

solution of potassium carbonate = 0.015 m

Potassium carbonate (K₂CO₃) will dissociate into ions

K₂CO₃ ⇒ 2K⁺+ CO₃²⁻

Comparison of reaction coefficients = mole ratio = concentration ratio for the same volume, so

The mole ratio of the ions is

K⁺ : CO₃²⁻ = 2: 1

This comparison also shows the ratio of concentrations of ions: (K₂CO₃ concentration = 0.015 M)

K⁺: CO₃²⁻ = 2.0.015: 1.0.015

K⁺: CO₃²⁻ = 0.03: 0.015 = 2: 1

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Answer 2

Potassium carbonate (K2CO3) is a salt composed of potassium ions (K+) and carbonate ions (CO3^2-). The ratio of the concentration of potassium ions to the concentration of carbonate ions in a solution of potassium carbonate can be determined by the stoichiometry of the salt.

Potassium carbonate is a 1:1 salt, which means that for every one potassium ion in the salt, there is one carbonate ion. Therefore, the ratio of the concentration of potassium ions to the concentration of carbonate ions in a 0.015 M solution of potassium carbonate is 1:1.

In other words, the concentration of potassium ions is the same as the concentration of carbonate ions in a 0.015 M solution of potassium carbonate.

Related Questions

As people entered the gym for the basketball tournament, members of the pep club were selling raffle tickets. They had $1. 50 tickets and $5 tickets. The number of $1. 50 tickets sold was two less than four times the number of $5 tickets sold, and the pep club raised $1,152 from the ticket sales. Let x represent the number of $1. 50 tickets sold and let y represent the number of $5 tickets sold. Which equations best represent the situation? check all that apply. X = 4y – 2 y = 4x – 2 x + y = 1152 1. 5x + 5y = 1152 x = 2 – 4y y = 2 – 4x

Answers

The equations that best represent the situation are:

X = 4y – 2

1.5x + 5y = 1152

The first equation represents the fact that the number of $1.50 tickets sold was two less than four times the number of $5 tickets sold.

The second equation represents the fact that the pep club raised $1,152 from the ticket sales, where 1.5x represents the total amount of money earned from the $1.50 tickets and 5y represents the total amount of money earned from the $5 tickets.

x = 2 - 4y and y = 2 - 4x are not correct equations as they don't represent the given information in the problem.

Enter the molecular equation representing solid chromium (iii) hydroxide reacting with nitrous acid

Answers

The net ionic equation required in the question is; 3OH⁻ (aq) +  3H⁺ (aq) → 3H₂O(l)

For the SAT, do you receive an equation sheet?

You do receive some equations on exam day, to start. Any one of the two math parts on the SAT comes with a Reference Sheet. You don't need to spend a lot of time memorising these equations, but you should be familiar with them anyway.

The molecular equation must first be written down as follows:

Cr(OH)₃(aq) + 3HNO₂(aq) ------> Cr(NO₂)₃(aq) + 3H₂O(l)

The entire ionic equation is then written;

Cr³⁺ (aq) + 3OH⁻ (aq) +  3H⁺(aq) + 3NO₂⁻ (aq) ------> Cr³⁺(aq) +  3NO₂⁻ (aq) + 3H₂O(l)

Lastly, we arrive at the net ionic equation.

3OH⁻(aq) +  3H⁺(aq) -------> 3H₂O(l)

After the spectator ions are eliminated, we arrive at the net ionic equation. The spectator ions in this reaction are Cr³⁺ and 3NO₂⁻. Both ends of the ionic relationship contain these ions.

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