What is the product of 10 x 10 x 10, using an exponent? ​

Answer:

I want to say 900 many sorry if it's wrong

Answer:

88.75%

Step-by-step explanation:

add all the terms given = 355

there are 4 terms.in this set.

355 ÷ 4 = 88.75

Answer:

2/5, 1/2, 6/10

Step-by-step explanation:

did problem

Answer:

1. 2/5

2. 1/2

3. 6/10

Step-by-step explanation:

Hope this helps

May I get braineist pls

Answer:

y=4x-3

Step-by-step explanation:

Answer:

DO i care... no ask your dam teacher won der why u aint pass

Step-by-step explanation:

Answer:

x = 9

Step-by-step explanation:

i took the quiz

[tex]\mathfrak{-2(x-6)=6} [/tex]

[tex]\mathfrak{-2x+12=6} [/tex]

[tex]\mathfrak{-2x=6-12} [/tex]

[tex]\mathfrak{-2x=-6} [/tex]

[tex]\boxed{\mathfrak{x=3} }[/tex]

The expression which is equivalent to 1/4 (5x + 6) is; Choice A: {5(1/4)x} + {6(1/4)x}.

According to the question:

In a bid to expand the expression; we must multiply each term in the parenthesis by (1/4);

In essence; we have;

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Answer:

C. [tex] \frac{ {m}^{2} - m - 2}{ {m}^{2} - 1} [/tex]

Explanation:

[tex] \frac{ {m}^{2} - m - 2}{ {m}^{2} - 1} \\ = \frac{ {m}^{2} - 2m + m - 2 }{ {(m)}^{2} - {(1)}^{2} } \\ = \frac{ m(m - 2) + 1(m - 2)}{(m - 1)(m + 1)} \\ = \frac{(m + 1)(m - 2)}{(m - 1)(m +1) } \\ = \frac{(m - 2)}{(m - 1)} [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

16/100 = 4/25

Step-by-step explanation:

4/10 * 4/10 = 16/100

Answer:

Step-by-step explanation:

90+31=121

180-121=59

Answer:

a=59

basic fact:

angles on a straight line add up to 180

Step-by-step explanation:

we can ignore b for a start

31+90+a=180

121+a=180

121+59=180

a=59

Step-by-step explanation:

Speed is the correct answer

The two numbers whose sum is 7500 and whose product  is a maximum value are 3750 and 3750.

Let the two numbers be x and y.

Since their sum equals 7500,

x + y = 7500  (1)

Their product f(x,y) = xy  (2)

We desire to maximize the product.

From (1), x = 7500 - y

Substituting x into (2), we have

f(x,y) = xy

f(x,y) = (7500 - y)y

f(y) = 7500y - y²

To maximize the product, we find the value of y that maximizes f(y), we differentiate f(y) and equate it to zero.

So, df(y)/dy = d(7500y - y²)/dy

f'(y)/dy = d(7500y)/dy - dy²/dy

f'(y)/dy = 7500 - 2y

Equating it to zero, we have

7500 - 2y = 0

7500 = 2y

y = 7500/2

y = 3750

To determine if this gives a maximum for f(y), we differentiate f'(y) with respect to y.

So, f"(y) = d(7500 - 2y)dy

f"(y) = 0 - 2

f"(y) = -2 < 0.

So, y = 3750 gives a maximum for f(y) = f(x, y)

Since x = 7500 - y

Substituing y = 3750 into the equation, we have

x = 7500 - 3750

x = 3750

So, the two numbers whose sum is 7500 and whose product is a maximum product are 3750 and 3750.

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Answer:

£0.76

Step-by-step explanation:

1kilogram = 1000grams

1000g of grapes costs £2

380g costs = (380 × 2)/ 1000

760/1000 = £0.76

Answer:

Uggghhh

Step-by-step explanation:

I dont know

Answer:

Part A: Garcia mixed 4 cups of red with 1 cup of yellow.

Part B: 1/4 because 4 cups of red requires 1 cup of yellow, so 1 divided by 4 is 1/4.

Part C: $7

Hope this helps! :)

Step-by-step explanation:

Answer:

  length ≈ 5.583 ft

  width ≈ 3.583 ft

Step-by-step explanation:

If we let x represent the length of the table in feet, then the width is (x-2). The area is ...

  A = LW

  20 = x(x -2)

Writing this in standard form gives ...

  x^2 -2x -20 = 0

The coefficients used in the quadratic formula are a=1, b=-2, c=-20. The solutions are ...

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4(1)(-20)}}{2(1)}\\\\=\dfrac{2\pm\sqrt{4+80}}{2}=1\pm\sqrt{21}[/tex]

Of these values, the only one that makes sense is ...

  length = 1+√21 ≈ 5.583 ft

  width = length -2 ≈ 3.583 ft

Let width is x

length be x+2

On solving

we get

x is around 3.58 or 3.6ft

Answer:

10 quarters, 9 dimes, and 20 nickels.

Step-by-step explanation:

q - 1 = d, 2q = n or q = 1/2n

.25q + .10(q - 1) + .05(2q) = 4.40

.25q + .10q - .10 + .10q = 4.40

.45q - .10 = 4.40

.45q = 4.50

4.5/.45 = 10

He has 10 quarters, 9 dimes, and 20 nickels.

Answer:

5/6 + 1/3 = 7/6

Step-by-step explanation:

Answer:

ABC & E are true statements about the graph

Answer:

It is D

Step-by-step explanation:

I am not exactly sure how to explain but i'll try.

The 2 dollars is added to her price, so it is not A.

The 25 dollars is every day, so it is mutlipled by x. So its not B.

The 2 dollars is not everyday like the 25 dollars, so its not C b/c its not everyday.

Answer:

49%.

Step-by-step explanation:

2205      100        220500

........... x ..........  =  ..................  = 49 (49%).

4500        1              4500

The theater filled up with 49% of seats with 6th grade students.

A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have a middle school that took all of its 6th grade students on a field trip to see a symphony at a theater that has 4500 seats. The students filled 2205 of the seats in the theater.

Assume that the theater filled up [x]% of seats at the theater. Then, we can write -

[x]% = (2205/4500) x 100

[x]% = 0.49 x 100

[x]% = 49%

Therefore, the theater filled up with 49% of seats with 6th grade students.

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You likely mean to write the differential equation,

y'' - 2y' + y = exp(x)

The homogeneous part

y'' - 2y' + y = 0

has characteristic equation

r² - 2r + 1 = (r - 1)² = 0

with a root at r = 1 with multiplicity 2, so the characteristic solution is

y = C₁ exp(x) + C₂ x exp(x)

For the particular solution, we assume an ansatz

y = ax² exp(x)

where a is an unknown constant. Differentiating the ansatz twice:

y' = ax² exp(x) + 2ax exp(x) = (ax² + 2ax) exp(x)

y'' = (ax² + 2ax) exp(x) + (2ax + 2a) exp(x) = (ax² + 4ax + 2a) exp(x)

Substitute y and its derivatives into the DE:

(ax² + 4ax + 2a) exp(x) - 2 (ax² + 2ax) exp(x) + ax² exp(x) = exp(x)

Solve for a :

(ax² + 4ax + 2a) - 2 (ax² + 2ax) + ax² = 1

2a = 1

a = 1/2

Then the particular solution is

y = 1/2 x² exp(x)

The general solution is then

y = C₁ exp(x) + C₂ x exp(x) + 1/2 x² exp(x)

Answer:

y= -2x+9

Step-by-step explanation:

First of all, since they need to be parallel, they must have the same slope to never intercept. Next, you can use a graphing calculator to test y-intercepts like desmos. You will find that 9 works, as it goes through (4,1) and never intercepts with the 1st line.

The difference in the proportions of both surveys goes from a maximum of 12.57% to a minimum of 4.76%.

Given that a survey found that in a sample of 75 families, 26 owned dogs, while a survey done 15 years ago found that in a sample of 60 families, 26 owned dogs, to find the 95% confidence intervals of the true difference in the proportions, the following calculation must be performed:

Therefore, the difference in the proportions of both surveys goes from a maximum of 12.57% to a minimum of 4.76%.

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Answer:

put your equation into fractions and then see what or which 1mathces with the image

Step-by-step explanation:

Answer:

try 90°C for an answer, good luck

Answer: 2.8 W. 2.6 W. 2.4 W. 2.2 W. 2.0 W. 1.9 W. 1.7 W

Step-by-step explanation:

Answer:

LCD/ LCM = 100

Step-by-step explanation:

- 12.2 + 2.8W - 8.8 = 1.05W

- 12 [tex]\frac{2}{10}[/tex] + 2 [tex]\frac{8}{10}[/tex] W - 8 [tex]\frac{8}{10}[/tex] = 1 [tex]\frac{5}{100}[/tex] W

- [tex]\frac{122}{10}[/tex] + [tex]\frac{28}{10}[/tex] W - [tex]\frac{88}{10}[/tex] = [tex]\frac{105}{100}[/tex] W

the LCM/ LCD is 100

We can explicitly find the inverse. If [tex]f^{-1}(x)[/tex] is the inverse of [tex]f(x)[/tex], then

[tex]f\left(f^{-1}(x)\right) = \dfrac{f^{-1}(x)+2}{f^{-1}(x)+6} = x[/tex]

Solve for the inverse :

[tex]\dfrac{f^{-1}(x) + 2}{f^{-1}(x) + 6} = x[/tex]

[tex]\dfrac{f^{-1}(x) + 6 - 4}{f^{-1}(x) + 6} = x[/tex]

[tex]1 - \dfrac4{f^{-1}(x) + 6} = x[/tex]

[tex]1 - x = \dfrac4{f^{-1}(x) + 6}[/tex]

[tex]f^{-1}(x) + 6 = \dfrac4{1-x}[/tex]

[tex]\implies f^{-1}(x) = \dfrac4{1-x} - 6[/tex]

Then when x = -6, we have

[tex]f^{-1}(-6) = \dfrac4{1-(-6)} - 6 = \dfrac47-6 = \boxed{-\dfrac{38}7}[/tex]

Alternatively, we can first solve for x such that [tex]f(x) = -6[/tex]. Then taking the inverse of both sides, [tex]x = f^{-1}(-6)[/tex]. (The difference in this method is that we don't compute the inverse for all x.)

We have

[tex]\dfrac{x+2}{x+6} = -6[/tex]

[tex]x + 2 = -6 (x + 6)[/tex]

[tex]x + 2 = -6x - 36[/tex]

[tex]7x = -38[/tex]

[tex]\implies x = \boxed{-\dfrac{38}7}[/tex]

We want to find the average speed of the plane in still air, we will get that the average speed of the plane in still air is 355.3 km/hr

So we know that the total trip is 9900km, so from Texas to Frankfurt the distance is half of that:

9900km/2 = 4950km

Now, The speed of the plane in still air is x km/hr

The speed of the air is 50 km/hr, and it flows from Frankfurt to Texas.

So in the first part of the trip, the wind blows in opposite direction to the motion of the plane, thus the speed of the plane will be:

(x - 50) km/hr

While in the return trip the wind blows in favor of the plane, in this case, the speed is:

(x + 50)km/hr

Then if the first part of the trip lasts for T hours (the second for T - 4 hours) we can write the system of equations:

(x - 50)*T = 4950

(x + 50)*(T - 4) = 4950

Where I removed the units so it is easier to read.

If we isolate T in the first equation we get:

T = 4950/(x - 50)

Now we can replace this in the other equation to get:

(x + 50)*(4950/(x - 50)  - 4) = 4950

If we multiply both sides by (x - 50) we get:

(x + 50)*4950 - 4*(x + 50)*(x - 50) = 4950*(x - 50)

Now we can solve this for x:

(x + 50)*4950 - 4*(x^2 - 2500) - 4950*(x - 50) = 0

100*4950 - 4*(x^2 - 2500)  = 0

495000 - 4*x^2 + 10000 = 0

505000 = 4*x^2

√(505000/4) = x = 355.3

The average speed of the plane in still air is 355.3 km/hr

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Factorization involves breaking down an expression.

The sum of cubes is given as:

[tex](a^3 + b^3) = (a + b)(a^2 -ab + b^2)[/tex]

(a) Verify the formula

Expand the expression on the right-hand side

[tex](a^3 + b^3) = a^3 -a^2b + ab^2 +a^2b - ab^2 + b^3[/tex]

Collect like terms

[tex](a^3 + b^3) = a^3 -a^2b +a^2b+ ab^2 - ab^2 + b^3[/tex]

[tex](a^3 + b^3) = a^3 + b^3[/tex]

The formula has been verified

(b) Factorized 8x^3+ 27

We have:

[tex]8x^3 + 27[/tex]

Express 27 as 3^3

[tex]8x^3 + 27 =8x^3 + 3^2[/tex]

Express 8 as 2^3

[tex]8x^3 + 27 =2^3x^3 + 3^3[/tex]

Rewrite as:

[tex]8x^3 + 27 =(2x)^3 + 3^3[/tex]

Given that:

[tex](a^3 + b^3) = (a + b)(a^2 -ab + b^2)[/tex]

The expression becomes

[tex]8x^3 + 27 =(2x + 3)((2x)^2 - (2x)3 +3^2)[/tex]

[tex]8x^3 + 27 =(2x + 3)(4x^2 -8x3 +9)[/tex]

(c)The other factor of 2^3 - b^3

By difference of cubes, we have:

[tex]x^3 - y^3=(x-y)(x^2+xy+y^2)[/tex]

So, the equation becomes

[tex]2^3 - b^3=(2-b)(2^2+2b+b^2)[/tex]

This gives

[tex]2^3 - b^3=(2-b)(4+2b+b^2)[/tex]

Hence, the other factor of [tex]2^3 - b^3[/tex] is [tex]4+2b+b^2[/tex]

(c) Factor x^3 - 1

We have:

[tex]x^3 - y^3=(x-y)(x^2+xy+y^2)[/tex]

Express 1 as 1^3 in x^3 - 1

[tex]x^3 - 1 =x^3 - 1^3[/tex]

[tex]x^3 - y^3=(x-y)(x^2+xy+y^2)[/tex] becomes

[tex]x^3 - 1^3=(x-1)(x^2+x+1^2)[/tex]

[tex]x^3 - 1^3=(x-1)(x^2+x+1)[/tex]

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