What is the probability that a student who plays an instrument does not play a sport?
What is the probability that a student plays an instrument given that they play a sport?

Answers

Answer 1

Answer:

.2222

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Related Questions

Please can anyone tell me what the L.C.M of c, 3c , 3 is?

Answers

The least common multiple ( LCM ) is A = 3c

Given data ,

Let the three numbers be represented as c , 3c and 3

Now , The prime factorization of each number is:

c: c

3c: 3 * c

3: 3

The LCM is the product of the highest power of each prime factor. In this case, the highest power of c is c, and the highest power of 3 is 3. Therefore, the LCM is:

LCM = c * 3 = 3c

Hence , the LCM of c, 3c, and 3 is 3c

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Find the height of the triangle in meters.
Area = 1 m²
4 m
h=?

Answers

Answer:

0.25 m

Step-by-step explanation:

The equation for the area of a triangle is:

A= 1/2bh

We substitute in what we know to find the height (h).

1 m = 4m(h)

Divide 4 m from both sides.

1/4 = h

So the height of the triangle is 1/4 m or this substitutes to 0.25.

Proportional or not proportional?

Answers

The given equations [tex]y = -4x \ and \ \frac{1}{6} + 3x = y[/tex] are not proportional equations.

To determine if the given equations [tex]y = -4x \ and \ \frac{1}{6} + 3x = y[/tex] are proportional, we need to check if the ratios of the corresponding coefficients are equal. Let's solve the second equation for y and compare the coefficients:

Given equation 1: [tex]\( y = -4x \)[/tex]

Given equation 2: [tex]\( \frac{1}{6} + 3x = y \)[/tex]

To determine if the equations are proportional, we'll compare the coefficients of x and y in both equations.

Comparing the coefficients of x:

In equation 1, the coefficient of x is [tex]-4[/tex].

In equation 2, the coefficient of x is [tex]3[/tex].

Since the coefficients of x are different [tex](-4 \ and \ 3)[/tex], the equations are not proportional.

Comparing the coefficients of y:

In equation 1, the coefficient of y is -1.

In equation 2, the coefficient of y is 1.

Since the coefficients of y are different (-1 and 1), the equations are not proportional.

Hence, the given equations [tex]y = -4x \ and \ \frac{1}{6} + 3x = y[/tex] are not proportional.

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When using substitution to solve a system of equations, how can you tell when a system has no solution? Make a selection from the drop down menu. A system has no solution when the resulting equation is always Choose... .

Answers

Answer: False

Step-by-step explanation:

When a system has infinite or 0 solutions the same thing happens;

the variables cancel out, and you're left with an equation of numbers

if it is true, there are infinite solution, if it is false there are none;

for example:

if you get something like 5 = 5, obviously that is true so there are infinite solutions

but if you get something like 3 = 21, which is obviously not true, there are none solutions

So the resulting equation has to be false for there to be no solutions.

A statement That is accepted if the sample data provide sufficient evidence that the null hypothesis is false, is called
A. Simple Hypothesis
B. Composite Hypothesis
C. Statistical Hypothesis
D. Alternative Hypothesis

Answers

The correct answer for the statement is,

⇒  Alternative Hypothesis

Hence, Option D is true.

We have to given that;

To complete the sentence,

A statement is,

That is referred to as ___ and is accepted if the sample data provide enough evidence to refute the null hypothesis.

Now, We know that;

Definition of Alternative Hypothesis,  

When the sample data support the null hypothesis sufficiently, a statement is taken as true, yet it is untrue.

Hence, Complete sentence is,

A correct statement which is accepted for the sample data provided sufficient evidence that the null hypothesis is false, is called Alternative Hypothesis.

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Please can anyone tell me what the L.C.M of c, 3c , 3 is?

Answers

The L.C.M of c, 3c , 3 is 3c.

The L.C.M of c, 3c, and 3, we first need to factor each term:
c cannot be factored any further.
3c can be factored as 3 x c.
3 cannot be factored any further.
Next, we look for the highest common factors among the factors of these terms.

The only common factor is 3, which is included in both 3c and 3.
Therefore, the L.C.M of c, 3c, and 3 is 3c.
The L.C.M (Least Common Multiple) of c, 3c, and 3 can be found by analyzing the factors of each term.
For c, the only factor is c itself.
For 3c, the factors are 3 and c.
For 3, the only factor is 3.
Now, find the LCM by taking the highest power of each unique factor:
LCM(c, 3c, 3) = 3 * c = 3c

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11. A.APR.2 For an unknown polynomial function p(x), p(4) + 2 = 2. . Which
binomial is a factor of p(x)?
A.X-2
B. x+2
C. X-4
D.x+4

Answers

After considering all the given data we conclude that the binomial that is a factor of the polynomial P(x) is (x-4), which is Option C

As it is seen in the context of the remainder theorem of polynomials, in the event that a  polynomial function f(x) is divisible by a factor (x-a), the remaining reminder is zero, now the generated value of f(a) will be also zero. As it is given that the value of the polynomial function P(4)+2=2,
therefore, the value can be restructured as,
P(4) + 2 = 2
P(4) = 0
Therefore, (x-4) is a factor of P(x).
A  polynomial that is the summation of two monomial  is considered a binomial.
For instance , x + 2 is a binomial, here x and 2 are two separate terms.
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can someone answer 15 16 and 17 with steps?

Answers

The required measure of side GH is 23.25, and measures of angles G and H are 64.5° and 25.5°.

From the given figure,
The measure of GH is given by, the Pythagorean theorem,
GH = √[10² + 21²]
GH = 23.25

Now applying the trig ratio to determine, angles H and G,
tang=21/10
G = tan⁻¹[21/10]
G = 64.53°

Similarly,
H = 25.5°

Thus, the required measure of side GH is 23.25, and measures of angles G and H are 64.5° and 25.5°.

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2. A new pesticide company took a random sample of 200 farms using their new product. The results showed that 160 farms no longer have a problem with caterpillars feeding on their crops, with a margin of error of ±13 farms. If the pesticide company is working with 1,470 farms, how many farms will be expected to no longer have a problem with caterpillars feeding on their crops? ​

Answers

Answer: To estimate the number of farms expected to no longer have a problem with caterpillars feeding on their crops among the total 1,470 farms based on the random sample of 200 farms, we can use proportion estimation.

First, let's find the proportion of farms in the sample that no longer have a problem with caterpillars:

Proportion = (Number of farms with no caterpillar problem in the sample) / (Total number of farms in the sample)

Proportion = 160 / 200

Proportion = 0.8

Next, we'll use this proportion to estimate the number of farms in the total population of 1,470 farms:

Estimated number of farms = Proportion * Total number of farms in the population

Estimated number of farms = 0.8 * 1,470

Estimated number of farms = 1,176

Therefore, it is expected that approximately 1,176 farms will no longer have a problem with caterpillars feeding on their crops based on the sample data.

Step-by-step explanation:

help asap and brainliest!!!!!!!!!!!!!!!!!!!!!!!!
The box plots display data collected when two teachers asked their classes how many sheets of paper they used in a week.

A box plot uses a number line from 5 to 49 with tick marks every one unit. The box extends from 8 to 12 on the number line. A line in the box is at 11. The lines outside the box end at 7 and 45. The graph is titled Mr. Howard's Class, and the line is labeled Sheets Of Paper.

A box plot uses a number line from 2 to 52 with tick marks every one unit. The box extends from 8 to 25 on the number line. A line in the box is at 16. The lines outside the box end at 5 and 50. The graph is titled Mrs. Potter's Class, and the line is labeled Sheets Of Paper.

Which class used the most paper overall based on the data displayed?

Mrs. Potter's class; it has a larger median value of 16 pieces of paper
Mr. Howard's class; it has a larger median of 11 pieces of paper
Mrs. Potter's class; it has a narrow spread in the data
Mr. Howard's class; it has a wide spread in the data

Answers

The spread of the data is not relevant to determining which class used the most paper overall.

Mrs. Potter's class used the most paper overall based on the data displayed because it has a larger median value of 16 pieces of paper. The median value of Mr. Howard's class is 11 pieces of paper.

The spread of the data is not relevant to determining which class used the most paper overall.

Therefore, the correct answer is Mrs. Potter's class; it has a larger median value of 16 pieces of paper.

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AXYZ AMNL
X
XY =
33°
Y
LA
12
N
124°
N
8
M

Answers

Answer:

  8

Step-by-step explanation:

You want to know the measure of segment XY if ∆XYZ ≅ ∆MNL and MN = 8.

Corresponding sides

Segment XY is named using the first two vertices listed in the name of ∆XYZ. That means the segment is the same length as the one named by the first two vertices listed in the name of congruent ∆MNL, segment MN.

Segment MN is given as 8 units long. Segment XY is congruent, so is also 8 units long.

  XY = 8 units

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net bookmarks
12-3: Question Set: Homework
Kurt recorded the amount of rainfall in each month for one year. What was the
total rainfall that year?
Choose the correct answer below.
OA. 22 in.
OB. 13 in.
OC, 27 in.
OD, 19 in.
Click to select your answer.
0
Monthly Rainfall Amounts
:..:
13
-
4
1
42
+ + +
1
1
1 32
1 17 14
4 2
Amount (in inches)
1

Answers

The total rainfall for the year is given as follows:

D. 19 inches.

What is the dot plot?

The dot plot gives a dot to each measure for each time that it appears, hence it says the same thing as a table, in a different format.

Hence the rainfall in this problem is divided as follows:

One month of zero inches.1 month of 0.5 inches.2 months of 0.75 inches.3 months of 1.75 inches.1 month of 2 inches.1 month of 2.25 inches.Three months of 2.5 inches.

Hence the total rainfall is obtained as follows:

0 + 1 x 0.5 + 2 x 0.75 + 3 x 1.75 + 1 x 2 + 1 x 2.25 + 3 x 2.5 = 19 inches.

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100 Points! Algebra question. Photo attached. Please show as much work as possible. Thank you!

Answers

Answer:

Refer to the step-by-step.

Step-by-step explanation:

Verify the given identity.

[tex]E_0\cos^4(\theta)=E_0(\frac{1}{2} +\frac{\cos(2\theta)}{2} )^2[/tex]

Pick the more complex side to manipulate, in this case it is the R.H.S.

(1) - Apply the following double-angle identity

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Double-Angle Identity:}}\\\\\cos(2A)=1-2\sin^2(A)\end{array}\right}[/tex]

[tex]E_0(\frac{1}{2} +\frac{\cos(2\theta)}{2} )^2\\\\\Longrightarrow \boxed{ E_0\Big(\frac{1}{2} +\frac{1-2\sin^2(\theta)}{2}\Big )^2}[/tex]

(2) - Split of the right fraction

[tex]E_0(\frac{1}{2} +\frac{1-2\sin^2(\theta)}{2} )^2\\\\\Longrightarrow E_0(\frac{1}{2} +\frac{1}{2} -\frac{2\sin^2(\theta)}{2})^2\\\\\Longrightarrow \boxed{E_0(1 -sin^2(\theta))^2}[/tex]

Apply the following Pythagorean identity

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Pythagorean Identity:}}\\\\1-\sin^2(A)=\cos^2(A)\end{array}\right}[/tex]

[tex]E_0(1 -sin^2(\theta))^2\\ \\\Longrightarrow E_0(\cos^2(\theta))^2\\\\\therefore \boxed{E_0\cos^4(\theta)=E_0\cos^4(\theta)}[/tex]

Thus, the identity is verified.

It has been proven and verified that [tex]E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{cos2 \theta}{2} )^2[/tex] below.

How to verify the equality of the cosine function?

In Mathematics and Geometry, the standard equation of a cosine function is represented or modeled by the following mathematical equation (formula):

y = Acos(Bx - C) + D

Where:

A represents the amplitude.B = 2π/P.P represents the period.C represents the phase shift.D represents the center line (midline).

In this exercise, you are required to prove that the right-hand side of the cosine function is equal to left-hand side of the cosine function;

[tex]E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{cos2 \theta}{2} )^2[/tex]

From the double-angle formulas, we have:

2sin²θ = 1 - cos2θ

cos2θ = 1 - 2sin²θ

Next, we would evaluate the right-hand side of the cosine function by substituting "1 - 2sin²θ" for cos2θ as follows;

[tex]E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{1-2sin^2 \theta}{2} )^2\\\\E_0cos^4 \theta = E_0(\frac{1}{2} +\frac{1}{2} -\frac{2sin^2 \theta}{2})^2\\\\E_0cos^4 \theta = E_0(1 -\frac{2sin^2 \theta}{2})^2\\\\E_0cos^4 \theta = E_0(1 -sin^2 \theta)^2\\\\[/tex]

E₀cos⁴θ = E₀(1² - (sin²θ)²)

E₀cos⁴θ = E₀(1 - sin⁴θ)  ⇒ (Verified).

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socks up his told was to pull he​

Answers

I don’t understand the question

The volume of a box is 36 cubic inches. If the length is 3 inches and the width is 3 inches, what is the height of the box?

Answers

The height of the box is 4 inches.

The volume of a box is given by the formula V = lwh, where V is the volume, l is the length, w is the width, and h is the height. We are given that the volume of the box is 36 cubic inches, the length is 3 inches, and the width is 3 inches.

So, we can plug in these values into the formula and solve for the height h:

V = lwh

36 = 3 x 3 x h

36 = 9h

h = 36/9

h = 4

Therefore, the height of the box is 4 inches.

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In a recent poll, 130 people were asked if they liked dogs, and 65% said they did. Find the Margin of Error for this poll, at the 99% confidence level. Give your answer to four decimal places if possible.​

Answers

We can say with 99% confidence that the true proportion of people who like dogs is within 8.44 percentage points of the sample proportion (65%).

To find the Margin of Error (MoE) for a poll, we need to use the formula:

MoE = [tex]z \times (\sqrt{(p \times q / n)} )[/tex]

where:

z is the z-score associated with the desired confidence level (99% confidence level corresponds to z = 2.576)

p is the proportion of people who said they liked dogs (0.65 in this case)

q is the complement of p (i.e., q = 1 - p)

n is the sample size (130 in this case)

Plugging in the values, we get:

MoE = [tex]2.576 \times (\sqrt{(0.65 \times 0.35 / 130)} )[/tex] ≈ 0.0844

Rounding to four decimal places, the Margin of Error is approximately 0.0844. Therefore, we can say with 99% confidence that the true proportion of people who like dogs is within 8.44 percentage points of the sample proportion (65%).

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A player gets a "cap" each time they play for their national team.
The players in Team A have a total of 36 caps. The players in Team B have a total of 12 caps. Mel moves from Team A to Team B.
Now, the players in Team A have twice as many caps in total as the players in Team B.
Work out how many caps Mel has. ​

Answers

Hello!

x = number of caps of Mel

36 - x = 2(12 + x)

36 - x = 24 + 2x

36 - 24 = 2x + x

12 = 3x

x = 12/3

x = 4

The answer is 4.

verification:

36 - 4 = 32

12 + 4 = 16

16 x 2 = 32 or 32/2 = 16

it's correct.

2079 [Optional] Set A Q.No. 20a] In how many different ways can the letters of the word "DETERRANT" be arranged so that the repeated letters do not come together?

Answers

There are 70,560 different ways to arrange the letters of the word "DETERRANT" so that the repeated letters do not come together.

How many ways the word "DETERRANT" be arranged so that the repeated letters do not come together

The word "DETERRANT" has 9 letters, out of which there are 2 E's, 2 R's, and 1 T.

To determine the total number of possible arrangements, we begin with 9! (9 factorial), which counts all possible arrangements if all letters are distinct.

We must, however, account for the repeated letters. For the two E's, we divide by 2, which is the number of different ways they can be arranged without changing the overall arrangement. Likewise, we divide by 2! for the two R's.

As a result, the total number of arrangements with repeated letters that do not come together is:

9! / (2! x 2!) - 8! / (2! x 2!) = 90720 - 20160 = 70560

Therefore, there are 70,560 different ways to arrange the letters of the word "DETERRANT" so that the repeated letters do not come together.

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find the maximum rate of change of f(x, y, z) = e ^ (3x) * sin(y + 2z) at (3, - 1, 1) and the direction in which this m

Answers

The maximum rate of change of f(x, y, z) = e³ˣ × sin(y + 2z) at (3, -1, 1) is |∇f(3, -1, 1)| = √(10e¹⁸ × sin²(1) + 5e¹⁸ × cos²(1)), and the direction in which this maximum rate of change occurs is given by the unit vector u = (∇f(3, -1, 1) / |∇f(3, -1, 1)|).

How did we get the values?

To find the maximum rate of change of the function f(x, y, z) = e³ˣ × sin(y + 2z) at the point (3, -1, 1) and the direction in which this maximum rate of change occurs, we can use the gradient vector.

The gradient vector of a function represents the direction of the maximum rate of change, and its magnitude represents the maximum rate of change itself. The gradient vector is given by:

∇f(x, y, z) = (∂f/∂x, ∂f/∂y, ∂f/∂z)

Let's calculate the partial derivatives of f(x, y, z) with respect to each variable:

∂f/∂x = 3e³ˣ × sin(y + 2z)

∂f/∂y = e³ˣ × cos(y + 2z)

∂f/∂z = 2e³ˣ × cos(y + 2z)

Now, we can evaluate these partial derivatives at the point (3, -1, 1):

∂f/∂x = 3e³ ˣ ³ × sin(-1 + 2 × 1) = 3e⁹ × sin(1)

∂f/∂y = e³ ˣ ³ × cos(-1 + 2 × 1) = e⁹ × cos(1)

∂f/∂z = 2e³ ˣ ³ × cos(-1 + 2 × 1) = 2e⁹ × cos(1)

Therefore, the gradient vector ∇f(3, -1, 1) is:

∇f(3, -1, 1) = (3e⁹ × sin(1), e⁹ × cos(1), 2e⁹ × cos(1))

The magnitude of the gradient vector represents the maximum rate of change of the function at the given point. Let's calculate the magnitude:

|∇f(3, -1, 1)| = √((3e⁹ × sin(1))² + (e⁹ × cos(1))² + (2e⁹ × cos(1))²)

= √(9e¹⁸ × sin²(1) + e¹⁸ × cos²(1) + 4e¹⁸ × cos²(1))

= √(10e¹⁸ × sin²(1) + 5e¹⁸ × cos²(1))

To find the direction in which the maximum rate of change occurs, normalize the gradient vector by dividing it by its magnitude:

u = ∇f(3, -1, 1) / |∇f(3, -1, 1)|

The direction vector u represents the unit vector pointing in the direction of the maximum rate of change.

Therefore, the maximum rate of change of f(x, y, z) = e³ˣ × sin(y + 2z) at (3, -1, 1) is |∇f(3, -1, 1)| = √(10e¹⁸ × sin²(1) + 5e¹⁸ × cos²(1)), and the direction in which this maximum rate of change occurs is given by the unit vector u = (∇f(3, -1, 1) / |∇f(3, -1, 1)|).

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A guide wire is attached to the top of a 75 foot tower and meets the ground at 65 degree angel how many feet long is the wire

Answers

The length of wire is 82.78 foot.

After guiding wire,

It form a right angle triangle which have

One angle is of 65 degree

perpendicular = 75 foot

And we have to find hypotenuse of the triangle which is length of wire.

Since we know that,

The trigonometric ratio sin is the ratio of opposite side of angle and

hypotenuse.

Therefore,

⇒ Sin65 = 75/hypotenuse

⇒ 0.906 = 75/hypotenuse

⇒  hypotenuse = 82.7 foot

Since hypotenuse of triangle represents  length of wire

So, required length of wire is 82.7 foot.

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please hurry, 100 points

Answers

Answer:

a. Since blue occurs a fraction z of the time and the red and green portions have equal area, the probability of landing on green is (1 - z)/2.

b. The area diagram for spinning the spinner twice would have three sections: blue, green, and red. Each section would be divided into three smaller sections: BB, BG, BR, GB, GG, GR, RB, RG, and RR. The diagram would show all 9 possible outcomes of spinning the spinner twice.

c. The region on the area diagram corresponding to getting the same color on the spinner twice would be the diagonal line from the upper left to the lower right, going through the GG, BB, and RR sections.

d. The probability that both spins give the same color can be calculated as follows:

- The probability of getting blue on the first spin is z.

- The probability of getting green on the first spin is (1 - z)/2.

- The probability of getting red on the first spin is (1 - z)/2.

- If the first spin is blue, the probability of getting blue again on the second spin is z. The same applies to green and red.

- Therefore, the probability of getting the same color on both spins is z^2 + ((1 - z)/2)^2 + ((1 - z)/2)^2 = z^2 + (1 - z)^2/4.

e. If you know that you got the same color twice, the probability that the color was blue can be calculated using Bayes' theorem:

- Let A be the event that you got blue twice, and let B be the event that you got the same color twice.

- Then P(A|B) = P(B|A) * P(A) / P(B), where P(A) = z^2, P(B|A) = 1, and P(B) = z^2 + ((1 - z)/2)^2 + ((1 - z)/2)^2 = z^2 + (1 - z)^2/4.

- Therefore, P(A|B) = z^2 / (z^2 + (1 - z)^2/4).

Step-by-step explanation:

Hope this helps

Hala had 42 sheets of paper.
She gave 17 sheets to Kari.
How many sheets of paper
does Hala have now?

Answers

Answer:

25 sheets

Step-by-step explanation:

=42-17 = 25 sheets

Answer:

25 sheets of paper

Step-by-step explanation:

42-17=25

Pls help me find the unknown length

Answers

Answer:

slon

7+15

AGAIN

L+B⅔

²2

AE

Please help me with this question thanks

Answers

The procedure step that the student could follow to accomplish the goal of increasing the force of the electromagnet would be C. Add more batteries in series at location 3.

How to increase electromagnetic force ?

Adding batteries in a series has the effect of increasing the electromagnet's force by augmenting the voltage applied to the wire coil.

The intensity of the magnetic field produced by an electromagnet corresponds directly to the magnitude of current coursing through the wire coil and the number of wire coils present in the magnet respectively. Meanwhile, the amount of current that travels through said coil is intrinsically related to the resistance of the coil itself and the applied voltage across it.

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In a certain Integrated Math II class of 29 students, 6 of them play golf and 14 of them play soccer. There are 9 students who play neither. Create a table to find probabilities.
5. What is the probability that a student chosen randomly from the class plays golf or
soccer?
6. What is the probability that a student chosen randomly from the class plays golf and soccer?
I rlly need the help!

Answers

The solution is:

20/29 is the probability that a student chosen randomly from the class plays golf or soccer.

0 is the probability that a student chosen randomly from the class plays golf and soccer.

Here, we have,

given that,

In a certain Integrated Math II class of 29 students, 6 of them play golf and 14 of them play soccer.

There are 9 students who play neither.

Number of students that play = 20

let, students play golf = A

students play soccer = B

so, given that,

n ( A) = 6 and, n ( B) = 14

so, total sample space = 29

now, P(A) = 6/29

P(B) = 14/29

and, P(students who play neither) = 9/29

we get, 6/29 + 14/ 29 + 9/29 = 29/29 = 1

i.e. there are no students who play both golf and soccer = 0

all the events are independent.

so, we have,

the probability that a student chosen randomly from the class plays golf or soccer = P(A) + P(B)

               = 6/29 + 14/ 29

               = 20/29

and, the probability that a student chosen randomly from the class plays golf and soccer = 0.

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Japanese garden has a circular koi pond in the middle that has a radius of 3 feet.

A rectangle with length of 16 feet and width of 14 feet. A circle with radius 3 feet is cut out of the rectangle.

What is the area of the Japanese garden around the koi pond? Use 3.14 for Pi.
195.74 feet squared
224.00 feet squared
252.26 feet squared
337.04 feet squared

Answers

The area of the Japanese garden around the koi pond is 195.74 square feet.

To find the area of the Japanese garden around the koi pond, we need to subtract the area of the circular pond from the area of the rectangular garden. Let's use the given terms and follow these steps:
1. Calculate the area of the rectangular garden.
Area = Length × Width
Area = 16 feet × 14 feet
Area = 224 square feet
2. Calculate the area of the circular koi pond.
Area = π × (radius)^2
Area = 3.14 × (3 feet)^2
Area = 3.14 × 9 square feet
Area = 28.26 square feet
3. Subtract the area of the koi pond from the area of the garden.
Garden area around the koi pond = Area of the rectangle - Area of the circle
Garden area = 224 square feet - 28.26 square feet
Garden area = 195.74 square feet
Your answer: The area of the Japanese garden around the koi pond is 195.74 square feet.

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(16 - 2 ) x (12 - 2 ) + 92=

Answers

Answer:

x+116

Step-by-step explanation:

add the expressions.

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According to the data set, where should the upper quartile line of the box plot be placed?

45 47 48 49 51 53 55 55 56 57 64


(Picture is shown)

Answers

The upper quartile line of the box plot be placed at D

The left and right sides of the box are the lower and upper quartiles.

In the given figure the A represents the minimum value

The point E represents the maximum value

The point B is the lower quartile of the data

The point C is median of the data

The point D is the upper quartile which is 56

Hence, the upper quartile line of the box plot be placed at D

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Shiva brought $52.75 to the art supply store. She bought a brush, a sketchbook, and a paint set.
The brush was 1/6 as much as the sketchbook, and the sketchbook cost 3/4 the cost of the paint
set. Shiva had $4.00 left over after buying these items.
What was the cost of each item?

The brush cost $__
The sketchbook cost $__
The paint set cost $__

Answers

the paint set, sketchbook, brush price in turn are : 26 ; 19,5 ; 3,25$

Step-by-step explanation:

assume the price of the paint set is x($)

we have an equation

52,75-4= X + 3/4X +1/6×3/4X (4$ is the remaining amount after shiva bought these things above)

<=> X=26($)

what is 17 divided by 6?

Answers

2 r5

How to find the answer:

Multiply the newest quotient digit (2) by the divisor 6 . Subtract 12 from 17 . The result of division of 17÷6 17 ÷ 6 is 2 with a remainder of 5

Hello!

It's a division.

17  I  6

-12 I   2

  5

the dividende = 17

the divider = 6

the quotient = 2

the rest = 5

17 = 2 x 6 + 5

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