Answer:
25.48
Explanation:
If you we're in charge of designing a wire to cart electricity across your city, state or provide, which of the following properties would be most important for your wire to have?
Should it be thick or thin, aluminum orchrome, buried underground or installed out in the sun?
Write a paragraph defending your choice.
PLEASE HELP!!
Answer:
It should be fibre optic cable , buried underground
Explain why pumice floats and why ironwood sinks
Answer:
A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.
Hope that helps. x
Answer:
Pumice is trapped in gas when the temperature is warm, but as the temp drops, it becomes dense, due to air bubbles. Iron wood is denser than water, thus making it sink.
Explanation:
What part of the reactor is used to control the speed of the nuclear reaction? How does it work?
Control rods
____________________
Control rods are inserted into the core of a nuclear reactor and adjusted in order to control the rate of the nuclear chain reaction
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a convex lens has a focal length of 0.5 it is combined with a second lens so combination has power 2.5 diopter which of the following could be second lens
A) concave lens focal length 2m
B) convex lens focal length 0.5m
C) concave lens 0.5m
D) convex lens 2m
Answer:
concave lens focal length 2m
if 9 joules of energy are expended pushing on one coulomb of charge round a circuit, what is the emf across the circuit?
[tex]\\ \sf\Rrightarrow V=\dfrac{W}{Q}[/tex]
[tex]\\ \sf\Rrightarrow V=\dfrac{9}{1}[/tex]
[tex]\\ \sf\Rrightarrow V=9V[/tex]
1. A ball rolls off a desk at a speed of 3.0 m/s, lands 0.40 seconds later, and lands 1.2 m away from the desk
b) how high is the desk
Answer:
0.784m
Explanation:
This is a projectile motion problem so we analyze the horizontal and vertical motions separately. Since the question is asking for the height of the desk, it shows we need to analyze the vertical motion.
Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?
answers:
3.26 meters
3.26 minutes
69 meters
69 minutes
Answer:
69 meters
Explanation:
how to calculate velocity with acceleration and time
Answer:
Multiply the acceleration by time to obtain the velocity change:
Example:
Velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h
I have two questions. I hope anyone can help me <3 Question 8 & Question 9.
Answer:
i have not study it till now
Explanation:
sorry i don't know
A 0.5 kg rock is thrown straight downward off a cliff. If the rock only experience a gravitation force for 4.3 seconds, and ends with a downward velocity of 46.1 m/s, what was rock initial velocity? What is the gravitational force?
Answer:Answer:
See diagram for answers. The force and acceleration vectors are directed inwards towards the center of the circle and the velocity vector is directed tangent to the circle.
Explanation:
which planet should punch travel to if his goal is to weigh in at 118 lb? refer to the table of planetary masses and radii given to determine your answer.
The planet that Punch should travel to in order to weigh 118 lb is Pentune.
The given parameters:Weight of Punch on Earth = 236 lbDesired weight = 118 lbThe mass of Punch will be constant in every planet;
[tex]W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}[/tex]
The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;
[tex]F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}[/tex]
where;
M is the mass of Earth = 5.972 x 10²⁴ kgR is the Radius of Earth = 6,371 kmFor Planet Tehar;
[tex]g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g[/tex]
For planet Loput:
[tex]g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g[/tex]
For planet Cremury:
[tex]g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g[/tex]
For Planet Suven:
[tex]g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g[/tex]
For Planet Pentune;
[tex]g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g[/tex]
For Planet Rams;
[tex]g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g[/tex]
The weight Punch on Each Planet at a constant mass is calculated as follows;
[tex]W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb[/tex]
Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.
The complete question is below:
Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.
Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (find the image attached).
In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.
Learn more about effect of gravity on weight here: https://brainly.com/question/3908593
What is the wavelength of an AM radio wave in a vacuum if its frequency is 810 kHz?
Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes soft. What state of matter is the softer wax? Is it possible for the wax to change without changing its state?
Answer:
An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.
Explanation:
Hope this helps
May I get braineist pls?
how to put in velocity into a graphing calculator
Answer:
You need a graphing calculator that implemented vectors. I don't know any that have it. Sorry.
Answer:
Provided an object traveled 500 meters in 3 minutes , to calculate the average velocity you should take the following steps:
Change minutes into seconds (so that the final result would be in meters per second). 3 minutes = 3 * 60 = 180 seconds ,
Divide the distance by time: velocity = 500 / 180 = 2.77 m/s .
Explanation:
How to do this question plz
Answer:
Let L be the length of the wire.
N λ = M L where N is the number of wavelengths λ. Also, M and are integers and L is the length of the wire
There must be nodes at the ends of the wire and anti-nodes at the points of zero displacement - λ/2, λ, 3λ/ 2, etc.
The simplest would be 2 λ = L or L = λ / 2
In such a situation one would have
N-A-N or node-antinode-node
There is a 180 degree phase change upon reflection of the wave creating the standing wave
The distance between nodes or anti-nodes must be λ/2 and there must be nodes at the ends of the wire
Under the Big Top elephant. Ella [2500 kg]. is attracted to Phant, the 3,000 kg elephant. They are separated by 8 m. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)
Hi there!
We can use the same equation for Gravitational Force:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]
Fg = force due to gravity (N)
G = gravitational constant
m1,m2 = masses of objects (kg)
r = distance between objects (m)
Plug in the values provided:
[tex]F_g = (6.67*10^{-11})\frac{(2500)(3000)}{8^2} = \large\boxed{7.814 * 10^{-6}N }[/tex]
[tex]\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}[/tex]
Here we've been given,
Universal gravitational constant (G) = [tex] \sf{6.67 \times {10}^{ - 11} }[/tex]Mass of object 1 (m1) = 2500 kg Mass of object 2 (m2) = 3000 kg Distance between two objects (r) = 8 mWe have to find the gravitational attraction force (Fg) = ?
The standard formula to solve is given by,
[tex]:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^{2} } } [/tex]
[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{(2500 )(3000)}{ {8}^{2} } }[/tex]
[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{7500000}{64} }[/tex]
[tex]:\implies\tt{F_g = 7.814 \times {10}^{ - 6} }[/tex]
Gravitational force of attraction is 7.814 × 10^-6 N.PLEASE HELP-I LITERALLY NEED THIS RIGHT NOW!!! I'LL GIVE BRAINLIEST AND 5 STARS!!!!!!!!!!!!!!!!
why has the number of islands in hawaii increased over the last 100 million years
Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.
Answer:
Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.
You are trying to find the amount of heat transferred between two substances. In order to do this, you plan
to place both substances in a thermally isolated container and wait until the system reaches thermal
equilibrium. You need to decide what measurements you should take.
Remember that heat transfer is described by the equation Q =mcAT where m is the mass, c is the
specific heat, and AT is the change in temperature. Assume you are able to look up the specific heat
capacities of both substances.
Which of the following sets of measurements would best allow you to determine the heat transfer
between the two substances?
The mass, the initial and the final temperature would let you determine the heat transfer between two substances.
What is meant by heat transfer?Heat transfer refers to the movement of thermal energy from one location or substance to another as a result of a difference in temperature. There are three primary mechanisms for heat transfer: conduction, convection, and radiation.
Conduction is the transfer of heat through direct contact of substances, such as when heat travels from a hot pan to your hand through the handle.
Convection is the transfer of heat through the movement of a fluid, such as when hot air rises and cool air sinks.
To determine the heat transfer between two substances, you need to measure their mass, initial temperature, and final temperature. With these measurements, you can calculate the change in temperature (AT) and use the equation Q = mcAT to determine the heat transfer. The specific heat capacities of both substances can be looked up.
Read more on heat transfer here:https://brainly.com/question/16055406
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What is the gravitational force between two objects of masses 20kg and 50kg separated by a distance of
4m?
Answer:
4.16875×10^-9
Explanation:
given,
mass(M1)=20kg
mass(M2)= 50kg
distance(d)=4m
gravitational constant value (G)=6.67×10^-11
we know,
gravitational force=(Gm1m2)÷d^2
=(6.67×10^-11×20×50)÷4^2
=(6.67×10^-8)÷16
= 4.16875×10^-9
7 point
The heat energy from convection currents in magma also drives the rock
cycle. Convection and movement of the plates causes rock to move
between Earth's surface and interior. It provides the heat that changes
rocks inside Earth to form metamorphic rocks. Igneous rocks form when
magma cools and solidifies. The older rocks that are broken down and
converted to sedimentary rocks might come from igneous and
metamorphic rocks or even older sedimentary rocks. TRUE or FALSE: The
rock cycle is directly related to convection currents.
True
False
If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50 km/h?
Answer:
This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h
24.29m/s or 87.4km/h
Explanation:
Let's find the acceleration of the car:
let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s
a = (vf-vi)/Δt
a = (16.67m/s-0)/8.0
a = 2.08m/s^2
Now we can use this acceleration to find vf in the second part:
50km/h is 13.89m/s
a = (vf-vi)Δt
vf = aΔt + vi
vf = 2.08m/s^2*5.0+13.89m/s
vf = 24.29m/s (87.4km/h)
What does 'has no fixed volume' mean??
Answer:
the volume changes overtime
sometimes because of weather, temperature ...
Explanation:
HELP!!!!!!!!!!!!
9. Estimate the change in the thermal energy of water in a pond with a mass of
1000 kg and a specific heat of 4200 J/(kg. C) if the water cools by 1°C.
Answer:
-4,200,000 J
Explanation:
Which impact would be more forceful, decreasing speed from 60mph to 0 mph over 2 seconds or 0.5 seconds? Explain
A student holds an egg outside of an open window and let's go. The window is 40 meters above the ground and the egg is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
How far will the egg travel after 2 seconds? Be sure to use the 5 steps to solve the problem. Show which equation you used, what each variable equals, and answer the question in a complete sentence.
The distance traveled by the egg after 2 seconds is 19.6 m.
The given parameters:
Height of the window, h = 40 mThe distance traveled by the egg after 2 seconds is calculated as follows;
[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\[/tex]
where;
[tex]v_0_y[/tex] is the initial vertical velocity of the egg = 0g is acceleration due to gravity = 9.8 m/s²t is the time of motion, = 2 s[tex]h = 0 \ + \ \frac{1}{2} \times 9.8 \times (2)^2\\\\h = 19.6 \ m[/tex]
Thus, the distance traveled by the egg after 2 seconds is 19.6 m.
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An aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m drops a package of supplies.
a) Express the initial velocity of the package as a vector. What
observer on the ground.
b) How long will it take for the package to reach the ground?
c) How fast will it be going as it lands? Express your answer as
a vector.
d) Describe the path of the package as seen by a stationary
assumptions have you made about the frame of reference?
e) Describe the path of the package as seen by someone in the
aeroplane.
The motion of the package can be described as the motion of a projectile,
given that it has an horizontal velocity and it is acted on by gravity.
a) [tex]\vec{v}[/tex] = 70·ib) The package will reach ground in approximately 12.77 seconds.c) The speed of the package as it lands is approximately 145.51 m/s.d) The path of the package based on a stationary frame of reference is parabolice) The path of the package as seen from the plane is directly vertical downwards
Reasons:
Velocity of the aircraft = 70 m/s
Direction of flight of the aircraft = Eastward
Height from which the aircraft drops the package, h = 800 m
a) The initial velocity of the package, [tex]\vec{v}[/tex] = 70·i
b) The time it will take the package to reach the ground, t, is given by the formula;
[tex]\displaystyle h = \mathbf{\frac{1}{2} \cdot g \cdot t^2}[/tex]
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
[tex]\displaystyle t = \mathbf{\sqrt{ \frac{2 \cdot h}{g} }}[/tex]
Which gives;
[tex]\displaystyle t = \sqrt{ \frac{2 \times 800}{9.81} } \approx \mathbf{12.77}[/tex]
The time it will take the package to reach the ground, t ≈ 12.77 seconds
c) The vertical velocity just before the package reaches the ground, [tex]v_y[/tex], is given as follows;
[tex]v_y^2[/tex] = 2·g·h
Therefore;
[tex]v_y[/tex] = √(2·g·h)
Which gives;
[tex]v_y[/tex] = √(2 × 9.81 × 800) ≈ 125.28
[tex]v_y[/tex] ≈ 125.28 m/s
Which gives; [tex]\vec{v}[/tex] = 70·i - 125.28·j
Therefore, |v| = √(70² + (-125.28)²) ≈ 143.51
The speed of the package as it lands, |v| ≈ 143.51 m/s
d) The motion of the package that includes both horizontal and vertical motion is a projectile motion.
Therefore;
The path of the package is the path of a projectile, which is a parabolic shape.
e) As seen by someone on the aeroplane, the horizontal velocity will be
zero, therefore, the package will appear as accelerating directly vertical
downwards.
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Pleaseeeee HELPPPP THIS IS TIMED ALSO,
A book slides along a table and comes to a stop. Explain, in detail, all the forces acting on the book.
Answer:
Friction, normal force, and weight
Explanation:
If the book slows down, it means that there must be friction acting in the opposite direction of the direction the book is moving in.
Weight is caused by the gravitational pull of the Earth on the book, and normal force is the table pushing the book up because the book is pushing down on the table (3rd law.)
Note that weight and normal force is not the 3rd law action-reaction pair. The pair is the force of the book on the table and the force of the table on the book.
A roller coaster
produces acceleration due
to changes in both speed
and direction. Applying
Concepts Describe the
acceleration occuring at this
instant on the
rollercoaster ride.
Answer:
the answer is the rollar coster
Explanation:
because the rollar coster is
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ramp from the floor to the top of the same table. Which student did the MOST work?
The student who did the most work is student 2 with 2500 Joules.
Given the following data:
Force 1 = 500 NewtonDistance 1 = 1.2 meterForce 2 = 500 NewtonDistance 2 = 5 meterTo determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
[tex]Work\;done = Force \times distance[/tex]
For student 1:
[tex]Work\;done = 500 \times 1.2[/tex]
Work done = 600 Joules
For student 2:
[tex]Work\;done = 500 \times 5[/tex]
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
Read more: Read more: brainly.com/question/13818347
Answer:student 2 did the most work
Explanation:student 2 did more work because he pushed it up 5 m instead of 1.2.
how is the thermal efficiency of a heat engine defined?