Answer:
It is 2 seconds.
The period of a wave will bed 2 second. Frequency is the inverse of the time period;Option A is correct.
What is frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
Frequency is given by the formula as,
[tex]\rm f = \frac{1}{t} \\\\ t= \frac{1}{f} \\\\ t= \frac{1}{0.5} \\\\ t= 2\ second[/tex]
The period of a wave will be 2 second.
Hence, option A is correct.
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1. Two boxes stacked on top of one another weigh 100 kg total. They apply
a friction force of 250N. You apply a force of 300N in the right direction.
What is the total net force and direction of the box?
Answer:
150
Explanation:
Someone please please please help me with this. I’ll give u whatever rating u want
The vertical forces add up to zero.
The net force on the object is 60N to the right.
F = m • a
60N right = (10kg) • (a)
a = (60N right) / (10kg)
a = 6 m/s^2 to the right
Multi-engine Commercial would be nice.
An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5.0 m. What is its velocity?
Answer:
v = 7.74 m/s
Explanation:
Given that,
The acceleration of the object, a = 12 m/s²
The radius of the circle, r = 5 m
We need to find the velocity of the object. The centripetal acceleration act on the object that is given by :
[tex]a=\dfrac{v^2}{r}\\\\v=\sqrt{ar} \\\\v=\sqrt{12\times 5} \\\\v=7.74\ m/s[/tex]
So, the velocity of the car is 7.74 m/s.
Which of the following examples, would best represent the input energy and then
'wasted energy forms when watching TV.
A. Chemical, and then heat and electrical.
B. Chemical, and then heat, kinetic, sound
C. Electrical, and light, sound, heat
D. Electrical, and then sound and heat
Answer:
I think the answer is c electrical, and light , sound hewt
Suppose that 6 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 43 cm. (a) How much work is needed to stretch the spring from 33 cm to 38 cm
Answer:
Workdone = 0.67 Joules
Explanation:
Given the following data;
Workdone = 6J
Extension = 43 - 28 = 15cm to meters = 15/100 = 0.15m
The workdone to stretch a string is given by the formula;
Workdone = ½ke²
Where;
k is the constant of elasticity.
e is the extension of the string.
We would solve for string constant, k;
6 = ½*k*0.15²
6 = ½*k*0.0225
Cross-multiplying, we have;
12 = 0.0225k
k = 12/0.0225
k = 533.33N/m
a. To find the workdone when e = 33, 38.
Extension = 38 - 33 = 5 to meters = 5/100 = 0.05m
Workdone = ½*533.33*0.05²
Workdone = 266.67 * 0.0025
Workdone = 0.67 Joules
Therefore, the amount of work (in J) needed to stretch the spring from 33 cm to 38 cm is 0.67.
Why won’t anyone help me please anybody help me I really need help .
Answer:
1➡️ this is the method of decomposition
2➡️ H2 and O2
3➡️ b
sorry if I am wrong
A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis through its center, how large is the torque acting on the cylinder? With work please
Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder, [tex]\alpha =0.023\ rad/s^2[/tex]
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
[tex]\tau=I\alpha[/tex]
Where
I is the moment of inertia of the cylinder,
For cylinder,
[tex]I=\dfrac{mr^2}{2}[/tex]
So,
[tex]\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m[/tex]
So, the required torque on the cylinder is 0.011 N-m.
Consider a 2 m wide and 5 m long slab resting on flat, fixed, earthen bed. The slab is 20 cm thick with uniform properties. You may assume the slab is much longer and wider than it is thick. Write the reduced form of the governing equation for the slab. Clearly identify your coordinate system on a sketch and state your assumptions identifying which terms you are eliminating and why.
Answer:
Explanation:
The coordinate sketch for the system is shown in the attached file below. Also, in the cartesian coordinate system, since the height is less than the length and width, we did neglect the height. Thus, we eliminate the height and converted it to a two-dimension.
Please answer this question correctly
20 push ups
hope thats correct^^
Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes to an A-note at 440 Hz while the Boston Symphony Orchestra tunes to 442 Hz. If the speed of sound is constant at 343 m/s, find the magnitude of difference between the wavelengths of these two different A-notes. (Enter your answer in m.)
Answer:
Δλ = 3*10⁻³ m.
Explanation:
At any wave, there exists a fixed relationship between the speed of the wave, the wavelength, and the frequency, as follows:[tex]v = \lambda* f (1)[/tex]
where v is the speed, λ is the wavelength and f is the frequency.
Rearranging terms, we can get λ from the other two parameters, as follows:[tex]\lambda = \frac{v}{f} (2)[/tex]
Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:[tex]\lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m (3)[/tex]
[tex]\lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m (4)[/tex]
The difference between both wavelengths, is just the difference between (3) and (4):[tex]\Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)[/tex]
⇒ Δλ = 3*10⁻³ m.
during what part of their drive are the not moving?
inertia is a measure of
a) a push or pull on an object
b) the difficulty of changing an object's motion
c) a velocity of an object
d) none of the above
Answer:
b.. a difficulty of changing an object's motion, that's my ✨ g u e s s ✨
Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 mm apart and are emitting 1700-HzHz sound waves into a room where the speed of sound is 340 m/sm/s . Consider a point 4.0 mm in front of speaker 1, which lies along a line from speaker 1, that is perpendicular to a line between the two speakers. Is this a point of maximum constructive interference, a point of perfect destructive interference, or something in between
Answer:
The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.
Explanation:
Given data in the question;
first we find the wavelength of the sound λ
Then we find the path-length difference to the point from the two speakers, and divide it by the wavelength.
wavelength λ = velocity / frequency = 340 m/s / 1700 Hz = 0.2 m
L1 = 4 m
L2 = √(4² +2² ) m
delta L = L2 - L1 = √(4² +2² ) m - 4 m = 0.472 m
x = deltaL / λ
If the result is nearly an integer, the waves reinforce at the point.
If it is nearly an integer + 0.5, the waves interfere destructively at the point.
If it is neither, the point is "something in between".
so we solve for x
x = 0.472 m / 0.2m
x = 2.36
since its not an integer, it is not point maximum constructive interference
delta L = ( 2x + 1 ).λ/2
x = ((2deltaL/λ) - 1)/2
x = (((2×0.472)/0.2) - 1)/2
x = 3.72 / 2
x = 1.86
Here also, it is not an integer, so it is not a point perfect destructive interference.
Therefore, The point is neither maximum constructive interference nor perfect destructive interference, the interference is something in between.
how does different color show exist
Answer:Light is made up of wavelengths of light, and each wavelength is a particular colour. The colour we see is a result of which wavelengths are reflected back to our eyes. The visible spectrum showing the wavelengths of each of the component colours. The spectrum ranges from dark red at 700 nm to violet at 400 nm.
Explanation:
hope it helps
Answer:When light hits an object, the object reflects some of that light and absorbs the rest of it. Some objects reflect more of a certain wavelength of light than others. That's why you see a certain colour. For example, a lemon reflects mainly yellow light.
Explanation:
Suppose that the air resistance a car encounters is independent of its speed. When the car travels at 15 m/s, its engine delivers 20 hp to its wheels. What is the power delivered to the wheels when the car travels at 30 m/s
Answer:
22.5 hp
Explanation:
The power delivered to an object is given by :
[tex]P=F\times v[/tex]
Where
F is force and v is velocity of the car.
For the same force, power is directly proportional to the velocity.
So,
[tex]\dfrac{P_1}{P_2}=\dfrac{v_1}{v_2}\\\\P_2=\dfrac{P_1v_2}{v_1}\\\\P_2=\dfrac{15\times 30}{20}\\\\P_2=22.5\ hp[/tex]
So, the new power is 22.5 hp.
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
This question is incomplete, the complete question is;
A positive charge of magnitude Q1 = 6.5 nC is located at the origin.
A negative charge Q2 = -3.5 nC is located on the positive x-axis at x = 16.5 cm from the origin. The point P is located y = 10.5 cm above charge Q2.
Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C.
Answer:
the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
Explanation:
Given the data in the question;
Q1 = 6.5 nC, Q2 = -3.5 nC
from the image below, to get our angle ∅
tan∅ = opp/adj
tan∅ = 10.5 / 16.5
tan∅ = 0.636363
∅ = tan⁻¹( 0.636363 )
∅ = 32.47°
also, r1 = √( 16.5² + 10.5²)
r1 = √( 272.25 + 110.25 )
r1 = √382.5
r1 = 19.55 cm = 0.1955 m
Now, the x-component of the electric field at point P due to charge Q1 will be;
Ex = E2cos32.47°
= (kQ1/r1²)cos32.47°
we know that; k is Coulomb's law constant ( 9 × 10⁹ N.m²/ C²
Q1 = 6.5 nC = 6.5 × 10⁻⁹ C
so we substitute
= ((9 × 10⁹ × 6.5 × 10⁻⁹) / (0.1955)²) cos32.47°
= (58.5 / 0.03822025) × 0.843672
= 1291.33 N/C
Therefore, the x-component of the electric field at point P due to charge Q1 is 1291.33 N/C
A toaster has a resistance of 30 ohms. It draws 2A of current from the outlet. What is the potential difference ?
A. 60v
B. 2v
C. 15v
D.30v
Answer:
60V
Explanation: . V = IR = 1
30*2=60
Water boils to power a steam engine. Which statement best describes the changes in the water as it boils?
Option B
kskmsnsnsmjsjsn
Answer:
C. The potential energy of the particles increases as the intermolecular forces are overcome
Explanation:
A man standing on the Earth can exert the same force with his legs as when he is standing on the moon. We know that the mass of the man is the same on the Earth and the moon. We also know that F=ma is true on both the Earth and the moon. Will the man be able to jump higher on the moon than the Earth? Why or why not?
PLEASE HELPPPP
Answer:
yes
Explanation:
earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity
Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The force on the moon is less than earth as gravity is 1/6 on the moon
When man jump than he will jump high on the moon than the earth.
Earth has gravity force that is high than the moon gravity force which is 1/6 of earth gravity.
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A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exerted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest
Answer:
[tex]m=90.1kg[/tex]
Explanation:
From the question we are told that
Force F=39400
Initial speed [tex]V_1=35m/s[/tex]
Distance[tex]d=1.4m[/tex]
Generally the equation for acceleration is mathematically given by
[tex]a=\frac{V^2-U^2}{2d}[/tex]
[tex]a=\frac{0^2-35^2}{21.4}[/tex]
[tex]a=\frac{0^2-35^2}{21.4}[/tex]
[tex]a=-437.5m/sec^2[/tex]
Generally the equation for mass is mathematically given by
[tex]F=ma\\m=F/a[/tex]
[tex]m=\frac{-39400}{-437.5}[/tex]
[tex]m=90.1kg[/tex]
Besides gravity, what factor keeps the moon and Earth in orbit?
force
inertia
mass
distance
Answer:
interna
Explanation:
please mark as brainllest
1) The cause of magnetism is
A. atoms forming “domains” that are arranged randomly
B. atoms forming "domains” that are arranged uniformly
C. atoms forming "dolomites” that are arranged randomly
D. atoms forming “dolomites” that are arranged uniformly
Answer:
I think it's A, I'm not sure though
I need help with this question
Option 3) a Soccer Ball
will travel the farthest distance.
Answer:
a bowling ball
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Minimum interplanar spacing required for Bragg's diffraction is:
Answer:
Explanation:
\frac{\lambda }{2} is the minimum interplanar spacing which is required for Bragg's diffraction to occur.
Based on the model you saw in the study predict what will happen to the interactions between water molecules as the temperature in the system decreases.
Marking brainliest
Answer:
1 st one
Explanation:
The interactions between water molecules as the temperature in the system decreases b) The interaction between the molecule will become stronger
What is molecular interaction?
Molecular interactions are attractive or repulsive forces between molecules and between non-bonded atoms
When temperature of the system decreases the average kinetic energy of the molecules decreases and they move slowly , the molecular motion get decreased , if the molecules are near each other , the slower they go , more will be molecular interactions , the intermolecular forces attract them to each other .
the correct answer is :
b) The interaction between the molecule will become stronger
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Plz answer this question correctly
Answer:
changing the direction in which a force is exerted
Which equation will tell you the acceleration of the object?
Answer:
In summation, acceleration can be defined as the rate of change of velocity with respect to time and the formula expressing the average velocity of an object can be written as: a =Δ v/ Δt The other 4 equations: d = vit+ (1/2) at2
Explanation:
A rocket has a mass of 156,789 kg and is traveling at 45.6 m/s. How much kinetic energy does the rocket
possess?
Explanation:
K.E =1/2 mv^2
=1/2(156789)(45.6)^2
=78,394.5 × 2,079.36
=163,010,387.52 kg m/s
This should be your answer.
What is the kinetic energy of a 30 kg dog that is running at a speed of 8.6 m/s (about 19 mi/h)?
Answer:
Uhm thags hsed
Explanation:
Dkrr
The floor on a dance hall can take a pressure of 3.5MPa before getting damaged. A lady of mass 60kg wears high heeled shoes. What is the smallest area of the sole of a heel she could wear such that it won't permanently damage the floor
Answer:
smallest area of the heel is 0.000168 m^2
Explanation:
Recall that pressure is defined as: Force / area. Therefore to reach a pressure of 3,500,000 Pa using a force: m * g = 60 kg * 9,8 m/s^2 = 588 N, one needs:
Area = 588 / 3500000 m^2 = 0.000168 m^2