Answer:
204/1015 (irreducible) = 20.1%
1/8120 (irreducible) = 0.01232%
1/5832 (irreducible) = 0.01715%
1/6 (irreducible) = 16.67%
Step-by-step explanation:
PLEASE HURRY! i walked north 8 miles, the west 4 miles, and finally south 5 miles, at the end how far was i from where i started
Answer:
5 miles away
Step-by-step explanation:
If you walked north 8 miles, then west 4 miles, then south 5 miles, you have, in total, travelled 4 miles west and [tex]8-5=3[/tex] miles north.
This creates a triangle, in which we can find the the length of the hypotenuse to find how far away you are now.
We can use the Pythagorean theorem since this is a right triangle.
[tex]a^2+b^2=c^2\\3^2+4^2=c^2\\9+16=c^2\\25=c^2\\c=5[/tex]
Hope this helped!
Answer:
5 miles away
Step-by-step explanation:
An Uber driver provides service in city A and city B only dropping off passengers and immediately picking up a new one at the same spot. He finds the following Markov dependence. For each trip, if the driver is in city A, the probability that he has to drive passengers to city B is 0.25. If he is in city B, the probability that he has to drive passengers to city A is 0.45. Required:a. What is the 1-step transition matrix? b. Suppose he is in city B, what is the probability he will be in city A after two trips? c. After many trips between the two cities, what is the probability he will be in city B?
Answer:
a. 1-step transition matrix is be expressed as:
[tex]P= \left[\begin{array}{cc}0.75&0.25\\0.45&0.55\\\end{array}\right][/tex]
b. The probability that he will be in City A after two trips given that he is in City B = 0.585
c. After many trips, the probability that he will be in city B = 0.3571
Step-by-step explanation:
Given that:
For each trip, if the driver is in city A, the probability that he has to drive passengers to city B is 0.25
If he is in city B, the probability that he has to drive passengers to city A is 0.45.
The objectives are to calculate the following :
a. What is the 1-step transition matrix?
To determine the 1 -step transition matrix
Let the State ∝ and State β denotes the Uber Driver providing service in City A and City B respectively.
∴ The transition probability from state ∝ to state β is 0.25.
The transition probability from state ∝ to state ∝ is 1- 0.25 = 0.75
The transition probability from state β to state ∝ is 0.45. The transition probability from state β to state β is 1 - 0.45 = 0.55
Hence; 1-step transition matrix is be expressed as:
[tex]P= \left[\begin{array}{cc}0.75&0.25\\0.45&0.55\\\end{array}\right][/tex]
b. Suppose he is in city B, what is the probability he will be in city A after two trips?
Consider [tex]Y_n[/tex] = ∝ or β to represent the Uber driver is in City A or City B respectively.
∴ The probability that he will be in City A after two trips given that he is in City B
=[tex]P(Y_0 = 2, Y_2 = 1 , Y_3 = 1) + P(Y_0 = 2, Y_2 = 2 , Y_3 = 1)[/tex]
= 0.45 × 0.75 + 0.55 × 0.45
= 0.3375 + 0.2475
= 0.585
c. After many trips between the two cities, what is the probability he will be in city B?
Assuming that Ф = [ p q ] to represent the long run proportion of time that Uber driver is in City A or City B respectively.
Then, ФP = Ф , also p+q = 1 , q = 1 - p and p = 1 - q
∴
[tex][ p\ \ \ q ] = \left[\begin{array}{cc}0.75&0.25\\0.45&0.55\\\end{array}\right] [ p\ \ \ q ][/tex]
0.75p + 0.45q = q
-0.25p + 0.45q = 0
since p = 1- q
-0.25(1 - q) + 0.45q = 0
-0.25 + 0.25 q + 0.45q = 0
0.7q = 0.25
q = [tex]\dfrac{0.25} {0.7 }[/tex]
q = 0.3571
After many trips, the probability that he will be in city B = 0.3571
what percent is equal to 7/25
What is the solution to the system of equations? -2x-3y+z=-6, z=6, 3x-y+z=13
Answer:
B is the correct answer.
Step-by-step explanation:
-2x+3y+z=-6
z=6
-2x+3y+6=-6
-2x+3y=-12
-2(3)+3(2)
-6+6=0 A is incorrect
-2(3)+3(-2)=-12
-6-6=-12
B is the correct answer.
I am not going to show C or D, because you have the right answer. Hope this helps you. Thank you.
Helppppp thank you!!!
Answer:
G.) 72°
Step-by-step explanation:
A regular pentagon has all it's sides equal.
And all it's internal angles = 108°
The sum of all it's internal angles= 540°
AEB = TRIANGLE
And sum of internal angles In a triangle= 180°
EBDC is quadrilateral and a quadrilateral has it's internal angles summed up to 360°
But DEB = CBE
Let DEB = X
x + x +108+108= 360
2x= 360-216
2x= 144
X= 144/2
X=72
DEB = 72°
Evaluate the polynomial when x = 3 and y = - 8
x2 + y2 + xy
Work Shown:
Replace x with 3, replace y with -8. Use order of operations PEMDAS to simplify.
x^2 + y^2 + x*y
3^2 + (-8)^2 + 3*(-8)
9 + 64 - 24
73 - 24
49
Answer:
49
Step-by-step explanation:
We are given the polynomial:
[tex]x^2+y^2+xy[/tex]
We want to evaluate when x=3 and y= -8. Therefore, we must substitute 3 for each x and -8 for each y.
[tex](3)^2+(-8)^2+(3*-8)[/tex]
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction
Solve the parentheses first. Multiply 3 and -9.
3*-8=-24
[tex](3)^2+(-8)^2 + -24[/tex]
[tex](3)^2+(-8)^2-24[/tex]
Now, solve the exponents.
3^2= 3*3 =9
[tex]9+ (-8)^2 -24[/tex]
-8^2= -8*-8= 64
[tex]9+64-24[/tex]
Add 9 and 64
[tex]73-24[/tex]
Subtract 24 from 73
[tex]49[/tex]
The polynomial evaluated for x=3 and y= -8 is 49.
gaurrik had 15 marbles lakhima had 22 marbles and kairuv had 30 marbles how many marbles did they have altogether?
Answer:
67 marbles
Step-by-step explanation:
15+30=45
45+22=67
Step-by-step explanation:
you cannot add some simple numbers ? you don't know how to use a calculator ?
to solve this yourself is way shorter than putting this in here.
15 + 22 + 30 = 67
Many elementary school students in a school district currently have ear infections. A random sample of children in two different schools found that 16 of 42 at one school and 18 of 34 at the other have ear infections. At the 0.05 level of significance, is there sufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools? Group of answer choices
Answer:
Step-by-step explanation:
The summary of the given data includes;
sample size for the first school [tex]n_1[/tex] = 42
sample size for the second school [tex]n_2[/tex] = 34
so 16 out of 42 i.e [tex]x_1[/tex] = 16 and 18 out of 34 i.e [tex]x_2[/tex] = 18 have ear infection.
the proportion of students with ear infection Is as follows:
[tex]\hat p_1 = \dfrac{16}{42}[/tex] = 0.38095
[tex]\hat p_2 = \dfrac{18}{34}[/tex] = 0.5294
Since this is a two tailed test , the null and the alternative hypothesis can be computed as :
[tex]H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0[/tex]
level of significance ∝ = 0.05,
Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.
The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.
[tex]\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}[/tex]
[tex]\bar p = \dfrac{16 +18}{42 +34}[/tex]
[tex]\bar p = \dfrac{34}{76}[/tex]
[tex]\bar p = 0.447368[/tex]
[tex]\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632[/tex]
The pooled standard error can be computed by using the formula:
[tex]S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }[/tex]
[tex]S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }[/tex]
[tex]S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }[/tex]
[tex]S.E = \sqrt{ 0.01177284105}[/tex]
[tex]S.E = 0.1085[/tex]
The test statistics is ;
[tex]z = \dfrac{\hat p_1 - \hat p_2}{S.E}[/tex]
[tex]z = \dfrac{0.38095- 0.5294}{0.1085}[/tex]
[tex]z = \dfrac{-0.14845}{0.1085}[/tex]
z = - 1.368
Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.
Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools
Locate the points of discontinuity in the piecewise function shown below.
Answer:
Step-by-step explanation:
The given piecewise function i
From the given function it is clear that function is divided at x=-1 and x=2. It means we check the discontinuity at x=-1 and x=2.
For x=-1,
LHL:
Since LHL ≠ f(-1), therefore the given function is discontinuous at x=-1.
For x=2,
LHL:
Since LHL ≠ f(2), therefore the given function is discontinuous at x=2.
Therefore, the correct option is A.
Daniel and Jack together sell 96 tickets to a raffle. Daniel sold 12 more tickets than his friend. How many raffle tickets each friend sell?
Answer:
Daniel sold 54 and Jack sold 42
Step-by-step explanation:
D = number of tickets that Daniel sold
J = number of tickets that Jack sold
D + J = 96
D = 12+ J
Substitute the second equation into the first equation
12 + J + J = 96
Combine like terms
12 + 2J = 96
Subtract 12 from each side
2J = 84
Divide by 2
J = 42
D = J+12
D = 54
Daniel sold 54 and Jack sold 42
Answer:
Jack sold 42 & Daniel sold 54.
Step-by-step explanation:
96 - 12 = 84
84 / 2 = 42
Jack sold 42.
42 + 12 = 54
Daniel sold 54.
42 + 54 = 96
The place value of 7 in 87534 is____________
Plz answer asap question in picture
Answer:
-1 <x < 7
(-1,7)
Step-by-step explanation:
open circle on the left means the number is greater than
-1 <x
Open circle on the right means the number is less than
x < 7
Since both statements are true. we combine them
-1 <x < 7
open circles means parentheses, closed circles mean brackets
Please help me to find this answer
Step-by-step explanation:
angle of a triangle is 180, therefore to get the remaining one, subtract the sum of the two knows from 180, also for the second one; angle on a straight line is as well 180, since you have fine the interior one, subtract it from 180 to get the second answer
Answer:
so angles in a triangle add up to 180,
32+50+m<MQP=180
82+m<MQP=180
m<MQP=180-82
=98°
and angles on a straight line add up to 180 therefore
m<MQR=180-m<MQP
=180-98
=82
I hope this helps and if you don't understand feel free to ask
A scientist needs 120mL of a 20% acid solution for an experiment. The lab has available a 10% solution and a 25% solution. How many milliliters of the 10% solution and how many milliliters of the 25% solution should the scientist mix to make the 20% solution?
Answer:
40 mL of 10% acid
80 mL of 25% acid
Step-by-step explanation:
x = volume of 10% acid solution
y = volume of 25% acid solution
Total volume is:
x + y = 120
Total amount of acid is:
0.10 x + 0.25 y = 0.20 (120)
Solve by substitution.
0.10 x + 0.25 (120 − x) = 0.20 (120)
0.10 x + 30 − 0.25 x = 24
0.15 x = 6
x = 40
y = 80
Simply. Who ever answers this will be marked Brainlist.
Answer:
Step-by-step explanation:
Hello,
[tex]r^3s^{-2}\cdot 8r^{-3}s^4\cdot 4rs^5\\\\=r^{3-3+1}s^{-2+4+5}\cdot 8\cdot 4\\\\\boxed{=32\cdot r\cdot s^7}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Angles One angle is 4º more than three times another. Find
the measure of each angle if
a. they are complements of each other.
b. they are supplements of each other.
[tex] \Large{ \boxed{ \bf{ \color{purple}{Solution:}}}}[/tex]
Let the smaller angle be x
Then, Larger angle would be x + 4°
Case -1:❍ They are complementary angles.
This means, they add upto 90°So,
➙ x + x + 4° = 90°
➙ 2x + 4° = 90°
➙ 2x = 86°
➙ x = 86°/2 = 43°
Then, x + 4° = 47°
So, Our required answer:
Smaller angle = 43°Larger angle = 47°Case -2:❍ They are supplementary angles.
This means, they add upto 180°So,
➙ x + x + 4° = 180°
➙ 2x + 4° = 180°
➙ 2x = 176°
➙ x = 176°/2 = 88°
Then, x + 4° = 92°
So, Our required answer:
Smaller angle = 88°Larger angle = 92°✌️ Hence, solved !!
━━━━━━━━━━━━━━━━━━━━
16% of 242 = ?
Please help me solve this
Answer:
16% of 242 = 38.72
Step-by-step explanation:
16% = 16/100 = 0.16
242 * 0.16 = 38.72
Answer:
38.72
Step-by-step explanation:
242 * .16 = 38.72
look at the image below
A tank contains 1080 L of pure water. Solution that contains 0.07 kg of sugar per liter enters the tank at the rate 7 L/min, and is thoroughly mixed into it. The new solution drains out of the tank at the same rate.Required:a. How much sugar is in the tank at the begining?b. Find the amount of sugar after t minutes.c. As t becomes large, what value is y(t) approaching ?
(a) Let [tex]A(t)[/tex] denote the amount of sugar in the tank at time [tex]t[/tex]. The tank starts with only pure water, so [tex]\boxed{A(0)=0}[/tex].
(b) Sugar flows in at a rate of
(0.07 kg/L) * (7 L/min) = 0.49 kg/min = 49/100 kg/min
and flows out at a rate of
(A(t)/1080 kg/L) * (7 L/min) = 7A(t)/1080 kg/min
so that the net rate of change of [tex]A(t)[/tex] is governed by the ODE,
[tex]\dfrac{\mathrm dA(t)}[\mathrm dt}=\dfrac{49}{100}-\dfrac{7A(t)}{1080}[/tex]
or
[tex]A'(t)+\dfrac7{1080}A(t)=\dfrac{49}{100}[/tex]
Multiply both sides by the integrating factor [tex]e^{7t/1080}[/tex] to condense the left side into the derivative of a product:
[tex]e^{\frac{7t}{1080}}A'(t)+\dfrac7{1080}e^{\frac{7t}{1080}}A(t)=\dfrac{49}{100}e^{\frac{7t}{1080}}[/tex]
[tex]\left(e^{\frac{7t}{1080}}A(t)\right)'=\dfrac{49}{100}e^{\frac{7t}{1080}}[/tex]
Integrate both sides:
[tex]e^{\frac{7t}{1080}}A(t)=\displaystyle\frac{49}{100}\int e^{\frac{7t}{1080}}\,\mathrm dt[/tex]
[tex]e^{\frac{7t}{1080}}A(t)=\dfrac{378}5e^{\frac{7t}{1080}}+C[/tex]
Solve for [tex]A(t)[/tex]:
[tex]A(t)=\dfrac{378}5+Ce^{-\frac{7t}{1080}}[/tex]
Given that [tex]A(0)=0[/tex], we find
[tex]0=\dfrac{378}5+C\implies C=-\dfrac{378}5[/tex]
so that the amount of sugar at any time [tex]t[/tex] is
[tex]\boxed{A(t)=\dfrac{378}5\left(1-e^{-\frac{7t}{1080}}\right)}[/tex]
(c) As [tex]t\to\infty[/tex], the exponential term converges to 0 and we're left with
[tex]\displaystyle\lim_{t\to\infty}A(t)=\frac{378}5[/tex]
or 75.6 kg of sugar.
If tanA = 3
evaluate
CosA + sinA\
casA - SinA
Answer:
Hi, there!!!
I hope you mean to evaluate cosA+ sonA /cosA - sinA.
so, i hope the answer in pictures will help you.
Using only four 4's and any operational sign find the value of 8
Answer:
The answer is 4 + 4 + 4 - 4 = 8
Step-by-step explanation:
The four fours problem is one of the problems given in the book "The Man Who Calculated" by Malba Tahan, a Brazilian-born professor of mathematical sciences.
There are many complicated problems in this book made with the intention of using logic to find a value.
The 4 fours problem is based on using these numbers and using any operation to result in the numbers 1 through 10.
The paper usage at a small copy center is normally distributed with a mean of 5 boxes of paper per week, and a standard deviation of 0.5 boxes. It takes 2 weeks for an order of paper to be filled by its supplier. What is the safety stock to maintain a 99% service level?
Answer:
1.649 approximately 2
Step-by-step explanation:
S.d = standard deviation = 0.5
Time taken = lead time = 2 weeks
Mean = demand for week = 5 boxes
We are required to find the safety stock to maintain at 99% service level.
At 99% level, the Z value is equal to 2.326.
Therefore,
Safety stock = z × s.d × √Lt
= 2.326 × 0.5 x √2
= 1.649
Which is approximately 2.
How do "Combinations" work? What's the formula to solve this equation?
[tex]_nC_k=\dfrac{n!}{k!(n-k)!}\\\\\\_{34}C_{34}=\dfrac{34!}{34!0!}=1[/tex]
In general, [tex]_nC_n=1[/tex]
Solving a word problem on proportions using a unit rate
Lucy made $95 for 5 hours of work.
At the same rate, how much would she make for 13 hours of work?
sl
X Х
5
?
Answer:
$247
Step-by-step explanation:
$95 = 5 h
1 h = 95 ÷ 5 = $19/h
$19 × 13h = $247
she would make $247 after 13 hours of work.
Divide (3x^4-2x^3+4x-5) / (x^2+4)
3x ⁴ = 3x ² • x ². Then
(3x ⁴ - 2x ³ + 4x - 5) - 3x ² (x ² + 4) = -2x ³ - 12x ² + 4x - 5
-2x ³ = -2x • x ². Then
(-2x ³ - 12x ² + 4x - 5) - (-2x) (x ² + 4) = -12x ² + 12x - 5
-12x ² = -12 • x ². Then
(-12x ² + 12x - 5) - (-12) (x ² + 4) = 12x + 43
So we've shown
[tex]\displaystyle \frac{3x^4-2x^3+4x-5}{x^2+4} = 3x^2 - \frac{2x^3+12x^2-4x+5}{x^2+4} \\\\ = 3x^2 - 2x - \frac{12x^2-12x+5}{x^2+4} \\\\ = \boxed{3x^2 - 2x - 7 + \frac{12x+43}{x^2+4}}[/tex]
If
A. x = 62; mZROS = 31°
B. x = 60; mZROS = 28°
C. x= 31; mZROS = 62°
D. X = 28; mZROS = 60°
Answer:
x = 31
ROS = 62
Step-by-step explanation:
QOR + ROS = 90 degrees as indicated by the box
28+ 2x = 90
Subtract 28 from each side
2x = 90 -28
2x = 62
Divide by 2
2x/2 = 62/2
x = 31
ROS = 2x = 2*31 = 62
Answer:
C. x= 31; mZROS = 62°
Step-by-step explanation:
90=28+2x
2x= 90-28
2x= 62
x= 62/2
x=31°
2(x)= 2× 31 = 62
I hope I helped you^_^
A deli sandwich shop is offering either a ham or turkey sandwich, either tomato or vegetable soup, and either coffee or milk for their lunch special. What is the probability that a customer will choose vegetable soup as part of the chosen combination?
Answer:
Ok, the first step is to count all the possible selections that we have and the number of options in each selection:
1) Sandwich: 2 options, ham or turkey.
2) Soup, 2 options, tomato or vegetable.
3) Drink, 2 options, coffee or milk.
(i assume that the sandwich and the soup are separated selections)
Now, if the customer chooses at random, the probability that in one given selection he selects a given outcome is equal to the number of options that match the outcome divided by the total number of options for that selection.
Then in the soup selection we have: options that match the outcome (one, is the vegetable soup). Total number of options = 2.
Then the probability is:
P = 1/2 = 0.5
or 0.5*100% = 50% in percentage form.
Answer:
1/2
Step-by-step explanation:
Write the equation of the line that contains the point (2,1) and is parallel to the line 4x−2y=3
Answer:
y=2x-3
Step-by-step explanation:
4x-2y=3
-2y=3-4x
2y=4x-3
y=4x/2-3/2
y=2x-1.5 m1=2 (the number near x)
If the searched line is parallel to the line 4x−2y=3, m1=m2= 2
y=m2x+b - the searched line
1=2*2+b
b=-3
y=2x-3
Because the sum of angle measures in each triangle is 180°, the
sum of interior angle measures in a quadrilateral is
2 x 180°=
Answer:
It's 360
Step-by-step explanation:
2 x 180 = 360
Can someone please help me solve the equation?
Subtracting 10 from the original equation will shift the graph down 10 units
The answer is D.