WHAT IS THE PERCENT OF HYDROGEN IN CU(C2H3O2)2?
WITH SOLUTION

Answers

Answer 1

Answer:

Hydrogen H 3.330% Carbon C 26.450% Oxygen O 35.234%

Explanation:


Related Questions

Which number is the same as 2.5
10-3?

Answers

The number that is the same as the exponentiation given as follows: 2.5 × 10-³ is 0.0025.

What is exponentiation?

Exponentiation is the process of calculating a power by multiplying together a number of equal factors, where the exponent specifies the number of factors to multiply.

For example, if 10 is multiplied three times, then it can be written as "10 raised to 3" which means 10³. In this case, 10 is the base, and 3 is the exponent.

Therefore, a number 0.0025 can be written in exponentiation as 2.5 × 10-³ by counting the number of zeros forward.

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A 25 L sample of oxygen gas (O2) has a mass of 48 grams and a pressure of 3.0 atm. What would be the temperature of the sample? Reminder: Use the equation PV=nRT, with the constant R = 0.0821 L atm/mol K.
A.
609 K

B.
305 K

C.
19.0 K

D.
1.60 x 10-2 K

Answers

The temperature of the oxygen gas sample is 609 K, which is approximately 336°C or 637°F. The answer is A.

We can use the ideal gas law equation, PV = nRT, to solve for the temperature of the oxygen gas sample.

First, we need to calculate the number of moles of oxygen gas present in the sample using its mass and molar mass:

n = m/M

where:

n = number of moles

m = mass (in grams)

M = molar mass (in g/mol)

The molar mass of oxygen gas (O2) is 32.00 g/mol.

n = 48 g / 32.00 g/mol = 1.50 mol

Next, we can rearrange the ideal gas law equation to solve for temperature (T):

T = (PV) / (nR)

where:

T = temperature (in Kelvin)

P = pressure (in atm)

V = volume (in liters)

n = number of moles

R = gas constant (0.0821 L atm/mol K)

Plugging in the given values, we get:

T = (3.0 atm x 25 L) / (1.50 mol x 0.0821 L atm/mol K)

T = 609 K

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