Answer:
4
Explanation:
In a rate law, The reaction order is basically the superscript (power) of the concentration of the reaction. It defines the extent to which the rate of the reaction depends on the concentration of the reaction.
In this rate law, the order of the reactants are;
[BrO3] = 1
[Br] = 1
[ht] = 2
The overall reaction order is the sum total of the individual orders. We have;
1 +1 + 2 = 4
How is a magnetic field produced?
O when an electromagnetic field interacts with a magnet
O when a current runs through a conductor
O when an object has an electric charge
O when electrons move through a circuit
Answer:
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. ... Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.
Answer: when an electromagnetic field interacts with a magnet
Explanation:
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
Answer:
The pH of the buffer is 3.90
Explanation:
The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:
pH = pKa + log [A-] / [HA]
Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.
To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:
CH3COO- + HCl → CH3COOH + Cl-
The moles of CH3COO- are its initial moles - the moles of HCl added
And moles of CH3COOH are its initial moles + moles HCl added
Moles CH3COO-:
Initial moles = 0.100L * (0.010mol / L) = 0.00100moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.000500 moles
Moles CH3COOH:
Initial moles = 0.100L * (0.040mol / L) = 0.00400moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.003500 moles
pH is:
pH = 4.75 + log [0.000500] / [0.00350]
pH = 3.90
The pH of the buffer is 3.90
The pH of the buffer after addition of 10.0 mL of 50.0mM HCl is 3.90
What is the Henderson-Hasselbach equation?The Henderson-Hasselbach equation is given as:
pH = pKa + log [A-] / [HA]where
pKa of acetic acid (4.75), [A-] is moles of the conjugate base[HA] the moles of thw weak acid.How to determine the moles of CH3COO- and CH3COOHThe formula for calculating number of moles is:
Moles = concentration × volumeThe equation of the reaction is given below:
CH3COO- + HCl → CH3COOH + Cl-
moles of CH3COO- = initial moles - moles of HCl added
moles of CH3COOH = initial moles + moles HCl added
Moles CH3COO-
Molarity = 0.010 M
volume = 100 mL = 0.100 L
Initial moles = 0.100 L * 0.010 M = 0.001 moles
Moles HCl = 0.010L * 0.050 M= 0.0005 moles
Moles CH3COO- = 0.001 - 0.0005 moles
Moles of CH3COO- = 0.000500 moles
Moles CH3COOH:
Molarity = 0.040 M
volume = 100 mL = 0.100 L
Initial moles = 0.100L * (0.040mol / L) = 0.00400moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.004 - 0.0005 moles
Moles CH3COO- = 0.003500 moles
Substituting the calculated values:
pH = 4.75 + log [0.000500] / [0.00350]
pH = 3.90
Therefore, the pH of the buffer after addition of the 10.0 mL 50.0mmHg HCL is 3.90
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can someone help me with this?
Answer:
The growth of any plant is controlled by many factor and it depends on them.
Explanation:
The words are sorted according to their genetic factors and the environment factors by the category on which they effect and impact the growth of a plant.
Genetic factor :
Waxy leaves, bad tasting leaves, disease, leaf structure, types of stem, plant structure, reproduction, types of roots.
Environment factor : sunlight, drought, fire, flood, heat wave, insects, wind, space, pH of soil, temperature, pollution, terrain, soil conditions, lack of air.
What is the theoretical yield of SO3 produced by 8.96 g of S?
Answer: Theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles[/tex]
The balanced chemical equation is:
[tex]2S+3O_2\rightarrow 2SO_3[/tex]
According to stoichiometry :
2 moles of [tex]S[/tex] produce = 3 moles of [tex]SO_3[/tex]
Thus 0.28 moles of [tex]S[/tex] will produce=[tex]\frac{3}{2}\times 0.28=0.42moles[/tex] of [tex]SO_3[/tex]
Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g[/tex]
Thus theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g
After two half-lives, how much of the original material has decayed? 25 percent 50 percent 75 percent 100 percent
The original material has decayed 75%
Further explanationGiven
two half-life
Required
The decayed sample
Solution
General formulas used in decay:
[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t = 2 x t 1/2
Input the value :
[tex]\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%[/tex]
The amount of Nt = 25% No
Calculate the [H+]
and pH of a 0.000295 M
butanoic acid solution. Keep in mind that the a
of butanoic acid is 1.52×10-5
[H⁺]=6.696 x 10⁻⁵
pH = 4.174
Further explanationGiven
The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution
Required
the [H+] and pH
Solution
Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids
For weak acid :
[tex]\tt [H^+]=\sqrt{Ka.M}[/tex]
Input the value :
[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴
[H⁺]=6.696 x 10⁻⁵
pH = - log [H⁺]
pH = - log 6.696 x 10⁻⁵
pH = 5 - log 6.696
pH = 4.174
Phosphate, PO43−, is a polyatomic ion that can combine with any cation to form an ionic compound.
Identify all the formulas below that correctly represent phosphate compounds.
Select one or more:
Combined with lithium:
Li3PO4
Combined with iron(III):
Fe3(PO4)3
Combined with iron(III):
FePO4
Combined with copper(I):
Cu3PO4
Combined with copper(I):
(Cu)3PO4
Combined with magnesium:
Mg3(PO4)2
Combined with magnesium:
Mg2(PO4)3
Combined with lithium:
Li2PO4
Answer:
Li3PO4 - correct
FePO4 - correct
Cu3PO4 - correct
Mg3(PO4)2 - correct
Explanation:
In order to answer this question we must be conversant with the idea of valency as well as the idea of writing formula of ionic substances.
Lithium has a valency of 1 while PO4^3- has a valency of 3 so the correct formula of lithium phosphate must be Li3PO4 after the exchange of valencies.
Iron III has a valency of 3 while the phosphate ion also has a valency of 3 so the subscripts cancel out and iron III phosphate is FePO4.
Copper I ion has a valency of 1 and the phosphate ion has a valency of 3. When they exchange valencies, the formula of the compound is Cu3PO4.
Magnesium has a valency of 2 while the phosphate ion has a valency of 3. The exchange of valency gives us the formula Mg3(PO4)2.
Which statement best defines the resistance of an electric circuit?
it limits the amount of electrical energy that can pass through a circuit.
It is the amount of electrical energy that is available in a circuit
It is the measurement of the rate of electrical energy in a circuit.
It describes how much electrical energy passes in a circuit.
Answer:
electric circuits can be dangerous
Explanation:
Answer:
The first one
it limits the amount of electrical energy that can pass through a circuit.
The Lewis dot notation for two atoms is shown.
Mg is written with two dots on its right. O is written on the right of Mg. There are six dots around O. Two arrows point from the dots near Mg to O.
What is represented by this notation?
Mg gains two protons from O.
Mg donates two protons to O.
Mg gains two electrons from O.
Mg donates two electrons to O.
Answer:
Mg donates two electrons to O
Explanation:
Lewis dot notation uses dots and crosses to represent valence electrons on atoms.
Magnesium is a metal and would donate or lose electrons during bonding.
Oxygen is a non metal and would gain electrons during bonding.
The correct option is;
Mg donates two electrons to O
From where do the placenta and umbilical cord develop?
Answer:
it develops from the womb
Answer:
outer cells of the blastocyst
Explanation:
on edg:)
When an oxidant is present, vitamin C can be converted to a product described as (5R)-5-[(1S)-1,2-dihydroxyethyl]-3,4-dihydroxy-furan-2,3,4(5H)-trione, which retains the furan-based nomenclature of vitamin C and describes the hydrogen placement at atom 5 of the ring. Which of the following statements best describes this vitamin C derivative?A) Vitamin C is reduced to yield a furan ring with 4 carbonyl groups and no double bonds.B) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and 1 double bond.C) Vitamin C is reduced to yield a furan ring with 1 carbonyl group and no double bonds.D) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and no double bonds
Answer:
D) Vitamin C is oxidized to yield a furan ring with 3 carbonyl groups and no double bonds
Explanation:
We can tell that the compound " (5R)-5-[(1S)-1,2-dihydroxyethyl]-3,4-dihydroxy-furan-2,3,4(5H)-trione " has 3 carbonyl groups due to it having "trione" in the name (and it lacking other carbonyl group names, like amide or carboxylic acid).
As there is no "-ene" part of the name referencing a double bond, the only option left is option D).
What is a property of a moving object that makes it hard to stop?
1. Give examples of a catalyst and the reaction it catalyses.
1
Answer:
Explanation:
Iron Haber process = (making ammonia)
Vanadium (V) oxide = Contact process (a stage in making sulfuric acid)
Manganese dioxide = Decomposition of hydrogen peroxide (produces water and oxygen)
A cook grabs the handle of the frying pan and their hand gets very warm. The cook's hand gets very warm because of?
a. conduction
b.radiation
c.convetion
Which of the following does not describe a chemical property?
A. Gasoline burns.
B. Gold does not react with oxygen.
C. Bleach is poisonous when swallowed.
D. Lead is more dense than gold.
The one that does not describe a chemical property is bleach is poisonous when swallowed. The correct options are C.
What are chemical properties?Chemical properties are those properties that show the reactivity of an element. These chemical properties are pH, chemical stability, reactivity, radioactive decay, flammability, toxicity, etc.
Gasoline is a chemical compound, its burning will be a chemical property because it shows how it reacts when it comes in contact with another chemical.
Gold is a pure element, its reactivity tendency is a chemical property, and it is not reactive with oxygen. Density is also a property of an element. And lead is denser than gold, which will show a chemical property.
Thus, the correct options are C. Bleach is poisonous when swallowed.
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A geochemist in the field takes a 25.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 26.° C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 350. mL. Then he filters it and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 3.00 g.1) Using only the information above, can you calculate the solubility of X in water at 26 degrees Celsius.? Yes or No2) If yes than calculate the solubility of X. Round your answer to 3 significant digits
Answer:
Yes we can calculate the solubility
The solubility of the mineral is 120 g/L
Explanation:
We have the information that the sample taken originally from the rock pool is 25.0 mL
So,
25.0 mL of the sample contained 3.000 g of the sample
10000mL of the sample now contains 1000 * 3.000/25 = 120 g
This means that 120 g of the sample dissolves in 1000mL or 1L of solution.
Therefore, the solubility of the mineral is 120 g/L
If an object gets smaller due to a change in state, what happens to its volume? How will this affect its density?
Answer:
the volume of a object will go down but the density stays the same
Which group of elements is listed in order of decreasing size? O oxygen, nitrogen, carbon, boron O xenon, krypton, argon, neon O carbon, silicon, germanium, tin O lead, thallium, mercury, gold
Answer:
oxygen, nitrogen, carbon, boron
Explanation:
What do you call the new material that are created in chemical
Asapp please
The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen,
8.38 % Nitrogen, and 9.57 % Oxygen. If its molar mass is 334.0 g/mol what is its empirical and
molecular formula?
The empirical and molecular formula : C₂₁H₂₂N₂O₂
Further explanationGiven
The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen, 8.38 % Nitrogen, and 9.57 % Oxygen
Required
The empirical and molecular formula
Solution
C : 75.42 : 12 = 6.285
H : 6.63 : 1 = 6.63
N : 8.38 : 14 = 0.599
O : 9.57 : 16 = 0.598
Divide by 0.598
C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2
The empirical formula : C₂₁H₂₂N₂O₂
(C₂₁H₂₂N₂O₂)n = 334
(334)n=334
n = 1
Observation of balloon rub with cloth?
Answer:
When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.
It is common to mix polar solvents (e.g., acetone) with non-polar solvents (e.g., hexane) to obtain an eluting solvent of intermediate polarity. Would it be appropriate to use a water-DMSO mixture
Answer:
No, it is not appropriate to mix water and DMSO
Explanation:
We have to realize that DMSO is a highly polar solvent and water is a highly polar solvent. The question explicitly says that our target is to produce a solvent of intermediate polarity.
We can only do this by mixing a polar and a nonpolar solvent. We have been given the example of the mixture of acetone/hexane which is quite a perfect mixture.
Thus, it is inappropriate to mix DMSO and water.
The water-DMSO mixture has a high polarity and is not appropriate for intermediate polarity solution.
The interactions between solute-solvent result in the solubility and the polarity of the solution. The polar and non-polar solvents result in intermediate polarity of the solution.
What is the polarity of Water-DMSO solute?The water and DMSO both are highly polar in nature. The addition of polar DMSO to polar water results in the dipole-dipole interaction between the molecules.
The interactions result in the solubility of the solute with solvent. However, the polarity of the solution will be high as both the molecules gave synergistic mixture polarity to the solution.
Thus, to obtain the solution of intermediate polarity, water-DMSO mixture is not appropriate.
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Help plz :( Convert 48,000 seconds into hours. (Two step problem, use two conversion factors in a row)
Answer:
13.3 h
Explanation:
Step 1: Given data
Time (t): 48,000 seconds
Step 2: Convert "t" from seconds to minutes
We will use the conversion factor 1 min = 60 s.
48,000 s × 1 min/60 s = 800 min
Step 3: Convert "t" from minutes to hours
We will use the conversion factor 1 h = 60 min.
800 min × 1 h/60 min = 13.3 h
To sum up, 48,000 seconds is equal to 13.3 hours.
How many moles are there in 6.33x10^23 molecules of NH3?
An electric circuit has an expected current of 80 amps An electrician measures the current in the circuit at 120 amps. Which
statement provides a possible explanation for this observation?
There is not enough voltage in the circuit.
The circuit has an extra resistor
A resistor in the circuit is broken
There is not enough electrical energy in the circuit.
How are acids and alkalis
similar?
Answer:h
Explanation:
Answer:
Acids and alkalis both contain ions. Acids contain lots of hydrogen ions, which have the symbol H+. Alkalis contain lots of hydroxide ions, symbol OH-. Water is neutral because the number of hydrogen ions is equal to the number of hydroxide ions.
When N,N-Dimethylaniline is treated with bromine, ortho and para products are observed. However, when N,N-Dimethylaniline is treated with a mixture of nitric and sulfuric acid, only the meta product is observed. Explain these results. (Hint: what can happen to the nitrogen atom in the presence of the strong acids
Answer:
See explanation below
Explanation:
To get a better understanding watch the picture attached.
In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.
In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.
Hope this helps.
A gas sample of 5 moles, has a volume of 95 L. How many moles of the same gas should I add to obtain a volume of 133 L at the same temperature and pressure.
C3H8 (g)+ 502 (g) 3CO2 (g) + 4 H2O (g) + 531 kcal
Answer:
Exotérmica.
Explanation:
¡Hola!
En este caso, dado que la mayoría de reacciones de combustión son exotérmicas, al generar calor en los productos, es posible inferir que esta reacción, referida a la combustion de metano es exotérmica debido a lo anteriormente mencionado, ya que el término de energía de reacción, 531 kcal, está al lado de los productos, lo que quiere decir que es energía generada.
¡Saludos!
Draw a mechanism for the reaction of methanol with sodium amide. In the box to the left, draw any necessary curved arrows. Show the products of the reaction in the box to the right. Include any nonzero formal charges and all lone pairs of electrons. Finally, check the box to indicate which side of the reaction is favored at equilibrium.
Answer:
See explanation
Explanation:
When sodamide reacts with methanol, the following equilibrium is set up;
CH3OH(aq) + NH2-(aq) ⇄ CH3O-(aq) + NH3(aq)
In the reaction, the sodamide acts as a base that abstracts a proton from methanol to yield the conjugate base of methanol which is the methoxide ion.
The forward reaction is favoured at equilibrium.