Answer:
the powerhouse of the cell
A chemist has a block of aluminum metal (density is 2.7 g/mL). The block weighs 2.3 g. What is the volume, in mL, of the aluminum block?
Answer:
0.85 mL
Explanation:
Step 1: Given data
Density of aluminum (ρ): 2.7 g/mLMass of the aluminum block (m): 2.3 gVolume of the aluminum block (V): ?Step 2: Calculate the volume of the aluminum block
Density is an instrisic property. It is equal to the mass of the block divided by its volume.
ρ = m/V
V = m/ρ
V = 2.3 g/(2.7 g/mL)
V = 0.85 mL
Radio waves are used to transmit information on various channels. What is the wavelength of a radio wave having the frequency of 5.40 × 1010 Hz?
Answer:
tyduyfjhg
Explanation:
?
Which of the following can you conclude about a particle labeled
Check all that apply.
D A. It has one nucleon.
B. It has one proton.
I C. It has no neutrons.
D. It has one neutron.
E. It is a beta particle.
F. It has one electron.
G. It is an alpha particle.
Answer:it has one proton,
and one electron
Explanation:
It has one neutron and It has one nucleon
Calculate the molar mass of hafnium (II) iodide, HfI2. This is 1 Hf and 2 Iodine. No hydrogen.
A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use this information to calculate the molarity of the glucose solution.
Answer:
M = 0.138 M
Explanation:
Given data:
Mass of glucose = 12.55 g
Volume of solution = 500 mL
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of glucose:
Number of moles = mass/molar mass
Number of moles = 12.55 g/ 180.156 g/mol
Number of moles = 0.069 mol
Volume in L:
500 mL × 1 L /1000 mL
0.5 L
Molarity:
M = 0.069 mol / 0.5 L
M = 0.138 M
if you know an object's distance from the sun in kilometers,how can you find the distance in AU?
Answer:
We divide our value by 1.5×10⁸
Explanation:
AU is a unit to determine distance in the space.
We know that AU means astronomic unit.
The value for conversion is 1.5×10⁸ Km
1 AU = 1.5×10⁸ Km
Let's see the example:
One star is located from the sun, around 3.35×10¹⁰ Km away. To determine the distance in AU we use the conversion factor:
3.35×10¹⁰ Km . 1 AU / 1.5×10⁸ Km = 223.3 AU
The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.150 M NaOH. It requires 21.4 mL of the NaOH solution to reach the end point of the titration. A buret filled with a titrant is held above a graduated cylinder containing an analyte solution. What is the initial concentration of HCl
Answer:
0.321 M
Explanation:
The neutralization reaction of HCl with NaOH is the following:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
So, 1 equivalent of HCl reacts with 1 equivalent of NaOH. In this case:
1 equivalent HCl = 1 mol HCl
1 equivalent NaOH = 1 mol NaOH
At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:
moles HCl = moles NaOH
M(HCl) x V(HCl) = M(NaOH) x V(NaOH)
We have:
M(NaOH) = 0.150 M
V(NaOH) = 21.4 mL = 0.0214 L
V(HCl) = 10.0 mL = 0.01 L
Thus, we calculate the initial concentration HCl as follows:
M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))
= (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M
Does acid rain make new substances? Construct an argument that uses data from this investigation as evidence for your claim.
Answer:
Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.
Explanation:
Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.
The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.40 moles moles of magnesium perchlorate, Mg(ClO4)2Mg(ClO4)2. Express the number of moles of MgM, Cl Cl, and OO atoms numerically, separated by commas.
Answer:Moles of Mg, Cl, 0 = 5.40, 10.80, 43.2
Explanation:
1 mole of Mg(ClO4)2 contains 1 mole of Magnesium, Mg atoms
2 Moles of Chlorine, Cl atoms
8 Molresof Oxygen atoms
Such that to find the number of moles of each element, We have that
------1 mole Magnesum atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles
------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles
------8 moles Oxygen atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles
An irregularly-shaped piece of aluminum (Al) has a mass of 66.0 grams. What is the volume in cm³ of this piece of aluminum if its density is 2.70 g/cm³?
Answer:
[tex]V=24.45\ \text{cm}^3[/tex]
Explanation:
Given that,
Mass of a piece of Aluminium, m = 66 grams
The density of Aluminium, d = 2.70 g/cm³
We need to find the volume of this piece in cm³.
We know that,
Density = mass per unit volume
[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{66\ g}{2.7\ g/cm^3}\\\\V=24.45\ \text{cm}^3[/tex]
So, the volume of the piece is [tex]24.45\ \text{cm}^3[/tex].
What were the two main reasons that Dmitri Mendeleev's periodic table was more successful than Lothar Meyer's?
Answer:
it helped alot of dcientisd
Explanation:
Answer:
Next, Mendeleev began a text for inorganic chemistry (concerned with substances that are not organic, such as minerals), and the result, Principles__of Chemistry (two volumes, 1868–1870), would become the standard text for the field until early in the 20th century. His research for this book would also lead him to his most renowned work.
Explanation:
A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
2 H2O(l) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is kJ/mol.
Answer: [tex]\Delta H^{0}=-173.72[/tex] kJ/mol
Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.
The standard enthalpy of formation of HCl is calculated as:
[tex]\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}[/tex]
[tex]Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}[/tex] → [tex]CaCl_{2}_{(s)}+2H_{2}O_{(l)}[/tex]
Standard Enthalpy of formation for the other compounds are:
Calcium Hydroxide: [tex]\Delta H^{0}=[/tex] -1002.82 kJ/mol
Calcium chloride: [tex]\Delta H^{0}=[/tex] -795.8 kJ/mol
Water: [tex]\Delta H^{0}=[/tex] -285.83 kJ/mol
Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.
Calculating:
[tex]-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H][/tex]
[tex]-17.2=-1367.46+1002.82-2\Delta H[/tex]
[tex]2\Delta H=17.2-364.64[/tex]
[tex]\Delta H=-173.72[/tex]
So, the standard enthalpy of formation of HCl is -173.72 kJ/mol
what is the molarity of a solutoin which contains 38.5 g of sodium chloride disolved in 325 ml solution ?
Answer:
Molarity = 2.02 M
Explanation:
Given data:
Molarity of solution = ?
Mass of sodium chloride = 38.5 g
Volume of solution = 325 mL (0.325 L)
Solution:
Number of moles = mass/molar mass
Number of moles = 38.5 g/ 58.44 g/mol
Number of moles = 0.658 mol
Molarity:
Molarity = number of moles / volume of solution in L
Molarity = 0.658 mol /0.325 L
Molarity = 2.02 M
Write the balanced COMPLETE ionic equation for the reaction when aluminum nitrate and sodium hydroxide are mixed in aqueous solution. If no reaction occurs, simply write only NR.
Answer:See explanation
Explanation:
MOLECULAR REACTION EQUATION;
Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)
complete ionic equation:
Al^3+(aq) + 3NO3^-(aq) + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)
Net ionic reaction equation;
Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)
What is missing from the temperature and volume
graph shown at right?
An ion can be created when a .................... is lost or gained by an element.
Answer:
electron and ignore this woejdnks
What volume of gold would be equal in mass to a piece of copper with a volume of 121 mL? The density of gold is 19.3 g/mL; the density of copper is 8.96 g/mL.
Answer:
We are tasked to solve for the volume of Gold given that the mass of Gold is equivalent to that of a copper.
Explanation:
Details:
Density of Copper= 8.96 g/ml
Volume of Copper=141 ml
mass of Gold = mass of Copper
Density of Gold=19.3 g/ml
In order to solve for the mass of copper, we need to use the density formula
Density= mass/volume
Since we are to solve for the mass of copper
mass of copper= Density of Copper * Volume of Copper
mass of copper= 8.96 g/ml* 141 ml= 1263.36 g
Thus,
mass of gold=mass of copper=1263.36 g
Hence,
Using still the density formula to solve for the volume of gold,
Volume of gold=mass of gold/ Density of gold
Volume of gold=1263.36 g/ 19.3 g/ml = 65.46 mL
Therefore, the volume of the gold must be 65.46 mL in order to have the same mass of a copper
When C2H4(g) reacts with H2O(g) to form CH3CH2OH(g) according to the following equation, energy is released into the surroundings. C2H4(g) H2O(g) CH3CH2OH(g) Is this reaction endothermic or exothermic
Answer:
Exothermic
General Formulas and Concepts:
Chemistry
Thermodynamics
Exothermic - releases heat as a productEndothermic - absorbs heat as a reactantExplanation:
We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is releasing heat.
This means that heat would be product as it is being released during the reaction.
Therefore, we have an exothermic reaction.
What are the ingredients in a margaritaWhat are the ingredients in a margarita drink
Answer:
cointreau, tequila,lime juice
Question text What is the mole fraction of benzene in a benzene-toluene solution whose vapor pressure is 51 torr at 20°C?
Answer:
Mole fraction for benzene is 0.683
Explanation:
We need to determine the colligative property about vapour pressure which formula is:
ΔP = P° . Xm
where P° is vapour pressure of pure solvent.
ΔP = Vapor pressure of pure solvent - Vapor pressure of solution
In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.
P° of benzene at 20°C is 74.7 Torr
Xm is the value for the mole fraction of solute.
Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm
Xm = 0.317 → That's the mole fraction for toluene.
Then, mole fraction for benzene will be: 1 - 0.317 → 0.683
how many moles of H2O are needed to react with a mole of 3.0 of Na?
Answer: 3.0 moles of water [tex](H_2O)[/tex] are needed to react with a mole of 3.0 of Na
Explanation:
The balanced chemical reaction of sodium with water is as follows:
[tex]2Na+2H_2O\rightarrow 2NaOH+H_2[/tex]
According to stoichiometry:
2 moles of sodium [tex](Na)[/tex] reacts with = 2 moles of water [tex](H_2O)[/tex]
Thus 3.0 moles of sodium [tex](Na)[/tex] reacts with = [tex]\frac{2}{2}\times 3.0=3.0[/tex] moles of water [tex](H_2O)[/tex]
3.0 moles of water [tex](H_2O)[/tex] are needed to react with a mole of 3.0 of Na
reddit mcat In a titration, 27.4 mL of a 0.0154 M solution of Ba(OH)2 is needed to neutralize 20.0 mL of HCl. What was the concentration of the acid solution
Answer:
0.422 M
Explanation:
Equation of the reaction,
2HCl(aq) + Ba(OH)₂(aq) ⇒ BaCl₂(aq)+2H₂O(l)
From the recation above,
2 moles of HCl is needed to neutralize 1 mole of Ba(OH)₂.
Using,
C'V'/CV = a/b......................... Equation 1
Where C' = concentration of acid, C = concentration of base, V' = volume of acid, V = volume of base, a = number of moles of acid, b = number of moles of base.
make C' the subject of the equation.
C' = aCV/bV'................. Equation 2
a = 2 mole, b = 1 mole, C = 0.0154 M, V = 27.4 mL, V' = 20 mL
Substitute into equation 2
C' = (2×0.0154×27.4)/(1×20)
C' = 0.422 M.
Hence the concentration of acid is 0.422 M
A substance has a density of .80g/cm3 if you have 60cm3 what is the mass?
Answer:
168.56
Explanation:
Answer:
48 grams
Explanation:
If p and V are already given, calculate m by multiplying those two values.
m = pV
m = 4/5 * 60/1
m = 240/5
m = 48 grams
The mass of that substance is 48 grams.
Why do earthquakes occur more often in some countries than in others?
Answer:
Some places have more earthquakes than others because they sit on the edges of tectonic plates.
A student measures 48.8 mL of concentrated nitric acid, which has a density of 1.55g/ mL. What is the mass of the acid?
The mass of the acid : 75.64 g
Further explanationGiven
volume = 48.8 ml
density = 1.55 g/ml
Required
the mass
Solution
Further explanation
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]
Input the value :
mass = ρ x V
mass = 1.55 g/ml x 48.8 ml
mass = 75.64 g
Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have to convert from grams to troy ounces as well.)
Answer:
0.010 $.
Explanation:
Hello!
In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:
[tex]1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}[/tex]
Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:
[tex]m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g[/tex]
Thus, the price is:
[tex]\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$[/tex]
Best regards!
Neutralisation reactions
A)endothermic
B)exothermic
Answer:
Neutralisation reactions are generally B) Exothermic.What is the mass of 1.2x10^25 atoms of Helium
Answer:
dunno
Explanation:
sorry
P4010
+ 4P + 5 O2
How many moles of phosphorus would be
produced if 8.19 mol of P4010 reacted? Enter
your answer with 2 decimal places.
Answer:
32.76mole of P
Explanation:
The reaction expression is given as;
P₄O₁₀ → 4P + 5O₂
Given parameters:
Number of moles of P₄O₁₀ = 8.19mol
Unknown:
Number of moles of P produced = ?
Solution:
From the balanced reaction expression;
1 mole of P₄O₁₀ will produce 4 mole of P
8.19mole of P₄O₁₀ will therefore produce 4 x 8.19 = 32.76mole of P
A 2.54 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL h2o. What will be the final volume reading on the graduated cylinder, in mL?
Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure
Explanation:
Answer:
12.49 ml
Explanation:
Density = mass / volume
Volume = mass / density
Volume of zinc = 2.54/7.14
Volume of zinc = 0.3557
Initial volume = 12.13 ml
Total volume = initial volume+ volume of zinc
Total volume = 12.13 + 0.3557
Total volume = 12.4857 = 12.49 ml