Answer:
Explanation:
In such a situation like this one, the first step would be to identify the brand and model of the video card itself. Once you find the brand and model you can simply go over to the brand manufacturer's website and go to the driver downloads section. There you simply search for the model series of the video card in your computer and download/install the latest version. The brand manufacturer's official website always has the most up to date drivers for all of their hardware.
Which is the first step in the process of reading materials critically
Answer:
SQRRR or SQ3R is a reading comprehension method named for its five steps: survey, question, read, recite, and review. The method was introduced by Francis P. Robinson, an American education philosopher in his 1946 book Effective Study. The method offers a more efficient and active approach to reading textbook material
A file concordance tracks the unique words in a file and their frequencies. Write a program that displays a concordance for a file. The program should output the unique words and their frequencies in alphabetical order. Variations are to track sequences of two words and their frequencies, or n words and their frequencies.
Below is an example file along with the program input and output:
example.txt
I AM SAM I AM SAM SAM I AM
Enter the input file name: example.txt
AM 3
I 3
SAM 3
Answer:
I am writing a Python program.
def concordance(filename): # function that takes a file name as parameter and returns the concordance for that file
file = open(filename,"r") #opens file in read mode
unique={} #creates and empty list
for word in file.read().split(): #loops through every word in the file
if word in unique: # if words is already present in the list
unique[word] += 1 #add 1 to the count of the existing word
else: #if word is not present in the list
unique[word] = 1 #add the word to the list and add 1 to the count of word
file.close(); # close the file
for x in sorted(unique): #sort the list and displays words with frequencies
print(x, unique[x]); #prints the unique words and their frequencies in alphabetical order
#prompts user to enter the name of the file
file_name=input('Enter the input file name: ')
concordance(file_name) #calls concordance method by passing file name to it
Explanation:
The program has a function concordance that takes a text file name as parameter and returns a list of unique words and their frequencies.
The program first uses open() method to open the file in read mode. Here "r" represents the mode. Then creates an empty list named unique. Then the for loop iterates through each word in the file. Here the method read() is used to read the contents of file and split() is used to return these contents as a list of strings. The if condition inside the loop body checks each word if it is already present in the list unique. If the word is present then it adds 1 to the count of that word and if the word is not already present then it adds that unique word to the list and assign 1 as a count to that word. close() method then closes the file. The second for loop for x in sorted(unique): is used to display the list of unique words with their frequencies. sorted() method is used to sort the list and then the loop iterates through each word in the list, through x, which acts like an index variable, and the loop displays each word along with its frequency.
The conversion of symbolic op codes such as LOAD, ADD, and SUBTRACT to binary makes use of a structure called the ____.
Answer:
Op code table.
Explanation:
In Computer programming, an Op code is the short term for operational code and it is the single instruction which can be executed by the central processing unit (CPU) of a computer.
The conversion of symbolic op codes such as LOAD, ADD, and SUBTRACT to binary makes use of a structure called the Op code table. The Op code can be defined as a visual representation of the entire operational codes contained in a set of executable instructions.
An Op code table is arranged in rows and columns which basically represents an upper or lower nibble and when combined depicts the full byte of the operational code. Each cells in the Op code table are labeled from 0-F for the rows and columns; when combined it forms values ranging from 00-FF which contains information about CPU cycle counts and instruction code parameters.
Hence, if the operational code table is created and sorted alphabetically, the binary search algorithm can be used to find an operational code to be executed by the central processing unit (CPU).
A continuous-time periodic signal x(t) is real valued and has a fundamental period T = 8. The nonzero Fourier series coefficients for x(t) are specified as
a_1 = a*_-1 = j, a_5 = a_-5 = 2.
Express x(t) in the form
x(t) = sigma^infinity_k=0 A_k cos(W_k t + phi_k).
Answer:
x(t) = −2 cos ( [tex]\frac{\pi }{4}t[/tex] − [tex]\frac{\pi }{2}[/tex] ) + 4 cos ( [tex]\frac{5\pi }{4}t[/tex] )
Explanation:
Given:
Fundamental period of real valued continuous-time periodic signal x(t) = T = 8
Non-zero Fourier series coefficients for x(t) :
a₁ = [tex]a^{*}_{-1}[/tex] = j
a₅ = [tex]a_{-5}[/tex] = 2
To find:
Express x(t) in the form
∞
x(t) = ∑ A[tex]_{k}[/tex] cos ( w[tex]_{k}[/tex] t + φ[tex]_{k}[/tex] )
[tex]_{k=0}[/tex]
Solution:
Compute fundamental frequency of the signal:
w₀ = 2 π / T
= 2 π / 8 Since T = 8
w₀ = π / 4
∞
∑ [tex]a_{k}e^{jw_{0}t }[/tex]
x(t) = k=⁻∞
= [tex]a_{1}e^{jw_{0} t} + a_{-1}e^{-jw_{0} t} + a_{5}e^{5jw_{0} t}+a_{-5}e^{-5jw_{0} t}[/tex]
= [tex]je^{j(\pi/4)t} - je^{-j(\pi/4)t} +2e^{(5\pi/4)t}+2e^{-(5\pi/4) t}[/tex]
= −2 sin ( [tex]\frac{\pi }{4}t[/tex] ) + 4 cos ( [tex]\frac{5\pi }{4}t[/tex] )
= −2 cos ( [tex]\frac{\pi }{4}t[/tex] − [tex]\frac{\pi }{2}[/tex] ) + 4 cos ( [tex]\frac{5\pi }{4}t[/tex] )
in an agile team who is responsible for tracking the tasks
Answer:
All team members
Explanation:
In respect of the question, the or those responsible for tracking the tasks in an agile team comprises of all the team members.
Agile in relation to task or project management, can be refer to an act of of division of project or breaking down of project or tasks into smaller unit. In my opinion, these is carried out so that all team members can be duly involved in the tasks or project.
Summary
In this graded assignment, you will write Python programs that use loops to implement various algorithms.
Learning Outcomes
In completing this assignment, you will:
• Gain more experience converting an algorithm expressed using flowchart to one implemented in a Python program.
• Write a Python program using loops
Description
In a previous assignment in this course, you were asked to draw a flowchart for an algorithm that finds the two smallest items in a list, and then another assignment asked you to convert that flowchart to pseudocode.
Here is a pseudocode implementation of that algorithm:
1. min1- list
2. min2 - list,
3. for each item in list
4. if item
5. then if min1
6. then min2
7. else mint
8. else if item
9. then min2
10. output: min1, min2 item item item
Now, implement the algorithm in Python so that it correctly sets the values of min1 and min2 which should hold the two smallest values in the list, though not necessarily in that order.
In the code below, we have provided a list called "list" and initialized min 1 and min2 to hold the first two elements. Write your code starting at line 5 (you can remove the comments starting at line 6, and may need more space than what is provided), and be sure that the values of min1 and min2 are correctly set before the code reaches the "return (min1, min2)" statement on line 11.
As in the previous assignment, we will be using the Coursera automatic grading utility to test your code once you submit this quiz for grading, and this requires it to be within a function. So be sure that all of the code after line 1 is indented, and that you do not have any code after the "return (min 1, min2)" statement.
Keep in mind that the goal here is to write a program that would find the two smallest values of any list, not just the one provided on line 2. That is, don't simply set min 1 and min2 to-2 and -5, which are the two smallest values, but rather write a program that implements the algorithm from the flowchart and correctly sets min1 and min2 before reaching the return (min1, min2)" statement.
As before, you can test your program by clicking the "Run" button to the right of the code to see the results of any "print" statements, such as the one on line 10 which prints min1 and min2 before ending the function. However, please be sure that you do not modify the last two lines of the code block
1. def test(): # do not change this line!
2. list = [4, 5, 1, 9, -2, 0, 3, -5] # do not change this line!
3. min1 = list[0]
4. min2 = list[1]
5.
6. #write your code here so that it sets
7. #min1 and min2 to the two smallest numbers
8. # be sure to indent your code!
9.
10. print(min1, min2)
11. return (min1, min2) # do not change this line!
12. # do not write any code below here
13.
14. test() # do not change this line!
15. # do not remove this line!
Hints: The Python code for this algorithm is very similar to the pseudocode! Just be sure you are using the correct syntax. As in previous activities, don't forget that you can use the "print" function to print out intermediate values as your code is performing operations so that you can see what is happening
what is the difference between ram and rom
Answer:
RAM is used to store programs and data the CPU needs. ROM has prerecorded data and is used to boot the computer
Explanation:
Normally you depend on the JVM to perform garbage collection automatically. However, you can explicitly use ________ to request garbage collection.
Answer:
System.gc()
Explanation:
System.gc() can be defined as the method which can be used to effectively request for garbage collection because they runs the garbage collector, which in turn enables JMV which is fully known as JAVA VIRTUAL MACHINE to claim back the already unused memory space of the objects that was discarded for quick reuse of the memory space , although Java virtual machine often perform garbage collection automatically.
Consider a system running ten I/O-bound tasks and one CPU-bound task. Assume that the I/O-bound tasks issue an I/O operation once for every millisecond of CPU computing and that each I/O operation takes 10 milliseconds to complete. Also assume that the context switching overhead is 0.1 millisecond and that all processes are long-running tasks. What is the CPU utilization for a round-robin scheduler when:
Answer:
10 minutes
Explanation:
Write a program that takes as command-line arguments an integer N and a double value p (between 0 and 1), plots N equally spaced dots of size .05 on the circumference of a circle, and then, with probability p for each pair of points, draws a gray line connecting them.
Answer:
Please see below
Explanation:
Suppose N = 10. And you have these dots equidistant from each other, and probability = 0.3. According to the data provided in the question statement, we will then have forty-five pairs of points. The task is to draw lines amongst these pairs, all 45 of them, with a 30% probability. Keep in mind that every one of the 45 lines are independent.
A few lines of simple code (just some for loops) needed to run this is attached in the image herewith, .
#The Fibonacci sequence is a number sequence where each #number is the sum of the previous two numbers. The first #two numbers are defined as 0 and 1, so the third number is #1 (0 + 1 = 1), the fourth number is 2 (1 + 1 = 2), the #fifth number is 3 (1 + 2 = 3), the sixth number is 5 #(2 + 3 = 5), and so on.
#
#Below we've started a class called FibSeq. At any time, #FibSeq holds two values from the Fibonacci sequence: #back1 and back2.
#
#Create a new method inside FibSeq called next_number. The #next_number method should:
#
# - Calculate and return the next number in the sequence, # based on the previous 2. # - Update back2 with the former value of back1, and update # back1 with the new next item in the sequence.
#
#This means that consecutive calls to next_number should #yield each consecutive number from the Fibonacci sequence. #Calling next_number 5 times would print 1, 2, 3, 5, and 8.
class FibSeq:
def __init__(self):
self.back1 = 1
self.back2 = 0
def next_number(self):
self.back1=self.back1+self.back2 # updated the back1 value to the next number in the series first
self.back2=self.back1-self.back2 #updated the back2 value with previous back1 value
yield (self.back1) # yielded the next number in the series since it is updated as back1 so yielded back1
f = FibSeq()
for i in range(5): # here i have iterated the series only 5 times u can change it as you like
s=f.next_number()
print(next(s))# here next is an iterator function for the yield generator.
#The code below will test your method. It's not used for
#grading, so feel free to change it. As written, it should
#print 1, 2, 3, 5, and 8.
newFib = FibSeq()
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
Answer:
Here is the next_number method:
def next_number(self): #method to return next number in the sequence
temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable
self.back2 = self.back1 #Updates back2 with the former value of back1,
self.back1 = temporary #update back1 with the new next item in the sequence.
return temporary #
Explanation:
I will explain the working of the above method.
back1 = 1
back2 = 0
At first call to next_number() method:
temporary = back1 + back2
= 1 + 0
temporary = 1
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 1
return temporary
This return statement returns the value stored in temporary variable i.e. 1
Output: 1
back1 = 1
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 1 + 1
temporary = 2
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 2
return temporary
This return statement returns the value stored in temporary variable i.e. 2
output: 2
back1 = 2
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 2 + 1
temporary = 3
self.back2 = self.back1
self.back2 = 2
self.back1 = temporary
self.back1 = 3
return temporary
This return statement returns the value stored in temporary variable i.e. 3
Output: 3
back1 = 3
back2 = 2
At second call to next_number() method:
temporary = back1 + back2
= 3 + 2
temporary = 5
self.back2 = self.back1
self.back2 = 3
self.back1 = temporary
self.back1 = 5
return temporary
This return statement returns the value stored in temporary variable i.e. 5
Output: 5
back1 = 5
back2 = 3
At second call to next_number() method:
temporary = back1 + back2
= 5 + 3
temporary = 8
self.back2 = self.back1
self.back2 = 5
self.back1 = temporary
self.back1 = 8
return temporary
This return statement returns the value stored in temporary variable i.e. 8
Output: 8
Calling next_number 5 times would print 1, 2, 3, 5, and 8.
The complete program along with its output is attached.
What will be displayed if code corresponding to the following pseudocode is executed? Set Number = 4 Repeat Write 2 * Number Set Number = Number + 2 Until Number = 8
Answer:
8
12
Explanation:
I made the code a bit easier to understand then worked out how it would go. Here's what I did.
number = 4
repeat until number = 8:
write 2 * number
number = number + 2
Following this itenary, we have, the system first writes "8" as it multipled 4 by 2. Number is now equal to 6.
Next repetition, the system writes "12" as it multipled 6 by 2. Now, number = 8. The proccess now stops as number is now equal to 8.
You want to change your cell phone plan and call the company to discuss options. This is a typical example of CRM that focuses on_______loyalty programs for current customerscustomer service and supportprofitability for the companyacquisition of new customers.
Answer:
customer service and support
Explanation:
-Loyalty programs for current customers refer to incentives companies provide to existing customers to encourage them to keep buying their products or services.
-Customer service and support refers to the assistance companies provide to their existing customers to help them solve issues or provide information about their current products or services and other options.
-Profitability for the company refers to actions that will increase the financial gains of the company.
-Acquisition of new customers refers to actions implemented to attract clients.
According to this, the answer is that this is a typical example of CRM that focuses on customer service and support because you call the company to get assistance with options to change your current products.
The other options are not right because the situation is not about incentives for the customer or actions the company implements to increase its revenue. Also, you are not a new customer.
What can you do using the start menu in windows 10
Answer:
The start menu in windows 10 has similarities.
Explanation:The windows 10 is start menu and start screen. Installed windows 10 on a PC, the start button after windows appear start menu.Windows app you can access windows apps right the menu. click the left display all apps installed your personal computer. click right to open a window app NEWS,MAIL, or CALENDAR. POWER button at the bottom of the left side, and display the to shut down and restart.
Right click your account name at the top the menu.You add files explorer to taskbar.Simply click the option you needed
A password checking system that disallows user passwords that are proper names or words that are normally included in a dictionary is an example of _____ with respect to security systems.
Open up your database administraton GUI, and use the appropriate SQL Query Tool to write the SQL CREATE statement for your BOOK_TAGS table. You can either write the script manually and execute it through pgAdmin or you can create the table by using pgAdmin's wizard.
Afterwards, insert one row of dummy data that adds a tag to the sample book in the BOOKS table.
Answer:
nxlskshwhhwwlqlqoejebx znznxjslaa
The machine has to be returned to the vendor for proper recycling. Which stage of the hardware lifecycle does this scenario belong to?
Answer:
Decommission/Recycle
Explanation:
This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.
A brand of shame .. from infancy " is a brand on Jocasta
Answer: DIDN'T UNDERSTAND
Draw the BST where the data value at each node is an integer and the values are entered in the following order 36,22,10,44,42,16,25,3,23,24 solution
Answer and Explanation:
A BST is the short form for Binary Search Tree. It is a special type of binary tree data structure in which nodes are arranged in a particular order such that;
i. the left subtree of a particular node should always contain nodes whose key values are less than that of the key value of the node itself.
ii. the right subtree of a particular node should always contain nodes whose key values are greater than that of the key value of the node itself.
iii. the right and left subtrees should also be a binary search tree.
For the given set of data:
36,22,10,44,42,16,25,3,23,24;
The equivalent binary search tree is attached to this response.
As shown in the attachment:
i. the first data value (36) is the root node value.
ii. the second value (22) is less than the root node value (36), therefore, 22 goes to the left of the root node.
iii. the third value is 10. This is less than 36 and then also less than 22, so 10 goes to the left of 22.
iv. the fourth value is 44. This is greater than the root node value (36), therefore, 44 goes to the right of the root node.
v. the fifth value is 42. This is greater than the root value (36) so it is going to be positioned somewhere at the right of the root node. But it is less than the value (44) of the direct right node of the root node. Therefore, 42 goes to the left of the direct right (44) of the root node.
vi. the sixth value is 16. This is less than the root node value (36). So it is going to be positioned somewhere at the left of the root node. It is also less than the value (22) of the direct left node of the root node. So it is going to be positioned somewhere at the left of the node with 22. But it is greater than the node with 10. Therefore, 16 is going to be to the right of the node with 10.
This trend continues until all data values have been rightly positioned.
PS: A binary tree is a data structure in which each node cannot have more than two nodes directly attached to it.
Write a program that reads ten integers, and then display the number of even numbers and odd numbers. Assume that the input ends with 0. Here is the sample run of the program
Answer:
I am writing a JAVA program. Let me know if you want this program in some other programming language.
import java.util.Scanner; // class to take input from user
class EvenOddNum{ //class name
static void EvenOdd(int array[]) { //function that takes an array as input and displays number of even numbers and odd numbers
int even = 0; // counts even numbers
int odd = 0; //counts odd numbers
for(int i = 0 ; i < array.length-1 ; i++){ //loop through the array elements till the second last array element
if ((array[i] % 2) == 1) { // if the element of array is not completely divisible by 2 then this means its an odd number
System.out.println(array[i]+" = odd"); //display that element to be odd
odd++ ; } //adds 1 to the count of odd every time the program reads an odd number
else{ // if above IF condition evaluates to false then the number is an even number
System.out.println(array[i]+" = even"); //display that element to be odd
even++ ; } } //adds 1 to the count of odd every time the program reads an odd number
System.out.println( "Number of even numbers = " + even); //counts the total number of even integers in the array
System.out.println( "Number of odd numbers = " + odd); } //counts the total number of odd integers in the array
public static void main (String[] args){ //start of main function body
Scanner scan= new Scanner(System.in); //creates Scanner class object
int [] integers = new int[10]; //declares an array named integers that stores 10 integers
System.out.print("Enter numbers: "); //prompts user to enter the integers
for(int i = 0;i<integers.length;i++){ //loops to read the input integers
integers[i] = scan.nextInt(); } //scans and reads each integer value
EvenOdd(integers); } } //calls function EvenOdd to display number of even and odd numbers
Explanation:
The program has a method EvenOdd that takes an array of integers as its parameter. It has two counter variables even and odd. even counts the number of even input integers and odd counts the number of odd input integers. The for loop iterates through each element (integer) of the array except for the last one. The reason is that it is assumed that the input ends with 0 so the last element i.e. 0 is not counted. So the loop iterates to length-1 of the array. The number is odd or even is determined by this if condition: if ((array[i] % 2) == 1) A number is even if it is divisible by 2 otherwise its odd. If the element of array is not completely divisible by 2 i.e. the remainder of the division is not 0 then the number is odd. The modulo operator is used which returns the remainder of the division of number by 2. Each time when an odd or even number is determined, the array[i]+" = even" or array[i]+" = odd" is displayed on the output screen for each integer in the array. Here array[i] is the element of the array and even or odd depicts if that element is even or odd. The last two print statement display the total number of even and odd numbers in the array.
What is displayed in the alert dialog box after the following code is executed? var scores = [70, 20, 35, 15]; scores[scores.length] = 40; alert("The scores array: " + scores);
Answer:
The scores array: 70,20,35,15,40
Explanation:
I will explain the code line by line:
var scores = [70, 20, 35, 15];
The above statement declares and assigns values to an array named scores
scores[scores.length] = 40;
The above statement uses length to set the length of the scores array. It sets the last element of the scores array to 40. So this means 40 is set as the last element of scores.
scores.length returns the length of the scores array i.e. 4 as there are 4 elements in scores array 70,20,35,15
So the statement becomes:
scores[4] = 40;
This assigns value 40 to the 4th index of the scores array. Do not confuse 4th index with 4th element of the array because array element location starts from 0. So scores[4] does not mean 4th element but scores[4] means 4th index position of scores array. This makes 5th element of scores. So set the element 40 as 5th element at 4th index of scores.
alert("The scores array: " + scores);
This displays an alert box with the following message:
The scores array: 70,20,35,15,40
if the bandwidth-delay product of a channel is 500 Mbps and 1 bit takes 25 milliseconds to make the roundtrip, what is the bandwidth-delay product
Answer:
2500 kb
Explanation:
Here, we are to calculate the bandwidth delay product
From the question, we are given that
band width = 500 Mbps
The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3
= 2500 Kbits
Write a program that extracts the last three items in the list sports and assigns it to the variable last. Make sure to write your code so that it works no matter how many items are in the list
Answer:
sports = ["football", "basketball", "volleyball", "baseball", "swimming"]
last = sports[-3:]
print(last)
Explanation:
*The code is in Python.
Create a list called sports
Create a variable called last and set it to the last three elements of the sports list using slicing
Print the last
Write a method isSorted that accepts a stack of integers as a parameter and returns true if the elements in the stack occur in ascending (non-decreasing) order from top to bottom, and false otherwise.
Explanation:
bottom [20, 20, 17, 11, 8, 8, 3, 21 top the following stack is not sorted (the 15 is out of place), so passing it to your method should return a result of false: bottom [18, 12, 15, 6, 11 top an empty or one-element stack is considered to be sorted. when your method returns, the stack should be in the same state as when it was passed in. in other words, if your method modifies the stack, you must restore it before returning.
Using a variable length array, write a C program that asks the user to enter test scores.Then, the program should calculate the average, determine the lowest test score, determine the letter grade, and display all three.
Answer:
Here is the C program :
#include<stdio.h> // to use input output functions
int main(){ //start of main() function body
int n; //to store the number of tests taken
int test_scores[n], i; //a variable length array test_score
float sum=0,average; //to store the sum and average of test scores
int lowest; //to store the lowest test score
printf("Enter the number of tests taken :");//prompts user to enter number of test scores
scanf("%d",&n); / / reads the value of n from user
printf("Enter test scores: "); //prompts user to enter test scores
for(i=0; i<n; i++) {
scanf("%d",&test_scores[i]); //read the values of input test scores
sum = sum + test_scores[i]; } //calculates the sum of the test scores by adding the values of test scores
average=sum/n; // compute the average by dividing sum of all test scores with the total number of test scores
printf("Average is %.2f",average); //displays the average
printf("\nGrade is "); // prints Grade is
if (average >= 90) { //if value of average is greater than or equal to 90
printf("A"); } //print the grade letter A
else if(average >= 80 && average < 90) { //if value of average is greater than or equal to 80 and less than 90
printf("B"); } //print the grade letter B
else if(average>60 && average<80){ //if value of average is between 60 and 80
printf("C"); } //print the grade letter C
else if(average>40 && average<=60) { //if value of average is greater than 40 and less than or equals to 60
printf("D"); } //print the grade letter D
else { //if the value of average is below 40
printf("F"); } //print the grade letter F
lowest = test_scores[0]; //lowest points to the 1st element of test scores means the first input test score
for (int j = 1; j < n;j++) { //loop iterates through the scores
if (test_scores[j] < lowest) { // if the element at j-th index position of test_scores array is less than the element stored in the lowest variable
lowest = test_scores[j]; } } //then assign that element value of test_score to the lowest
printf("\nLowest test score is: %d.\n", lowest); } //displays the lowest test score
Explanation:
The program is well explained in the comments mentioned with each statement of the code.
The program prompts the user to enter the number of test scores as they are not already specified in the array because array test_scores is a variable length array which means its length is not fixed. The program then prompts the user to enter the test scores. The program then adds all the test scores and store the result in sum variable. Then it computes the average by dividing the value in sum variable to the number of test scores n. Then in order to determine the letter Grade the average value is used. The if else conditions are used to specify conditions in order to determine the Grade. Next the lowest score is determined by setting the value of lowest variable to the first element of the test_scores array. Then using for loop, the index variable j moves to each array element i.e. score and determines if the the value of element is less than that stored in the lowest variable. If the value positioned at j-th index of test_scores is less than that of lowest than this value is assigned to lowest. At last the lowest holds the minimum of the test scores.
Complete this truth Table. Write a program that you can enter from the keyboard, a 1 or 0 into three Boolean variables, A,B,C. Write an if statement that tests the condition ( (A or B ) and C ). Run the program 8 separate times, testing each of the following 8 combinations. Write the results below in the following truth table.
Module 9-Alternative Sequences and Complex logical Criteria v17 (1).pdf. Adobe Acrobat Reader DC
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Home Tools Module 9 - Altema...X
A B C (A or B ) (A or B ) and C
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
Answer:
Following are the code to this question:
#include<stdio.h>//defining header file
int AND(int x,int y) //defining a method AND that hold two variable in its parameter
{
if(x==1 && y==1)//defining if block to check x and y value is equal to 1
{
return 1;//return value 1
}
else //defining else block
{
return 0;//return value 0
}
}
int OR(int x,int y)//defining method OR that hold two variable in its parameter
{
if(x==0&&y==0)//defining if block to check x and y value is equal to 1
{
return 0;//return value 0
}
else //defining else block
{
return 1;//return value 1
}
}
int main()//defining main method
{
int a,b,c;//defining integer variable
int k=1;//defining integer variable k that holds a value 1
while(k<=8)//defining while loop for 8 time input
{
printf("Please insert 3 numbers in (0 0r 1):\n ");//print message
scanf("%d%d%d", &a, &b, &c);//input value
k++;//increment the value of k by 1
printf("value: %d\n",AND(OR(a,b),c));
}
return 0;
}
Output:
please find the attachment.
Explanation:
In the above-given C language code two methods "AND and OR" is declared, holds two integer variable "x and y" in its parameters, inside the method a conditional it used that can be defined as follows:
In the AND method, inside a conditional statement, if block check x and y both value is same that is 1 it will return 1 or it will goto else block in this it will return value 0. In the OR method, inside a conditional statement, if block check x and y both value is the same, that is 0 it will return 0 or it will goto else block in this it will return value 1.In the main method, four integers "a,b,c, and k" is declared in which variable "a, b, c" is used in the loop for 8 times input values from the user and print method is used to call the method and prints its return values.Which is a software configuration management concept that helps us to control change without seriously impeding justifiable change?
Answer:
Baselines
Explanation:
The idea of software configuration management is that of monitoring and controlling changes in the software. The baseline is the standard and formally accepted form of a software item that is meant to be configured. It is like a generally accepted reference point, which could be applied in effecting incremental changes in the software.
There are three types of baselines which are the functional, developmental, and product baselines. Functional baselines provide an overview of the functionality and specifications of a system. The product baseline encompasses both the functional and physical details of the system.
Recall that within the ArrayBoundedQueue the front variable and the rear variable hold the indices of the elements array where the current front and rear elements, respectively, of the queue are stored. Which of the following code sequences could be used to correctly enqueue element into the queue, assuming that enqueue is called on a non-full queue and that the code also correctly increments numElements?
a. numElements++; elements[rear) - element:
b. front++; elements(front) - element:
c. rear = (rear + 1) % elements.length; elements[rear) - element;
d. front = (front + 1) % elements.length; elements[front) - element;
Answer:
c. rear = (rear + 1) % elements.length; elements[rear] = element;
Explanation:
In the above statement:
Name of the array is elements.
rear holds current index of elements array where current rear element of queue is stored. Front are rear are two open ends of the queue and the end from which the element is inserted into the queue is called rear.
element is the element that is required to enqueue into the queue
Enqueue basically mean to add an element to a queue.
Here it is assumed that the queue is not full. This means an element can be added to the queue.
It is also assumed that code also correctly increments numElements.
rear = (rear + 1) % elements.length; This statement adds 1 to the rear and takes the modulus of rear+1 to the length of the array elements[]. This statement specifies the new position of the rear.
Now that the new position of rear is found using the above statement. Next the element can be enqueued to that new rear position using the following statement:
elements[rear] = element; this statement sets the element at the rear-th (new position) index of elements[] array.
For example we have a queue of length 5 and there are already 4 elements inserted into this queue. We have to add a new element i.e. 6 to the queue. There are four elements in elements[] array and length of the array is 5 so this means the queue is not full. Lets say that rear = 3
elements.length = 5
rear = 3
Using above two statements we get.
rear = (rear + 1) % elements.length;
= 3 + 1 % 5
= 4%5
= 4
This computes the new position of rear. So the new position of rear is the 4-th index of elements[]. Now next statement:
elements[rear] = element;
elements[4] = 6
This statement adds element 6 to the 4-th index of elements[] array.
Thus the above statement enqueues element (element 6 in above example) into the queue.
Assemble a Server computer based on your budget (state the amount in Ghana Cedis), discussing the type of components (giving their exact names, model numbers, types, cost, architecture, etc.) you would need and give reasons why you need them.
Answer:
Following are the answer to this question:
Explanation:
The server would be generally a powerful processor instead of a desktop pc. It must choose the Dell server browser to choose a server for industrial applications.
Dell Poweredge R730 has been its pattern. There should be the reason whether these servers are efficient, available, flexible, and support the concept of even a virtual environment. Its same servers are easy to use, as well as the memory will be connected to this server is 8 TB.____ enable users to create and edit collaborative Web pages quickly and easily; they are intended to be modified by others and are especially appropriate for collaboration.
Answer:
Wikis
Explanation:
Wikis can be defined as a database that was designed by users which gives users the opportunity to add, edit and delete collaborative web pages easily.
It lets users to manage contents easily and they are used to create static websites.
some wikis can be accessed by the public. A great example is Wikipedia.
Wikis allows publishing and sharing of documents to be done easily.