Answer:
Lead sulfide.
Explanation:
Consider the Fischer ester synthesis of methyl benzoate from benzoic acid and methanol in the presence of sulfuric acid as a catalyst. A reaction was performed in which 3.8 g of benzoic acid was reacted with excess methanol to make 2.0 g of methyl benzoate. Calculate the theoretical yield and percent yield for this reaction.
Answer:
48.8%
Explanation:
The reaction has a 1:1 mole ratio so;
Number of moles of benzoic acid reacted = mass/molar mass = 3.8 g/122.12 g/mol = 0.03 moles
So;
0.03 moles of methyl benzoate is formed in the reaction
Mass of methyl benzoate formed = 0.03 moles * 136.15 g/mol = 4.1 g
percent yield = actual yield/theoretical yield * 100/1
percent yield = 2.0 g/4.1 g * 100 = 48.8%
Which of the following compounds is the most stable?
Answer:
Hey mate......
Explanation:
This is ur answer......
fluoridesThus, fluorides are the most stable while iodides are the least stable.
Hope it helps!
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Answer:
LICI
Explanation:
a p e x :)
To determine the concentration of a sodium thiosulfate solution as in this experiment, a student pipetted 25.0 mL of 0.0100 M potassium iodate (KIO3) solution into a 125 mL Erlernmeyer flask. Potassium iodide and sulfuric acid were added as in this experiment. The titration needed 15.21 mL of the sodium thiosulfate to reach the end point. What is the concentration of the sodium thiosulfate solution
Answer:
0.0986M is the concentration of the Na₂S₂O₃ solution
Explanation:
Potassium iodate, KIO₃, reacts with sodium thiosulfate, Na₂S₂O₃, as follows:
KIO₃ + 6Na₂S₂O₃ +5KI + 3H₂SO₄ → 3H₂O + 3K₂SO₄ + 3Na₂S₄O₆ + 6NaI
To solve this question we must find the moles of sodium thiosulfate that reacts as follows:
Moles KIO₃:
0.0250L * (0.0100mol / L) = 2.5x10⁻⁴moles KIO₃
Moles Na₂S₂O₃:
2.5x10⁻⁴moles KIO₃ * (6mol Na₂S₂O₃ / 1mol KIO₃) = 1.5x10⁻³ moles Na₂S₂O₃
Molar concentration:
1.5x10⁻³ moles Na₂S₂O₃ / 0.01521L =
0.0986M is the concentration of the Na₂S₂O₃ solution