What is the mole ratio of ammonia (with a pKb of 4.75) to ammonium chloride in a buffer with a pH of 9.15

The decrease in temperature is 147.075 K. The SI unit for temperature is the kelvin (K), but it can also be measured in degrees Celsius (°C) or Fahrenheit (°F).

What is Temperature?

Temperature is a physical property that measures the degree of hotness or coldness of an object or system, as compared to a standard reference point. It is a measure of the average kinetic energy of the particles (atoms or molecules) in a substance or system.

To solve this problem, we need to use the Charles's law equation which states:

V1/T1 = V2/T2

where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

We can rearrange the equation to solve for T2:

T2 = (V2/T2) x T1

First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15:

T1 = 21.0°C + 273.15 = 294.15 K

The initial volume (V1) is 6.0 L, and the final volume (V2) is 3.0 L. Substituting these values into the equation, we get:

(6.0 L/294.15 K) = (3.0 L/T2)

Solving for T2, we get:

T2 = (3.0 L x 294.15 K) / 6.0 L

T2 = 147.075 K

Finally, we can find the decrease in temperature by subtracting the final temperature (T2) from the initial temperature (T1):

ΔT = T1 - T2

ΔT = 294.15 K - 147.075 K

ΔT = 147.075 K

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Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.

Explanation:

Explanation:

Answer:

D

Explanation:

because replusive force is much more

Answer:

many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?

volume: 16 mL

First, we need to calculate the number of moles of Zn:

m(Zn) = 5.05 g

M(Zn) = 65.38 g/mol (molar mass of Zn)

n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol

According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:

n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol

Now we can use the molarity of the HCl solution to calculate the volume needed:

M(HCl) = 1.50 mol/L

n(HCl) = V(HCl) × M(HCl)

V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL

Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).

When a protonated epoxide is attacked by water, the nucleophile attacks from the "top" or "front" of the epoxide ring in an "S_N2" substitution nucleophilic bimolecular process.

A protonated epoxide is a molecule that contains an epoxide ring (a three-membered ring consisting of two carbon atoms and one oxygen atom) that has been protonated, or had a hydrogen ion (H+) added to it.

The protonation of an epoxide ring can occur in the presence of an acidic medium, such as a strong acid like sulfuric acid (H2SO4) or hydrochloric acid (HCl).

In acidic conditions, the lone pair of electrons on the oxygen atom of the epoxide ring can interact with the positively charged hydrogen ion, resulting in the formation of a protonated epoxide.

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Answer: Solubility increases so more solute dissolves

Explanation:

The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.

Answer:

4 millllllermeeters jb

Explanation:

I don't have a personal opinion, but I can say that there is no single research method that is effective in all situations.

Different research methods are appropriate for different types of research questions and situations. For example, if the research question is focused on understanding the relationship between two variables, a correlational research method may be appropriate. However, if the research question is focused on understanding the cause-and-effect relationship between variables, an experimental research method may be necessary.

In addition, some research methods may be more appropriate for certain types of data or populations, such as qualitative research methods for exploring subjective experiences or quantitative research methods for analyzing numerical data.

Therefore, researchers need to carefully consider their research question and choose the research method that is most appropriate for their specific situation.

The most standard and widely used research methods

Survey research

This method involves collecting data from a sample of individuals through questionnaires, interviews, or online surveys.

Experimental research

This method involves manipulating one variable (the independent variable) to observe its effect on another variable (the dependent variable) while controlling for other variables.

Observational research

This method involves observing and recording behavior in natural settings without any intervention or manipulation of variables.

Case study research

This method involves in-depth examination and analysis of a single case or a small group of cases to understand a particular phenomenon or situation.

Content analysis

This method involves analyzing and interpreting the content of documents, media, or other communication sources to identify patterns, themes, and trends.

These methods are commonly used across various fields of research, including social sciences, psychology, education, business, and healthcare. However, the choice of research method depends on the research question, the type of data needed, and the availability of resources.

Answer:

The density of an object is constant.

Density is a derived unit of measure.

The density of an object determines whether it will sink or float.

Answer:

Continuous Spectrum, a spectrum that contains all wavelengths of light within a specific range, with no gaps or lines. It is produced by a hot, dense object such as a star or a light bulb.

Emission Spectrum, a spectrum that contains bright lines or bands of specific wavelengths, with dark spaces in between. It is produced when light is emitted from a hot gas or plasma, and the specific wavelengths of the lines or bands depend on the elements present in the gas.

Absorption Spectrum, a spectrum that contains dark lines or bands of specific wavelengths, with bright spaces in between. It is produced when a continuous spectrum passes through a cool gas, and the specific wavelengths of the lines or bands depend on the elements present in the gas.

The heat capacity of an object is defined as the amount of heat required to raise its temperature by 1 degree Celsius (or 1 Kelvin). It is denoted by the symbol "C" and has units of J/°C (Joules per degree Celsius) or J/K (Joules per Kelvin).

We can use the formula for heat capacity to calculate its value for the object:

where:

Substituting the given values, we get:

Note that the units of temperature must match (either Celsius or Kelvin) in order for the calculation to be correct. Since the given change in temperature is in Celsius, we can use Celsius for the units of heat capacity as well.

Dividing, we get:

Therefore, the heat capacity of the object is 95.8 J/°C. This means that it requires 95.8 Joules of heat to raise the temperature of the object by 1 degree Celsius (or Kelvin).

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Answer:

The density of a substance is given by dividing the mass by the volume.

The S.I units of density are kg/m³, but can be measured by other units such as g/cm³

The mass of the iron is 29 kg or 29000 g

Therefore; Density = 29000 g/ 3680 cm³

                              = 7.880 g/cm³

Hence, the density of the iron plate is 7.880 g/cm³

Explanation:

No, 28 moles of solid carbon would not be enough to produce 15 moles of [tex]C_2H_6[/tex] (Ethane).

This is because the reaction requires more than 1 mole of carbon to produce 1 mole of [tex]C_2H_6[/tex]. The mole ratio of [tex]C_2H_6[/tex]:C is 2:1, so 28 moles of carbon would only be enough to produce 14 moles of [tex]C_2H_6[/tex].A chemical compound having the molecular formula  [tex]C_2H_6[/tex], ethane is an organic substance. Ethane is an odourless, colourless gas at ordinary pressure and temperature. Ethane is separated from natural gas on an industrial scale, and it is produced as a by-product of the petrochemical process used to refine crude oil. Its primary usage is as a feedstock for the creation of ethylene.The ethane moiety is known as an ethyl group, and it can be used to create related compounds by swapping out a hydrogen atom for another functional group.

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The volume of the gas will be 560 mL when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Substituting the given values, we get:

P₁ = 350.0 kPa (initial pressure)

V₁ = 200 mL (initial volume)

P₂ = 125.0 kPa (final pressure)

V₂ = ?

Solving for V₂, we get:

V₂ = ( P₁ × V₁ ) / P₂

V₂ = (350.0 kPa × 200 mL) / 125.0 kPa

V₂ = 560 mL

Therefore, the final volume of the gas is  560 mL.

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To solve for Δ2, we need to reverse the reaction and change the sign of Δ1:

2Al2O3(s)⟶4Al(s)+3O2(g)Δ2 = -Δ1

Therefore, Δ2 = -Δ1.

To solve for Δ3, we need to add the reactions for the formation of two moles of Al2O3 from aluminum and oxygen:

4Al(s)+3O2(g)⟶2Al2O3(s)Δ1

2Al2O3(s)⟶4Al(s)+3O2(g)Δ3

Adding these equations gives:

12Al(s)+9O2(g)⟶6Al2O3(s)Δ3

Therefore, Δ3 = 2Δ1.

To solve for Δ4, we need to divide the reaction for the formation of two moles of Al2O3 by two:

2Al(s)+3O2(g)⟶Al2O3(s)Δ1/2

Multiplying this equation by 16 gives:

32Al(s)+48O2(g)⟶16Al2O3(s)8Δ1/2

We can then cancel out the formation of 14 moles of Al2O3:

2Al(s)+32O2(g)⟶Al2O3(s)Δ4 = 8Δ1/2 - 7Δ1

Therefore, Δ4 = 8Δ1/2 - 7Δ1.

Answer:

Absolute zero is the theoretical temperature at which all matter would have zero thermal energy and all molecular motion would stop. This temperature is equal to -273.15 degrees Celsius or -459.67 degrees Fahrenheit. It is the lowest possible temperature in the universe and cannot be reached in practice, as it is impossible to completely eliminate all thermal energy from matter.

Answer:

D

Explanation:

Answer:

B) Mass- I searched it up

Answer:

24.31 g/mol.

Explanation:

moles =mass/molar mass

n=w/m

Answer:

21% percent

Explanation:

Air has small amounts of other gases, such as carbon dioxide,neon, and hydrogen. Oxygen shares some parts of air basically. The highest percentage of oxygen we can breathe is approximately 60℅

40.5%

Explanation:

Ca×1 = 40

C×4 = 48

H×6 = 6

O×4 = 64

64÷158×100% = 40.5%

The mole fraction of HCl in the given solution is 0.051.

To calculate the mole fraction of HCl in the given solution, we need to first find the mass of HCl and water present in the solution.

Let's assume we have 100 g of the solution, so 9.8 g of it is HCl, and 90.2 g is water.

Next, we need to find the moles of HCl present in the solution.

To do this, we divide the mass of HCl by its molar mass.

The molar mass of HCl is 36.46 g/mol (1.01 g/mol for hydrogen + 35.45 g/mol for chlorine).

moles of HCl = 9.8 g / 36.46 g/mol = 0.269 mol

The moles of water can be calculated using its molar mass which is 18.015 g/mol.

moles of water = 90.2 g / 18.015 g/mol = 5.005 mol

The total number of moles in the solution is the sum of the moles of HCl and water.

total moles = 0.269 mol + 5.005 mol = 5.274 mol

The mole fraction of HCl can now be calculated by dividing the moles of HCl by the total number of moles.

mole fraction of HCl = 0.269 mol / 5.274 mol = 0.051

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Answer:

The nuclide formed by the β decay of 26Al is 26Mg.


Mark my answer as brainliest! this was a difficult one

Answer:

To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law: P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

Using the given values:

P1 = 30.0 atm

V1 = 2 L

P2 = 10.0 atm

Substituting these values into the Boyle's Law equation, we get:

30.0 atm x 2 L = 10.0 atm x V2

Simplifying and solving for V2, we get:

V2 = (30.0 atm x 2 L) / 10.0 atm

V2 = 6 L

Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.

I Hope This Helps!

Answer:

d

Explanation:

Nitrogen is the limiting reactant.

42 g N2x (1mole N2/28 g N2) X (2 moles NH3/ 1mole N2) X (17 grams NH3/1mole NH3) = 51 g

13 g H2 x (1 mole H2/2 g H2) X (2 moles NH3/3moles H2) X (17 g NH3/1mole NH3) =73.66g

since 51 is smaller than 73.66 and it started with N2 that is why N2 is the limiting reactant)