What is the minimum mass of magnetite (Fe,O2), a iron ore, from which 120. g of pure iron could be extracted? Be sure your answer has a unit symbol, if necessary, and is rounded to 3 significant digits.

Answers

Answer 1

Answer:

166 g

Explanation:

Step 1: Write the reaction for the obtaining of Fe from magnetite

Fe₃O₄ ⇒ 3 Fe + 2 O₂

Step 2: Calculate the moles corresponding to 120 g of Fe

The molar mass of Fe is 55.85 g/mol.

120 g × (1 mol/55.85 g) = 2.15 mol

Step 3: Calculate the moles of Fe₃O₄ required to produce 2.15 moles of Fe

The molar ratio of Fe₃O₄ to Fe is 1:3. The moles of Fe₃O₄ required are 1/3 × 2.15 mol = 0.717 mol

Step 4: Calculate the mass corresponding to 0.717 moles of Fe₃O₄

The molar mass of Fe₃O₄ is 231.53 g/mol.

0.717 mol × 231.53 g/mol = 166 g


Related Questions

how do you make it so that 43200 ml have only 3 significant figures? I will give brainiest pls help

Answers

Answer:

3 sig figs

Explanation:

one of the rules for sig figs is a when a whole number has zeros if they are sandwiched between whole number for ex. 34007 they would all be sig figs. hope this helps!

btw all the zeros behind the decimal are significant for ex. 0.4800

Answer:

you could make it 43.2 x 10^2

Explanation:

A wooden block has the following measured dimensions: height 1.25 cm; width 2.5 cm and length of 15.956 cm. Calculate its volume in ml with the proper number of significant figures.

Answers

Answer:

[tex]V=50mL[/tex]

Explanation:

Hello,

In this case, by knowing that the volume of an object is computed by considering its dimensions, width, length and height, for the given measurements, we obtain:

[tex]V=W*H*L=1.25cm*2.5cm*15.956cm\\\\V=49.86cm^3[/tex]

Moreover, since one cubic centimetre equals one millilitre, the required volume is:

[tex]V=49.86cm^3*\frac{1mL}{1cm^3}\\ \\V=49.86mL[/tex]

Finally, since 2.5 cm has the fewest significant figures (2), the proper result is:

[tex]V=50mL[/tex]

Regards.

Rank the following compounds in order of reactivity toward nitration with HNO3:_______. thiophene, benzene, 3-methylthiophene, and 2-methylfuran.

Answers

Answer:

3-methylthiophene > thiophene > benzene > 2-methylfuran

Explanation:

Primarily, five membered heterocyclic aromatic rings undergo nitration at carbon-2. This is because, nitration at carbon-2 leads to the formation of three resonance structures while attack at carbon-3 yields only two resonance structures, hence it is less stabilized.

The presence of a methyl group which donates electrons promotes the stabilization of the cation formed in the nitration of 3-methylthiophene.

2-methylfuran is the least reactive towards nitration because the 2-position has been blocked by a methyl group.

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?

Answers

Answer:

6.096799125kg

Explanation:

According to the question, three different samples weighed using different types of balance had masses: 0.6160959 kg, 3.225 mg, and 5480.7 g.

Based on observation, the mass units in the three measurements are different but must be uniform in order to find the total mass. Hence, we need to convert to the standard unit (S.I unit of mass), which is kilograms (kg)

Since 1kg equals 1,000,000mg

Hence, 3.225mg will be 3.225/1000000

= 0.000003225kg

Also, 1kg equals 1000g

Hence, 5480.7g will be 5480.7/1000

= 5.4087kg

Hence, the total mass of the three samples (now in the same unit) are:

5.4807kg + 0.000003225kg + 0.6160959 kg

= 6.096799125kg

suggest what the effect of using growth hormone on meat cattle might be

Answers

Answer:

Natural BGH and rBGH both increase the level of another hormone called insulin-like growth factor (IGF-1) in the cow.

Beef cattle are often given steroids to increase and speed growth. Common steroids include:

Natural steroids like estradiol, testosterone, and progesterone Man-made steroids from compounds

Major groups such as FDA and Food and Agricultural Organization state track level of hormones in food. They state that the levels of hormones in food are safe to eat. Not everyone agrees.

Explanation:

Hormones are present in all animal products. Some are natural, others may be added through supplements. Hormones and steroids are given to livestock. It can increase the number of dairy products and beef.

FDA establishes the acceptable safe limits for hormones in meat. A safe level for human consumption is a level of drug in the meat that would be expected to have no harmful effect in humans based on extensive scientific study and review.  

Which of the following statements is true concerning the reaction given below?2H2S(g) + O2(g) → 2S(s) + 2H2O(g)a. The reaction is second-order in H2S(g) and first-order in O2(g).b. The reaction is first-order in H2S(g) and second-order in O2(g).c. The rate law is Rate = k[H2S]2[O2].d. The rate law is Rate = k[H2S][O2].e. The rate law may be determined only by experiment.

Answers

Answer:

The rate law may be determined only by experiment.

Explanation:

For a reaction, A + B ---> C, the rate law can only be determined from experimental data. Chemists determine the rate of reaction by carefully observing the changes in the concentration of species as the reaction progresses.

Hence, the rate law is not determined by inspection of the chemical reaction equation, it must be obtained from the experimental data, hence the answer given.

What volume (mL) of a 0.3428 M HCl(aq) solution is required to completely neutralize 23.55 mL of a 0.2350 M Ba(OH)2(aq) solution

Answers

Answer:

The volume required for complete neutralize is 32.29 mL

Explanation:

The computation of the volume required for complete neutralize is shown below:

As we know that, the balanced equation is

[tex]Ba(OH)_2 + 2Hcl\rightarrow Bacl_2 + 2H_2O[/tex]

Now

The number of moles of [tex]Ba(OH)_2[/tex] = n_1 = 1

And, the number of moles of Hcl = n_2 = 2

Therefore

The equation i.e. to be used to find out the volume is given below:

[tex]\frac{M_1V_1}{n_1} = \frac{M_2V_2}{n_2}[/tex]

[tex]V_2 = \frac{M_1V_1}{n_1} \times \frac{n_2}{M_2} \\\\ = \frac{0.2350 \times 23.55}{1} \times \frac{2}{0.3428} \\\\ = \frac{11.0685}{0.3428}[/tex]

= 32.29 mL

Hence, the volume is 32.29mL

The distance between the nuclei of two iron atoms is about 4 angstroms.a. Trueb. False

Answers

Answer:

The correct option is b. false

Explanation:

The distance between the nucleus of an atom and it's outermost shell is called is atomic radius. The atomic radius of an Iron atom (Fe) is 0.126 nm or 1.26 angstrom. The distance between the nuclei of two Iron atoms will be 1.26 × 2 = 2.52 angstroms.

Since 2.52 angstroms is lower than 4 angstroms, the correct option is false

Iron(III) oxide gets mixed with elemental carbon and heated to make elemental iron and carbon dioxide.
a) If they want to convert 1.00kg of iron (III) oxide to elemental iron, how much carbon needs to be added to the mix?
b) That 1.00kg of iron (III) oxide, with an excess of carbon, produces how much elemental iron.

Answers

Answer:

Explanation:

Iron(III) oxide gets mixed with elemental carbon and heated to make elemental iron and carbon dioxide.

2Fe₂O₃   +    3C    =    4 Fe   +    3 CO₂

2 x 160       3 x 12       4 x 56

320 gram of iron ( iii ) oxide requires 36 g of carbon for reduction

1 kg of iron will require 36 / 320 g of carbon

carbon required = 36 / 320 g

= .1125 g

= .113 g rounding off to 3 significant fig .

b )

320 gram of iron ( iii ) oxide produces  224  g of iron  after  reduction

1 g of iron will produce 224 / 320 g of iron

iron produced = 224 / 320 g

= 0.700 g .

A 14.584 g sample of CaCl2 was added to 12.125 g of K2CO3 and mixed in water. What is the limiting reactant and what is the theoretical yield of CaCO3

Answers

Answer:

The correct answer is 8.786 g CaCO₃

Explanation:

The balanced reaction is the following:

CaCl₂(ac) + K₂CO₃(ac) → CaCO₃(s) + 2 KCl(ac)

From the stoichiometry, 1 mol of CaCl₂ (111 g) reacts with 1 mol of K₂CO₃ (138 g) to form 1 mol CaCO₃(100 g) and 2 moles of KCl (149 g).

The stoichiometric ratio CaCl₂/K₂CO₃ is: 111 g/138 g= 0.80 g CaCl₂/K₂CO₃.

We have 14.584 g CaCl₂ and 12.125 g K₂CO₃, which gives a ratio of: 14.584g/12.125 g= 1.2 g CaCl₂/K₂CO₃.

0.8 ∠ 1.2 ⇒ K₂CO₃ is the limiting reactant

We use the limiting reactant to calculate the grams of CaCO₃ produced. For this, we know that from 138 g K₂CO₃  100 g of CaCO₃ are produced. So, we multiply the amount of K₂CO₃ by this stoichiometric ratio to obtain the grams of CaCO₃ produced:

12.125 g K₂CO₃ x 100 g CaCO₃/138 g K₂CO₃= 8.786 g CaCO₃

Therefore, the theoretical yield of CaCO₃ is 8.786 g.

C-12 has 6 protons.
How many neutrons does C-13 have?
A. 6
B. 7
C. 13
D. 19

Answers

Answer:

B-7

Explanation:

13-6=7

1 to 2= 1 proton 12\2=6 protons add one neutron you have 6 still unless you add two then you would have 7

The answer is A). 6

Which of the following species is not capable of acting as an Arrhenius acid in aqueous solution?
A) CHCl_3
B) HNO_3
C) H_2SO_4
D) H_3O^+
E) HClO_4

Answers

Answer:

CHCl_3

Explanation:

An Arrhenius acid produces H^+ in solution. If we look at the options provided, all the other species are acids that contain at least one replaceable hydrogen ion hence they possess H^+ and can act as Arrhenius acids in solution.

However, CHCl_3 does not contain a replaceable hydrogen ion hence it does not function as an Arrhenius acid.

The species that should not be capable of acting as an  Arrhenius acid in an aqueous solution is option A.  CHCl_3.

What is Arrhenius acid?

it is a compound that rised the concentration of hydrogen ion (H +) in an aqueous solution. Here the CHCl_3 should not generate the proton at the time when it should be mixed with water since it creates two immiscible layer. Moreover, the HNO3, H2SO4, H3O+, and HCIO4 should produce proton in aqueous.

Therefore, the option A should be considered.

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Is it possible for a piece of cork to have more mass than a piece of rock?

Answers

Answer:

Yes

Explanation:

It is entirely possible for a piece of cork to have more mass than a piece of rock. This would largely depend on the volume of the two objects. The density of a substance remains the same irrespective of the size of the substance.

                   Density = mass/volume

At constant density, it means that the mass of an object depends only on the volume of the object.

Hence, a piece of cork can weigh more than a piece of rock if the volume or size of the cork is bigger enough than that of the rock.

A stack of ten 3.5 in diskettes is 34 mm high. How many diskettes does it take to make a stack 100 yards high?

Answers

Answer:

3.5 divided by 34 then divide again 100

Explanation:

math

1.How did the electrolyte properties of the NaCl solution compare as you added more salt to the water

Answers

Explanation:

The dissociation of NaCl increases. This happens because of the Le Chatalier's principle which says that, the rate of reaction shift to product side when more product is added to the reaction. Therefore, its electrolytic properties are enhanced.

If you have 24 grams of an unstable atom with a half life of 5,000 years, how many grams would be left after 15,000 years

Answers

Answer:

3 g.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 24 g

Half life (t½) = 5000 years

Time (t) = 15000 years

Amount remaining (N) =?

Next, we shall determine the rate constant K. This can be obtained as follow:

Half life (t½) = 5000 years

Rate constant (K) =.?

K = 0.693 / t½

K = 0.693 / 5000

K = 1.386×10¯⁴ / years

Finally, we shall determine the amount remaining (N) after 15000 years as follow:

Original amount (N₀) = 24 g

Time (t) = 15000 years

Rate constant (K) = 1.386×10¯⁴ / years

Amount remaining (N) =?

Log (N₀/N) = kt/2.3

Log (24/N) = 1.386×10¯⁴ × 15000/2.3

Log (24/N) = 2.079/2.3

Log (24/N) = 0.9039

24/N = antilog (0.9039)

24/N = 8.01

Cross multiply

24 = N × 8.01

Divide both side by 8.01

N = 24/8.01

N = 3 g

Therefore, the amount remaining after 15000 years is 3 g.

Heptane and water do not mix, and heptane has a lower density (0.684 g/mL.) than water (1.00 g/
mL). A 100-ml graduated cylinder with
an inside diameter of 3.08 cm contains 37.8 g of heptane and 34.7 g of water. What is the combined height of the two liquid layers in
the cylinder? The volume of a cylinder is r’h, wherer is the radius and h is the height.
cm

Answers

Answer:

Explanation:

volume of heptane= mass / density

volume of heptane = 37. 8 / .684

= 55.26 mL

volume of water  = 34.7  / 1

= 34.7 mL or cc.

If l₁ be the length of heptane layer in the graduated cylinder

volume = cross sectional area x length or height  of layer

π r² x l where r is radius of bore of the cylinder  , l is height of liquid inside cylinder .

for heptane

π r² x l₁ =  55.26

3.14 x 1.54² x l₁ = 55.26

l₁ = 7.42 cm

for water

π r² x l₂ =   34.7

3.14 x 1.54² x l₂ = 34.7

l₂ = 4.65  cm

Combined height = l₁ + l₂

= 7.42 + 4.65

= 12.07 cm .

how potassium iodide aids the titration of the cyclohexane layer.

Answers

Answer:

to avoid iodine vapor from escaping.

Explanation:

This question is all about an experimental work on the determination of the distribution of iodine between waters and cyclohexane. To understand this question one has to understand the topic "Equilibrium" very well.

One important thing that must be noted in this question is for us to remember that water and cyclohexane are two immiscible liquids. So, when Iodine is added to the two solvents, the iodine dissolves in both water and cyclohexane to certain rate ands then to an equilibrium which is;

Kd = I₂[Cyclohexane]/ I₂[water]. ----------------------------------------[**].

There is a release of I⁻¹ From the added potassium iodide which helps in making sure that the iodine vapor does not escape. Thus, forming a tri-iodide ion.

When cyclohexene is treated with KMnO4, H2O, the syn-1,2-diol is produced. What reaction occurs when benzene is similarly treated

Answers

Answer:

No reaction is observed

Explanation:

The benzene ring is aromatic. Being an aromatic ring, the benzene ring is remarkably stable to all reactions that destroy the aromatic ring.

Alkenes are oxidized to alkanols in the presence of KMnO4 but this reaction does not occur with benzene. However, substituted benzenes having hydrogen atoms attached to the substituent carbon atom can be oxidized to the corresponding carboxylic acid.

Give one example of how studying chemistry could be
useful in everyday life

Answers

Answer:

Chemistry is used almost everywhere you go. from the car you use to get to work (gasoline burning) to the nuclear reactors that power many homes ( uranium becoming unstable to product electricity.

Which statement is true?

Answers

Please give the statement also
Thanks

Answer:

where is statements if you give statements then ican answer okk

What is the percent by mass of the solution formed when 5.0 g of solute is dissolved in 40. g of water

Answers

Answer:

2

Explanation:

so let say 5.0/100×40

that is 2

thank you please follow me

The percent by mass is the estimation of the solute present in the solution or the substance. The percent by mass of 5 gm solute is calculated to be 11.11%.

What is the percent by mass?

The percent by mass is defined as the division of the mass of the solute of the element by the mass of the compound or the solution as the whole. The formula for percent by mass is given as:

mass percent = (mass of solute ÷ total mass of compound or solution) x 100%

The mass of the solute has been the numerator and the mass of the solution has been the denominator that must be multiplied by 100 to get the percent by mass or mass percentage. It is represented using %.

Given,

Mass of solute = 5.00 grams

Mass of compound (solution) = solute + water

= 40.0 grams + 5.00 grams

= 45.00 grams

Substituting the values above as:

mass percent = (mass of solute ÷ total mass of compound or solution) x 100%

The percent by mass = (5.00 ÷ 45.00) x 100%

= 11.11 %

Therefore, 11.11 % is the percent by a mass of 5.00-gram solute dissolved in 40.0 grams of water.

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(5.391 ´ 10-7) + (2.5531 ´ 10-6) =

Answers

Answer:

[tex](5.391 * 10^{-7}) + (2.5531 * 10^{-6}) = 3.0922 * 10^{-6}[/tex]

Explanation:

Given

[tex](5.391 * 10^{-7}) + (2.5531 * 10^{-6})[/tex]

Required

Solve

[tex](5.391 * 10^{-7}) + (2.5531 * 10^{-6})[/tex]

Remove the brackets

[tex]5.391 * 10^{-7} + 2.5531 * 10^{-6}[/tex]

Express [tex]10^{-7}[/tex] as [tex]10^{-1-6}[/tex]

[tex]5.391 * 10^{-1-6} + 2.5531 * 10^{-6}[/tex]

Apply law of indices

[tex]5.391 * 10^{-1} * 10^{-6} + 2.5531 * 10^{-6}[/tex]

[tex]0.5391 * 10^{-6} + 2.5531 * 10^{-6}[/tex]

Factorize:

[tex](0.5391 + 2.5531)10^{-6}[/tex]

[tex](3.0922)10^{-6}[/tex]

Remove bracket

[tex]3.0922 * 10^{-6}[/tex]

Hence:

[tex](5.391 * 10^{-7}) + (2.5531 * 10^{-6}) = 3.0922 * 10^{-6}[/tex]

The displacement by CH3CO2- on (a) bromoethane or (b) bromocyclohexane. ___ Submit AnswerTry Another Version

Answers

Answer:

The displacement by [tex]CH_{3}CO_{2}^{-}[/tex] on bromoethane.

Explanation:

Given that,

The displacement by [tex]CH_{3}CO_{2}^{-}[/tex] on bromoethane or bromocyclohexane.

We know that,

Bromoethane is not stable. It can easily break. But bromocyclohexane is more stable obstruct and very strong to displace.

Bromocyclohexane is a ring and we can not break easily of a ring.

So, bromocyclohexane does not displace by [tex]CH_{3}CO_{2}^{-}[/tex].

Hence, The displacement by [tex]CH_{3}CO_{2}^{-}[/tex] on bromoethane.

The radius of a nickel atom is 125 pm. How many nickel atoms would have to be laid side by side to span a distance of 1.74 mm

Answers

Answer:

6960000 Nickel atoms

Explanation:

radius = 125 pm = 125 x 10^-12 m

diameter of each atom = 125 pm x 2 = 250 pm = 250 x 10^-12 m

span of distance to be achieved = 1.74 mm = 1.74 x 10^-3 m

number of nickel atoms = (1.74 x 10^-3 m)/(250 x 10^-12 m) = 6960000 Nickel atoms

HF:______
a) dispersion force
b) dipole-dipole force
c) hydrogen bond

Answers

Answer:

HF: hydrogen bond

Explanation:

The hydrogen bond is a type of interaction that is established between a molecule that presents hydrogen with another that presents an atom with a high electronegativity, such as oxygen, fluorine or nitrogen (O, F, N), joining covalently due to their opposite charges.

The hydrogen atom has a positive charge and is known as a donor atom. The oxygen, fluorine or nitrogen atom is the bond acceptor atom.

So:

HF: hydrogen bond

6. Describe the energy inputs and outputs for the campfire. Use the law of conservation of energy to construct a valid qualitative equation that includes all the input and output energies involved.

Answers

Answer:

Energy in the campfire originates from the potential chemical energy of the wood, before it is burnt to warm and give light around the campfire.

Explanation:

For a camp fire, the energy input is in the form of the potential chemical energy, stored up in the firewood used to fuel the flame.

The energy output is in the form of heat energy that the campfire radiates all around, light energy given off from the flame, and a little bit of sound energy, heard in the cracking of the firewood as they burn in the flame.

chemical energy ⇒ heat energy + light energy + sound energy

The energy inputs of a campfire are logs and fuel, which is the stored potential energy in the form of chemical energy. The output of a campfire is light and heat energy.

What is energy?

Energy is an entity that can not be created, not destroyed. It's just transformed into other forms. There are different forms of energy present in the environment.

The energy input for a campfire comes in the form of the chemical potential energy that is stored in the firewood used to feed the blaze.

The campfire's energy production takes the form of heat energy that it radiates outward, light energy that it emits, and a little amount of sound energy from the crackling of the fuel as it burns.

Chemical potential energy ⇒ heat energy + light energy + sound energy.

Thus, logs and fuel, which is chemical energy that has been stored as potential energy, are the sources of energy for a campfire. A campfire produces light and heat energy.

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What is the Ksp of Al(OH)3 if the concentration of OH– in a saturated solution of Al(OH)3 is 1.6 × 10–8 M?

Answers

Answer:

[tex]Ksp=2.2x10^{-32}[/tex]

Explanation:

Hello,

In this case, since the dissociation of aluminum hydroxide is:

[tex]Al(OH)_3(s)\rightleftharpoons Al^{3+}+3OH^-[/tex]

The equilibrium expression is:

[tex]Ksp=[Al^{3+}][OH^-]^3[/tex]

Thus, given the concentration of hydroxyl ions in the solution, and the 3:1 mole ratio with the aluminum ions, the concentration of those turn out:

[tex][Al^{3+}]=1.6x10^{-8}\frac{molOH^-}{L}*\frac{1molAl^{3+}}{3molOH^-} =5.3x10^{-9}M[/tex]

Therefore, the solubility product, Ksp turns out:

[tex]Ksp=(5.3x10^{-9}M)[1.6x10^{-8}M]^3\\\\Ksp=2.2x10^{-32}[/tex]

Regards.

what do you mean by saying that the molality of a solution is 2​?

Answers

Answer:

2 molal solution means that 2 moles of solute is dissolved in 1 kg of solvent.

How do biotic factors impact ecological organization?

Answers

Answer:

plz mark as BRAINLIEST plz

Explanation:

The biotic factors in an ecosystem are the living organisms, such as animals. Biotic factors in an ecosystem are the participants in the food web, and they rely on each other for survival. ... These living organisms affect each other and influence the health of the ecosystem.

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