Answer:
The minimum mass of ethylene glycol = 6.641 Kg
Explanation:
[tex]\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f[/tex]
Where T_f = freezing point of pure solvent water, 0°C
T_f'= Freezing point of solvent after mixture
K_f = Freezing point depression constant = 1.86 °C/m
Moecular weight of ethylene glycol = 60 g/mol
Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g
molality of ethylene glycol
[tex]m = \frac{weight}{mol.wt} \times\frac{1000}{V}[/tex]
Substitute the values to calculate m
[tex]m = \frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]
by formula
[tex]0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]
calculating we get w = 6641.93 g
Therefore, The minimum mass of ethylene glycol = 6.641 Kg
Look at the table of dissociation constants for some acids.
Acid Ka Acetic acid 18 x 10-6 1.2 x 10-2 Chlorous acid Nitrous acid 4.0 x 10 -4 Propionic acid 1.3 x 10-5
Which of these is the strongest acid?
acetic acid
chlorous acid
nitrous acid
propionic acid
*Answer is B*
Answer:
chlorous acid
Explanation:
The acidic equilibrium of weak acids, HX, occurs as follows:
HX ⇄ H+ + X-
Where Ka is written as:
Ka = [H+] [X-] / [HX]
The strongest acid is the acid that produce more H+. The acid with the higher Ka is the acid that produce more [H+] and is, thus, the strongest acid.
The higher Ka is the Ka of chlorus acid = 1.2x10-2
Right answer is:
chlorous acidAnswer:
chlorous acid :)
Explanation:
NO LINKS PLEASE
1. What are the reactants at the start of this chemical reaction? What do you start with?
2. What are the products at the end of this chemical reaction? What do you end with?
3. If the total mass of the reactants equals 150 grams, what would the total mass of the
products be?
Answer:
1.The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products
2.The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products
3.The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. For example, the mass of sodium plus the mass of chlorine that reacts with the sodium equals the mass of the product sodium chloride.
Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s
To Find :
The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s.
Solution :
The horizontal range of a projectile is given by :
[tex]R = \dfrac{u^2 sin 2\theta}{g}[/tex] ( Here, g is acceleration due to gravity = 10 m/s² )
Putting all value in above equation :
[tex]R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m[/tex]
Therefore, the horizontal range of projectile is 80 m.
decay mode for cesium-137
Answer:
Beta decay
Explanation:
Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.
Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.
The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.
Beta decay decreases the neutron - proton ratio.
please help me quickly ????
Calculate the equilibrium solubility of silver arsenate
(Ksp = 6 * 10-23) in a solution that buffered to a pH of :
a) 3
b) 6
c) 9
For H3ASO4
Ka1 = 5 * 10-3
Ka2 = 1.1 * 10-7
Ka3 = 3.2 * 10-12
Answer:
sorry don't know the answer!!!
How many sides does a dodecahedron have?
Answer:
the correct answer is 12 sides (:
Explanation:
Given the reaction: N2 + O2 = 2NO for which the Keq at 2273 K is 1.2 x 10-4
a. Write the equilibrium constant expression for the reaction.
b. Write the equation that would allow you solve for the concentration of NO.
c. What is the concentration of NO if [NZ] = 0.166M and [02] = 0.145M?
Answer:
(a): The expression of equilibrium constant is [tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b): The equation to solve the concentration of NO is [tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex]
(c): The concentration of NO is 0.0017 M.
Explanation:
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term [tex]K_{eq}[/tex]
(a):
The given chemical equation follows:
[tex]N_2+O_2\rightarrow 2NO[/tex]
The expression for equilbrium constant will be:
[tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b):
The equation to solve the concentration of NO follows:
[tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex] ......(1)
(c):
Given values:
[tex]K_{eq}=1.2\times 10^{-4}[/tex]
[tex][N_2]_{eq}=0.166M[/tex]
[tex][O_2]_{eq}=0.145M[/tex]
Plugging values in equation 1, we get:
[tex][NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}[/tex]
[tex][NO]=\sqrt{2.88\times 10^{-6}}[/tex]
[tex][NO]=0.0017 M[/tex]
Hence, the concentration of NO is 0.0017 M.
Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.
Answer:
See Explanation
Explanation:
In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.
The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.
The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.
Consider the reaction 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. If 8 moles of FeS2 react with 15 moles of O2, what is the limiting reactant? (3 points)
SO2
O2
Fe2O3
FeS2
Answer:
O2
Explanation:
for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:
MM FeS2 = 120n = 26.2g / 120g/mol = 0,218 mol
MM O2 = 32n = 5,44g/32g/mol = 0,17 mol
The limiting reactant is
O2
Write the formulas for each of the compounds in the following table.
1.
Ferric sulfate
2.
Strontium oxalate
3
.
Chromic acid
4.
Nickel(III) carbonate
5.
Silver bromate
6
.
Dinitrogen difluoride
1.
Magnesium molybdate
8.
Sodium hydrogen phosphate
Answer:
1. Ferric sulfate - Fe2(SO4)3
2. Strontium oxalate – SrC2O4
3. Chromic acid – CrO3
4. Nickel (III) carbonate – NiCO3
5. Silver bromate – AgBrO3
6. Dinitrogen difluoride - N2H2
7. Magnesium molybdate – MgMoO4
8. Sodium hydrogen phosphate - Na2PO4
How do isotopes of the same atom react chemically? How do isotopes of the same atom compare in size?
Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.
Match each element to the correct description of its usual behavior in a
chemical reaction.
Answer:
Calcium (Ca) - will lose electrons
Sulfur (S) - will gain electrons
Carbon (C) could lose or gain electrons
Neon (Ne) Does not gain or lose electrons
If the temperature decreases, then the pressure will
In the ground state, the valence electrons of a krypton atom are found in
1. The first shell
2. The outermost shell
3. Both the nucleus and the first shell
4. Both the first shell and the outermost shell
Answer: 2. The outermost shell
Explanation:
In an elements ground state, its electrons have the least amount of energy that they could have so they stay in their shells. When Krypton is in this state therefore, its valence electrons will stay in the outermost shell.
As Krypton has a total of 36 electrons in this state, there will be 8 valence electrons and they will all be in the outer shell.
A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0.840 J/g°C and the temperature goes up by 9.25°C of soil. How many grams of soil are there?
Answer:
823.7g
Explanation:
Using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
Using the information given in this question as follows:
Q = 6,400 J
m = ?
c of soil = 0.840 J/g°C
∆T = 9.25°C
Using Q = mc∆T
m = Q ÷ c∆T
m = 6,400 ÷ (0.840 × 9.25)
m = 6400 ÷ 7.77
m = 823.7g
Answer:
There are 823.68 grams.
Explanation:
Calorimetry is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.
Between heat and temperature there is a relationship of direct proportionality. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body. In summary, the amount of heat Q that receives or transmits a mass m of a substance with specific heat C to raise its temperature from T1 to T2 is given by the formula:
Q= C*m* (T2- T1) = C*m* ΔT
In this case:
Q= 6400 JC= 0.840 [tex]\frac{J}{g*C}[/tex]m= ?ΔT= 9.25 CReplacing:
6400J= 0.840 [tex]\frac{J}{g*C}[/tex] *m* 9.25 C
Solving:
[tex]m=\frac{6400 J}{0.840 \frac{J}{g*C} *9.25 C}[/tex]
m=823.68 grams
There are 823.68 grams.
Please help this is due tonight
What is the total mass of products formed when 64.18 grams of CH4 is burned with excess oxygen?
If 10.0 moles of NO are reacted with 6.0 moles of O2, How many moles of NO2 are produced?
Answer:
We have to find out which of the reactants that is the Limiting Reagent.
The Limiting Reagent is the reactant that finishes before reaction is complete or simply put... Its the reactant that's NOT IN EXCESS.
We use the reactant that's not in excess to find the Number of moles of product because once that reactant is used up.... The reaction also ends or stops(hence the name;Limiting reactant).
Now
We have 10moles of NO
We also have 6moles of O2
The balanced equation of Reaction is
2NO + O2 ===> 2NO2
Now
looking at this equation
2moles of NO is required to react with 1mole of O2
So since we have NO=10moles and O2 = 6moles
It means that
20moles of NO is required to react with 6 moles of O2.
We were only given 10moles of NO and this is not even enough to react with the whole 6moles of Oxygen because from what we just discovered... We need 20moles of NO to react with all 6moles of O2.
So
This means that NO is the LIMITING REACTANT. It is in short supply and would be used up before the whole reaction takes place.
So we use the limiting reactant to find the Number of Moles of Product formed.
Now
From the eqn of reaction
2moles of NO forms 2Moles of NO2.
Their Mole ratio is 2:2 or 1:1...
This simply means that an equal amount of NO2 will be Produced
MEANING.... 10 MOLES OF NO2 IS PRODUCED.
HAVE A GREAT DAY!!!
Magnesium metal reacts with a solution of silver nitrate in a single-replacement reaction, producing aqueous magnesium
nitrate and silver metal.
If a reaction starts with 0.480 mol Mg, how many moles of silver are produced?
You must show a proper set up for the calculation, the answer with a proper unit, and
the proper significant figures.
Answer:
0.960 mol of Ag
Explanation:
Mg(s) + 2AgNO3(aq) → Mg(NO3)2(aq) + 2Ag(s)
1.00 mol of Mg ---- 2.00 mol of Ag
0.480 mol of Mg ---- x
x = (0.480×2)/1 = 0.960 mol of Ag
How it affects your lives or the lives of people near the area where soil erosion happened?
Please Answer! thanks!
Answer:
negatively
Explanation:
when soil erosion happens,by the agent of water for example,the soil will eventually lose it's valuable minerals and become infertile, people won't be able to grow crops there.
THIS NOT MY WORK. its for my sister. HELP HER
Answer:
Your answer will be b(molten material from the outer core makes its way to the surface of earth)
Explanation:
Answer:
C
Explanation:
I'm pretty sure molten material comes from the inner core. I think you can search up this though, try to find where molten material comes from. Goodluck!
What would the IUPAC name be?
Answer:
methyl ethanoate
Explanation:
To name the compound given above, the following must be obtained:
1. Determine the functional group of the compound.
In this case, the functional group is R–COOR' where R and R' are alkyl groups. Thus, the compound is an ester.
2. Determine the longest chain before the functional group and the compound after the functional group.
In this case, the longest chain before the functional group is carbon 2 i.e ethane and the compound after the functional group is methyl.
3. Name the compound by naming the compound after the functional group first, followed by the compound before the functional group and ending it with –oate.
This is illustrated below:
After the functional group => methyl
Before the functional group => ethane
Name of the compound => methyl ethanoate
g What is the relationship between the moles of the limiting reagent and the change in temperature (i.e. directly proportional or indirectly proportional)
Answer:
number of moles is inversely proportional to the Temperature
Explanation:
As we know
PV = nRT
where P is the pressure
V is the volume
n is the number of moles
R is the gas constant
and T is the temperature
If we see the equation, we can find that n is inversely proportional to the Temperature
The MO diagram of CN is similar to N2. Based on the molecular orbital energy-level diagram of CN, which of the following statements are correct?
i. The CN bond order is 2.
ii. CN is diamagnetic.
iii. The bond enthalpy in CN- ion is higher than CN.
iv. CN has longer bond length than CN-
answer choices:
a. ii, iv
b. iii, iv
c. i, iii
d. i, ii
e. i, iv
Answer:
Nitrogen molecule (N2)
The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.
The total number of electrons present in the nitrogen molecule (N2) is 14.
In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.
N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2
Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.
The bond order of N2can be calculated as follows:
Here, Nb = 10 and Na = 4
Bond order = (Nb−Na) /2
B.O = (10−4)/2
B.O = 3
So your answer should be C3.
Which of these is NOT a producer in the coral reef ecosystem? *
1. phytoplankton
2. sea grass
3. microalgae
4. coral
Answer:
option number 4. 'coral'
Explanation:
-
. When is separation of substances necessary ?Name four methods used to separate solid substances ?
the one of 2 who send correct answer will get the brainliest and 40 points
hello HELP ME pLS ANYONE with this question I will give u 18 points pls I need real help here:((
Answer:
Boiling - The process of a liquid changing to gas.
Boiling point - The temperature at which a liquid boils.
Condensing - The process of a gas changing to a liquid.
Distillate - The liquid collect from the condenser.
Residue - The liquid left behind in the distillation flask.
Vapour - Another name for gas.
Hope it helps :)
How many moles are 4.20 * 10 ^ 25 atoms of Ca?
Answer:
~69.744 moles of Ca
Explanation:
Using Avogadro's constant , we know that:
1 mole = 6.022 x 10^23 atoms
S0, the number of moles in 4.20 x 10^25 atoms of Ca:
=(4.20 x 10^25 x 1 )/(6.022 x 10^23)
~69.744 moles of Ca
Q2:How many atoms are in 0.35 moles of oxygen?
1 mole = 6.022 x 10^23 atoms
S0, the number of atoms in 0.35 moles of oxygen:
=[0.35 x (6.022 x 10^23)]
=2.1077 x 10^23 atoms of Oxygen
Hope it helps:)
Hydration of alkynes gives good yields of single compounds only with symmetrical or terminal alkynes. Draw the major organic product(s) formed when 3-methylcyclodecyne undergoes hydration in the presence of HgSO4 and H2SO4.
Answer:
Following are the solution to the given choice:
Explanation:
Hex-2-yne is just not alkyne symmetric, therefore two things respectively hexan-3-one and hexan-2-one are to be given.
The attached file it displayed the response along with the mechanism, please find the.
Given 32.0 g of water, if we see a temperature change from 25.0°C to 20.0°C, then how much heat energy (q) is transferred from the water?
(The specific heat of water is 4.184 J/g°C )
Answer:
Q = 669.44 J
Explanation:
Given that,
Mass of water, m = 32 g
The temperature change from 25.0°C to 20.0°C.
We need to find the amount of heat energy transferred. Let it is Q. We know that,
[tex]Q=mc\Delta T[/tex]
Where
c is the specific heat of water
Put all the values,
[tex]Q=32\times 4.184 \times (20-25)\\Q=669.44\ J[/tex]
So, 669.44 J of heat energy is transferred from the water.