What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The density of water is 1.00 g/mL)

Answers

Answer 1

Answer:

13.5 %

Explanation:

First we calculate the mass of 500 mL of water, using its density:

Volume * Density = Mass500 mL * 1.00 g/mL = 500 g

Then we calculate the mass percent of potassium sulfate, using the formula:

Mass of Potassium Sulfate / Total Mass * 100%

78 g / (78 + 500) g * 100 % = 13.5 %


Related Questions

The correct value of m, n, x and y to obtain a balanced equation is?

m B2O3(s) + n HF(l) → x BF3(g) + y H2O(l)

a.
m=1, n=1, x=1 and y=1


b.
m=1, n=6, x=2 and y=3


c.
m=1, n=1.5, x=1 and y=1


d.
m=2, n=12, x=4 and y=6​

Answers

Answer:

d

Explanation:

answer d makes the equation balance

When sodium hydroxide NaOH dissociates in water, the oxygen atoms on the hydroxide anions will interact with:

Answers

Answer:

Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.

Explanation:

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?

Answers

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

[tex]P\cdot V = k[/tex] (1)

Where:

[tex]P[/tex] - Pressure, in kilopascals.

[tex]V[/tex] - Volume, in cubic centimeters.

[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)

Where:

[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.

[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

[tex]P\cdot \dot V = -\dot P\cdot V[/tex]

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Mass of watch glass + filter paper = 105.98 g
Mass of watch glass + filter paper + crystallized product = 109.03 g
Mass of uncrystallized product (show work) =
Mass of methyl benzoate = 3.08 g
Volume of nitric acid used = 2.0 mL

Theoretical yield based on each of the starting materials

(Please use two Dimensional Analysis (DA) equations, one for the maximum amount of product obtainable from the amount of methyl benzoate you used and the other from the concentrated nitric acid, then use the lesser of the two to determine the Limiting Reagent; you must determine the number of moles in 2.00 mL of concentrated nitric acid [concentration 69.0% (w/w), and density (1.42 g/mL)].

Required:
a. Identity of the Limiting reagent (LR) based on the above two DA equations = __________
b. Max amount of product obtainable from the LR = ___________
c. Mass of the product you obtained: ____________

Answers

Answer:

Explanation:

Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)  

Mass of uncreystaliized product = 109.03 gm - 105.98 gm

Mass of uncrystaliized product = 3.05 gm

For methyl benzoate;

mass = 3.08 g

no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole

It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.

moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles

mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol

mass of nitro methyl benzoate = 4.098 gm

For HNO_3 solution:

mass = 1.42 gm/ml × 2.0 ml

mass = 2.84 gm

Mass of HNO3 in 2.84 gm solution[tex](69\% w/w)= 2.84 gm * \dfrac{69}{100 }[/tex]

= 1.9596 gm

Moles of HNO3 = [tex]\dfrac{ 1.9596 \ gm }{ 63.01 gm /mol}[/tex]

= 0.0311 mole

1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate

Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole

The mass for nitro methyl benzoate can now be determined as:

= 0.0311 mole × 181.5 gm/mole

= 5.634 gm

Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.

The mass obtainable from the LR = 4.098 gm

What type of solution would have a pH of 8 ?

Answers

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Answer: Weak base

Explanation:

I hope this helped!

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Answer and Explanation:

Solutions that have a pH of 8 would be considered a Weak Base.

This is because a weak base is a base that, upon dissolution in water, does not dissociate completely.

Solutions/liquids that have a pH higher than a pH of 7 are basic solutions, while solutions/liquids that have a pH lower than a pH of 7 are acidic solutions.

When the pH level is closer to 7, it is weak, and when it is far from 7, like if it is 1 or 12, then it is a strong acid/base.

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If anyone could help I’d appreciate it

Answers

Answer: 2.00 mol

Explanation:

The balanced chemical equation is:

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]  

According to stoichiometry :

2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex]  of [tex]O_2[/tex]

Thus both will act as limiting reagents and will be fully consumed.

2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex]  of [tex]H_2O[/tex]

  Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.

Which contains the greatest number of moles of oxygen atoms?

Answers

Answer:

B. OR C.

Explanation:

So, 1 mol of ethanol, C2H5OH contains 1 mol of atoms of O; 1 mol of formic acid, HCO2H contains 2 moles of atoms of O; and 1 mol of water, H2O contains 1 mol of atoms of O.

Answer: So, of the three compounds given, formic acid, HCO2H, contains the greatest number of moles of oxygen atoms.

What is the name of this molecule?

Answers

Answer:

pentanoic acid

Explanation:

it has 5 carbon atoms which gives it the parent name pent, and its attached to the ester group

Potassium chlorate, a common oxidizing agent in fireworks and matchheads, undergoes a solid-state disproportionation reaction when heated:

4KClO3 (s) ⟶ Δ3KClO4 (s) + KCl (s).

Use ΔHf ° and S° values to calculate ΔG_sys ° (which is ΔGrxn °) in kJ at 25°C for this reaction.

Answers

Answer:

Explanation:

[tex]\text{From the information given:}[/tex]

[tex]\text{The chemical reaction is : } 4 KClO_{3(s)} \to 3 KClO_{4(s)} + KCl_{(s)}[/tex]

[tex]\text{To find} \ \Delta G^0_{rxn}\ \text{using the formula}: \\ \\ \Delta G^0_{rxn} = \sum n_p \times \Delta _f G^0 (Products) - \sum n_R \times \Delta _fG^0 ( Reactants) \\ \\ where; n_p = \text{no of moles of products } \ and; \\ \\ n_R = \text{no of moles of reactants }[/tex]

[tex]\implies G^0_{rxn} = 3 \times \Delta _fG^0 [KClO_4{(s)}] + \Delta_fG^0[KCl_{(s)}] - 4 \times \Delta _f G^0 [ KClO_3 (s) ][/tex]

[tex]\Delta _fG^0 \ values \ at \ 25^0 \ C (298 \ K) are\ given \ as:\\\\ \Delta _fG^0 [KClO_4(s)] = -303.09 \ kJ \\ \\ \Delta _fG^0 [KCl(s) ] = - 409.14 \ kJ \\ \\ \Delta_f G^0 [KClO_3_{(s)}] = -296.25 \ kJ \\ \\ replacing \ the \ above \ values \ into \ equation (1) ; then:\\ \\ \\\Delta G^0_{rxn} = 3 *(-303.09) + (-409.14) - 4*(-296.25) \ kJ \\ \\ = (-909.27 - 409.14 + 1185) \ kJ \\ \\ = -133.41 \ kJ \\ \\ \mathbf{\Delta G^0_{rxn} = -133.4 \ kJ }[/tex]

The standard free energy change of the reaction is -133 kJ.

From the reaction equation, we have; 4KClO3 ⇄ 3KClO4 (s) + KCl (s). The standard free energy of formation of each specie is given below;

ΔG°f KClO3 = -296.35 kJ

ΔG°f KClO4 = -303.09 kJ

ΔG°f KCl = -409.14 kJ

Hence;

ΔG°rxn = [3(-303.09)] + ( -409.14)] - [(4( -296.35))]

ΔG°rxn = (-909.27) + (-409.14) - (-1185.4)

ΔG°rxn = -133 kJ

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What is 2AI(s) + FeO3(s) = Ai2O3(s) + 2Fe(s)

Answers

Answer:

it's a double displacement Reaction.

How can y’all do this

Does Borax pure substance?

Answers

Answer:

Borax is a natural mineral with a chemical formula Na2B4O7 • 10H2O. Borax also is known as sodium borate, sodium tetraborate, or disodium tetraborate. It is one of the most important boron compounds. The International Union of Pure and Applied Chemistry (IUPAC) name for borax is sodium tetraborate decahydrate.

i
CH3-CH2-CO-CH2-CH2-CH3 + H2
Pd​

Answers

Answer:

i don't know but I just want to have coins

which answer? Is this

Answers

Answer:

law of segregation

have a good day!

Explanation:

What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2

Answers

Answer:

Cl⁻ was oxidized.

Explanation:

4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.
Cr2O3(s) + 2Al(s) → 2Cr(s) + Al2O3(s)

a=Calculate the mass of aluminium needed to react with 50 g of Cr2O3.
b=Calculate the mass of chromium produced from 50 g of Cr2O3.
c=Calculate the mass of chromium produced from 5 kg of Cr2O3.
d=Calculate the mass of chromium produced from5 tonnes of Cr2O3.

Note: 1 tonne = 1,000,000 g
Ar: Cr = 52, O = 16, Al = 27

Answers

I’m taking a good estimation and gonna say B but I’m torn between that and D

Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equation)

Answers

Answer:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

Explanation:

Solid Iron = FeCopper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)Metal Copper = Cu

Writing the equation using symbols leaves us with:

Fe + CuNO₃ → Fe(NO₃)₃ + Cu

It is not balanced yet. Now we balance the NO₃ species on the left side:

Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu

Finally we balance the Cu species on the right side:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

What is the concentration of a solution with a
volume of 2.5 liters containing 660 grams of
calcium phosphate Ca3(PO4)2 ?

Answers

Answer:

660gx Imol = 2.1278 mol 310.189 2.5L 1.85 m).

Explanation:

The number of moles of 660 grams of calcium phosphate is 2.127. Then the molarity of the solution of 2.5 liter volume is 0.85 M.

What is molarity ?

Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute particles to the volume of solution in liters. Hence, its unit is mol/L or molar.

The molarity of a solution is a colligative quantity as well as temperature dependent.

Given,

molar mass calcium phosphate,  Ca₃(PO₄)₂  =310.18 g/mol

Then,

no.of moles of calcium sulphate in 660 g = 660 g/310.18 g/mol = 2.127 moles

volume of solution = 2.5 L

Molarity = no.of moles of solute/ volume of solution in L

M = 2.127 moles/ 2.5 L

   = 0.85 M.

Therefore, the molarity of the given solution is 0.85 molar.

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Question 1 of 10
What variable represents thermal energy in the equation Q=MAT?
O A. The variable e
O B. The variable Q
O c. The variable
O D. The variablem

Answers

Option b I think :) hope this helped!

A student places 2 mL of 2% ethanolic silver nitrate solution into test tube. They add 2 drops of an unknown compound into the test tube while gently mixing. After five minutes, the student heated the test tube in a water bath and a white precipitate formed. They added 2 drops of 1 M nitric acid to the mixture which was cooled to room temperature and still noticed the precipitate did not dissolve in response to the nitric acid. What compound is most likely the unknown

Answers

Answer:

hi

Explanation:

i am smart but i need this app cuz some are realy hard

Calculate the mass of CO2 that can be produced if the reaction of 54.0 g of propane and sufficient oxygen has a 64.0% yield.

Answers

Answer:

103.9 g

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First we convert 54.0 g of propane (C₃H₈) into moles, using its molar mass:

54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈

Then we convert 1.23 moles of C₃H₈ into moles of CO₂, using the stoichiometric coefficients:

1.23 mol C₃H₈ * [tex]\frac{3molCO_2}{1molC_3H_8}[/tex] = 3.69 mol CO₂

We convert 3.69 moles of CO₂ into grams, using its molar mass:

3.69 mol CO₂ * 44 g/mol = 162.36 g

And apply the given yield:

162.36 g * 64.0/100 = 103.9 g

what is another name for horse

Answers

Answer:

Mount, Charger, Colt, Pony, and Folt

Explanation:

Answer:

A stallion or a mare

Explanation:

What is the other product for this reaction? Hbr + NaOH —> ( select 2)

Answers

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Answer: HBr + NaOH = nabr + h2o

Explanation:

I hope this helped!

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Exit ticket: Name the 2 factors that Terrestrial Biomes are separated by ___________ & ________

Answers

Answer:

temperature and rainfall

Explanation:

Using the periodic table, choose the more reactive nonmetal.
Te or O

Answers

Answer:

answer is TE

Explanation:

Answer:

Tellurium is more reactive than Oxygen

This timeline woulchre useful to someone who was writing a report titled

Answers

A la clase d no me voy al trabajo y me voy al colegio a las

If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?

Answers

Answer:

2.64 M

Explanation:

Use the dilution equation M1V1 = M2V2, where:

M1 = 12.0 M HCl

V1 = 220 mL HCl

M2 = ?

V2 = 1000 mL HCl

(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)

M2 = 2.64 M HCl

PLEASE HELP!!
A scientist places a pH meter in a sample of concentrated potassium hydroxide (KOH). The scientist slowly adds nitric acid (HNO3) to the KOH and monitors the pH. Describe how the pH and hydronium ion concentration will change in the solution as the acid is added.

Answers

Answer:

pH of the solution will decrease & hydronium ion concentration will increase in the solution as the acid is added.

Explanation:

A 20 mL sample of human urine was found to have 10 mg of
urea during analysis. The molar mass of urea is 60.1 g/mol.
Calculate the molarity of urea in the given sample.

Answers

0.008
Molarity=
Mw
2

×V
sol

(in mL)
W
2

×1000

⟹W
2

=5 mg =5×10
−3
g
∴M=
60×10
5×10
−3
×10
3


=0.008

If a mechanical wave has a frequency of 0.147 Hz and a wavelength of 12.05 m, what is the velocity of the wave? (round to the hundredths place)

Answers

Answer:

0.147 Hz   because I took the test

The velocity of a wave is the product of its frequency and wavelength. The  velocity of wave with 0.147 Hz and 12.05 m is 1.77 m/s.

What is frequency ?

The frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of time period of the wave. It is inversely proportional to the wavelength. Unit of frequency is Hz which is equivalent to s⁻¹.

The wavelength of a wave is the distance between two consecutive crests or troughs. The wavelength λ, and frequency ν of a wave is related to the velocity  v of the wave as follows:

v = νλ

Given that,

frequency = 0.147 Hz

wavelength = 12.05 m

then, velocity = 0.147 Hz × 12.05 m = 1.77 m/s.

Therefore, the velocity of the mechanical wave is 1.77 m/s.

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When air hockey is played, a small plastic puck slides across a table that has holes through which air is forced. What effect does the air have on the game?

Answers

Answer:

it reduces the atmospheric pressure

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