Answer:
20.49
Explanation:
number of mole equal mass/molar mass and the number of mol is 0.17 and the molar mass is 12 then you substitute and solve.
which of these is not a process of chemical weathering?
1.cracked sidewalk.
2.wearing away of the inscriptions on a New York City Monument.
3.Rusty Nail.
4.dissolving of limestone which makes caves.
A rock-climbing group reached the top of Mount Everest in the Himalayan mountains. Mount Everest is about 29,000 feet above sea level and formed by the interaction of two tectonic plates. The group leader was surprised to find fossilized marine organisms on top of the mountain. Which of the following describes the geologic history of Mount Everest?
Answer:
Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.
Explanation:
:)
Adaptation for animals that live in the desert
Answer:
have thick fur on feet protecting them from the hot ground; have large, bat-like ears radiate body heat and help keep them cool; have long, thick hair that insulates them during cold nights and protects them from the hot sun during the day; have light coloured fur to reflect sunlight and keep their bodies cools.
Explanation:
I hope this helps!
Given the atomic mass of select elements, calculate the molar mass of each salt.
Element Molar mass
(g/mol)
Beryllium (Be) 9.012
Magnesium (Mg) 24.31
Cobalt (Co) 58.93
Cadmium (Cd) 112.41
Bromine (Br) 79.90
Match the numbers to the appropriate blanks in the sentences below. Make certain each sentence is complete before submitting your answer.
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1. The molar mass of MgBr2 is The molar mass of M g B r 2 is blank..
2. The molar mass of BeBr2 is The molar mass of B e B r 2 is blank..
3. The molar mass of CoBr2 is The molar mass of C o B r 2 is blank..
4. The molar mass of CdBr2 is The molar mass of C d B r 2 is blank..
3. What molecule or ion acts as the nucleophile in the base-catalyzed reaction between acetic anhydride and vanillin? A. Vanillin as a neutral phenol B. Vanillin as a phenoxide ion (conjugate base) C. Acetic anhydride D. Sodium hydroxide 4. According to the class notes, the first step in the acid-catalyzed reaction between acetic anhydride and vanillin is: A. Loss of a proton from the alcohol group in vanillin B. Protonation of acetic anhydride C. Protonation of the alcohol group in vanillin D. Departure of water as a leaving group in vanillin FOR QUESTIONS 5 AND 6 USE THE FOLLOWING INFORMATION: • Vanillin (solid) MW = 152.15 g/mol • Acetic anhydride (liquid) MW = 102.04 g/mol • Acetic anhydride density = 1.082 g/mL 5. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the BASE CATALYZED reaction as described in the textbook? A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride B. 45.6 mmol of vanillin and 82 mmol acetic anhydride C. 8.45 mmol of vanillin and 2 mmol acetic anhydride D. 2 mmol of vanillin and 2 mmol acetic anhydride 6. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the ACID CATALYZED reaction as described in the textbook? A. 23 mmol of vanillin and 102 mmol acetic anhydride B. 11 mmol of vanillin and 1 mmol acetic anhydride C. 1 mmol of vanillin and 10.6 mmol acetic anhydride D. 1 mmol of vanillin and 9 mmol acetic anhydride
Answer:
B
B
A
C
Explanation:
3
B. Vanillin as a phenoxide ion (conjugate base)
4
B. Protonation of acetic anhydride
5
A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride
6
C. 1 mmol of vanillin and 10.6 mmol acetic anhydride
The center part of an atom is called the
Answer: Nucleus (Hope it is Right!)
K2HPO4 is a highly water-soluble salt. It can be used as a buffering agent, food additive, or
fertilizer. The neutralization of phosphoric acid with potassium hydroxide can be used to form
potassium hydrogen phosphate.
H3PO4 + 2KOH K2HPO4 + 2H2O
100 g of phosphoric acid (H3PO4) is reacted with excess potassium hydroxide. The final mass
of K2HPO4 produced is found to be 163 g.
What is the percent yield?
Answer:
91.7%
Explanation:
The percent yield when it could be used as a buffering agent should be considered as the 91.74%.
Calculation of the percent yield:Since we know that
Number of moles = Mass in gram / Molar mass
And,
Molar mass of H3PO4 = 97.994 g/mol
So,
Number of moles of H3PO4
= 100 g / 97.994 g/mol
= 1.02 mol
Now
Molar mass of K2HPO4 = 174.2 g/mol
So,
Theoretical yield of K2HPO4 = 174.2 g/mol * 1.02 mol
= 177.684 g
So finally
Percent yield = Actual yield * 100 / Theoretical yield
= 163 g * 100 / 177.684 g
= 91.74%
hence, The percent yield when it could be used as a buffering agent should be considered as the 91.74%.
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LO
82
KE<200 after three years and Rs.
82. Compound interest. The
A sum of money becomes Rs.
4400 after six years on
is:
400482.82 KF
32017, KF0018?
00018282 KF0018282 KF0018282 K
SKO 282 KF0018282 KF001Non KF0018
018282'KF0018282 KF0018
R 00786 2 KF00182825
0182
500182
82 KF0018282 KF
Answer: Rs. 1,100
Explanation:
Compound interest calculation at three years:
2,200 = Amount * (1 + r) ³
Compound interest at six years.
4,400 = Amount * (1 + r) ⁶
Divide them to eliminate variables:
4,400/ 2,200 = (Amount * (1 + r) ⁶) / (Amount * (1 + r) ³)
2 = (Amount * (1 + r) ³)
If (Amount * (1 + r) ³ is 2 then Amount at 3 years is:
2,200 = Amount * 2
Amount = 2,200 / 2
= Rs. 1,100
A weather balloon contains 394 L of hydrogen gas at STP. How many moles of hydrogen are present?
Answer:
PV=nRT
STP is 100kPa and 273.15K
PV/RT=n
n=17.3moles
Explanation:
How might a rock form very quickly, and then remain stable, or unchanged, for a very long period of time? Include a specific example in your explanation.
Answer:
igneous rocks
Explanation:
One type of rock that forms very quickly would be igneous rocks. These are rocks that form after a volcanic eruption, where the molten magma melts everything into lava which then hardens shortly after. This creates a new rock that is a mixture of many other materials called Igneous rocks. Once hardened they usually remain stable and unchanged for a very long time until the next volcanic eruption. An example if the eruption of Tambora which after finishing has created lots of igneous rocks and has not erupted again since 1815.
A rock form easily through volcanic eruption, and remain stable, or unchanged, for a very long period of time because of strong bonding in constitute minerals.
What is rock?Rock is a solid substance which is naturally occur in the environment, it is made up from minerals. Mainly three types of rocks are present, which are igneous rock, metamorphic rock and sedimentary rock.
We obtain rocks generally by the volcanic eruption and as it is made up of minerals and different minerals have different crystal structure and bonding in these minerals are very strong which not break easily. That's why rocks remain stable or unchanged for a very long time. Only volcanic eruption will break rocks because only they have that much of energy to break. Examples of hard rocks are granite, syenite, unikite, andesite, etc.
Hence, due to strong bonds rocks will stay stable for long time.
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Can a chemical reaction be both exothermic and endothermic? Explain.
Answer:
It cannot be both, because the heat released or absorbed is also equal to the difference in total heat content of the reactants and products. So, it cannot be both.
Answer:
B
Explanation:
Antonio and Addie want to know if perfume fumes affect plant height. They place five identical bean plants in five identical light boxes. In four of the boxes, they place 200 milliliters (mL) of perfume at different distances from the plants, and they make observations twice a week for one month. Which choice best identifies the observation data that should be included in their data table?
Answer:
I think its C I'm sorry if I'm wrong good luck guys!
Explanation:
A certain substance has a heat of vaporization of 64.08 kJ/mol. At what Kelvin temperature will the vapor pressure be 6.50 times higher than it was at 355 K?
Answer:
[tex]T_2 =388.50K[/tex]
Explanation:
Given
[tex]p_1 = ??[/tex] -- Initial vapour pressure
[tex]p_2 = 6.50p_1[/tex] --- Final vapour pressure
[tex]T_1 = 355K[/tex] ---- Initial temperature
[tex]T_2 = ??[/tex] --- Final temperature
[tex]\triangle _{vap}H = 64.08kJmol[/tex] --- Enthalpy of vaporization
Required
Calculate T2
To do this, we make use of Clausius-Clapeyron equation.
Which states that:
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex]
Where:
[tex]R = 8.314 J.K^{-1}mol^{-1}[/tex] --- Universal Gas constant
[tex]\triangle _{vap}H = 64.08kJmol[/tex]
[tex]\triangle _{vap}H = 64080\ kJmol[/tex]
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex] becomes
[tex]ln(\frac{6.50p_1}{p_1}) = \frac{64080}{8.314}(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(\frac{6.50p_1}{p_1}) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(6.50) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]1.872 = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
Take LCM
[tex]1.872 = 7707.48(\frac{T_2 - 355}{355T_2})[/tex]
[tex]1.872 = 7707.48*\frac{T_2 - 355}{355T_2}[/tex]
[tex]1.872 = \frac{7707.48*(T_2 - 355)}{355T_2}[/tex]
Cross Multiply
[tex]355T_2*1.872 = 7707.48*(T_2 - 355)[/tex]
[tex]664.56T_2 = 7707.48T_2 - 2736155.4[/tex]
Collect Like Terms
[tex]664.56T_2 - 7707.48T_2 =- 2736155.4[/tex]
[tex]-7042.92T_2 =- 2736155.4[/tex]
Make T2 the subject
[tex]T_2 =\frac{- 2736155.4}{-7042.92}[/tex]
[tex]T_2 =388.497299416[/tex]
[tex]T_2 =388.50K[/tex]
The final temperature is 388.50K
The temperature at which the vapor pressure will be 6.50 times higher than it was at 355K is 389 K
The Clausius-Clapeyron Equation is widely used for the determination of the vapor pressure of another temperature, provided we know the vapor pressure at a certain temperature as well as the heat of vaporization.
Given that:
the heat of vaporization [tex]\mathbf{\Delta H_{vap} = 64.08 \ kJ/mol = 64.08 \times 10^3 J/mol}[/tex] the initial temperature T₁ = 355 Kthe final temperature T₂ = ???if the pressure at T₁ = P₁then, the pressure at T₂ = 6.5P₁the universal gas constant = 8.314 J/K/molBy using the Clausius-Clayperon Equation:
[tex]\mathbf{In \Big( \dfrac{P_2}{P_1} \Big) = \dfrac{\Delta H_{vap}}{R} \Big (\dfrac{1}{T_1} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In \Big( \dfrac{6.5P_1}{P_1} \Big) = \dfrac{64.08 \times 10^3 }{8.314} \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In(6.5)=7707.48 \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{1.872 =21.71 - \dfrac{7707.48}{T_2} }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 21.71- 1.872 }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 19.838 }[/tex]
[tex]\mathbf{T_2= \dfrac{7707.48}{19.838} }[/tex]
[tex]\mathbf{{T_2}=388.521 \ K }[/tex]
T₂ ≅ 389 K
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1. How many liters of water can be produced with 45 moles of sodium hydroxide?
What is the maximum number of grams of HCl that will dissolve in 200 grams of water at 70°C?
Answer:
34.0
Explanation:
Answer:
34.0g will be the amount that will dissolve in 200g of water at 70°C.
What is the formula for Disulfur Pentafluoride?
Answer:
please mark me as brainliest so difficulty to find me and edit
. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Answer:
Answer is explained in the explanation section below.
Explanation:
This question is requires the diagram, which I have drawn and it is attached in the attachment below. Please for this answer, refer to the diagram attached in the attachment below.
Referring to the diagram, attached. As we know that, Allylic secondary carbocations are more stable than Allylic tertiary carbocations.
Hence,
C2 will have a more positive charge since a tertiary carbocation (C2) is more stable than a secondary carbocation (C4). Therefore, the resonance structure will favor the positive charge at C2.
The resonance structure formed for 2-methyl 1-3 penatdiene are allylic secondary and tertiary carbocation compounds.
What is protonation?Protonation is the addition of hydrogen or the protons to the carbon in an organic compound. The addition of hydrogen takes place at the carbon that forms the stable compound.
The protonation of 2-methyl-1,3 pentadiene is given in the image attached.
The expected carbocation in the structure with the positive charge is C-2, as it forms a more stable product than C-4 due to less repulsion.
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1) G to H.
2) I to J.
3) J to I.
4) I to H.
3 ..............................
b. If you have 50 grams of Molybdenum-99, how many grams will remain
after 11 days?
Answer:
6.25gm
half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times
Explanation:
If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Molybdenum-99 follows first-order decay.
What is first-order decay?First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.
The half-life (th) of Mo-99 is 66 h.
We will find its rate constant (k) using the following expression.
k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹
Next, we will convert 11 days to hours, knowing that 1 day = 24 h.
11 d × 24 h/1 d = 264 h
If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.
[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]
where,
[Mo] is the final amount of Mo-99.[Mo]₀ is the initial amount of Mo-99.t is the elapsed time.If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
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The theoretical yield of Baso, is 58.35 g. If 44.34 g of BaSO4 are produced from the reaction shown above, what is the percent yield of Ba50_?
BaCl2(aq)+Na2SO4(aq)—>2NaCl(aq)+BaSO4(s)
a85.17%
b75.99%
c31.67%
d52.03%
Answer:75.99
Explanation:saw it on quizlet
When the theoretical yield of Baso, is 58.35 g And, there is 44.34 g of BaSO4 are produced so the percent yield is option b 75.99%.
Calculation of the percent yield:Since
The theoretical yield of Baso, is 58.35 g. And, there is 44.34 g of BaSO4 are produced
So, here the percent yield is
= Actual yield / theoretical yield
= 44.34 / 58.35
= 75.99%
Hence, the option b is correct.
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Use Avogadro's number, 6.02E23, to calculate the number
of particles found in 0.004 moles of carbon dioxide
CO2
Answer:
2.408 × 10²¹ is the correct answer!!reactivity of alkali metals increases down the group while reactivity of helogens decreases down the group
Complete question is;
Chemical reactivity of alkali metals increases down the group while reactivity of halogens decreases down the group. Give reasons
Answer:
Explained below
Explanation:
Alkali metals exhibit reactivity due to their electropositivity. Now, for alkalis, their electro-positivity increases down their group. Since their reactivity increases with increase in electropositivity, it means their reactivity also increases down the group.
Whereas, the reactivity of halogens occurs as a result of their electronegativity. Now, electronegativity for halogens decreases down the group. Since their reactivity decreases with decrease in electronegativity, it means that their reactivity will also decrease down the group.
Would the chlorine atom or ion be larger?
Answer:
Chlorine Ion
Explanation:
The chlorine ion is adding 1 valence electron in order to complete its outer most shell. It has a charge of 1- meaning it is adding an electron.
Please help :) hope you have a good day
Have a wonderful day :) thanks for the points
differences between reversible and irreversible changes
Answer:
Difference between reversible changes and irreversible changes. A substance can return to its original state. ... Most physical changes are reversible changes. All chemical changes are irreversible changes.
Explanation:
i hope i helped answer your question
:D
Answer:
Difference between reversible changes and irreversible changes. A substance can return to its original state. ... Most physical changes are reversible changes. All chemical changes are irreversible changes.
PLS mark me brainllest
What is a word that means carbon and water
Answer:
When Carbohydrates are burned (decomposed ) they break down into carbon and water.
Explanation:
The formula for glucose sugar is C6H12O6 If the compound is broken down it results in
6C+6H2O six carbon atoms and six water molecules.
An experiment that illustrates this well is to pour concentrated sulfuric acid about 1/3 deep into the volume of graduated sucrose sugar in a beaker about 1/4 full
The sulfuric acid is hydrophilic it will break the sucrose sugar molecule apart. The water will rise as steam above the beaker.
The sugar will turn brown and the a black carbon cone will rise out of the sugar sulfuric acid solution. The carbon cone will rise about the top of the beaker.
This experiment shows that the carbohydrate sugar is made of only Carbon and Water.
A first-order decomposition reaction has a rate constant of 0.00683 yr−1. What is the half-life of the reaction?
Answer:
101 years
Explanation:
Use the half life equation, where t1/2 is the half life, and k is the rate constant:
t1/2 = 0.693/k
t1/2 = 0.693/0.00683 yr -1
t1/2 = 101 years
Which property does an acid have?
tastes bitter
reacts with metals
tastes salty
feels slippery
An acid have a property to reacts with metals.
What is acid?An acid is a substance which produces H⁺ ion in the aqueous solution.
An acid has a property to react with metal to produce salt and hydrogen gas, in the given way:
2HCl + M²⁺ → H₂ + MCl
Acid has a sour taste and base has a bitter taste.
Hence, an acid have a property to reacts with metals.
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Your uncle complained about feeling weak and dizzy and having experienced
palpitations. The doctor’s diagnosis is that he has hyperthyroidism, which may lead to
goiter. Which of the following ions is related to this disorder?
A. Calcium ion
B. Potassium ion
C. Iodine ion
D. Sodium ion
Answer:
C.Iodine ion
Explanation:
BECAUSE HIS LACK OF IODINE THAT'S WHY HE HAS GOITER
1. Mixing Water at Two Temperatures
a. One flask contains 150.0 g water at 20.0 °C. A second flask contains 350.0 g water at 95.0 °C. If the two water samples are mixed, what will the final temperature of the water be?
-Assume that the density of water it 1.000 g/cm^3
-The specific heat capacity for water is 4.184 J/g °C
Answer:
[tex]T_f=72.5\°C[/tex]
Explanation:
Hello!
In this case, since this a problem in which the cold water is heated by the hot water, we can write:
[tex]Q_{hot}+Q_{cold}=0[/tex]
Thus, by plugging in the mass, specific heat and temperatures, we obtain:
[tex]m_{hot}C_{hot}(T_f-T_{hot})+m_{cold}C_{cold}(T_f-T_{cold})=0[/tex]
Now, we can also write:
[tex]m_{hot}(T_f-T_{hot})+m_{cold}(T_f-T_{cold})=0[/tex]
Then, after applying some algebra, it is possible to obtain:
[tex]T_f=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]
If we plug in, we obtain:
[tex]T_f=\frac{350.0g*95.0\°C+150.0g*20.0\°C}{350.0g+150.0g}[/tex]
[tex]T_f=72.5\°C[/tex]
Best regards!