Answer:
m = 7.29 grams
Explanation:
Given that,
Initial temperature, T₁ = 25ºC
Final temperature, T₂ = 31.5ºC
The specific heat of the metal is 0.89 J/gºC.
We know that the heat released due to the change in temperature is given by :
[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g[/tex]
So, the mass of the piece is equal to 7.29 grams.
Which of the following masses represent 0.500 mol of the
indicated substance?
Answer: 103.6 g
Explanation:
On CK-12
How many L of 3.0M solution
can be made with 78g of
NaCl?
Answer:
Need to find moles NaCl.
526 grams NaCl (1 mole NaCl/58.44 grams)
= 9.0 moles NaCl
----------------------------------------------------
now,
Molarity = moles of solute/Liters of solution
or, for our purposes
Liters of solution = moles of solute/Molarity
Liters of solution = 9.0 moles NaCl/3.0 M
= 3.0 liters in volume
PLEASEEE HELPPP WILL MARK BRAINLIEST FOR RIGHT ANSWER!!!
You have an unknown concentration of 0.035 L of HCl acid and added 0.033 L of 0.3 M NaOH before the equivalence point was reached. What is the concentration of the HCl?
HCl + NaOH -> H2O + NaCl
A) 0.28 M HCl
B) 0.11 M HCl
C) 0.035 M HCl
D) 3.14 M HCl
Answer:
A
Explanation:
Answer:
C
Explanation:
Pretty sure!
Calculate the specific heat of a substance given that 49 joules of heat is required to raise the temperature of 25.0 g of the substance from 92.6 ºC to 99.4 ºC.
Answer:
0.29 J/g.°C
Explanation:
Step 1: Given data
Added heat (Q): 49 JMass of the substance (m): 25.0 gInitial temperature: 92.6 °CFinal temperature: 99.4 °CStep 2: Calculate the temperature change (ΔT)
ΔT = 99.4 °C - 92.6 °C = 6.8 °C
Step 3: Calculate the specific heat of the substance (c)
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C
The titration of HCl with NaOH is an example of:
A. a weak acid-weak base titration,
B. a weak acid-strong base titration.
c. a strong acid-strong base titration.
D. a strong acid-weak base titration.
Answer:
I’m pretty sure it’s C
Explanation:
AP Ex
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0L flask with 4.5 atm of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be 1.1 atm. Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
Kp = 7.4727
Explanation:
Let's write the balanced equilibrium reaction:
2NH₃ <-------> N₂ + 3H₂ Kp = ??
Now, if we want to calculate the Kp, we need to write an ICE chart with this reaction, which is the following:
2NH₃ <-------> N₂ + 3H₂
I. 4,5 0 0
C. -2x +x +3x
E. 4,5-2x x 3x
According to this chart, the Kp expression should be:
Kp = (PH₂)³ * (PN₂) / (PNH₃)² (1)
The value of x, we already know it because the problem states that the amount of nitrogen gas is 1.1 atm, so replacing this value into (1) we have:
Kp = (3*1.1)³ * (1.1) / (4.5 - (2 * 1.1))²
Kp = 39.5307 / 5.29
Kp = 7.4727Hope this helps
What is the percent yield of a reaction producing 26g Iridium V Sulfate from 30g Lithium Sulfate and 30g Iridium V Carbonate?
The substance ammonia has the following properties: normal melting point: 195.4 K normal boiling point: 239.8 K triple point: 5.9×10-2 atm, 195.3 K critical point: 111.5 atm, 405.5 K At temperatures above 405.5 K and pressures above 111.5 atm, NH3 is a _________ . NH3 does not exist as a liquid at pressures below atm. NH3 is a _________ at 5.90×10-2 atm and 249.5 K. NH3 is a _________ at 1.00 atm and 236.0 K. NH3 is a _________ at 24.6 atm and 185.6 K.
Answer:
a) Superficial fluid
b) 5.9*10^-2 atm
c) Gas
d) Liquid
e) Solid
Explanation:
a) At temperatures above 405.5 K and pressures above 111.5 atm, NH3 is a superficial fluid because liquid and gases does not exit at temperature and pressure greater than 405.5 K and 111.5 atm
b) NH3 does not exist as a liquid at pressures below 5.9*10^-2 atm , That is below the triple point there is existence of liquid
c) NH3 is a Gas at 5.90×10^-2 atm and 249.5 K.
d) NH3 is a Liquid at 1.00 atm and 236.0 K. because pressure and temperature ( standard ) is between the given normal melting and boiling point
e) NH3 is a solid at 24.6 atm and 185.6 K . because the pressure here is more than that of triple point while the temperature is lesser
What is all the colors in a rainbow
Answer:
Red, orange, yellow, green, blue, indigo, violet.
Explanation:
Answer:
Red, orange, yellow, green, blue, purple, violet.
Explanation:
What is the IUPAC name for the following compound?
a. benzenecarbonitrile
b. benzenecyanide
c. phenylcyanide
d. cyanophenyl
Answer:
Option a. Benzenecarbonitrile
Explanation:
You are not providing the picture of the compound. However, I manage to find the picture of it, so I'm gonna answer this with the picture. Its attached here at the end.
As for the IUPAC name of this compound, it would be Benzenecarbonitrile, or simply, benzonitrile.
This compound has the molecular formula C₆H₅CN. It receives this name over the other ones, because this is a aromatic cyanide, and aromatic cyanide has nitriles behavior, (Strength of the nitrogen over the carbon), therefore, this group has priority over the whole molecule. As the principal chain is the benzene, the carbonitrile is the radical of the group, and when cyano groups are as radical and not as principal chains, it has a behavior of nitrile, and it's named as nitrile. therefore, option b, cannot be the name.
phenylcyanide is naming the phenyl as radical, but the benzene is the principal group in this compound, and the cyanide is the radical. It happens the same thing with cyanophenyl.
Hope this helps
2C4H10(g) + 1302(g) → 8CO2(g) + 10 H2O(g)
3. How many moles of water is produced from 0.859 moles of C4H10?
Answer:
Explanation:...
A balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
the volume of the balloon when the temperature is 310K?
Answer:
What is
the volume of the balloon when the temperature is 310K?
how much corn syrup should be added to water to make 200 mL of a 10% by volume solution
To make 200 mL of a 10% by volume solution, add 20 mL corn syrup to water.
What is volume solution?Volume percent of a solution is defined as the ratio of the volume of solute present in a solution to the volume of the solution as a whole. It means that the volume of a closed figure determines how much three-dimensional space it can occupy. In terms of numerical value, volume is the amount of three-dimensional space enclosed by a closed surface. For example, a substance's space can be solid, liquid, gas, or plasma, or any other space-occupying shape. The volume percentage of a solution can be calculated by dividing the volume of solute by the volume of solution and multiplying the result by 100. The basic formula for volume is length width height, whereas the basic formula for area of a rectangular shape is length width height. The calculation is unaffected by how you refer to the various dimensions: you can, for example, use 'depth' instead of 'height.'To learn more about volume solution, refer to:
https://brainly.com/question/27030789
#SPJ2
When calcium forms an ion that has the same number of outer electrons as which noble gas?
1. neon
2. helium
3. argon
4. krypton
BRAINLIEST FOR HELP ASAP!!!!
What answer is it and how ? please help !!!!!! ill mark brainlyest if right
Answer:
The answer is B
Brainliest please!
12 moles of sodium into grams
Answer:
12 moles sodium= 275.87724000000003 grams
Explanation:
1 moles sodium = 0.043497607849056.
What volume is occupied by 2.0 mol of gas at 3.0 atm
and 27 °C?
Determine the number of molecules of C2CI4 contained in 73.1g of C2CI4
Answer:
2.35x10²³ molecules of C2Cl4 are present
Explanation:
To solve this question we must convert, as first, the mass of C2Cl4 to moles using its molar mass (C2Cl4 = 165.83g/mol). Then, using Avogadro's number we can find the number of molecules:
Moles C2Cl4:
73.1g * (1mol / 165.83g) = 0.441 moles C2Cl4
Molecules:
0.441 moles C2Cl4 * (6.022x10²³molecules / 1mol) =
2.35x10²³ molecules of C2Cl4 are presentWhat is the mass of 9.23*10^41 atoms of phosphorus (P)?
(Put your answer in scientific notation)
Answer:
[tex]m_P=4.75x10^{19}g\ P[/tex]
Explanation:
Hello there!
In this case, according to the given atoms of phosphorous, it is possible to calculate the mass of those atoms by bearing to mind the definition of mole in terms of the Avogadro's number; which refers to the mass and amount of particles in one mole of any element as equal to the atomic mass and the Avogadro's number respectively:
[tex]1 molP=6.022x10^{23}atoms\ P=30.97gP[/tex]
Which is used to obtain the required mass of P:
[tex]m_P=9.23x10^{41}atoms\ P*\frac{30.97g P}{6.022x10^{23}atoms\ P}\\\\m_P=4.75x10^{19}g\ P[/tex]
Regards!
Se prepara una concentración molar 0.5M de hidróxido de sodio (NaCH) con la finalidad de determinar el grado de acidez de una bebida embotellada. Calcula la cantidad de gramos de hidróxido de sodio (NaCH) que se requiere para preparar 5 litros de dicha solución.
Answer:
100 g
Explanation:
Primero hay que calcular el número requerido de moles de NaOH, usando la definición de molaridad:
Molaridad = moles / litros0.5 M = moles / 5 Lmoles = 2.5 molesAhora hay que convertir 2.5 moles de NaOH en gramos, usando su masa molecular:
2.5 mol * 40 g/mol = 100 gSe requieren 100 gramos de NaOH.
1. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -CH3
b) -CH2OH
c) -CH2NH2
d) -CH2BR2. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:a) -F
b) -CH2OH
c) -CHO
d) -CH3
Answer:
1. CH₂Br > CH₂OH > CH₂NH₂ > CH₃
2. -F > -CHO > - CH₂OH > CH₃
Explanation:
The arrangement of the above atom is due to their atomicity and electronegativity of the given compounds.
From (1) we will realize that Bromine (Br) possesses the greatest priority because its atomic number is the highest. This is followed by oxygen (O) in CH₂OH since atomic no 8 is higher than that of Nitrogen N(7). Lastly, CH₃ has the only hydrogen attached to it with the atomic no of (1)
In the second part of the question>
The electronegativity of an element increases across the period and down the group. Fluorine is highly electronegative and contains the highest atomic number of oxygen in -CHO. The oxygen (O) in -CHO has a double bond which gives an edge over the (O) in CH₂OH. Lastly, CH₃ contains a substituted hydrogen atom
Please help will give brainliest to right answer!!
You add 1.5 moles of HF to 6 liters of water. The concentration is at equilibrium when [H+] is at 0.10 M. What is the Ka of HF? HF -> H+ + F-.
A) 0.067
B) 0.10
C) 0.25
D) 1.5
Answer:
C
Explanation:
NP
1. Alexa and her family travelled 5 hours south east on 1-45 to crystal
beach this summer for vacation. If the trip was a total of 340 miles,
what was her average speed?
EQUATION
PLUG N NUMBERS
INTO THE EQUSTION
ENALANSWER WITH
UNTS
Answer:
Average speed = 68 mph
Explanation:
Given that,
Total distance traveled by the family, d = 340 miles
The family traveled 5 hours southeast.
We need to find her average speed. The speed of an object is given by the total distance covered divided by time taken. So,
[tex]v=\dfrac{d}{t}[/tex]
Put all the values,
[tex]v=\dfrac{340}{5}\\\\v=68\ mph[/tex]
So, her average speed is equal to 68 mph.
how many moles of solute are needed to make 250 mL of a 0.50 M solution of sodium phosphate
Answer:
0.125 moles of solute
Explanation:
The formula for molarity (M) is moles of solute/liters of solution. First, convert 250 mL into liters:
250 mL/1 * 1 L/1000 mL = 0.25 L.
Then, plug in the values of m/L = M
m/0.25 = 0.5
Solve for moles (m). You would multiply 0.5 by 0.25.
m = 0.125
Lastly, if you'd like to check it and see if it's correct, do 0.125/0.25, and you should get 0.5 M.
Answer:
[tex]\boxed {\boxed {\sf 0.125 \ mol }}[/tex]
Explanation:
Molarity is a measure of concentration. It is the moles of solute per liters of solution.
[tex]molarity = \frac{ moles \ of \ solute}{ liters \ of \ solution}[/tex]
We know the solution has a molarity of 0.5 M or moles per liter. There are 250 milliliters of solution. First, we need to convert to liters. 1 liter is equal to 1000 milliliters.
[tex]\frac {1 \ L}{ 1000 \ mL}[/tex][tex]250 \ mL *\frac {1 \ L}{ 1000 \ mL}[/tex][tex]\frac {250 }{ 1000 } \ L = 0.25 \ L[/tex]Now we can substitute the values we know into the formula.
molarity= 0.5 mol/L liters of solution = 0.25 Lmoles of solute=x (unknown)[tex]0.5 \ mol/L= \frac{ x}{0.25 \ L}[/tex]
Since we are solving for the moles of solute, we need to isolate the variable x. It is being divided by 0.25 L. The inverse of division is multiplication. Multiply both sides by 0.25 L.
[tex]0.25 \ L *0.5 \ mol/L= \frac{ x}{0.25 \ L}*0.25 \ L[/tex]
[tex]0.25 \ L * 0.5 \ mol/L =x[/tex]
[tex]0.25 * 0.5 \ mol=x[/tex]
[tex]0.125 \ mol =x[/tex]
0.125 moles of sodium phosphate are needed to make 250 mL of a 0.50 M solution.
PLEASE HURRY I WILL GIVE BRAINYEST
Where are the majority of temperate grasslands located?
A interiors of continents
B along the coastline
C in desert regions
D between mountain ranges
Answer:
D. Between mountain ranges
Explanation:
Usually in between mountains is where the most grass is.
Answer:
in the interior of continents
Explanation:
A 500.0 g sample of aluminium, I initially at 25.0 degrees, absorbs heat from its surroundings and reaches a final temperature of 90.7 degrees. How much heat (in KJ) has been absorbed by the sample? To one decimal place
Specific heat= 0.9930j g-1 K-1 for aluminium
A 500.0 g sample of aluminum, initially at 25.0 degrees, absorbs heat from its surroundings and reaches a final temperature of 90.7 degrees. 32.62245 kJ heat has been absorbed by the sample.
What is specific heat?The term specific heat is defined as the amount of heat required to increase the temperature of 1 gram of a substance 1 degree Celsius (°C).
To calculate the amount of heat absorbed by the sample, use the formula:
Q = mcΔT
where Q is the amount of heat absorbed by the sample, m is the mass of the sample, c is the specific heat of aluminum, and ΔT is the change in temperature of the sample.
Substituting the given values into the formula, we get:
Q = 500.0 g × 0.9930 J/g·K × (90.7°C - 25.0°C)
Q = 500.0 g × 0.9930 J/g·K × 65.7 K
Q = 32,622.45 J
To convert the result to kilojoules (kJ), we divide by 1000:
Q = 32.62245 kJ
Thus, the amount of heat absorbed by the sample is 32.6 kJ.
To learn more about the specific heat, follow the link:
https://brainly.com/question/11297584
#SPJ3
What volume of O2 is required to react with CS2 to produce 4 liters of CO2?
Answer:
12 L of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
CS₂ + 3O₂ —> CO₂ + 2SO₂
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Finally, we shall determine the volume of O₂ required to produce 4 L of CO₂. This can be obtained as follow:
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Therefore, xL of O₂ will react to produce 4 L of CO₂ i.e
xL of O₂ = 3 × 4
xL of O₂ = 12 L
Thus, 12 L of O₂ is needed for the reaction.
When 1 mol of a nonvolatile, nondissociating solute is dissolved in 3 mol of volatile solvent, the ratio of vapor pressure of the solution to that of the pure solvent (at the same temperature) is approximately:________
Answer:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Explanation:
Hello there!
In this case, since the solvation of a nonvolatile-nondissociating solute in a volatile solvent is modelled via the Raoult's law:
[tex]P_{solution}=x_{solvent}P_{solvent}^{vap}[/tex]
Thus, we can calculate the ratio of the vapor pressure of the solution to that of the pure solvent, mole fraction, as shown below:
[tex]x_{solvent}=\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{n_{solvent}}{n_{solute}+n_{solvent}}[/tex]
Thus, we plug in the moles of solvent and solute to obtain:
[tex]\frac{P_{solution}}{P_{solvent}^{vap}} =\frac{3}{3+1}\\\\ \frac{P_{solution}}{P_{solvent}^{vap}} =0.75[/tex]
Regards!
determine the maximum amount of NaN03 that was produced during the experiment. Explain how you determined the amount
Answer:
9 moles of NaNO3 is obtained
Explanation:
The balanced chemical reaction equation for the reaction is;
Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3
Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.
1 mole of Al(NO3)3 yields 3 moles of NaNO3
4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3
Also,
3 moles of NaCl yields 3 moles of NaNO3
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3
Hence, NaCl is the limiting reactant and 9 moles of NaNO3 is obtained.
9 moles of NaNO₃ is obtained.
Balanced chemical reaction:
[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]
From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.
1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃
4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃
Also,
3 moles of NaCl yields 3 moles of NaNO₃
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃
Hence, NaCl is the limiting reactant and 9 moles of NaNO₃ is obtained.
Find more information about Balanced chemical reaction here:
brainly.com/question/15355912
To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).
Answer: 2.20 g Pb
They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88