3.44 × 10⁻¹⁰ g Pb
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 1.00 × 10¹² atoms Pb
[Solve] grams Pb
Step 2: Identify Conversions
Avogadro's Number
[PT] Molar Mass of Pb - 207.2 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 1.00 \cdot 10^{12} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})(\frac{207.2 \ g \ Pb}{1 \ mol \ Pb})[/tex][DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 3.44072 \cdot 10^{-10} \ g \ Pb[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
3.44072 × 10⁻¹⁰ g Pb ≈ 3.44 × 10⁻¹⁰ g Pb
Answer:
[tex]\boxed {\boxed {\sf 3.44 *10^{-10} \ g \ Pb}}[/tex]
Explanation:
1. Atoms to Moles
Use Avogadro's Number to convert atoms to moles. This number: 6.022*10²³, tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of lead.
[tex]\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]
Multiply by the given number of atoms.
[tex]1.00 *10^{12} \ atoms \ Pb *\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]
Flip the fraction so the atoms of lead cancel.
[tex]1.00 *10^{12} \ atoms \ Pb *\frac {1 \ mol \ Pb}{6.022*10^{23} \ atoms \ Pb}[/tex]
[tex]1.00 *10^{12}*\frac {1 \ mol \ Pb}{6.022*10^{23}}[/tex]
[tex]\frac {1.00 *10^{12}\ mol \ Pb}{6.022*10^{23}} = 1.66057788*10^{-12} \ mol \ Pb[/tex]
2. Moles to Grams
Use the molar mass to convert moles to grams. This can be found on the Periodic Table. For lead it is 207.2 grams per mole.
[tex]\frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]
Multiply by the number of moles we calculated.
[tex]1.66057788*10^{-12} \ mol \ Pb* \frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]
[tex]1.66057788*10^{-12}* \frac {207.2 \ g\ Pb}{ 1 }[/tex]
[tex]1.66057788*10^{-12}* {207.2 \ g\ Pb}= 3.44071737*10^{-10} \ g \ Pb[/tex]
3. Round
The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, it is the hundredth place. The 0 in the thousandth place tells us to leave the 4.
[tex]3.44 *10^{-10} \ g \ Pb[/tex]
WS 3.5 more Lewis structures
A wave is a disturbance that carries...
What would happen if cell differentiation did not happen during the
development of the embryo?
Answer:
Without the process of cell differentiation, multicellular organisms would not be possible.
Convert to moles 12.06 x 10^22 molecules
Answer:
0.2 mole
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 12.06×10²²
Number of mole =?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
12.06×10²² molecules = 12.06×10²² / 6.02×10²³
12.06×10²² molecules = 0.2 mole
Thus, 12.06×10²² molecules is equivalent to 0.2 mole
What can wind energy be transformed or converted into?
Answer:
Electrical energy
Explanation:
The wind Mill is an example of a device that converts wind energy into electrical energy
How many moles are in 6.5e23 atoms of Ne?
1.1 mol Ne
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 6.5 × 10²³ atoms Ne
[Solve] moles Ne
Step 2: Identify Conversion
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 6.5 \cdot 10^{23} \ atoms \ Ne(\frac{1 \ mol \ Ne}{6.022 \cdot 10^{23} \ atoms \ Ne})[/tex][DA] Divide [Cancel out units]: [tex]\displaystyle 1.07938 \ mol \ Ne[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
1.07938 mol Ne ≈ 1.1 mol Ne
A student claims that signals transmitted by wireless computer networks are more beneficial than signals transmitted by other devices. Which statement supports the student’s claim?
im giving brainliest and 11 points
Answer: The wireless signals can carry large amounts of data at high radio frequencies.
Explanation: the others don’t specify the kind of signal
A 15 g sample of steam at 100°C is emitted from a volcano. It condenses, cools, and falls as snow at 0°C. How many kilojoules of heat were released? [Specific heat of liquid water = 1.00 cal/g°C or 4.184 J/g°C); solid water 0.485 cal/g°C or 2.03 J/g°C]
Answer:
q= -40.236 or 40.236 KJ of heat released
Explanation:
I attached a picture + a cooling curve.
4. How many moles of gold (Au) are in a pure gold nugget having a mass of 25.0 grams.
0.127 mol Au
General Formulas and Concepts:Math
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightChemistry
Atomic Structure
Reading a Periodic TableMolesStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 25.0 g Au
[Solve] moles Au
Step 2: Identify Conversions
[PT] Molar Mass of Au - 196.97 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})[/tex][DA] Multiply/Divide [Cancel out units: [tex]\displaystyle 0.126923 \ mol \ Au[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.126923 mol Au ≈ 0.127 mol Au
Answer:
[tex]\boxed {\boxed {\sf 0.127 \ mol \ Au}}[/tex]
Explanation:
To convert from mass to moles, the molar mass must be used. This can be found on the Periodic Table.
Gold (Au): 196.96657 g/molUse this number as a ratio.
[tex]\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]
Multiply by the given number of grams.
[tex]25.0 \ g \ Au*\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]
Flip the fraction so the grams of gold will cancel.
[tex]25.0 \ g \ Au*\frac {1 \ mol \ Au}{196.96657 \ g\ Au }[/tex]
[tex]25.0*\frac {1 \ mol \ Au}{196.96657 }[/tex]
[tex]\frac {25.0 \ mol \ Au}{196.96657 }[/tex]
[tex]0.1269250919 \ mol \ Au[/tex]
The original measurement has 3 significant figures, so the answer must have the same. For the number we calculated that is the thousandth place. The 9 in the ten thousandth place tells us to round the 6 to a 7.
[tex]0.127 \ mol \ Au[/tex]
25.0 grams of gold is about 0.127 moles of gold.
Consider these compounds:
a. CuCO3
b. ZnS
c. Ni(CN)2
d. Ag2CrO4
Complete the following statements by entering the letter corresponding to the correct compound. Without doing any calculations it is possible to determine that silver carbonate is more soluble than _________ , and silver carbonate is less soluble than ____________. It is not possible to determine whether silver carbonate is more or less soluble than _______________ by simply comparing Ksp values.
Explanation:
If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.
- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B
what type of energy is playing the piano
A.light
B. Thermal
C.electrical
D.mechanical
E.sound
Answer:
E sound
Explanation:
In matrix form structure PVC stands for what?
Answer:
polyvinyl chloride
Explanation:
Pleaaase argent !!! Explain ur answers
Consider the following reaction:
Fe3+(aq) + SCN-(aq) ↔︎ [Fe(SCN)]2-(aq)
1)Explain what is meant by the term dynamic equilibrium.
2)Write the equilibrium expression for the reaction.
3) The numerical value of Kc at 298K is about 1000 for the reaction. What does this tell you about the position of the equilibrium at 298K?
Answer:
1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.
2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]
For the given chemical reaction:
[tex]Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)[/tex]
The expression for [tex]K_c[/tex] is written as:
[tex]K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}[/tex]
3) The value of [tex]K_c[/tex] is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.
can someone please help!!
Answer:
1:aerobic
2:anaerobic
3:aerobic
A certain electromagnetic wave a wavelength of 415 nm. What is the frequency of the wave in hz?
Answer:
The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz
Explanation:
The wavelength of the electromagnetic wave, λ = 415 nm
The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s
Given that an electromagnetic wave is a periodic wave, we have;
The speed of the electromagnetic wave, c = f×λ
Where;
f = The frequency of the electromagnetic wave
Therefore, we have;
f = c/λ
From which we have;
f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz
The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz
Which two statements about redox reactions are true?
A. Double-replacement reactions are redox reactions.
B. Acid-base reactions are redox reactions.
C. One type of atom is oxidized and another is reduced.
D. Electrons are transferred from one atom to another.
SUBMIT
Answer:
C. One type of atom is oxidized and another is reduced
D. Electrons are transferred from one atom to another
Explanation:
just took the test, i hope this helps!!
have a nice day and take care of yourself!! :))
One type of atom is oxidized and another is reduced and Electrons are transferred from one atom to another. Therefore, the correct options are options C,D.
What is redox reaction?Any chemical process in which a participating chemical species' oxidation number changes is known as an oxidation-reduction reaction, often known as a redox reaction. The phrase refers to a broad range of processes. Numerous oxidation-reduction processes are as frequent and well-known as fire, metal corrosion and disintegration, fruit browning, respiration, and photosynthesis—basic life processes.
The combined processes of oxidation and reduction are known as redox reactions due to their complimentary nature. The oxidising agent is the reactant that causes the oxidation, while the reducing agent itself reduces this reagent. One type of atom is oxidized and another is reduced and Electrons are transferred from one atom to another.
Therefore, the correct options are options C,D.
To know more about redox reaction, here:
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Which of the following wavelengths penetrate earth's atmosphere?
O Microwaves
O Gamma rays
O Radio waves
O X-rays
Answer:
Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.
Let me know if this helps!
type of environmental factors such as temperature or amount of light that might affect an organism's phenotype is___________
Somebody help me asap please giving brainliest (answer to the both of them)
Answer:
1. Causes air to vibrate 2. A hydroelectric dam generating electricity on a river
What are some differences between earth and mars
Oki,
1. Earth is third planet away from the Sun whiles Mars is the fourth planet away from the Sun.
2.. Earth takes 365 days to revolve around the Sun whiles Mars takes 687 days to do so.
3. Earth is the fifth largest planet in the Solar System whiles Mars is the second smallest planet.
4. Mars is reddish in colour but Earth is not
5. About 70% of the earth is covered with water but Mars is just covered with bare dust and rocks.
Hope this is enough
A paleontologist finds a fish fossil in a desert. What might the paleontologist learn from this?
Answer:
sometime back there might be a water body there
Answer:
Paleontologists can identify organisms that may be ancient relatives of those living today. By looking at fossils from the same layer of rocks, they can also suggest how these organisms lived together in their ancient habitat.
Also, he/she can find out that there was water there millions of year ago.
What is the term used for the elements and compounds after a chemical reaction takes place?
Answer: reactants.
Explanation:
To the right of the arrow we have the 'after' situation. This side represents the substances that we have after the reaction has taken place. They are called the products
EXPERIMENT 1: Identify the oxidation and reduction half-reactions that occur in
Cell 5: Mn(s) | Mn(NO3)2 (aq) || Zn(NO3)2(aq) | Zn(s)
Remember to use proper formatting and notation.
Answer:
Cathode: Mn → Mn²⁺ + 2e⁻ (Oxidation)
Anode: Zn²⁺ + 2e⁻ → Zn (Reduction)
Mn | Mn²⁺ || Zn²⁺ | Zn
Explanation:
To identify the half reaction we need to see the oxidation states.
Mn(s) → Ground state → Oxidation state = 0
Mn(NO₃)₂ → Mn²⁺ → The oxidation state has increased.
This is the oxidation reaction. It has released two electrons:
Mn → Mn²⁺ + 2e⁻
Zn(NO₃)₂ → Zn²⁺
Zn → Ground state → The oxidation state was decreased.
This is the reduction reaction. It has gained two electrons:
Zn²⁺ + 2e⁻ → Zn
Cathode: Mn → Mn²⁺ + 2e⁻
Anode: Zn²⁺ + 2e⁻ → Zn
Mn | Mn²⁺ || Zn²⁺ | Zn
help help plz what is the difference between normal and transition elements
Answer:
hope it helps you
mark me as brainliest!!
Which of the following can limit the growth of a population of organisms?
O Both diseases and the availability of resources can limit the growth of a population of organisms.
Diseases can limit the growth of a population of organisms, but the availability of resources cannot.
O The availability of resources can limit the growth of a population of organisms, but diseases cannot.
O Neither diseases nor the availability of resources can limit the growth of a population of organisms.
Answer: The answer is both diseases and availability of resources can limit the growth of a population of organisms which is A
Explanation:
gas laws escape room
Answer:
what are you asking
Explanation:
The gas laws are Boyle's law, Charles law, ideal gas law, and Gay-Lussac law.
What are the different gas laws?The first law is Boyle's law that states that at constant temperature, the pressure varies with volume of the gas.
The second law is Charles's law that states that at constant pressure, the volume of the gas is directly proportional to the temperature of the gas.
Above, both laws form the ideal gas law. PV = nRT.
Thus, the gas laws are Boyle's law, Charles law, ideal gas law, and Gay-Lussac law.
Learn more about gas laws
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When a large rock falls down a slope and breaks into small pieces, this is called _____________ _______________.
Group of answer choices
Answer: Mechanical weathering
Explanation:
Mechanical weathering breaks rocks into smaller pieces
Calculate the value of the equilibrium constant, c, for the reaction
Q(g)+X(g)=2M(g)+N(g)
given that
M(g)=Z(g) c1=3.97
6R(g)=2N(g)+4Z(g) c2=0.523
3X(g)+3Q(g)=9R(g) c3=11.8
Question is asking for c
What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal?
Answer:
0.559 L
Explanation:
Step 1: Given data
Moles of sodium iodide (n): 0.405 molMolar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)Step 2: Calculate the volume of solution (V)
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
V = n/M
V = 0.405 mol/(0.724 mol/L) = 0.559 L
The volume in Litres of a 0.724 M Nal solution that contains 0.405 mol of Nal is 0.56L.
HOW TO CALCULATE VOLUME:
The volume of a solution can be calculated by dividing the number of moles by the molarity as follows:Volume = no. of moles ÷ molarityAccording to this question, 0.724 M sodium iodide (NaI) solution contains 0.405 mol of Nal, the volume can be calculated as follows:Volume = 0.405mol ÷ 0.724MVolume = 0.56 LitresTherefore, the volume in Litres of a 0.724 M Nal solution that contains 0.405 mol of Nal is 0.56L.Learn more at: https://brainly.com/question/15626439?referrer=searchResults
which part of the red blood cells can you find hemoglobin
Answer:
The cytoplasm of erythrocytes is rich in hemoglobin, an iron-containing biomolecule that can bind oxygen and is responsible for the red color of the cells and the blood. Each human red blood cell contains approximately 270 million of these hemoglobin molecules.