Complete Question
A very long, straight solenoid with a cross-sectional area of 2.39cm2 is wound with 85.7 turns of wire per centimeter. Starting at t= 0, the current in the solenoid is increasing according to i(t)=( 0.162A/s2) t2. A secondary winding of 5 turns encircles the solenoid at its center, such that the secondary winding has the same cross-sectional area as the solenoid. What is the magnitude of the emf induced in the secondary winding at the instant that the current in the solenoid is 3.2A ?
Answer:
The value is [tex]\epsilon = 1.83 *10^{-5} \ V[/tex]
Explanation:
From the question we are told that
The cross-sectional area is [tex]A = 2.39 \ cm^2 = \frac{2.39}{10000} = 0.000239 \ m^2[/tex]
The number of turns is [tex]N = 85.7 \ turns/cm = 8570 \ turns / m[/tex]
The initial time is t = 0s
The current on the solenoid is [tex]I(t) = (0.162 \ A/s^2) t^2[/tex]
The number of turns of the secondary winding is [tex]n = 5 \ turns[/tex]
Generally At I = 3.2 A
[tex]3.2 = (0.162 )t^2[/tex]
=> [tex]t^2 = 19.8[/tex]
=> [tex]t = 4.4 \ s[/tex]
Generally induced emf is mathematically represented as
[tex]\epsilon = A * \mu_o * n * N \frac{d(I)}{dt}[/tex]
[tex]\epsilon = 0.000239 * 4\pi * 10^{-7} * 8570 * 5 * (0.162) * 2t[/tex]
[tex]\epsilon = 0.000239 * 4\pi * 10^{-7} * 8570 * 5 * (0.162) * 2 * 4.4[/tex]
[tex]\epsilon = 1.83 *10^{-5} \ V[/tex]
1: A generator produces electricity at about 21,600 V. This voltage needs to be increased to about 345,000 V via a transformer before being transmitted through the power grid. What is the ratio of windings between the secondary coil and the primary coil needed to do this
Answer:
16:1
Explanation:
From the question,
Since the voltage of the transformer is increased, then the winding in the secondary coil is greater than the winding in the primary coil
Applying transformer's equation
Vs/Vp = Ns/Np............. Equation 1
Where Vs = Secondary voltage, Vp = primary Voltage, Ns/Np = Ratio of the winding between the secondary coil to the winding in the primary coil.
Given: Vs = 345000 V, Vp = 21600 V
Substitute these values into equation 1
Ns/Np = 345000/21600
Ns/Np = 16:1
A string is waved up and down to create a wave pattern with a wavelength of 0.5 m. If the waves are generated with a frequency of 2 Hz, what is the speed of the wave that travels through the string to the other end?
Wave speed = (wavelength) x (frequency)
Wave speed = (0.5 m) x (2 /sec)
Wave speed = 1 m/s
if abus travelling at 20m/s is subject to steady decceleration of 5m/s².how long will it take yo come to rest.
Answer:
4 seconds
Explanation:
Given:
v₀ = 20 m/s
v = 0 m/s
a = -5 m/s²
Find: t
v = at + v₀
0 m/s = (-5 m/s²) t + 20 m/s
t = 4 s
A person drives a car around a circular cloverleaf with a radius of 77 m at a uniform speed of 10 m/s. What is the acceleration of the car?
Answer:
770m/s
Explanation:
caculation using one of the newton law of motion
Examine the scenario. A circuit is arranged so that 20 A of current is flowing through it. The battery is replaced with another battery with ¼ the original voltage. Which choice correctly describes the effect on the current? The current reduces to ¼ of the original current because a smaller voltage indicates that there is less energy to move the charge. As voltage decreases in a circuit, current also decreases. The current decreases to ½ of the original amount because a smaller voltage indicates that the flow of charge is being restricted, but only by half. As voltage decreases, current will decrease also, but by a smaller amount. The current increases to 4 times the amount because a smaller voltage indicates that there is less to restrict the flow of charge. As voltage decreases in a circuit, current increases The current stays the same because a smaller voltage means there is less energy for each charge, but more charges are moving through the circuit. Current and voltage do not affect each other.
Answer:
The current reduces to ¼ of the original current because a smaller voltage indicates that there is less energy to move the charge. As voltage decreases in a circuit, current also decreases.
Explanation:
A poundal is the force required to accelerate a mass of 1 lbm at a rate of 1 ft/s2 , and a slug is the mass of an object that will accelerate at a rate of 1 ft/s2 when subjected to a force of 1 lbf. (a) Calculate the mass in slugs and the weight in poundals of a 135 lbm woman (i) on earth and (ii) on the moon, where the acceleration of gravity is one-sixth of its value on earth. (b) A force of 405 poundals is exerted on a 35.0-slug object. At what rate (m/s2 ) does the object accelerate?
Answer:
We are given that
The
Mass of person = 135lbm
Weight of person on earth will be
= mass x gravity constant
= 135lbm x 32.174 ft/s2
=4343.49 lbm-ft/s2 x 1 poundal-s2/lbm-ft
= 4343.49 poundal
Again we are given that
Mass of person = 135 lbm
But here remember Mass remains the same
So
Weight of person on moon will be
mass x gravity constant on moon
= 135 lbm x 32.174 ft/s2 x 1/6
= 723.9 lbm-ft/s2 x 1 poundal-s2/lbm-ft
= 723.9poundal
But we know that
1 ft slug / lbf-s2 = 32.174 ft lbm/ lbf-s2
So
1 slug = 32.174 lbm
So then the Mass of person
= 135lbm x 1slug/32.174 lbm
=4.2slugs
So finally
Weight = 405 poundals is same as
405 lbm-ft/s2
So
Mass = 35 slug x 32.174 lbm/slug = 1126.09 lbm
Acceleration rate = weight /mass
= (405 lbm-ft/s2) / (1126.09 lbm)
= 0.3597ft/s2 x 0.305m/ft
= 1.179 m/s²
A Nichrome wire 50 cm long and 0.27 mm in diameter is connected to a 1.5 V flashlight battery. What is the electric field inside the wire
Answer:
E=3V/m
Explanation:
The electric field here is simply the voltage running through the wire divided by its length. (Meaning E is independent of the diameter of the wire.)
Short work is in the attachment.
(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
Complete Question
(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
The tensile strength of the nylon string is [tex]600*10^{6} \ N/m^2[/tex]
Answer:
A
T = 471.3 \ N
B
To prevent breakage the thickness of the string is increased
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
Explanation:
From the question we are told that
The diameter is [tex]d = 1.00 \ mm = 0.001 \ m[/tex]
The tensile strength of the nylon string is [tex]\sigma = 600 *10^{6} \ N/m^2[/tex]
Generally the radius is mathematically evaluated as
[tex]r= \frac{d}{2}[/tex]
=> [tex]r = \frac{0.001}{2}[/tex]
=> [tex]r = 0.0005 \ m[/tex]
The cross sectional area is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * (0.005)^2[/tex]
=> [tex]A = 7.855*10^{-7}\ m^2[/tex]
Generally the tensile strength of nylon is mathematically represented as
[tex]\sigma = \frac{T}{ A }[/tex]
Where T is the tension on the maximum tension on the string
So
[tex]T = \sigma * A[/tex]
=> [tex]T = 600*10^{6} * 7.855*10^{-7}[/tex]
=> [tex]T = 471.3 \ N[/tex]
Form the equation above we see that
[tex]T \ \alpha \ A[/tex]
So if the tension is increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional area )
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
A 1700 W laser emits light with a wavelength of 700 nm into a 3.0 mm diameter beam. What force does the laser beam exert on a completely absorbing target?
Answer:
F=5.7×10⁻⁶
Explanation:
Not knowing a formula outright, I decided to follow the units of some relationships I did know. Radiation pressure is defined as force per area and also intensity divided by velocity (the speed of light here of course). Breaking intensity down into power per area and isolating force gave me the relationship F=(Power/Velocity),where power is given and the velocity is a constant.
My work is in the attachment, where I double checked the units too, comment with any questions.
The force exerted by the beam on a completely absorbing target is of 0.0120 N.
Given data:
The power of laser beam is, P = 1700 W.
The wavelength of light emitted from the laser is, [tex]\lambda = 700 \;\rm nm[/tex].
The diameter of the beam is, [tex]d =3.00 \;\rm mm =3.00 \times 10^{-3} \;\rm m[/tex].
When the laser beam strikes the target, then the force exerted by the laser beam on the target is equal to the product of the laser power and the area of projection of beam.
Then the expression is,
[tex]P = \dfrac{F}{A}\\\\F = P \times \dfrac{\pi}{4} d^{2}[/tex]
Solving as,
[tex]F = 1700 \times \dfrac{\pi}{4} \times (3.00 \times 10^{-3})^{2}[/tex]
F = 0.0120 N
Thus, we can conclude that the force exerted by the beam on a completely absorbing target is of 0.0120 N.
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A trucker drives with an average velocity of 27 m/s toward the east on a perfectly
straight highway.What will the trucker's displacement be after 2.0 h?
Answer:
The displacement of the driver is 194400m in the east direction
Explanation:
In physics, the displacement of a body is the distance the body travels in a specified direction.
We are told that the trucker is driving east on a perfectly straight highway. From this, we know that his direction is East. The thing left will be to find the distance travelled within 2 hours.
We can convert the time (2 hours) to seconds by multiplying it by 3600
2 hours = 7200 seconds
The distance travelled will be obtained by a product of truck's speed and the time travelled.
distance = 27m/s X 7200 s = 194400m
Therefore the displacement of the driver is 194400m in the east direction
Using Newton's Second Law, can you explain why one of the major advancements in spaceflight was the development of strong ceramic (clay)
materials to build their rockets out of instead of heavy metals?
Answer:
high density can withstand high acceleration and applied forces
Heavy metals are toxic to humans,
the clay is quite abundant and in general it is not toxic
Explanation:
The selection of materials for the construction of rockets takes into account many aspects, the technical resistance to the demands of space travel, but also the abundance of the material. Heavy metals have two very serious problems. The first one, some of them are a little scarce in nature, but the most serious problem is that almost all of them are toxic to humans, for example: lead and mercury.
On the other hand, the clay is quite abundant and in general it is not toxic to living beings.
If we use Newton's second law
F = m a
let's use the concept of density
rho = m / V
m = rho V
let's substitute
F = rho V a
From this expression we see that a material with high density can withstand high acceleration and applied forces, such as those existing in spacecraft clearance and re-entry to Earth.
Unfortunately with this law there is no criterion to select a material unless its density is high, in addition to this criterion low toxicity criteria for human beings are used,
whos on the 1 dollar bills
Answer:
George Washington
Explanation:
The image of the famous first President of the United States-George Washington (from 1789 to 1797) is found on every $1 bill. George Washington's image began to be found on the $1 bill in 1869.
Which parenting style is thought to produce children who grow up to be emotionally withdrawn,
distant, and lacking in curiosity?
Answer:
Uninvolved (provide little guidance , nuturing and attention) that causes to grow up to be emotionally withdrawn, distant and lacking in curiosity.
Explanation:
. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional analysis, find the dimensionality of B.
Answer:
The dimensionality of B is length per cubic time.
Explanation:
Units for displacement and time are length [tex][L][/tex] and time [tex][T][/tex], respectively. Then, formula can be tested for dimensional analysis as follows:
[tex][L] = B\cdot [T]^{3}[/tex]
Now, let is clear [tex]B[/tex] to determine its units:
[tex]B = \frac{[L]}{[T]^{3}}[/tex]
The dimensionality of B is length per cubic time.
A small metal ball is given a negative charge, then brought near to end A of an insulating rod. What happens to end A of the rod when the ball approaches it closely this first time
Answer:
Weak attraction will be observed
Explanation:
This is because the charge induction is less than the insulating rod, and a postive charge is induced when a a negative sphere is placed closed to the end of the rod
A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns through an angle of 80 radians. Assuming the wheel started from rest, how long had it been in motion at the start of the 4.0-s interval?
a. 3 s.
b. 6 s.
c. 9 s.
d. 12 s.
Answer:
a. 3 s.
Explanation:
Given;
angular acceleration of the wheel, α = 4 rad/s²
time of wheel rotation, t = 4 s
angle of rotation, θ = 80 radians
Apply the kinematic equation below,
[tex]\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s[/tex]
Given initial angular velocity, ω₀ = 0
Apply the kinematic equation below;
[tex]\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s[/tex]
Therefore, the wheel had been in motion for 3 seconds.
a. 3 s.
5. What occurs when an enzyme and a substrate interact at an
active site?
a. Activation energy is reduced.
b. The products are bound irreversibly.
c. The enzyme is changed by the reaction.
d. Activation energy is increased.
Answer:
B
Explanation:
The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex
When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.
What are enzymes?Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.
All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.
Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.
Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.
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A resistance of 4 ohm is offered by a conductor when a potential difference of 6 V l'd applied across it. Calculate the current through it?.
Answer:
1.5 Ampere
Explanation:
The formula is V=IR
so now we can derive out the formula which is
I =V
R
I = 6
4
I = 1.5 Ampere
in a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance they travel by a multiple of
Answer:
The path difference will be zero.
Explanation:
Given that,
In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.
Suppose, we find the multiple of wavelength
In young's double slit experiment,
We need to calculate the multiple of wavelength
Using formula of path difference
[tex]\Delta x=d\sin\theta[/tex]....(I)
[tex]d\sin\theta=m\lambda[/tex]
Where, m = fringe number
[tex]\lambda[/tex] = wavelength
For center of a bright fringe ,
m = 0
Put the value into the formula
[tex]d\sin\theta=0\times\lambda[/tex]
[tex]d\sin\theta=0[/tex]
Put the value in equation (I)
[tex]\Delta x=0[/tex]
Hence, The path difference will be zero.
a train it speed steading from 10 m/s to 20m/s in 1 minutes average speed during this time in m/s
how far does it travel while increase its speed
Explanation:
Given:
v₀ = 10 m/s
v = 20 m/s
t = 60 s
Find: v_avg and Δx
v_avg = ½ (v + v₀)
v_avg = ½ (20 m/s + 10 m/s)
v_avg = 15 m/s
Δx = v_avg t
Δx = (15 m/s) (60 s)
Δx = 900 m
Given that average speed is distance traveled divided by time, determine the values of mm and nn when the time it takes a beam of light to get from the Sun to the Earth (in ss) is written in scientific notation. Note: the speed of light is approximately 3.0××108 m/sm/s.
Complete Question
Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of light to get from the Sun to the Earth (in s) is written in scientific notation. Note: the speed of light is approximately 3.0×108 m/s.
Answer:
The values of m and n is 5 and 2
Explanation:
From the question we are told that
The speed of light is [tex]v = 3.0 *10^{8} \ m/s[/tex]
Generally the distance between the sun and the earth has a constant value
[tex]d = 1.5*10^{11} \ m[/tex]
So the time taken is mathematically evaluated as
[tex]t = \frac{1.5*10^{11}}{3.0*10^{8}}[/tex]
[tex]t = 5.0 *10^{2}[/tex]
Generally scientific notation is represented as
[tex]m* 10^n[/tex]
So comparing the standard representation of scientific notation and the value obtained we see that
m = 5 and n= 2
g a long, straight wire carries a current an electron Is it necessary to include the effects of gravity?
Answer:
The force is [tex]3.2\times10^{-20}\ N[/tex]
Explanation:
Given that,
A long, straight wire carries a current.
Suppose, a long, straight wire carries a current 0.86 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is 4.50 cm from the wire and traveling at speed of [tex]6\times10^{4}\ m/s[/tex] directly toward the wire. What are the magnitude of the force that the magnetic field of the current exerts on the electron?
We need to calculate the magnetic field
Using formula of magnetic field
[tex]B=\dfrac{\mu_{0}I}{4\pi r}[/tex]
Where, I = current
r = distance
Put the value into the formula
[tex]B=\dfrac{4\pi\times10^{-7}\times0.86}{2\pi\times4.5\times10^{-2}}[/tex]
[tex]B=0.0000038\ T[/tex]
[tex]B=3.8\times10^{-6}\ T[/tex]
We need to calculate the force
Using formula of force
[tex]F=qvB\sin\theta[/tex]
Here, [tex]\theta=90^{\circ}[/tex]
Where, q = charge of electron
v = velocity of electron
B = magnetic field
Put the value into the formula
[tex]F=1.6\times10^{-19}\times6\times10^{4}\times3.8\times10^{-6}\sin90[/tex]
[tex]F= 3.2\times10^{-20}\ N[/tex]
Hence, The force is [tex]3.2\times10^{-20}\ N[/tex]
What is the speed of an electron that has been accelerated to the point at which its total energy is 10.5 times its rest mass
Answer:
0.995*c= 2.98*10^8m/s
Explanation:
Using
E= mc²
10.5 mc² = mc²/√1-v²/c²
So
1-v²/c²=( 1/10.5)²
V= √1-0.009c
V= 0.995 x 3E8m/s
= 2.98*10^8m/s
A solid sphere of radius R has a uniform charge density and total charge Q. Find the total energy of the sphere U in terms of
Answer:
[tex]\mathbf{U = \dfrac{3 k_c Q^2_{total}}{5R}}[/tex]
Explanation:
From the information given;
The surface area of a sphere = [tex]4 \pi r ^2[/tex]
If the sphere is from the collection of spherical shells of infinitesimal thickness = dr
Then,
the volume of the thickness and the sphere is;
V = [tex]4 \pi r ^2 \ dr[/tex]
Using Gauss Law
[tex]V(r) = \dfrac{k_cq(r)}{r}[/tex]
here,
q(r) =charge built up contained in radius r
since we are talking about collections of spherical shells, to work required for the next spherical shell r +dr is
[tex]-dW= dU = V(r) dq = \dfrac{k_c \ q(r)}{r} \ dq[/tex]
where;
[tex]q (r) = \dfrac{4}{3} \pi r^3 \rho[/tex]
dq which is the charge contained in the next shell of charge
here dq = volume of the shell multiply by the density
[tex]dq = 4 \pi r^2 \ dr \ \rho[/tex]
equating it all together
[tex]dU = \dfrac{k_c \frac{4}{3} \pi r^3 \rho}{r} 4 \pi r^2 \ dr \ \rho = \dfrac{16 \pi^2 \ k_c \ \rho^2}{3} \ r^4 \ dr[/tex]
Integration the work required from the initial radius r to the final radius R, we get;
[tex]U = \int^R_0 \ dU[/tex]
[tex]U = \int^R_0 \dfrac{16 \pi^2 \ k_c \rho^2}{3} r^4 \ dr[/tex]
[tex]U = \int^R_0 \dfrac{16 \pi^2 \ k_c \rho^2}{3} [\dfrac{r^5}{5}]^R_0[/tex]
[tex]U = \dfrac{16 \pi^2 k_c \rho^2}{15} \ R^5[/tex]
Recall that:
the total charge on a sphere, i.e [tex]Q_{total} = \dfrac{4}{3} \pi R^3 \rho[/tex]
Then :
[tex]\mathbf{U = \dfrac{3 k_c Q^2_{total}}{5R}}[/tex]
Acceleration: A water rocket can reach a speed of 75 m/s in 0.050 seconds from launch. What is its average acceleration
Answer:
1500 m/s squared
Hope this helps :)
Explanation:
an rlc series circuit has a 40.0 resistor,a 3.00 mH inductor, and a 5.00 capacitor, (a find the circuits impendance at 60.0 Hz
Answer:
Z = 530.89 ohms
Explanation:
Given that,
Resistor, R = 40 ohms
Inductor, L = 3 mH
Capacitor, C = 5 μF
We need to find the impedance of the circuit at frequency of 60 Hz. For a series LCR circuit, its impedance is given by the formula as follows :
[tex]Z=\sqrt{R^2+(X_L-X_c)^2} \\\\Z=\sqrt{R^2+(2\pi fL-\dfrac{1}{2\pi fC})^2} \\\\Z=\sqrt{(40)^2+(2\pi \times 60\times 3\times 10^{-3}-\dfrac{1}{2\pi \times 60\times 5\times 10^{-6}})^2} \\Z=530.89\ \Omega[/tex]
So, the impedance of the circuit is 530.89 ohms.
2.
Which of the following is NOT a symptom of strong emotions?
A. Impulsiveness
B. Hostility
C. Blindness
D. Distraction
Answer:
blindness
Explanation:
got it right
Blindness is not a symptom of strong emotions in this scenario and is denoted as option C.
What is Emotion?These are mental states brought on by neurophysiological changes and examples include sad, happy etc.
Blindness is a physical condition which involves impairment of the eyes which is why it was chosen.
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Consider two di˙erent streams of air, both with a relative humidity of 65%. Stream A has a temperature of 15◦C, and stream B has a temperature of 25◦C. The mass flow rate of dry air is the same in both streams. Which stream has a higher mass flow rate of water
Answer:
stream B.
Explanation:
Stream B has higher mass flow rate of water due to higher temperature i.e. 25◦C as compared to stream A which has a lower temperature i. e. 15◦C because temperature affect the viscosity of liquid. Higher temperature make liquid or water thinner which means lower viscosity. This thinning of liquid make easier the flow of water in the pipes or other medium with the increase in temperature.
Draw the velocity vectors starting at the black dots and the acceleration vectors including those equal to zero. The orientation of the vectors will be graded. The location and length of the velocity vectors will be graded. The location and length of the nonzero acceleration vectors will not be graded. To draw a zero vector click at the point of its location.
Answer:
hello your question is incomplete attached below is the remaining part and the solution
Explanation:
The accelerations at points 1,2,3 is zero and this is because the velocities at points 1,2,3 are constants. attached below is the velocity vector diagram and the acceleration vectors
We use sponge when we have fever.Which phenomenon best describe the above statement in physics?
Answer: heat loss by conduction
Explanation:
As the thermal energy from our body is flowing to the sponge, our body is losing heat.