What is the length of the missing leg?

Answer:

Work out the Area of the figure, then multiply that answer by $25.

Given:

QRST is an isosceles trapezoid with RS||QT.

To find:

The value of x, angle R and angle T.

Solution:

If a transversal line intersect two parallel lines then the sum of same sides interior angles is 180 degrees.

[tex]m\angle Q+m\angle R=180[/tex]

[tex](6x-22)+(8x+34)=180[/tex]

[tex]14x+12=180[/tex]

[tex]14x=180-12[/tex]

[tex]14x=168[/tex]

Divide both sides by 14.

[tex]x=\dfrac{168}{14}[/tex]

[tex]x=12[/tex]

Now,

[tex]m\angle R=(8x+34)^\circ[/tex]

[tex]m\angle R=(8(12)+34)^\circ[/tex]

[tex]m\angle R=(96+34)^\circ[/tex]

[tex]m\angle R=130^\circ[/tex]

We know that the base angles of an isosceles triangle are equal.

[tex]m\angle T=m\angle Q=(6x-22)^\circ[/tex]

[tex]m\angle T=(6(12)-22)^\circ[/tex]

[tex]m\angle T=(72-22)^\circ[/tex]

[tex]m\angle T=50^\circ[/tex]

Therefore, [tex]x=12,\ m\angle R=130^\circ[/tex] and [tex]m\angle T=50^\circ[/tex].

Answer:

11.76

Step-by-step explanation:

j

Answer:

11 times

Step-by-step explanation:

hope this helps

Answer:

11.

Step-by-step explanation:

10 x 10 = 100

10 x 11 = 110

10 x 12 = 120 which is too much so its the one above.

Answer:

Step-by-step explanation:

The sum of these adjacent angles must sum to 180 degrees (also the sum of all angles must be 360)

a+5a=180

6a=180

a=30

The larger angle is 5a so the larger angle is

5(30)=150 degrees.

Answer:

D. 0.042%

Step-by-step explanation:

YOUR ANSWER

Graphical form: T%2Ahef%2Aor%2Amu%2Alar=A%5EP-1g%2Aiv%2Aest%2Ahei%2Ant%2Aer%2Aes%2Atr%2Aat%2Aer simplifies to T%2Ahef%2Aor%2Amu%2Alar-A%5EP%2Bg%2Aiv%2Aest%2Ahei%2Ant%2Aer%5E2%2Aes%2Atr%2Aat=0

Text form: T*hef*or*mu*lar=A^P-1g*iv*est*hei*nt*er*es*tr*at*er simplifies to T*hef*or*mu*lar-A^P+g*iv*est*hei*nt*er^2*es*tr*at=0

Cartoon (animation) form:  

For tutors: simplify_cartoon( T*hef*or*mu*lar=A^P-1g*iv*est*hei*nt*er*es*tr*at*er )

If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .

Remove extraneous '1' from product highlight_red%28+1+%29

It becomes T%2Ahef%2Aor%2Amu%2Alar=A%5EP-g%2Aiv%2Aest%2Ahei%2Ant%2Aer%2Aes%2Atr%2Aat%2Aer.

Look at .

Reduce similar several occurrences of highlight_red%28+er+%29 to highlight_green%28+er%5E2+%29

It becomes .

Look at .

Moved these terms to the left highlight_green%28+-A%5EP+%29,highlight_green%28+g%2Aiv%2Aest%2Ahei%2Ant%2Aer%5E2%2Aes%2Atr%2Aat+%29

It becomes .

Result: T%2Ahef%2Aor%2Amu%2Alar-A%5EP%2Bg%2Aiv%2Aest%2Ahei%2Ant%2Aer%5E2%2Aes%2Atr%2Aat=0

Answer:

two

Step-by-step explanation:

i used a calculator

Answer:

A. P = 3.3w

Step-by-step explanation:

A. P = 3.3w

B. P = 0.3w

C. P = 3.6w

D. P = 12w

P = price of the cereal

w = weight of the cereal

p = $3.60

w = 12-ounce

3.60p = 12w

Divide both sides by 3.60

3.60p / 3.60 = 12w / 3.60

P = 3.3w

The correct answer is A. P = 3.3w

Answer:

40 meters squared

Step-by-step explanation:

8 * 5 = 40

Answer:

460

Step-by-step explanation:

Answer:

460

Step-by-step explanation:

Answer:

QFQF

Step-by-step explanation:

FAFAF

Answer:

Your answer is -4y - 9

Step-by-step explanation:

Simplify the expression.

~Brainiliest please~

Answer: C

Step-by-step explanation: Because 2 times 1= 2 2times 2=4 2 times 3=6 etc...

Answer:

13

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer: 30 mins.

Step-by-step explanation:

The mode is the value that appears the most times.

In such a situation, first order the numbers in an ascending order:

15, 20, 25, 25, 30, 30, 30, 35, 35, 40, 45

As can be seen from the above, 30 is the number that appears the most so the mode is 30 mins.

Answer:

x= -2 y= -5

Step-by-step explanation:

Answer:

arc DC = 64

angle DCQ = 32

Step-by-step explanation:

Hello There!

The circumference of a normal circle is 360

Given that arc AD = 98 and having found arc ABC we can find arc DC by subtract the known arcs from 360

360 - 98 - 198 = 64

Hence arc DC = 64

The problem wants us to find angle DCQ having found arc DC

Remember like stated before an included angle is equal to 1/2 its opposite arc

64/2=32

so angle DCQ = 32

Answer:

a(n) = 4*(2)^(n - 1)

Step-by-step explanation:

The correct version of this formula is a(n) = a(1)*r^(n - 1).  Must use the " ^ " symbol to indicate exponentiation, and enclose the "n - 1" inside parentheses.

Here, if 4, 8, 16, 32, ..., then a(1) = 4 and r = 2 (e. g., 16/8 = 2, 32/2 = 16, and so on).

Then the correct formula for this geometric sequence is

a(n) = 4*(2)^(n - 1), where use of the parentheses as indicated is mandatory.

Answer:

a(n) = 4*(2)^(n - 1)

Step-by-step explanation:

The correct version of this formula is a(n) = a(1)*r^(n - 1).  Must use the " ^ " symbol to indicate exponentiation, and enclose the "n - 1" inside parentheses.

Here, if 4, 8, 16, 32, ..., then a(1) = 4 and r = 2 (e. g., 16/8 = 2, 32/2 = 16, and so on).

Then the correct formula for this geometric sequence is

a(n) = 4*(2)^(n - 1), where use of the parentheses as indicated is mandatory.

Answer:

D) 2275

Step-by-step explanation:

Answer:

Interest = $6,300 (Approx.)

Step-by-step explanation:

Given:

Amount deposit (P) = $26,000

Number of month = 36 month

Number of year (n) = 36 / 12 = 3 year

Rate of interest (r) = 7.5% = 0.075  

Find:

Interest  earned

Computation:

Interest = p[(1+r)ⁿ-1]

Interest = 26,000[(1+0.075)³-1]

Interest = 26,000[(1.075)³-1]

Interest = 6,299.71

Interest = $6,300 (Approx.)

Answer:

20% increased

Step-by-step explanation:

Answer:

14.04      

Step-by-step explanation:                                                                                                       :)

/frac{10 }{ \sqrt{149} } = \frac{10}{12.20} = 0.8192

first of all find the square root of 149 and 10 is divided by 12.20which is the square root of 149 and you get your answer.The fraction form is 512/625

Answer:

Step-by-step explanation:

[tex]\sqrt{149}\text{ is irrational. Though it is customary to rationalize the denominator.}\\ \\ \left(\frac{10}{\sqrt{149}}\right)\frac{\sqrt{149}}{\sqrt{149}}\\ \\ \frac{10\sqrt{149}}{149}[/tex]