What is the image of (-10,6) after a dilation by a scale factor of 1/2 centered at the.
origin?

Answer:

d

Step-by-step explanation:

Answer:

Vertical angles are congruent, so L3 = 37 degrees, and L4 = 143 degrees.

Let me know if this helps!

Answer:

c

Step-by-step explanation:

Answer:

2x and 4x i guess

Step-by-step explanation:

Answer:

Step-by-step explanation:

https://mypages.valdosta.edu/alazari/math1111/Classmaterials/2.5%20-%20HW.pdf

Answer:

The value of the remainder if undefined.

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Explanation:

Rotate the triangle so that the side 17 cm is completely horizontal and the triangle is pointing upward. The 10.3 cm portion is the height. The base and height are always perpendicular to one another.

Area = (base*height)/2

Area = (17*10.3)/2

Area = 87.55 square cm

The sides 12 cm and 15 cm are not needed at all. They might have been put in there as a distraction.

Answer: 20

Step-by-step explanation: 40/2

Answer:

X=11

Step-by-step explanation:

10x+19=12x-3

Dont worry I wont give you any links The awnser to your question is..... 68 Oh and if you need more help whith this ill be ready to awnser any more Enjoy the rest of your day !

Answer:

-2

Step-by-step explanation:

-3 -1 / 7-5 = -4/2 = -2

4 is 7/10

hope this helps

Answer:

the answer from what I see in the picture is C

Answer:

6x² - 19x + 10

Step-by-step explanation:

Given

(3x - 2)(2x - 5)

Each term in the second factor is multiplied by each term in the first factor, that is

3x(2x - 5) - 2(2x - 5) ← distribute both parenthesis

= 6x² - 15x - 4x + 10 ← collect like terms

= 6x² - 19x + 10

Using the triangle similarity theorems, the given pairs of triangles can be proven to be similar:

1.  [tex]\triangle STR $ and $ \triangle PQN[/tex] are similar by the SSS similarity theorem

2.  [tex]\triangle EFG $ and $ \triangle JHG[/tex] are similar by the AA similarity theorem.

3.  [tex]\triangle XYZ $ and $ \triangle XWT[/tex] are similar by SAS similarity theorem.

4. [tex]\triangle ANF $ and $ \triangle SEH[/tex] are similar by the AA similarity theorem.

5. [tex]\triangle RNQ $ and $ \triangle MNL[/tex] are similar by the SAS similarity theorem.

6. [tex]\triangle ECD $ and $ \triangle LMN[/tex] are similar by the SSS similarity theorem.

7.  [tex]\triangle AEB $ and $ \triangle BDC[/tex] are not similar.

8.  [tex]\triangle JLN $ and $ \triangle KLM[/tex] are similar by the SAS similarity theorem.

9.  [tex]\triangle SUT $ and $ \triangle WUV[/tex] are similar by the AA similarity theorem.

10.  [tex]\triangle DHK $ and $ \triangle BAE[/tex] are similar by the SAS similarity theorem.

The following are triangle similarity theorems that can be used to prove that two triangles are similar if we don't have all the information about the two triangles:

Using the above stated similarity theorems, let's prove the given pairs of triangles are similar or not:

1. [tex]\frac{ST}{PQ} = \frac{SR}{NP} = \frac{TR}{NQ}[/tex]

Plug in the values

[tex]\frac{55}{25} = \frac{44}{20} = \frac{37.4}{17} = 2.2[/tex] (All three sides of one triangle are proportional to all three sides of the other triangle).

Therefore,  [tex]\triangle STR $ and $ \triangle PQN[/tex] are similar by the SSS similarity theorem.

2. <F in [tex]\triangle EFG[/tex] is congruent to <H in [tex]\triangle JHG[/tex]

<EGF in  [tex]\triangle EFG[/tex] is congruent to <JGH in  [tex]\triangle JHG[/tex]

Therefore, [tex]\triangle EFG $ and $ \triangle JHG[/tex] are similar by the AA similarity theorem.

3.<YXZ in [tex]\triangle XYZ[/tex] is congruent to <WXT in [tex]\triangle XWT[/tex]

[tex]\frac{XY}{XW} = \frac{XZ}{XT}[/tex]

Substitute

[tex]\frac{35}{28} = \frac{38}{30} = 1.3[/tex]

This implies that the two corresponding sides of [tex]\triangle XYZ $ and $ \triangle XWT[/tex] are proportional to each other. Also the included angles are congruent.

Therefore, [tex]\triangle XYZ $ and $ \triangle XWT[/tex] are similar by SAS similarity theorem.

4. <A = <S = 29 degrees

<N = <E = 106 degrees (Note: <E = 180 - 29 - 45)

Therefore, [tex]\triangle ANF $ and $ \triangle SEH[/tex] are similar by the AA similarity theorem.

5. <RNQ in [tex]\triangle RNQ[/tex] is congruent to <MNL in [tex]\triangle MNL[/tex] (an included angle is congruent to each other)

[tex]\frac{MN}{NR} = \frac{LN}{NQ} = 1.25[/tex] (two sides of both triangles are proportional)

Therefore, [tex]\triangle RNQ $ and $ \triangle MNL[/tex] are similar by the SAS similarity theorem.

6. [tex]\frac{EC}{LM} = \frac{ED}{LN} = \frac{CD}{MN} = 1.8[/tex]  (three sides of both triangles are proportional).

Therefore, [tex]\triangle ECD $ and $ \triangle LMN[/tex] are similar by the SSS similarity theorem.

7. The information given is not enough to prove that the two triangles are similar by any of the similarity theorems.

Therefore, [tex]\triangle AEB $ and $ \triangle BDC[/tex] are not similar.

8. <JLN in [tex]\triangle JLN[/tex] is congruent to <KLM in [tex]\triangle KLM[/tex] (an included angle is congruent to each other)

[tex]\frac{JL}{KL} = \frac{NL}{ML} = 1.4[/tex] (two sides of both triangles are proportional)

Therefore, [tex]\triangle JLN $ and $ \triangle KLM[/tex] are similar by the SAS similarity theorem.

9. <T = <V = 72 degrees

<SUT = <WUV (Vertical angles)

Therefore, [tex]\triangle SUT $ and $ \triangle WUV[/tex] are similar by the AA similarity theorem.

10. <H = <A = 38 degrees (included angles)

[tex]\frac{AB}{HK} = \frac{AE}{HD} = 1.4[/tex]  (two sides of both triangles are proportional)

Therefore, [tex]\triangle DHK $ and $ \triangle BAE[/tex] are similar by the SAS similarity theorem.

In summary, using the triangle similarity theorems, the given pairs of triangles can be proven to be similar:

1.  similar by the SSS similarity theorem

2.  similar by the AA similarity theorem.

3. similar by SAS similarity theorem.

4. similar by the AA similarity theorem.

5. similar by the SAS similarity theorem.

6. similar by the SSS similarity theorem.

7.  not similar.

8. similar by the SAS similarity theorem.

9. similar by the AA similarity theorem.

10.  similar by the SAS similarity theorem.

Learn more here:

https://brainly.com/question/8762796

Answer:

It's true. The ratios of sides are equal

Answer:

Step-by-step explanation:

x/4=15/6

x=4(15)/6

x=60/6

x=10

Answer:

m=2

Step-by-step explanation:

(0,-4) -> (0,4)

(1,-2) -> (-1, 2)

2-4/-1-0

m= -2/-1

m= 2

x-2.5>8.7

+2.5 +2.5

x>11.2

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hope it helps

Answer:

The shorter leg, s, is the geometric mean between h and m

The longer leg, b, is the geometric mean between h and n

Step-by-step explanation:

By the right triangle geometric mean theorem, we have;

The altitude of a right triangle, 'h', which intersects with the hypotenuse side of the right triangle at a point such that it creates two segments, 'a' and 'b' on the hypotenuse side , then we have;

h = √(a·b)

Therefore, we have;

Description      [tex]{}[/tex]                                                                                 Proportion

The altitude of ΔAYES is the geometric mean between m and n   [tex]\dfrac{m}{a} =\dfrac{a}{n}[/tex]

a² = m·n → a = √(m·n)

The shorter leg, s, is the geometric mean between h and m   [tex]\dfrac{m}{s} =\dfrac{s}{h}[/tex]

s² = m·h → s = √(m·h)

The longer leg, b, is the geometric mean between h and n   [tex]\dfrac{n}{b} =\dfrac{b}{h}[/tex]

b² = n·h → s = √(n·h)

Answer:

i guess the two numbers were obtuse angles

Angle 1 and angle 5 are corresponding angles.

When two parallel lines are crossed by another line, comparable angles are the angles that are created in matching corners or corresponding corners with the transversal (i.e. the transversal).

Given:

Two lines cut by line t.

And lines are not parallel.

So, angle 1 and angle 5 are corresponding angles.

Therefore, corresponding angles is the required statement.

To learn more about the corresponding angles;

https://brainly.com/question/29147125

#SPJ6

Answer:

1(rise)/-1(run)  answer = -1

Step-by-step explanation

hope that helped

Answer:

(6, -3)

Step-by-step explanation:

sorry, i don't know what you have to write in the blanks.

Answer:

I think the answer is A

Step-by-step explanation:

8x4=32

then A says 32xpi

Answer:

1 is

for 1 disc is $16.50

for 2 disc is $33.00

for 3 disc is $49.50

and

2 is

for 1 book is $6.95

for 2 books is $13.90

for 3 books is $20.85

Step-by-step explanation:

brainliest pls

Answer:

1,317

Step-by-step explanation: