Answer:
hi your answer to this question is 220'
Explanation:
hope this helped you
What is the relationship between momentum and speed?
Answer:
Momentum is directly proportional to the object's mass and also its velocity.
Explanation:
Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.
explain the difference between vector and scalar quantities
Answer:
vector quantity have both magnitude and direction but scalar quantities have only magnitude
A car which is traveling at a velocity of 27 m/s undergoes an acceleration of 5.5 m/s^2 over a distance of 430 m. How fast is it going after that acceleration?
73.9m/s (1dp)
1) list everything that you are given using suvat, where s is distance, u is initial velocity(speed), v is final velocity(speed), a is acceleration and t is time
s = 430m
u = 27 m/s
v = ? (we need to work out)
a = 5.5m/s^2
t = (we are not given this value)
2) use an equation that doesn't involve the time
[tex] {v}^{2} = u {}^{2} + 2as[/tex]
3) input the values that we have
[tex] {v}^{2} = ( {27})^{2} + 2(5.5)(430)[/tex]
[tex]v {}^{2} = 5459[/tex]
[tex]v = \sqrt{5459} = 73.9[/tex]
so the answer is 73.9m/s to 1dp
What amount of heat is required to increase the temperature of 75. 0 grams of gold from 150°C to 250°C? The specific heat of gold is 0. 13 J/g°C. A. 750 joules B. 980 joules C. 1300 joules D. 1500 joules E. 2500 joules.
975 J of heat energy is needed to increase the temperature from 150°C to 250°C of given mass of gold.
From specific heat formula,
[tex]Q = mc \Delta T[/tex]
Where,
[tex]Q[/tex] - Heat absorbed
[tex]m[/tex] - mass of gold = 75. 0 g
[tex]c[/tex] - specific heat of gold = 0. 13 J/g°C
[tex]\Delta T[/tex]- temperature difference = 150°C - 250°C = 100°C
Put the values in the formula,
[tex]Q = 75\times 0.13 \times 100 }\\\\Q = 975 {\rm \ J}[/tex]
Therefore, 975 J of heat energy is needed to increase the temperature of given mass of gold.
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The heat required to increase the temperature of the gold is 980 J
The correct answer to the question is Option B. 980 J
We'll begin by calculating the change in the temperature of the gold
Initial temperature (T₁) = 150 °C Final temperature (T₂) = 250 °C Change in temperature (ΔT) =?ΔT = T₂ – T₁
ΔT = 250 – 150
ΔT = 100 °C
Finally, we shall determine the heat required.
Mass (M) = 75 gChange in temperature (ΔT) = 100 °C Specific heat capacity (C) = 0.13 J/gºC Heat (Q) =?Q = MCΔT
Q = 75 × 0.13 × 100
Q = 975 J
Q ≈ 980 J
The correct answer to the question is Option B. 980 J
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A gas in a closed container is heated with 10J of energy, causing the lid of the container to rise 2m with 3N of force. What is the total change in energy of the system
Explanation:
For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.
ΔU=Q−W
We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.
W=FΔx
W=3N×2m
W=6J
Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.
ΔU=Q−W
ΔU=10J−6J
ΔU=4J
Answer is 4J
i think this may help you very much
what happens to light when it travels from air into water
Answer:
Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.
Follow me on i n s t a g r a m, message me and I'll follow you back: ifaulkner24
what is the definition for the term Resistance?
Answer:
Hey mate....
Explanation:
This is ur answer.....
There are 2 definitions :-
The refusal to accept or comply with something.The ability not to be affected by something, especially adversely.Hope it helps!
Brainliest pls!
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12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?
Answer:
192 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 8 × 24 = 192
We have the final answer as
192 m/sHope this helps you
A 75 kg diver has 5,150.25 J of gravitational potential energy. Determine the diver’s height
Answer:3.4m
Explanation:
A 3-column table with 1 row. The first column titled distance travelled (meters) has entry 6. 1. The second column labeled lower track elapsed time (seconds) has entry 4. 92. The third column labeled higher track elapsed time (seconds) has entry 3. 36. Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the higher track? How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is. Calculate speeds for each track. How much faster was the car on the higher track than the lower track?.
Answer:
B,A,A
Explanation:
Answer:
Other guy is correct b,a,a
Explanation:
Chapter Name :- Vector
Question :-
A car is moving at Vc speed. Rain is falling vertically at a speed of 10 m / s. What is the value of Vc in this case,if the front glass of the car will get wet?
Answer :- Vc ≥ 10
I need Explanation! Please Don’t do copy from net! If you don’t know then no need to answer!
The value of the speed of the car, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
The given parameters:
Speed of the car, = VcSpeed of the rain, = 10 m/sThe relative velocity of the car with respect to the falling rain is calculated as;
[tex]V_{C/R} = V_C- V_R[/tex]
If the speed of the car equals the speed of the rain, the rain will fall behind the car.If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.If the speed of the car is greater than speed of the rain, the rain will fall on the car.Thus, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
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1. Three students are using sports equipment to model the relative motion of
Earth, the moon and the sun.
A. Identify which ball would be used to model the Sun, Earth and the Moo
B. Describe the relative (in relation to each other) motions of these bodies
Answer:
The golf ball would be revolving around the baseball while the baseball would be revolving around the basketball.
Explanation:
The basketball would be represented as the Sun, the baseball would be represented as the Earth and the golf ball would be represented as the moon. Since the Moon revolves around the Earth and the Earth revolving around the Sun makes a perfect explaination for this question.
What size resistor would produce a 3 amp current flow with a 12 volt battery?
Resistance = volts / amps
Resistance = 12 volts / 3 amps
Resistance = 4 Ohms
Answer: 4 Ohms
An object is dropped from a 42 m tall building. How long does it take to reach the ground?
Answer:
2.1 seconds
Explanation:
let D represent the height in meters
let g represent gravity in meters per second squared
let t represent time in seconds
D= -42 meters (negative because it falls down)
g= -9.8m/s^2
t= [tex]\frac{-42 meters}{9.8 m/s^2}[/tex]
this gives t= 4.2857 s^2
the meter units cancel out in the division
now we must simplify the units to singular seconds so...
[tex]\sqrt{4.3 s^{2} }[/tex] which simplifies to [tex]\sqrt{4.3}[/tex] x [tex]\sqrt{s^{2} }[/tex]
this equals 2.1 seconds
A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s
The impulse of the boxers punch is 28 kgm/s.
The given parameters;
applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 sThe impulse of the boxers punch is calculated as follows;
[tex]J = Ft[/tex]
where;
F is the applied force (N)t is the time of force action (s)The magnitude of the impulse is calculated as follows;
[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]
Thus, the impulse of the boxers punch is 28 kgm/s.
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I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?
Answer:
The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²
Explanation:
An object, initially at rest, moves 475 m in 19 s. What is its acceleration? *
[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]
[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]
[tex]\\ \sf\Rrightarrow 950=361a[/tex]
[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]
what is volume help plz
Answer:
Explanation:
Volume = Length x width x height
Multiply the length, width and, height to get the volume of the question.
You are handed two mystery materials, and told to find out which materials accepts negative charges more easily. A positively-charged, helium-filled balloon is tied to a tabletop with a string a meter long. What's a simple experiment you could run to find out which material accepts electrons more easily?
The simple experiment you could run to find out which material accepts electrons more easily is to rub them together and move the two charge misery materials one after the other to the positive - charge helium - filled balloon.
According to the fundamental law of static electricity which state that unlike charges attract each other while like charges repel.
The simple experiment you could run if you are handed two mystery materials, and told to find out which materials accepts negative charges more easily charging by friction.
This can be employed by rubbing the two misery materials together and move them one by one to a positively-charged, helium-filled balloon which is tied to a tabletop with a string of a meter long.
The misery material that accepts electron more easily will be attracted to the positive - charge helium - filled balloon. While the gravitational pull will pull down the other misery material. The attraction will not be effective.
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A 300 g ball swings in a vertical circle at the end of a 1.3-m-long string. When the ball is at the bottom of the circle, the tension in the string is 13 N.
What is the speed of the ball at that point?
Answer:
0.23N for the speed
at the bottom of the circle
Do I look good yes or no
Answer:
0/10
Explanation:
_--------------------
Answer:
No. -infinity/10
Explanation:
Ew. Just why, like no.
PLEASEE IS FOR A TEST!!!Which ionic compound is BOTH correctly written and named??
A mg0 magnesium oxide
B Mn02 manganese oxide
C N02 nitrogen oxide
D SrBr strontium bromide
Answer:
Letter A
Explanation:
Manganese dioxide- Mn02
Nitrogen Dioxide- n02
Strontium bromide- SrBr
A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second interval?
a. 2.5 m/s
b. 5.0 m/s
c. 6.5 m/s
d. 7.0 m/s
Answer:
a. 2.5 m/s
Explanation:
50 / 20 = 2.5 m/s
I need help with this physics question
Answer:
its B hope you have a good Day
Jacob has a disk that sinks to the bottom when placed in a vessel of water. He cuts some holes in the disk and immerses it again in a vessel of water. Which of these is likely to happen?
Answer:
it will float up cause its has gravity
When Jacob cuts some holes in the disk and immerses it again in a vessel of water it will now float at the top. Thus, the correct option for this question is A.
Why does an object float at the top of the water?An object floats when the weight force on the object is balanced by the upward push of the water on the object. The upwards push of the water increases with the volume of the object that is underwater. It is not affected by the depth of the water or the amount of water.
According to the context of this question, when a disk does not have holes in it, it will definitely sink to the bottom of the water because it has high density, but when the hole is made in the disk, the water is passed out from them and now, the upward force is minimized that cause less density as compared to previous.
Therefore, when Jacob cuts some holes in the disk and immerses it again in a vessel of water it will now float at the top. Thus, the correct option for this question is A.
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[tex] \huge \rm༆ question ༄[/tex]
Calculus proof of second equation of motion ~
Newton's second equation of motion :-
S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]
This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.
So let's see what pieces of information (bundles of equations) do we have with us, initially.
We have, a very primary equation with us,
dS/dt = v… (I)
(Considering motion in a straight line only)
And we also have the equation
dv/dt = a…(II)
Simply replacing the v in eqn (II) by eqn (I), we find
d2S/dt^2 = a…(III)
This is what we need to solve. It's easy.
You know,
d2S/dt^2 = d/dt(dS/dt) = a
⟹ dS/dt = ∫adt = at+c1
Since, dS/dt is the velocity of the particle,
Therefore, at t = 0, dS/dt|t = 0 = u
⟹ u = a∗0 + c1 = c1
⟹ c1 = u
Therefore, dS/dt = u + at
Thus, S = ∫(udt + atdt)
⟹ S = ut + 1/2at^2 +c^2
If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0
This makes S = S0 +ut + 1/2at^2
Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),
We get
S = ut + 1/2at^2
Hope it helps :)
Write any three facts in the support of molecular theory
Answer:
Every gas is made up of very small particles called molecules. Molecules of a gas are separated from each other by large distances so that volume is negligible as compared to total volume of gas. The force of gravitation on the molecules is also negligible.
Hope that helps. x
:
A baseball player at practice is pushing a tackling dummy across the field. He initially has to push the 130 kg dummy with 600 Newton’s of force to get it to start moving and maintain a force of 475 to keep it moving at a steady state. What are the coefficient of friction static and kinetic with the dummy on the ground
.
Answer:
Static= 600/(130*9.8)=0.47
Kinetic=475/(130*9.8)=0.37
Can the velocity of a body reverse the direction when acceleration is constant? If you think so, give an example.
Consider a particle moving to the left with some speed v. If we take leftward to be the negative direction, then the particle's velocity is -v, and it's moving in the negative direction.
Now give the particle a positive acceleration pointing rightward. The particle will eventually slow to a stop before increasing its speed in the positive direction.
So the answer is yes, the direction in which a body is moving can be reversed with constant acceleration.
When a squid pushes against the water, the squid moves forward because the
______________ pushes against the _______________.
Answer:
water pushes against the squid