What is the gravitational energy of a 2.63kg
book when it is lifted 14.29m off the floor?
Give your answer rounded to one place after the
decimal, no units.
Question 3

Answers

Answer 1

Answer:

G.P.E = 368.3

Explanation:

Given the following data;

Mass = 2.63kg

Height, h = 14.29m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

[tex] G.P.E = mgh[/tex]

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

[tex] G.P.E = 2.63*9.8*14.29 [/tex]

G.P.E = 368.3

Note: the unit of gravitational potential energy is Joules.


Related Questions

formula of average speed​

Answers

Answer:

Hey mate....

Explanation:

This is ur answer.....

Hope it helps!

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A ball is launched horizontally at a speed of 4.0m/s from the top of a cliff that is 24.6 meters high. Where in the ball's trajectory is the horizontal speed a maximum? Explain how you know.

Answers

Answer:

The horizontal speed of the ball is constant where there is little resistance from the air

Explanation:

From the given parameters of the ball, we have;

The horizontal speed of the ball = 4.0 m/s

The height of the cliff from which the ball is launched = 24.6 meters

The direction in which the ball is launched = Horizontally

The components of the forces acting on the ball are;

The vertical force = The Earth's gravitational attraction

The horizontal force = 0 N (There are no horizontal forces acting on the ball)

According to Newton's first law of motion, the ball will continue in its uniform motion or in its rest state unless acted upon by a force

Therefore, given that there are no horizontal forces component acting on the ball, (little air resistance) the ball will continue with the initial horizontal velocity, such that the horizontal velocity of the ball remains constant.

A tractor pulls a 978 kg wagon at a velocity of 4.9 m/s. How many watts of power are exerted by the tractor motor is the tractor pulls the wagon at a 60 degree angle?

Answers

Answer:

23481.78 W

Explanation:

The computation of number of watts of power is shown below:

M = 978 kg

V = 4.9 m/s

Theeta = 60°

As we know that  

 P = Fcos(theeta).V

F = Mg

P = (Mg)cos(theeta).V

P = 978×9.8×cos(60)×4.9

P = 23481.78 W

Which would increase the speed of a sound wave?

Answers

Answer:

I would say temperature

Water uptake to the atmosphere occurs through the processes of evaporation and transpiration from plants where it condenses to form clouds. Clouds release the water through precipitation. During a summer of extreme drought, what can we expect to happen to the surface groundwater stored in ponds and lakes?

a. Water levels will increase because there is more precipitation
b. Animals won't drink as much to save water, so water levels remain the same
c. Water levels will increase because there are more evaporation and transpiration
d. Water levels will decrease because there are more evaporation and transpiration

Answers

water level will decrease because there are more evaporation and transpiration

If the velocity of a car is 45km/h west, how far can it travel in 0.5 hours

Answers

Answer:

22.5km

Explanation:

Since 0.5 of an hour is half of an hour, you have to divide 45 by half, and you would get 22.5 km

does anybody have social media and could help me with my homework ? i will send you pictures of my work please all of my work is due tomorrow!! i need help

Answers

Yes I do I can help if you need some

A potato is which part of the plant?
root
stem
leaf
flower

Answers

I’m pretty sure it’s the root

Una bola se lanza verticlamente de la parte superior de un edificio con una velocidad inicial 25 m/s la bola impacta al suelo en la base del edificio 7 segundos despues de ser lanzada ¿que altura subio la bola

Answers

Answer:

S = 415.1 meters

Explanation:

Dados los siguientes datos;

Velocidad inicial = 25 m/s

Tiempo, t = 7 segundos

Para encontrar la altura (desplazamiento) de la pelota, usaríamos la segunda ecuación de movimiento;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Dónde;

S representa el desplazamiento o altura medida en metros.

u representa la velocidad inicial medida en metros por segundo.

t representa el tiempo medido en segundos.

a representa la aceleración medida en metros por segundo cuadrado.

Sustituyendo en la ecuación, tenemos;

[tex] S = 25*7 + \frac {1}{2}*(9.8)*7^{2}[/tex]

[tex] S = 175 + 4.9*49 [/tex]

[tex] S = 175 + 240.1 [/tex]

S = 415.1 meters

Fission reactions are currently used to provide energy for many different sources. Where does the energy produced during the reaction come from?

Answers

Answer: From the mass lost during the reaction, or the mass defect.

The energy produced during a reaction come from the heat energy which is released during splitting of uranium atoms.

What is a fission?

Nuclear energy originates from the splitting of uranium atoms in the atmosphere, a process called as fission. This reaction generates heat energy to produce steam, which is used by a turbine generator to generate electric energy. Because, the nuclear power plants do not burn fuel, they do not produce any greenhouse gas emissions.

Uranium and plutonium are the most commonly used atoms for fission reactions in nuclear power reactors because they are very easy to initiate and control with time. The energy which is released by fission in these reactor heats water into the steam. The steam generated is used to spin a turbine to produce carbon-free electric energy.

Learn more about Fission here:

https://brainly.com/question/2732120

#SPJ6

A force of 1000 N is exerted on a golf ball for 0.005 s. The change in momentum of the golf ball is - a 200,000 kg m//s b 50 kg m//s c 5,000 kg m//s d 5 kg m//s

Answers

Answer:

d) 5 Ns

Explanation:

Impulse = Ft = 1,000(0.005) = 5

the mass of the earth is 6 × 10²² kg and that of the moon is 7.4× 10²² Kg if the distance between the earth and moon is 3.84 × 10⁵ km . calculate the force of the earth exerted by it on the moon . Take G = 6.67×10¹¹ Nm² / kg²​

Answers

Answer:

Force = 20.08 x 10⁴⁷ N

Explanation:

Given:

M1 = 6 × 10²⁴ kg (rectified)

M2 = 7.4× 10²² Kg

Radius r = 3.84 × 10⁵ km

G = 6.67×10¹¹ Nm² / kg²​

Find:

Force

Computation:

F = GM1M2 / r²

Force = [(6 × 10²⁴)(7.4× 10²²)(6.67×10¹¹ )] / (3.84 × 10⁵)²

Force = [296.148 × 10⁵⁷] / [14.7456 × 10¹⁰]

Force = 20.08 x 10⁴⁷ N

DO NOW: You are picking up a pendulum (Clay ball on a string) as you pull the pendulum up on one side and let it fall, what types of energy are being used?

Answers

Answer:

The energy used in the pendulum is the initial Potential (Mechanical) Energy, P.E. given to the Clay ball attached to the inclined and extended string by virtue of its elevated position in relation to the rest position (lower state)

The swinging of the pendulum is brought about by the dynamic equilibrium between the initial potential energy, P.E. and the Kinetic Energy, K.E., of the pendulum when it is in motion

The (total) Mechanical Energy, M.E. of the ideal pendulum is constant at all times during the motion of the pendulum and it is given by the following formula;

M.E. = P.E. + K.E.

At the top of the swing, P.E. is maximum and K.E. is zero

Similarly, at the mid (lowest) point in the swing, instantaneously, P.E. is zero and K.E. is maximum

Explanation:

One of the solid reactants was treated in a coffee grinder before adding to

the reaction container. *

O

A. Concentration

B. Temperature

C. Surface Area

D. Catalyst

E. Agitation

Answers

Answer:

C. Surface area

Explanation:

The rate of  chemical reaction depends on various factors such as:

concentration and pressurenature of reactantstemperaturesurface areapresence of catalyst, etc.

Effect of surface area of reactants: the rate of a chemical reaction can be increased by increasing the the area of contact of the reacting substances. This is especially important when one or more of the reactants are solids., because only the particles of the solid that are exposed are able to take part in the reaction at each instant of time. Therefore, the greater the surface area of the solid reactant particles the faster the reaction.

The surface area of solid reactants can be increased by grinding or pelletizing, thus allowing for a greater contact between the reacting particles,

The instance in which one of the solid reactants was treated in a coffee grinder before adding to the reaction container is one way of increasing the surface area of a reactant.

A disturbance that generates a wave may be a simple pulse or shock

True or false

Answers

Answer:

That would be true.

-- a bell starts ringing (wave) when you tap it (simple pulse)

-- a pond starts rippling (wave) when a stone drops in (simple shock)

-- a guitar strings starts waving when you pluck it

Electrical current is defined as _____.

the strength of the electric field
the movement of charge past a certain point per unit time
the potential of the battery
the conservation of charge

Answers

Answer:

the strength of the electric field

3. Determine the units of the quantity described by the following com-
binations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s2)
c. (kg/s) (m/s)
d. (kg/s) (m/s)

Answers

B is the answer!! Hope this helps

two children of masses m1 = m2 = 20 kg , ride on the perimeter of a small merry-go- round . the merry -go-round us a disk of mass M = 30 kg answer

Answers

Answer:

c

Explanation:

M= 1000 g g= 10 m/s2 h= 10 K.E at GROUND = 400 j M.E = ....... ........J the answer is 400 so plz explain how

Answers

Answer:

M = 500 J

Explanation:

Given that,

Mass, M = 1000 g = 1 kg

Height, h = 10 m

Potential energy is given by :

P = mgh

P = 1×10×10

P = 100 J

The kinetic energy at ground = 400 J

Mechanical energy = sum of kinetic and potential energy

So,

M = 100 + 400

M = 500 J

So, the mechanical energy of the system is 500 J.

A centrifuge used in DNA extraction spins at a maximum rate of 7000rpm producing a "g-force" on the sample that is 6000 times the force of gravity. If the centrifuge takes 10 seconds to come to rest from the maximum spin rate: a) What is the angular acceleration of the centrifuge? b)what is the angular displacement of the centrifuge during this time

Answers

Answer:

A) a = 73.304 rad/s²

B) Δθ = 3665.2 rad

Explanation:

A) From Newton's first equation of motion, we can say that;

a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.

Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s

Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s

We are given; t = 10 s

Thus;

a = 733.04/10

a = 73.304 rad/s²

B) From Newton's third equation of motion, we can say that;

ω² = ω_o² + 2aΔθ

Where Δθ is angular displacement

Making Δθ the subject;

Δθ = (ω² - ω_o²)/2a

At this point, ω = 0 rad/s while ω_o = 733.04 rad/s

Thus;

Δθ = (0² - 733.04²)/(2 × 73.304)

Δθ = -537347.6416/146.608

Δθ = - 3665.2 rad

We will take the absolute value.

Thus, Δθ = 3665.2 rad

(b) Figure 4 shows a car travelling on a motorway.
A passenger wants to check the accuracy of the speedometer of the car.
The car is travelling at a constant speed.
The passenger has a stopwatch.
The lamp posts are 40 m apart.
lamp post
Figure 4
Describe how the passenger could determine the speed of the car as accurately
as possible.
(3)

Answers

Answer:

To calculate anything - speed, acceleration, all that - we need data. The more data we have, and the more accurate that data is, the more accurate our calculations will be. To collect that data, we need to measure it somehow. To measure anything, we need tools and a method. Speed is a measure of distance over time, so we'll need tools for measuring time and distance, and a method for measuring each.

Conveniently, the lamp posts in this problem are equally spaced, and we can treat that spacing as our measuring stick. To measure speed, we'll need to bring time in somehow too, and that's where the stopwatch comes in. A good method might go like this:

Press start on the stopwatch right as you pass a lamp postEach time you pass another lamp post, press the lap button on the stopwatchPress stop after however many lamp posts you'd like, making sure to hit stop right as you pass the last lamp postRecord your dataCalculate the time intervals for passing each lamp post using the lap dataCalculate the average of all those invervals and divide by 40 m - this will give you an approximate average speed

Of course, you'll never find an *exact* amount, but the more data points you have, the better your approximation will become.

2. How does laser light differ from
normal light?​

Answers

Answer:

Laser light differs from normal light because laser lights are monochromatic which means it only shines one color and only that color :3

Explanation:

:3

The major difference between laser light and light generated by white light sources (such as a light bulb) is that laser light is monochromatic, directional and coherent. ... Coherent means that the waves of light are in phase with each other. A light bulb produces many wavelengths, making it incoherent.

Question 2
What measurements are needed to calculate your BMI?

A. Weight and shoe size
B. Height and weight
C. heart and breathing rate per minute
D. core temperature and height


Answers

Answer:

B

Explanation:

Why are temperatures of the currents generally colder at the poles than the equator?
A. Tilt of the Earth on its axis
B. Angle of the sun's rays are less direct
C. Angle of the sun's rays are more direct
D. The Earth's revolution around the sun.​

Answers

Answer:

the answer is A

Explanation:

Putting the moon back to its original size, if it were suddenly to move to twice the
distance from the earth, how would that effect the force of gravitation with the
earth?

Answers

Link is a virus don’t click it trust me okay?

what is specific heat capacity?​

Answers

Specific heat capacity is defined as the amount of heat required to raise the temperature of 1 kilogram of a substance by 1 kelvin (SI unit of specific heat capacity J kg−1 K−1). From: Basic Physics and Measurement in Anaesthesia (Fourth Edition), 1995.

Answer: It is the amount of thermal energy (heat) needed to raise the temperature of 1kg of a substance by 1°C. *It is important to state that it is per kg because of the word "specific". cliffffy4h and 3 more users found this answer helpful.

who invented Pascal??​

Answers

What the guy above me said

Pls helppp. Is this right?

Answers

Answer:

yes you are totally right

Those are all correct great job!

Select the correct answer from each drop-down menu.

Photosynthesis is a process in which plants prepare food using carbon dioxide, chlorophyll, and water in the presence of sunlight.

During photosynthesis,(blank)
energy is transformed into(blank)
1.Chemical,electrical,kinetic, Solar ?
2.Chemical, Electrical, Kinetic, Solar


Answers

Answer:

During photosynthesis solar energy is converted into chemical energy

Explanation:

During photosynthesis solar energy is converted into chemical energy in the form of energy rich bond of ATP molecule.

ATP (Adenosine triphosphate) and ADP (Adenosine diphosphate) molecules are termed currency of energy. ADP molecule is converted into ATP molecules, whenever energy is available in certain exothermic reactions of metabolism.

ATP molecules are store- house of energy. ATP molecule is broken down into ADP molecule in presence of enzyme ATPase, releasing energy whenever energy is required.

The synthesis of ATP molecules, utilizing solar energy during photosynthesis, is termed photo-phosphorylation.

These ATP molecules produced during light reaction of photosynthesis are utilized in dark reaction of photosynthesis (Calvin cycle).

ATP molecules synthesized during photo-phosphorylation may also be used in other metabolic reactions.

Photo-phosphorylation is of 2 types, i.e. Cyclic and Non-cyclic photo-phosphorylation.

Chlorophyll molecules entrap solar energy . There are 2 types of photo-systems in chlorophyll. These are photo-system -I and photo-system-II .

The electrons of chlorophyll molecule of photo-system I get excited which pass through series of electron carriers in electron transport system arranged in the order of decreasing energy level.

During the passage of electrons from carriers of higher energy level to the carriers of lower energy level, the energy is lost which is utilized for converting ADP molecule into ATP molecule.

Photo-system I is concerned with light reaction of photosynthesis only, constituting cyclic photo-phosphorylation.

The electron transport during Photo-system II results in the synthesis of NADPH2 in presence of enzyme NADP reductase. NADPH2 is used in reduction reaction of Calvin cycle.

Both Photo-systems participate in non-cyclic photo-phosphorylation that results in the synthesis of NADPH2 in addition to the synthesis of ATP molecules.

Three vector are oriented as shown in figure below where. A=20.0units, B=40.0units, And C=30.0. (a) The x and Y component of the resultant vector. (b) The magnitude of the resultant vector. (c) Direction of the resultant vector ​ { please help me}

Answers

Answer:

Explanation:

a). Vertical component of vector B = Bsin(45)

                                                     = 40sin(45°)

                                                     = 28.28 units

Horizontal component of vector B = Bcos(45°)

                                                         = 40cos(45°)

                                                         = 28.28 units

Vertical component of vector C = Csin(45°)

                                                     = 30sin(45°)

                                                     = 21.21 units

Horizontal component of vector C = Ccos(45°)

                                                         = 30cos(45°)

                                                         = 21.21 units

Vertical forces = A + Bsin(45°) - Csin(45°)

                       = 20 + 28.28 - 21.21

                       = 27.07

Horizontal forces = Bcos(45°) + Ccos(45°)

                             = 28.28 + 21.21

                             = 49.49 units

b). Magnitude of resultant force = [tex]\sqrt{(27.07)^2+(49.49)^2}[/tex]

                                                = [tex]\sqrt{3182.045}[/tex]

                                                = 56.41 units

c). Direction of the resultant force → Along vector B (at an angle of 45° from the horizontal line)

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