What is the function of a lyase enzyme?

a. To assist the substrate by binding to the enzyme, enabling substrate to active site engagement
b. To facilitate a reaction of one substrate to form two products with the use of water
c. To facilitate a reaction of one substrate to form two products without the use of water
d. To tell fibs

Answer:

c2h6o

Explanation:

find the hcf of the numbers and divide each number by the HCF eg

HCF of 4,12,2 -> 2

4÷2=2

12÷2=6

2÷2=1

therefore

c2h6o

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Explanation:

The given reaction equation is as follows.

[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]

Now, the two half-reactions can be written as follows.

Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]

This will be balanced as follows.

[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)

Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]

This will be balanced as follows.

[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.

Answer:

Moles of NaNO2 = 0.158

Moles of HNO2 final = 0.098

Explanation:

Given

Moles of HCl = 12

Moles of HNO2 = 0.11

Moles of NaNO2 = 0.170

HCl +NaNO2 --> HNO2  + NaCl

1 mole of HCl react with one mole of NaNO2 to produce 1 mole of NaCl and 1 mole of HNO2

Moles of NaNO2 = 0.17 - 0.012 = 0.158

Moles of HNO2 final = 0.11 - 0.012 = 0.098

Answer:

6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.

Explanation:

The balanced reaction is:

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of each compound is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?

[tex]mass of Fe_{2} O_{3} =\frac{4.65 grams of Fe*159.7 grams of Fe_{2} O_{3}}{111.7grams of Fe}[/tex]

mass of Fe₂O₃= 6.65 grams

6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.

Answer:

37.5 g NaCl

Explanation:

Step 1: Given data

Step 2: Calculate how many grams of NaCl are in 250.0 g of solution

The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.

250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl

Answer:

Angle of incidence = angle of reflection = 0

Explanation:

Given that,

A light beam strikes a shiny object at a 90-degree angle.

The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.

Here, the beam strikes normally. So, the angle of incidence is 0.

A/c to the law of reflection,

Angle of incidence = angle of reflection

So, the angle of reflection is also equal to 0.

Answer:

[tex]m=3.90mol/kg[/tex]

Explanation:

Hello there!

In this case, since the molality of a solution is calculated by dividing moles of solute by kilograms of solvent, it turns out firstly necessary for us to calculate the moles of methyl alcohol in 75.0 grams as shown below:

[tex]n=\frac{75.0g}{32.04g/mol}=2.34mol[/tex]

Then, the kilograms of water, 0.600 kg, and finally, the resulting molality:

[tex]m=\frac{2.34mol}{0.600kg}\\\\m=3.90mol/kg[/tex]

Regards!

Answer:

"7.46" is the correct answer.

Explanation:

Given that:

[tex]pH=4.64[/tex]

[tex]C=0.015 \ M[/tex]

The equation:

⇒ [tex]HA \rightleftharpoons H^++A^-[/tex]

HA = C - Cα

H⁺ = Cα

A⁻ = Cα

now,

⇒ [tex]pH=-log(H^+)[/tex]

          [tex]=-log(C \alpha)[/tex]

          [tex]=4.64[/tex]

    [tex]C \alpha = 2.3\times 10^-5 \ M[/tex]

As we know,

⇒ [tex]K_a=C \alpha^2[/tex]

         [tex]=(\frac{C \alpha}{C} )^2\times C[/tex]

         [tex]=\frac{(2.3\times 10^{-5})^2}{0.015}[/tex]

         [tex]=3.5\times 10^{-8}[/tex]

hence,

⇒ [tex]pK_a=-log(K_a)[/tex]

           [tex]=7.46[/tex]          

Answer:

B.  Keq = 6.0 x 10-2.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to remember that any equilibrium constant is computed by dividing the concentration of products by that of reactants:

[tex]Keq=\frac{[Prod]}{[Reac]}[/tex]

Thus, a reaction that is reactant-favored will have a Keq>1 because the concentration of reactants prevail over that of products at equilibrium, and thus, the correct answer is B.  Keq = 6.0 x 10-2.

Regards!

Answer:

9.6x10⁹ mg

Explanation:

In order to solve this problem we need to convert 9600 kg into mg.

First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:

9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g

Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:

9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg

The mass of milk miligrams is 9.6x10⁹.

Answer:

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Explanation:

Answer:

q6= third option

q7= third option

Explanation:

kinetic molecular theory deals with temperature

pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant

Answer:

x~ 34.19 grams del sal o ~ 34 grams!

Explanation:

el porcentaje de masa se escribe como

% de masa = masa de sal / (masa de sal + masa de disolvente) * 100%

aquí, el disolvente se da como 500 g de agua.

usa x en lugar de masa de sal y resuelve usando álgebra

6.4 = x / (x+ 500) * 100

0.064 = x / (x+500)

0.064 x + 32 = x

32 = x-0.064x

32 = 0.936 x

x~ 34.19 grams del sal o ~ 34 grams!

Answer:

I think B

Explanation:

2Ca + O2 -> 2CaO

The product of the unbalanced equation: [tex]\rm Ca(s) + O_2(g)[/tex] is [tex]\rm CaO(s)[/tex]. The correct answer is option B.

A product is a material which arises from a chemical process. It is the end result of the reaction and is produced by the rearrangement of the atoms or molecules of the reactants.

This reaction's balanced chemical equation is:

[tex]\rm 2Ca(s) + O_2(g) \rightarrow 2CaO(s)[/tex]

The reaction begins by heating calcium metal in the presence of oxygen gas or by exposing calcium metal to oxygen-containing air. Calcium oxide  [tex](\rm CaO)[/tex] is formed by the reaction of calcium metal (Ca) with oxygen gas[tex]\rm (O_2)[/tex].

Therefore, the result of the stated chemical reaction is [tex]\rm CaO(s)[/tex]. Option B is the correct answer.

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Answer:

Accuracy decreases

Explanation:

All meaurements have an uncertainty (That is, the error of the measurement). The uncertainty of graduated cylinders is higher than uncertainty of pipets.

The accuracy is how close is the measurement to the real value.

If you use graduated cylinders rather than pipets, accuracy decreases because you will have more uncertainty in the measurements putting of the real value and the real value.

The accuracy of the determined value decreases if all measurement is done with graduated cylinders.

The accuracy is the measurement of how close the calculated value is to the real value.

When a student measures the volume with a graduated cylinder the chances of error increase.

Therefore, the accuracy of the determined value decreases if all measurement is done with graduated cylinders.

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Answer: The Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].

Explanation:

The chemical formula of hypochlorous acid is HClO. So, when it is added to water (solvent) then its dissociation is as follows.

[tex]HClO + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}[/tex]

When we write the equilibrium constant for this reaction then it is called acid acid dissociated constant.

Hence, the expression for acid dissociation constant of this reaction is as follows.

[tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex]

Thus, we can conclude that the Ka expression for an aqueous solution of hypochlorous acid is [tex]K_{a} = \frac{[H_{3}O^{+}][OCl^{-}]}{[HClO]}[/tex].

Answer: The value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

Explanation:

Given values:

Initial moles of [tex]SO_3[/tex] = 0.700 moles

Volume of conatiner = 3.50 L

The given chemical equation follows:

            [tex]2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)[/tex]

I:             0.700

C:              -2x           +2x           x

E:           0.700-2x      2x            x

Equilibrium moles of [tex]O_2[/tex] = x = 0.180 moles

Equilibrium moles of [tex]SO_2[/tex] = 2x = [tex](2\times 0.180)=0.360moles[/tex]

Equilibrium moles of [tex]SO_3[/tex] = 0.700 - 2x = [tex]0.700-(2\times 0.180)=0.340moles[/tex]

Molarity is calculated by using the equation:

[tex]Molarity=\frac{Moles}{Volume}[/tex]

So,

[tex][SO_3]_{eq}=\frac{0.340}{3.50}=0.0971M[/tex]

[tex][SO_2]_{eq}=\frac{0.360}{3.50}=0.103M[/tex]

[tex][O_2]_{eq}=\frac{0.180}{3.50}=0.0514M[/tex]

The expression of [tex]K_c[/tex] for above equation follows:

[tex]K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}[/tex]

Plugging values in above expression:

[tex]K_c=\frac{(0.0971)^2\times 0.0514}{(0.103)^2}\\\\K_c=0.0457[/tex]

Hence, the value of [tex]K_c[/tex] for the given chemical equation is 0.0457.

Answer:

The correct answer is -all of the above.

Explanation:

Muscle fatigue is a reduced ability in work capacity caused by work itself. It is known that altering oxygen is contracting skeletal muscle affects performance. Reduced O2 supply increases the rate of muscle fatigue.

The lactic acid is accumulated as it forms rapidly but the breaking of the lactic acid is slow down, which causes muscle fatigue. Less ATP and glycogen in muscle results in fatigue as the muscle is not able to generate energy to power contractions and therefore contributes to muscle fatigue.

Answer: 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

[tex]pH=-\log [H^+][/tex]      .....(1)

Given value of pH = 1.5

Putting values in equation 1:

[tex]1.5=-\log[H^+][/tex]

[tex][H^+]=10^{(-1.5)}=0.0316M[/tex]

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex]       .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

[tex]0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol[/tex]

The chemical equation for the reaction of HCl and calcium carbonate follows:

[tex]2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2[/tex]

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, [tex]4.74\times 10^{-4}mol[/tex] of HCl will react with = [tex]\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol[/tex] of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Moles of calcium carbonate = [tex]2.37\times 10^{-4}mol[/tex]

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

[tex]\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g[/tex]

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

Answer:

4 on the top

He in the middle

2 on the bottom

Explanation:

Correct on plato

The missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

The two atoms interact with each other as shown by the equation below;

[tex]^4_2He[/tex]

where;

Thus, the missing of the part of the chemical equation when the two atoms interact is Helium with mass number 4 and atomic number 2.

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Answer:

K = 1.93 °C/m

Explanation:

This question can be solved by formula of elevation of boiling point.

Boiling T° of solution - Boiling T° of pure solvent = K . m . i

Our solute is urea.

Our solvent is X.

We convert mass of urea to moles: 19.9 g . 1 mol / 60.06g = 0.331 mol

We convert g of solute to kg = 200 g . 1 kg/ 1000g = 0.2kg

m = molality → moles of solute / kg of solvent

m = 0.331 mol / 0.2 kg = 1.66 m

As urea is an organic compound, no ions will be formed.

i = 1 (a non ionizing compound)

Let's replace data in formula:

134,1°C - 130.9°C = K . 1.66 m . 1

3.2 °C / 1.66 m = K

K = 1.93 °C/m

Answer:

F₂ + At⁻

Explanation:

Astatine is the only Halogen that does not exist as a diatomic molecule. One Astatine atom would have a charge of 1⁻. Fluorine is the most electronegative element, and therefore very reactive and commonly forms a diatomic molecule.

Answer:

South China sea

Explanation:

To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).

Answer:

18 moles of H₂.

Explanation:

The balanced equation for the reaction is given below:

2Al + 6HCl –> 2AlCl₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 12 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H₂.

Therefore, 12 moles of Al will react to produce = (12 × 3)/2 = 18 moles of H₂.

Thus, 18 moles of H₂ were obtained from the reaction.

Answer:

For a: The IUPAC name of the compound is N-ethylethaneamide.

For b: The IUPAC name of the compound is N,N-diethylmethaneamide.

For c: The IUPAC name of the compound is ethyl pentanoate

Explanation:

To name a compound, first look for the longest possible carbon chain.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is [tex]R-CO-NH_2[/tex], where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

Esters are a kind of organic molecules having functional groups, [tex]R-COO-R'[/tex] where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

Answer:

There are about 68.33 grams of oxygen present in 93.98 g of CO2.

no sefdrcdftrgfkjj jhhhgfd

I am not sure abt the ans

molar mass= 88

1 molecule = 6.022×10^23

4.44 moles = 6.022×10^23×4.44/88

= 26.73768 × 10^23/88

= 0.3038372727 ×10^23