What is the force of gravity between two 40.0kg masses that are separated by 3.00m?

Explanation:

force=35

distance=18

time=30

power=f×d/t

p=35×18/30

p=21

La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.

Answer: I think the answer is b

Explanation:

Answer:

So an object with mass is attracted to another object with mass, and the gravitational force is directly proportional to the masses of the two objects, and inversely proportional to the square of the distance between the two objects.

If distance  were to increase, than the gravitational force would decrease. If mass were to increase, so would the gravitational force.

Explanation:

Explanation:

Lets take gravitational force(F) and mass(m) and distance (r)

now for a body in contact with the surface of the earth, its mass is also considered(m‘),now the mass of the earth(m") is also considered,then the distance from the body to the center of the earth (r).ie it r because its practically the radius of the earth. is also considered

So by using dimensional analysis ....

we get F a m'•m"/r² ,where a is proportional to.

now since F is directly increaseproportional to m ie. F a m, then an increase in mass of the body increases it's gravitational force(and clearly that makes sense because the bigger you are the stronger you get pulled to the ground)

then we also see that F is inversely proportional to r ie.F a 1/r ,then an increase in the distance between the ground an the object decrease it's gravitational force ( meaning as any object on earth keeps on moving away from the ground the gravitational force between the object and the center of the earth is weak, when it reaches space then the force becomes virtually negligible!)

So to answer the second question, we clearly see that doubling the mass of the body increases the gravitational force between it and the earth

and doubling the distance on the other hand will decrease the attraction between the body and the earth

So a body forcefully projected into the air fights against gravity but its easier as it keeps on getting higher, If it has a greater mass like that of a trail or truck , it will not even probably stay in the air for long , unless its projected with a very high velocity

I hope this helps, and you can ask me any question concerning this via the comments platform.

Answer:

false im just trying to get it if you'd like to give it to me

The answer is false :)

Answer:

They're going to come home as soon as the movie is over.

Answer:

B: They're going to come home as soon as the movie is over.

Explanation:

Answer:

OK we appreciate your concern.

Answer:2.23 m/s

Explanation:

Given

Mass of person and vehicle is [tex]m=1600\ kg[/tex]

Total work done is [tex]W_t=6000\ J[/tex]

Friction consumes one-third of the energy

The remaining two-third is consumed to increase the kinetic energy

[tex]\Rightarrow \dfrac{2}{3}\times 6000=\dfrac{1}{2}\times 1600\times v^2\\\\\Rightarrow 4000\times 2=1600\times v^2\\\\\Rightarrow v=\sqrt{5}\ \approx 2.23\ m/s[/tex]

Answer:

comparing the beam waist for both lasers ( ratio of the beam waists )

4.536 μm / 2.117 μm = 2.14

Explanation:

Nd-YAG laser system : emits at 532 nm , beam diameter = 8 mm

Ti-sapphire laser system : emits at 855 nm , Beam diameter = 6mm

Comparing the beam waist for both lase systems using a focusing lens

Focal length = 10 mm

assumption : light fills lenses in each laser system

Beam waist radius ( W ) =  [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex]

β = wavelength , D = diameter illuminated  , F = focal length

For

Nd-YAG laser system

β = 532 mm , D = 8 mm

hence ( Wn ) =   [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex] =  ( 2*532 / π ) ( 10 / 8 )   = 2.117 μm

For

Ti-sapphire laser

β = 855 nm ,  D = 6 mm

hence ( Wt )  [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex] =  ( 2* 855 ) / π ) ( 50 / 6 ) = 4.536 μm

comparing the beam waist for both lasers ( ratio of the beam waists )

4.536 μm / 2.117 μm = 2.14

Answer:

The first part is right (KE is conserved in an elastic collision).

The second part of the  statement is false,.

Since momentum is conserved, let moving mass m strike stationary mass M:

m v = (m + M) V   where m v is the momentum in

Obviously, v does not equal V.

Answer: Molecules of H202, H20 and 02 are still forming. ( A P E X )

Explanation: I know this is late but for anyone looking at this later

The above question is incomplete, I think the original  question is

Belinda observes that the reaction 2H20+02 2H2O2 appears to have stopped because the concentrations of reactants and products are not changing. Which statement is true at this point in the reaction?

A. Molecules of H₂O₂ are formed only when the reaction vessel is disturbed.

B. Molecules of H2O2 have stopped forming.

C. Molecules of H20 and O₂ have stopped forming.

D. Molecules of H2O2, H2O, and O2 are still forming.

At this point in the reaction, the system has reached a state of equilibrium i.e there is no net change in the concentrations of reactants and products. So the Molecules of H2O2 have stopped forming. The correct option is B.

In chemistry, a state of equilibrium refers to a situation where the concentrations of reactants and products in a chemical reaction are no longer changing over time.

This occurs when the rates of the forward and reverse reactions are equal, and there is no net change in the concentrations of reactants and products.

At equilibrium, the system is in a dynamic state, where the forward and reverse reactions continue to occur, but at the same rate, resulting in no overall change in the concentrations of the species involved in the reaction. The equilibrium state is typically characterized by the equilibrium constant, which is a measure of the relative concentrations of reactants and products at equilibrium for a given reaction under specific conditions of temperature, pressure, and concentration.

Here in this question,

The molecules of H2O2 have stopped forming. This means that the forward reaction (2H2O + O2 → 2H2O2) and the reverse reaction (2H2O2 → 2H2O + O2) are occurring at the same rate, resulting in no net change in the concentration of H2O2. However, molecules of H2O and O2 are still being consumed and produced as they are involved in the reaction, but their concentrations are not changing because they are being replenished at the same rate that they are being consumed.

Therefore, the correct answer is B i.e Molecules of H2O2 have stopped forming.

To learn about redox reactions click:

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Answer:

formed by the process of glaciation.

Explanation:

This problem involved half projectile.

initial velocity, vo = 20 m/s

time of flight, t = 7 s

(a) Simply use the formula to get the height, h:

h = vo*t - (1/2)gt^2

(b) To get the final vertical velocity or terminal velocity (vf), use the formula:

(vf)^2 - (vo)^2 = 2gh

(c) Use the formula find the horizontal distance traveled, R:

R = vo * cos(θ) * t

But since the angle involved with respect to horizontal is zero, and cos(0) = 1, we have

R = vo * t

Hope this helps~ `u`

Jai

Answer:

correct ooooooooooooo

Answer:

Mass of Exoplanet =  0.58 kg

Explanation:

First, we will calculate the speed of the forest moon:

[tex]speed = v = \frac{Circumference}{time}\\[/tex]

circumference = 2πr = 2π(14441566 m) = 90739035.3 m

time = 6 days 10 hr = (6 days)(24 h/1 day)(3600 s/1 h) + (10 h)(3600 s/1 h)

time = 554400 s

Therefore,

[tex]v = \frac{90739035.3\ m}{554400\ s}\\\\v = 163.67\ m/s[/tex]

We know that the centripetal force on forest moon will be equal to the gravitational force given by Newton's Gravitational Law, as follows:

[tex]Centripetal\ Force = Gravitational\ Force\\\frac{m_{moon}v^2}{r} = \frac{Gm_{moon}m_{exoplanet}}{r^2}\\\\m_{exoplanet} = \frac{v^2r}{G}\\\\m_{exoplanet} = \frac{(163.67\ m/s)^2(14441566)}{6.67\ x\ 10^{-11}\ N.m^2/kg^2}[/tex]

Mass of Exoplanet =  0.58 kg

Answer:

speed =distance /time

speed =4.82/0.00360

speed =1338.8m/s

Answer:

42

Explanation:

Multiply the difference by 8.4 to estimate the distance. ( kilometers )

P wave = 10

S wave = 15

Difference = 5

8.4 * 5 = 42

The initial wave (P wave) is less severe and moves faster, whereas the more damaging S wave moves slowly.

When an earthquake happens, it sends forth energy waves known as seismic waves. It's similar to the ripples that occur when a stone is thrown into water.

Here, There are two types of waves: P waves and S waves.

P waves travel faster and are formed first; they go in the exact opposite direction from where the earthquake occurs.

S waves, or secondary waves, on the other hand, are slower and travel in a perpendicular direction.

When these waves are generated in particular facilities, scientists can detect them.

The difference between time = 15 – 10 = 5

From the graph:

=8.4×5

= 42

Thus, the initial wave (P wave) is less severe and moves faster, whereas the more damaging S wave moves slowly.

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Answer:

A

Explanation:

The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:

d

→

L

d

t

=

0

or

→

L

=

→

l

1

+

→

l

2

+

⋯

+

→

l

N

=

constant

.

Note that the total angular momentum

→

L

is conserved. Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero.

Answer:

72 J

Explanation:

Use the Work formula

W= F x d

Given:

F - 48 N

d - 1.5 m

Solution:

W= F x d

W=  48 N x 1.5 m

W= 72 J

Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.

At one end of the electromagnetic wave line, which has the group of the visible spectrum. This has been referred to as the visible light of the spectrum. The visible light with the shortest of the wavelength has the blue light and the one with the longest has the red light.

The primary colors of the light has been the spectrum are red, blue, and green. The combination of these colors will form other as well as the colors which has been referred to as the secondary colors. The combination of the beam of the red light and the beam of green light will form yellow color.

Therefore, Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.

Learn more about flashlights on:

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Answer:

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Explanation:

By Principle of Energy Conservation and Work-Energy Theorem we present the equations that describe the situation of the roller coaster car on each top of the hill. Let consider that bottom has a height of zero meters.

From top of the first hill to the bottom

[tex]m\cdot g \cdot h_{1} = \frac{1}{2}\cdot m\cdot v_{1}^{2} +W_{1, loss}[/tex] (1)

From the bottom to the top of the second hill

[tex]\frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2}+W_{2,loss}[/tex] (2)

Where:

[tex]m[/tex] - Mass of the roller coaster car, in kilograms.

[tex]v_{1}[/tex] - Speed of the roller coaster car at the bottom between the two hills, in meters per second.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]h_{1}[/tex] - Height of the first top of the hill with respect to the bottom, in meters.

[tex]W_{1, loss}[/tex] - Work done by non-conservative forces on the car between the top of the first hill and the bottom, in joules.

[tex]v_{2}[/tex] - Speed of the roller coaster car at the top of the second hill, in meters per seconds.

[tex]h_{2}[/tex] - Height of the second top of the hill with respect to the bottom, in meters.

[tex]W_{2, loss}[/tex] - Work done by non-conservative forces on the car bewteen the bottom between the two hills and the top of the second hill, in joules.

By using (1) and (2), we reduce the system of equation into a sole expression:

[tex]m\cdot g\cdot h_{1} = m\cdot g\cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2} + W_{loss}[/tex] (3)

Where [tex]W_{loss}[/tex] is the work done by non-conservative forces on the car from the top of the first hill to the top of the second hill, in joules.

If we know that [tex]m = 175\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h_{1} = 18\,m[/tex], [tex]h_{2} = 8\,m[/tex] and [tex]v_{2} = 11\,\frac{m}{s}[/tex], then the work done by non-conservative force is:

[tex]W_{loss} = m\cdot\left[ g\cdot \left(h_{1}-h_{2}\right)-\frac{1}{2}\cdot v_{2}^{2} \right][/tex]

[tex]W_{loss} = 6574.75\,J[/tex]

The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.

Answer: kooi kooi

how r u and thanks for the free points :)

Answer:

118800 seconds

Explanation:

Given :

Voltage, V = 1.2 V

Resistance, R = 22 Ω

Applying Ohm's law, we get

Voltage, V = IR

Current [tex]$I=\frac{V}{R}$[/tex]

           [tex]$I=\frac{1.2}{22}$[/tex]

          I = 0.0545 A

Rate = 1800 mAh

Time taken, [tex]$t=\frac{1800 \times 10^{-3}}{0.0545}$[/tex]

                       = 33 hr

                      = 118800 s

Answer:

A Data is transmitted in the form of electromagnetic radiation.

B Signals travel faster through space than through fiber-optic cables.

C No ground equipment is needed to access the internet.

D The network is made of many satellites organized in a grid pattern.

Explanation:

THose are the options

Answer:

B

Explanation:

Answer:

2) a_y= -g  3) vₓ=constant v_y = v_{oy} - g t, 4)  vₓ = v₀ₓ - ax t

5)  changes the horizontal speed, should change range

7) changes the vertical speed change the maximum height

Explanation:

1) After reading your long writing, we are going to solve the exercise, in the attachment you can see the different vectors.

2) The acceleration vectors are vertical and directed downwards due to the attraction of the Earth (gravity force) this force is constant, on the x axis there is no acceleration

3) the velocity vectors on the x-axis are constant because there are no relationships and the y-axis changes value according to the expression

           v_y = v_{oy} - gt

at the point of maximum height, vy = 0 is equal to the maximum height

4) For someone to change the horizontal acceleration we must assume a friction with the air, in this case they relate it would be in the opposite direction to the horizontal speed

In the graph it would be directed to the left, therefore the velocity would be

           vₓ = v₀ₓ - ax t

5 and 6) If someone changes the horizontal speed, they should change the range of the shot for greater horizontal speed, the rock goes further.

the equations of motion are

           x = v₀ₓ t

           y = v_{oy} t - ½ g t²

7) If someone changes the vertical speed change the maximum height, but not the scope of the shot, for higher speed higher maximum height,

the equations of motion are the same.

Answer:Air bags can leave you in even more injury, From the impact they give

You could end up with a broken nose,arm

concussion