What is the final volume of a gas (in liters) when the initial volume is 14.00 L at
0.9600 atm, and the pressure changes to 0.01000 atm?

Answer: I got -4542.9kg/mol

Explanation:

Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol

Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :

Enthalpy of formation = product - Reactant

2219.2 = -2323.70 - (propane + 0)

2219.2 = - 2323.70 - propane

Propane = - 2323.70 - 2219.2

[tex] C_{3}H_{8} = - 4542.9 [/tex]

Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.

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Answer:

ozone

Explanation:

the ozone layer is the thickest air on the earth's atmosphere protecting us from ultra violent rays from the sun

Answer:

3.4e+25

Explanation:

One mole of methane or CH₄ contains 6.02 × 10²³ molecules. Then, number of moles of methane containing 1.34 × 10²⁴ molecules is 2.25.

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³  molecules. The mass of one mole of compound is called its molar mass. The number of moles of the compound can be determined by dividing the given mass by molar mass.

Methane  is a covalent compound formed from carbon and hydrogen atoms.   One mole of methane contains 6.02 × 10²³ molecules of CH₄  . Hence number of moles of  of 1.34 × 10²⁴ molecules of methane  is:

1.34 × 10²⁴/6.02 × 10²³  = 2.25 .

Hence, the number of moles of CH₄ that contains 1.34 × 10²⁴ molecules is 2.25 moles.

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Answer:

t = 39.42 days

Explanation:

To do this, we need to use the general expression for decay rate:

R = R₀ exp(-λt)    (1)

According to the problem, decay rate of A initially is 64 times rate of B, so we can say the following:

A₀ = 64B₀   (2)

The value of λ can be determined using:

λ = ln2 / t(1/2)  (3)

Let's calculate first the value of λ for each nuclei:

For A: λ₁ = ln2 / 5 = 0.1286 day⁻¹

For B: λ₂ = ln2 / 30 = 0.0231 day⁻¹

Now, let's write an expression using (1) for each nuclei.

A = A₀ exp(-0.1286t)

A = 64B₀ exp(-0.1286t)   (3)

B = B₀ exp(-0.0231t)    (4)

We want to know the time when A = B , therefore, we can actually equals (3) and (4) and solve for t:

64B₀ exp(-0.1286t) = B₀ exp(-0.0231t)

64 exp(-0.1286t) = exp(-0.0231t)

ln(64 * exp(-0.1286t)) = ln(exp(-0.0231t))

ln64 + ln(exp(-0.1286t))= -0.0231t

4.1589 - 0.1286t = -0.0231t

4.1589 = (0.1286 - 0.0231)t

t = 4.1589 / 0.1055

So, in 39 days, the decay rates of A and B will be the same.

Hope this helps

Answer: It will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.

Explanation:

The half-reaction equation is as follows.

[tex]Cu^{2+} + 2e^{-} \rightarrow Cu[/tex]

According to the standard values, 1 mole of an electron carries 96500 C. Therefore, charge carried by 2 moles of electrons is [tex]2 \times 96500 C[/tex].

Also, atomic mass of Cu is 63.5 g. According to the equation 2 moles of electrons are depositing 63.5 g of Cu.

Hence, charge required to deposit 19.5 kg (1 kg = 1000 g) or 19500 g of Cu is calculated as follows.

[tex]19500 g Cu \times \frac{2 \times 96500 C}{63.5 g Cu}\\= 5.92 \times 10^{7} C[/tex]

Formula used to calculate time is as follows.

[tex]Q = I \times t[/tex]

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

[tex]5.92 \times 10^{7} C = 38.5 \times t\\t = \frac{5.92 \times 10^{7} C}{38.5}\\= 1.53 \times 10^{6} sec[/tex]

As 1 hour contains 3600 seconds. So, converting seconds into hours as follows.

[tex]1.53 \times 10^{6} sec = 1.53 \times 10^{6} sec \times \frac{1 hr}{3600 sec}\\= 425 hr[/tex]

Thus, we can conclude that it will take 425 hours to plate 19.5 kg of copper onto the cathode if the current passed through the cell is held constant at 38.5 A.

Answer:

not B

Explanation:

my friend got it wrong

Answer:

4.034x10^24 atoms

Explanation:

6.7 x 6.023x10^23 = 4.034x10^24 atoms

4.0348348050000003e+24

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Answer:

matter is anything that occupies space

states of matter : solid,liquid, gas,plasma

Answer:

matter can be anything, tables chairs, literally anything. it has volume and takes up space.

Explanation:

Solids, liquids, gases, plasmas, and Bose-Einstein condensates (BEC)

Answer:

A mixture is a mix of two or more substances, with different physical and chemical properties so they can not become homogenous or combine. The substances in a mixture can easily be separated or filtered.

A solution is a special mixture in which one substance completely dissolves in another, and makes a homogenous single form. This can not be separated by filter or easily separated

For better understanding, make a homogeneous solution of sugar and water is a solution as sugar completely dissolves, but if there are any crystals of sugar or dissolve sand in the solution, it will become a heterogeneous mixture.

Answer: D.) non-spontaneous.

Explanation:

Answer:

1 mole contains 6.02⋅1023 particles

Explanation:

Explanation:

X×6.02⋅1023=3.75⋅1024→

X=3.75⋅10246.02⋅1023=0.623⋅101=6.23 moles

Answer:

736 mmHg = 0.97 atm (Approx.)

736 mmHg = 736 Torr

Explanation:

Given barometer in the laboratory atmospheric pressure data:

Atmospheric pressure in mmHg = 736 mmHg

Find:

Change given data into Torr

Change given data in atm (atmospheric pressure)

Computation:

We know that;

1 atm = 760 mmHg

So,

736 mmHg = 736 / 760

736 mmHg = 0.97 atm (Approx.)

We know that;

760 mmHg = 760 Torr

So,

736 mmHg = 736 Torr

Answer:

202 °C

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 90 °C

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T₁) = 90 °C

Initial temperature (T₁) = 90 °C + 273

Initial temperature (T₁) = 363 K

Next, we shall determine the final temperature.

Initial temperature (T₁) = 363 K

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

15.5 / 363 = 20.3 / T₂

Cross multiply

15.5 × T₂ = 363 × 20.3

15.5 × T₂ = 7368.9

Divide both side by 15.5

T₂ = 7368.9 / 15.5

T₂ ≈ 475 K

Finally, we shall convert 475 K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T₂ = 475 – 273

T₂ = 202 °C

Thus, the new temperature of the gas is 202 °C

Answer: I think it could be Decomposition

Explanation: I think is composition because decomposition starts by being together and ends up as two

Answer:

D. So electrons can flow from one electrode to another

Explanation:

An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.

An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.

Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.

Answer:

55.0g water can be made

Explanation:

To solve this question, we must convert the molecules of H2 to moles using Avogadro's constant. With the moles, and the reaction:

H2 + 1/2O2 → H2O

We can find the moles of H2O = Moles H2 and its mass of using molar mass of water -H2O = 18.01g/mol-

Moles H2 = Moles H2O:

1.84x10²⁴ molecules * (1mol / 6.022x10²³ molecules) = 3.055 moles H2O

Mass:

3.055 moles H2O * (18.01g / mol) = 55.0g water can be made

Answer:

C. 6.52 x 10^14 Hz

Explanation:

hope this helps

Answer:

I think the answer would be sodium

Answer: B: Sodium

Explanation:

Sodium if one attempted to experiment this it will result in that sodium will react violently and be exothermic because that the evolve hydrogen immediately ignites fire (Also I'm sorry if this is all wrong and unhelpful)

Answer:

Music CDs and smartphones are digital.

Explanation:

Music CDs and smartphones are digital. Analogue takes up a lot of space and degrades with the [passage of time while on the other hand, digital takes less space and degrades in large piece of time. Dimmer light switches and cameras that use film is it analog not digital. The major difference between both signals is that the analog signals have continuous electronic signals, while digital signals have non-continuous electronic signals.

Answer:

the oxidation state of nitrogen is +5

Answer:

Melting ice and rising seas

Explanation:

At the same time global warming causes polar ice sheets and glaciers to melt. The combination of these changes is causing sea levels to rise, resulting in flooding and erosion of coastal and low lying areas.

Answer:

194g of distilled water.

Explanation:

Hello there!

In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:

[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]

And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:

[tex]m_w=200g-6g=194g[/tex]

Therefore, the answer is 194g of distilled water

Regards!

Answer:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Explanation:

Let's consider the dissociation reaction of the complex ion Ag(NH₃)₂⁺.

Ag(NH₃)₂⁺(aq) ⇄ Ag⁺(aq) + 2 NH₃(aq)

The dissociation constant, Kd, is the equilibrium constant for the dissociation of the complex ion, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

The dissociation constant for this reaction is:

Kd = [Ag⁺] × [NH₃]² / [Ag(NH₃)₂⁺]

Answer: Hello attached below is the complete question and using data from ALEKS data tab

answer:

PbCl₂ :  Yes , PH = 3

CaC0₃ : Yes, PH = 3

AgCn : Yes , PH = 3 .

Explanation:

For PbCl₂  

PbCl₂ solubility will change ( decrease )  with increase in PH, and the PH at which PbCl₂ will be most soluble is at PH = 3

For CaC0₃

Addition of -ions which increases the PH level will cause a decrease in the solubility of  CaC0₃ hence the PH at which it will be most soluble in an aqueous solution is PH = 3

For AgCn

Increase in the PH level there would be a decrease in the solubility of AgCn hence the PH at which AgCn is most soluble ( highest solubility ) = 3

The ability of a solute to be able to dissolve is called solubility. Yes, at pH 3, the solubility of lead chloride, calcium carbonate, and silver cyanide.

The ability of the solute to get dissolved in a solvent to form a saturated solution is called solubility.

For lead chloride, the solubility will decrease as the pH will increase and is most soluble at a pH of 3.

For calcium carbonate, the addition of ions increases the pH will result in a decreased solubility, and will be most soluble at pH 3.

For silver cyanide increased pH decreases the solubility and is most soluble at a pH of three.

Therefore, solubility decrease with an increase in pH due to the concentration factor.

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Answer:

H3PO4 + 5 HCl → PCl5 + 4 H2O

Explanation:

The given equation is

H3PO4 + HCl = PCl5 + H2O

The above chemical equation has one P atom on both the sides, hence phosphorus is balanced

There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -

H3PO4 + 5HCl = PCl5 + H2O

Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become

H3PO4 + 5HCl = PCl5 + 4H2O

Let us check for oxygen

Oxygen on LHS = 4 and oxygen on RHS = 4

Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O

Answer:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Explanation:

https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l

Answer:

the answer is A.

Explanation:

Elemental fluorine, for example, is the strongest common oxidizing agent.

Answer:

c I do believe good luck with the answer