What is the exact area of a circle with a radius of 12 feet? 24π Square Feet 36π Square Feet 121π Square Feet 144π Square Feet Question 2. What is the approximate area of the circle? Use π = 3.14 (the circle has 10.4 inside it) 32.7 square centimeters 65.2 square centimeters 108.2 square centimeters 339.6 square centimeters Question 3. What is the approximate area of a circle with a radius of 28 centimeters? Use π = 3.14 87.9 square centimeters 175.8 square centimeters 2461.8 square centimeters 4923.5 square centimeters Question 4. What is the approximate area of a circle with a diameter of 50 centimeters? Use π = 3.14 87.9 square centimeters 379.9 square centimeters 1962.5 square centimeters 4923.5 square centimeters

Answer:

Ans = 76

Step-by-step explanation:

10y + [tex]x^{2}[/tex]

=> 10 * 4 + [tex]6^{2}[/tex]

=> 40 + 36

=> 76

Hope it helps :)

Answer:

c. Yes because ∠2 and ∠6 are congruent.

Step-by-step explanation:

From the picture attached,

m(∠2) = m(∠3) = m(∠6) = 40°

m(∠1) = 140°

Since (∠2 ≅ ∠6) (corresponding angles)

Therefore, by the converse theorem of corresponding angles lines c and d are parallel.

Option c is the answer.

Well the distance from the two points is 15 so that means the midpoint in -10+7.5=-2.5. There you go! Have a nice day.

Okay so multiple 17 times 8 and 16 times 33 and then add the answers together and you should get 664!

Step-by-step explanation:

here's your solution

=> Firstly divide above picture in two parts

=> 1st = traingle

=> 2nd = trapezium

=> area of traingle = 1/2*base*height

=> height = 8

=> we need to find out base by using Pythagoras formula

=> base^2 = 17^2 - 8^2

=> base^2 = 289 - 64 = 225

=> base = √225

=> base of traingle = 15

=> now, area of traingle = 1/2*15*8

=>60sq.units

=> area of trapezium = 1/2(sum of p. sides ) *

distance between them

=> area = 1/2*(33 + 15)*16

=> area = 1/2*16*48

=> area = 384sq.units

=> area of whole figure = 384 + 60

= 444 sq.units

Answer:

PJ = 41.34

Step-by-step explanation:

P is incenter, three angles bisector meet

∠MJP ≅ ∠OJP

PM = PN = PO = 22   (radius: property of incenter)

∠JPM = 90 - ∠MJP = 90 - OJP = ∠JPO

ΔJPM ≅ ΔJPO   (ASA) or (SAS)

LM = JO

2x + 3 = 5x - 45

3x = 48

x = 16

JM = 35

PJ = √35²+22² = √1709 = 41.34

The value of PJ in triangle KJL is 41.32 units.

The point formed at the intersection of the three angle bisectors of a triangle; also the centre of the incircle.

Given that, P is incenter of the triangle KJL,

Considering the triangles ΔMJP and ΔOJP

PM = PO (property of incenter)

∠ JMP ≅ ∠ JOP

JP is common segment.

ΔJPM ≅ ΔJPO  (by SAS rule)

JM = JO  (CPCTC)

2x + 3 = 5x - 45

3x = 48

x = 16

JM = 35

Using the Pythagoras theorem,

PJ² = PM²+JM²

PJ = √35²+22² = √1709 = 41.34

Hence, The value of PJ in triangle KJL is 41.32 units.

For more references on incenter, click;

https://brainly.com/question/29480777

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Answer:

20:25

Step-by-step explanation:

add how many parts (4+5=9)

45/9=5

4*5=20, 5*5=25

therefore, 20:25

Answer: 50 inches

Step-by-step explanation:

Answer:

B A A

Step-by-step explanation:

I had this question asked before lol

Answer:

X=[1 5 8 -1]

Step-by-step explanation:

B or Option 2

Answer:

yes, school is hard

thanks for points

have a good day ....❤

Answer:

$330

Step-by-step explanation:

$3 times 60 students = $180

$5 times 30 adults = $150

$180 + $150 = $330

Answer:

Step-by-step explanation:

you would find your answer by multiplying the amount of students/adults by how much each ticket costs

60 x $3 = $180

30 x $5 = $150

$180 + $150 = $330

The other no. is:

32

As you can see that in the ratio given, 3 is the smaller no. and 12 too.

So when we divide 12 by 3, we get 4

Then to find the other no. we need to multiply 4 with 8 (which is the other no.          in the ratio given)

Therefore, we get the other no. as 32

And also when you divide 12 by 32,

You get the answer as 3 by 8 (which is the given ratio)

Hope you found this helpful!

THANK YOU!!

∝ Sidhdi

Answer:

9 combinations are in the sample space

Step-by-step explanation:

Well there's 3 sizes 4 flavors and with or without nuts

3(Sizes)+ 4(flavors)+ 2(with or without)

Therefor when you add those up you get 9 things people can choose from, known as the sample space.

Answer:

y+4=-2(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=-2(x-(-1))

y+4=-2(x+1)

Answer:

345,512

Step-by-step explanation:

one liter is a thousand ml, so u just have to multiply

Answer:

The answers is x=3

Step-by-step explanation:

Divide both sides by the numeric factor on the left side then solve.

Hope this helps.

May i please have a brainless Thank you.

Answer:

5*x-3=12

the number is 3 because 5*3=15 and 15-3=12

Answer:

3

Step-by-step explanation:

x - 3 = 12

12 + 3 = 15

15 - 3 = 12

5( ? ) = 15

15/5

? = 3

5(3) = 15 - 3 = 12

Hope this helps dude

Answer:

Answer is D

Step-by-step explanation:

because its sideways its x = y^2

and because its facing right its positive.

Answer:

12 green bags

Step-by-step explanation:

Given data

The given ratio of green bags to white bags is

=2 to 5

=2:5

Number of white bags=30

Applying the part to part method, let the number of green bags be x

so

2/5=x/30

cross multiply

30*2=5x

60=5x

divide both sides by 5

x= 60/5

x=12

Hence there are 12 green bags

answer:

11x

step-by-step explanation:

x + 4x + 6x

= 11x

Answer:

11x

Step-by-step explanation:

just add them all together

x + 4x = 5x

5x + 6x = 11x

hope this helps :)

Answer:

I would use addition

Step-by-step explanation:

Since addition is the opposite of subtraction.

Answer:

Addition

Step-by-step explanation You would use addition because you can cancle out the numbers that way

Where exactly are the alleged statements?

Answer: 240 m

Step-by-step explanation:

Given

Football field measures [tex]100\ m\times 72\ m[/tex]

Another similar field of length

[tex]L=30\ m[/tex]

and width, say W is marked

So, their area must be the same

[tex]\Rightarrow 100\times 72=30\times W\\\\\Rightarrow W=\dfrac{7200}{30}=2540\ m[/tex]

The width of the football field is 41.7m

The football measures 100m by 72 m. The school football field is similar.

For similar rectangles, the corresponding sides have common ratios. Therefore, let's establish the proportion as follows:

cross multiply

3000 = 72w

divide both sides by 72

w = 3000 / 72

w = 41.6666666667

w = 41.7 m

learn more on proportion here: https://brainly.com/question/582443

Answer:

the answer is y=30x

Step-by-step explanation:

however many inches times 30 is the consistent answer to the equation    

Answer:

y=30x

Step-by-step explanation:

We can start out by writing our slope-intercept form equation: y=mx+b. In this case, our y-intercept is 0, so we can write y=mx.

Let's find the slope. We can take the points (1,30) and (2,60). We can use the formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] to find our slope. Plug these values in, and we get [tex]\frac{60-30}{2-1}[/tex]. Evaluate this, and our slope is 30. So, our equation is y=30x.

Hope this helped!

Answer:

11.66 units

Step-by-step explanation:

Given that he walks 10 blocks north and then 6 blocks west..

When combined with the straight line to the school, this forms a right angled triangle with the straight line as the hypotenuse.

Hence, let the straight line be h

h^2 = 10^2 + 6^2 (using Pythagoras theorem)

h^2 = 100 + 36

h^2 = 136

h = √ 136

h = 11.66 units

The approximate volume of first cone is 709[tex]mi^{3}[/tex] and the volume of second cone is 262 [tex]cm^{3}[/tex].

Volume is amount of substance a container can hold in its capacity. Volume of cone is basically 1/3 *π[tex]r^{2}h[/tex] in which r is radius and h is height of cone.

We have been given two cones. First is having radius of 7 mi and

height 14 mi and second is having radius of 5 cm and height of 10 cm. We are required to find out the volume of both the cones.

Volume of first cone=1/3 *π[tex]7^{2}* 14[/tex]

=(49*3.14*14)/3

=708.86

Approximately 709 [tex]mi^{3}[/tex]

Volume of second cone =1/3π[tex]5^{2} *10[/tex]

=(25*3.14*10)/3

=261.67

Approximately 262 [tex]cm^{3}[/tex].

Hence the approximate volume of first cone is 709[tex]mi^{3}[/tex] and the volume of second cone is 262 [tex]cm^{3}[/tex].

Learn more about volume at https://brainly.com/question/463363

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