what is the equation of the line

Answer: he average retail price of grapes is $2.09 per pound, according to United States Department of Agriculture's Economic Research Service, with most bags weighing in around two pounds. That's where it's easy to get tricked: Grapes for $3.99 per pound don't sound so bad, but a 2.5-pound bag would set you back nearly $10.

Step-by-step explanation:

Answer:

x = 6

Step-by-step explanation:

This means that they are equivalent to each other.

10 = 30 *Multiply by 3

2 = x

Since we multiplied by 3 to get 30, x is just 2 mulitplied by 3.

x = 6

Answer:

Hi

the answer would be:

10/40 = 2/2+x => if you solve the equation, it'll be equal to : x = 6

I hope that it's correct.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

We know that every second the bird's position lowers by 3(-3) so the equation for it is option D

Answer:

its A i got got right on my test

Step-by-step explanation:

A.P.E.X.

Answer:

349

Step-by-step explanation:

please give thanks by clicking the heart :)

Answer:

22x?

Step-by-step explanation:

is there more to this question? if not its just simple addition and then add "x" at the end

Answer:

p x 0.79 = 7.90 or 0.79 x p =7.90

Answer:

Step-by-step explanation:

Dimensions of rectangle:

The area is the product of the two dimensions:

Step-by-step explanation:

P * h = k, where k is a real constant.

Answer: Dried apricots are less expensive they are $8.75

Step-by-step explanation: I divided 21.98 by 2 and got 10.99 then I divided 26.25 by 3 and 8.75 which makes dried apricots less expensive

Answer:

16 17

Step-by-step explanation:

Step-by-step explanation:

In Quadrant II, cosine is negative.

We know that sin²x + cos²x = 1, so:

cosx = sqrt[1 - sin²x]

= sqrt[1 - (5/13)²]

= sqrt(144/169)

= -12/13 (since cosx is negative here)

The answer is -12/13. (B)

Option B is correct.

According to the given question

We have,  sin ∅ = 5/13

From the trigonometric identities we know that

[tex]sin^{2}[/tex]∅ + [tex]cos^{2}[/tex]∅ =1

substitute the value of sin∅ in the above identity

[tex](\frac{5}{13} )^{2} + cos^{2}[/tex]∅  =1

⇒ [tex]\frac{25}{69} +cos^{2}[/tex]∅  =1

⇒ [tex]cos^{2}[/tex]∅ = 1 - [tex]\frac{25}{169}[/tex]

⇒ [tex]cos^{2}[/tex]∅ = [tex]\frac{169-25}{69} =\frac{144}{169}[/tex]

⇒[tex]cos[/tex]∅ = [tex]\sqrt{\frac{144}{169} }[/tex]

⇒cos∅ = ±[tex]\frac{12}{13}[/tex]

Since, ∅ is in quadrant II, then cos<0

⇒ cos∅ = -[tex]\frac{12}{13}[/tex]

Hence, option B is correct.

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Answer: 1,120 frogs

Step-by-step explanation:

If 12 out of every 180 frogs in the population have spots on their backs, the number that do not are;

= 180 - 12

= 168 frogs

168 frogs out of every 180 do not have spots. Out of 1,200 that would be;

= 168/180 * 1,200

= 1,120 frogs

Answer:

A.In Nuuk, Greenland, in January, the average high-temperature is -4.6°C (23.7°F), and the average low-temperature is -10°C (14°F).

B. the average high-temperature is 5.7 degrees celsius and average low temperature is 3.3 degrees celsius

C. 4 degrees celsius

D. 39 degrees fahrenheit

E. Isla Hoste in august

F.On the average, the average low in January for Nuuk is 10/3 or 3.333 times farther below the freezing point of water than the average low for Isla Hoste in August.

Step-by-step explanation:

Hope this helps OwO

a) The average high and low temperatures are -8°C and -27°C.  b) The average high and low temperatures are 13°C and  7°C. c) The average net change in temperature is -19°C.  d) The average net change in temperature is 6°C.  e) Nuuk in January experiences a larger absolute change.  f) The January low for Nuuk is 3.8 times farther below the freezing point of water than the August low for Isla Hoste.

Part A

The average high temperature in Nuuk in January is -8°C and the average low temperature is -27°C.

Part B

The average high temperature in Isla Hoste in August is 13°C and the average low temperature is 7°C.

Part C

The average net change in temperature in Nuuk in January is -27°C - (-8°C) = -19°C.

Part D

The average net change in temperature in Isla Hoste in August is 13°C - 7°C = 6°C.

Part E

Nuuk in January experiences a larger absolute change between the high temperature and low temperature, with a net change of -19°C, compared to Isla Hoste in August, with a net change of 6°C.

Part F

The January low for Nuuk is -27°C, which is 27°C below the freezing point of water. The August low for Isla Hoste is 7°C, which is 7°C below the freezing point of water. Therefore, the January low for Nuuk is 27 / 7 = 3.8 times farther below the freezing point of water than the August low for Isla Hoste.

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Answer:

The formula f(t) will be:

[tex]\:f\left(t\right)=2150\left(0.962\right)^t[/tex]              

Step-by-step explanation:

We know that exponential decline in Maths can be termed as a consistent reduction of an amount by percentage over a certain period of time.

It can be expressed using the formula

[tex]f\left(t\right)=\:a\:\left(1-b\right)^t[/tex]

here

f(t) represents the final amount

a represents the original amount

b represents the decay factor

t represents the amount that has passed

Now, map our problem using the same concept formula

as

2150 members are at the beginning, so

a = 2150  

as the size of the population has been experiencing an annual decline of 3.8%. so

b = 3.8%= 0.038

so substituting b = 0.038 and a = 2150  

[tex]P=f\left(t\right)=\:a\:\left(1-b\right)^t[/tex]

[tex]\:f\left(t\right)=2150\left(1-0.038\right)^t[/tex]

[tex]\:f\left(t\right)=2150\left(0.962\right)^t[/tex]

Therefore, the formula f(t) will be:

[tex]\:f\left(t\right)=2150\left(0.962\right)^t[/tex]              

Answer:

Transitive property of segment congruence

Step-by-step explanation:

The reflexive, symmetric, and transitive properties are the criterion for an equivalence relation. In terms of congruence,

In terms of general equivalence relations,

That's the transitive property.

The fact that congruence is transitive means exactly what you have written: if A is congruent to B and B is congruent to C, then you can "bridge" from A to C.

Answer:

x - 10y = -59

(+)-4x + 10y = 86

-3x = 27

x = -9

substitute x into x - 10y = -59

-9 -10y = -59

-10y = -50

y = 5

Answer:

sorry bruv wish you the best i will pray for you

Step-by-step explanation:

Answer:

k = 0.25t^2

Step-by-step explanation:

Given the equation :

b = 0.25t

b = number of inches that has burned away

t = time

From our knowledge of variation;

Since candle length will decrease with time ;

b α 1/ t

b = k/t

Where k is the proportionality constant

Comparing the equation :

b = 0.25t

k/t = 0.25t

k = 0.25t^2

Answer:

In the slope-intercept form you use the slope of the line and the y-intercept to express the linear function. ... y=mx+b. Where m is the slope and b is the y-intercept.

Step-by-step explanation: I hope this helps

Answer:

y=mx + b

Step-by-step explanation:

Answer:

14z-9

Step-by-step explanation:

[tex]\frac{84z-54}{6}[/tex]

Answer:

95

Step-by-step explanation:

The equation is

x×2=285-x

3x=285

x=95

Answer:

x = 75°

Step-by-step explanation:

There are many Circle Geometry Rules. We will be using the following:

The angle at the centre of the circle is twice the angle at the circumference.

x = the angle opposite 285 - x.

This means that 360 - (285 - x) = 2x

360 - 285 + x = 2x

75 + x = 2x

We can simplify this by taking away x from both sides.

75 = x

We can check this by substituting x into the orginal equation.

360 - (285 - x) = 2x

360 - (285 - 75) = 2 * 75

360 - 210 = 2 * 75

150 = 2*75

150 = 150

Answer:

x=-2, 2.

Step-by-step explanation:

5x^2-20=0

factor out the 5

5(x^2-4)=0

5(x+2)(x-2)=0

(x+2)(x-2)=0/5

(x+2)(x-2)=0

x+2=0, x-2=0

x=0-2=-2,

x=0+2=2.

Answer:

x = 1.73

y = 2.45

z = 1.41

Step-by-step explanation:

1/z = z/2

z^2 = 2

z = sqrt(2)

1^2 + z^2 = x^2

1 + 2 = x^2

x^2 = 3

x = sqrt(3)

z^2 + 2^2 = y^2

2 + 4 = y^2

y^2 = 6

y = sqrt(6)

x = 1.73

y = 2.45

z = 1.41

Answer:

1/2

Step-by-step explanation:

Given that,

[tex]\lim_{n \to 1} (\dfrac{1+\cos\pi x}{\tan^2\pi x})[/tex]

Using L Hospital's rule to find it :

[tex]\lim_{n \to a} \dfrac{f(x)}{g(x)}= \lim_{n \to a} \dfrac{f'(x)}{g'(x)}[/tex]

We have,

a = 1, [tex]f(x)=1+\cos\pi x, \ \ g(x)=\tan^2\pi x[/tex]

[tex]f'(x)=\dfrac{d}{dx}(1+\cos\pi x)\\\\=-\pi \sin \pi x\ .....(1)[/tex]

[tex]g'(x)=\dfrac{d}{dx}(\tan^2\pi x)\\\\=2\tan\pi x\times \sec^2\pi x\times \pi\ .....(2)[/tex]

From equation (1) and (2) :

[tex]\lim_{n \to 1} \dfrac{f(x)}{g(x)}= \lim_{n \to 1} \dfrac{-\pi \sin\pi x}{2\tan \pi x\times \sec^2\pi x \times \pi}\\\\\lim_{n \to 1} \dfrac{-\pi \sin\pi x}{2\tan \pi x\times \sec^2\pi x \times \pi}\\\\=\lim_{n \to 1} \dfrac{-1}{2}\times\cos^3\pi x\\\\=\dfrac{-1}{2}\times \cos^3\pi \\\\=\dfrac{1}{2}[/tex]

So, the value of the given function is 1/2.