what is the equation between aqueous sodium carbonate and dilute hydrochloric acid​

Answers

Answer 1

Answer:

When solutions of sodium carbonate and hydrochloric acid are mixed, the equation for the hypothetical double displacement reaction is: Na2CO3 + 2 HCl → 2 NaCl + H2CO3 Bubbles of a colorless gas are evolved when these solutions are mixed.


Related Questions

Give the theoretical yield, in moles, of CO2 from the reaction of 1.45 moles of C8H18 with 1.45 moles of O2.

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

Answers

Answer:

vuvbuvivovoivuighhghgig

What volcano poses a threat on Sicily

Answers

Answer:

Mount Etna I believe

Explanation:

Mount Etna poses a threat

Which substance will form a solution when mixed with solid sodium chloride?
A. Cl2(g)
B. NaO2(s)
C. CCI4(I)
D. CH3OH(i)

Answers

Answer:

NaO2

Explanation:

Solutions are mixtures that are homogenous and comprise solutes and solvents. Methyl alcohol will react with solid sodium chloride to form a solution. Thus, option D is correct.

What are the solutions?

The solutions are the mixtures of the solute and the solvent. The solute and the solvent are capable of forming a solution only if they both are either polar or nonpolar.

Here, chlorine is a gas, and sodium superoxide is a solid that cannot react with solid sodium chloride to make a solution and hence is eliminated. As sodium chloride is polar it cannot react with nonpolar carbon tetrachloride.

Methyl alcohol is polar and so is sodium chloride. They will react together as,

CH₃OH + NaCl → CH₃Cl + NaOH

Therefore, option D. CH₃OH will react to form a solution.

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What number will go in the _?_ below to balance the equation?

3Gr3V2 + O3 --> 3GrO + __?__V

Question 1 options:
A. 1
B. 2
C. 3
D. 4
E. 5
F. 6
G. 9

Answers

Answer:

Option F 6 will be the answer.

How many grams are in 7.32 x 1023 molecules of potassium carbonate (K2CO3)?

Answers

(I leave off the x10^23 because they both will divide out)    Use your per

During which changes of state do atoms that connot move past one another becomes free to move?

a. Vaporization and sublimation
b. boiling and deposition
c. sublimation and melting
d. condensation and melting​

Answers

Answer:

c. sublimation and melting

Hope it helps...

Have a great day : )

Answer:

Option C is your answer

C. sublimation and melting

Explanation:

hope it helps u ^_^

have a great day/night

The diameter of a red blood cell is about 3 × 10−4 in. What is its diameter in centimeters?

Answers

Answer:

1 in. =2.54 cm

3*(10^-4)*2.54=7.62*10^-4

Explanation:

7.62 • 10^ -4 explanation in photo

_Na+ Cl2 - -> _NaCl

A 2,4
B 1,2
C 3,3
D 2,2

Answers

Answer:

D 2,2

Explanation:

We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side

Now we have Na + Cl2 --> 2NaCl

The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side

2Na + Cl2 --> 2NaCl

Now it's balanced!

Name 2 diatomic molecules.

Answers

Hydrogen, Nitrogen, Flourine, Oxygen, Iodine, Chlorine, Iodine, and Bromine.
That’s more than 2 hopes this answers your question

When gases are treated as real, via use of the van der Waals equation, the actual volume occupied by gas molecules ________ the pressure exerted and the attractive forces between gas molecules ________ the pressure exerted, as compared to an ideal gas.
decreases, increases
does not affect, decreases
increases, decreases
does not affect, increases
increases, increases

Answers

Answer:

Increases, decreases

Explanation:

Benzoic acid is a white crystalline powder used as a food preservative the compound contains 68.8% carbon, 5.0% hydrogen and 26.2% oxygen by mass what is the empirical formula

Answers

So in this task first I think you should use the formula of the: Density/percentage

68.8% divided 26.2%= 2.625954198473282

2.625954198473282 X =

13.12977099236641

Which of the following do omnivores eat?
A. only
B. plants and meat
C. meat only
D. they make their own food

Answers

Answer:

(B. Plants and meat)

Explanation:

B. plants and meat. Omnivores eat plants and meat.

Weather is caused by the:
mesosphere
stratosphere
troposphere
thermosphere
I WILL MARK BRAINLIST

Answers

the troposphere is the area where most sheathed occurs.

What is 72.9 g HCI into moles

Answers

1.9993999057621666 moles
1 mole = 36.46094
1.99999999999 that the answer

The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 18.2 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

Answers

Answer: 12.1 ml of ethanol is needed

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} CO_2=\frac{18.2g}{44g/mol}=0.414moles[/tex]  

[tex]C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)[/tex]  

According to stoichiometry :

2 moles of [tex]CO_2[/tex] is produced by = 1 mole of [tex]C_2H_5OH[/tex]

Thus 0.414 moles of [tex]CO_2[/tex] is produced by=[tex]\frac{1}{2}\times 0.414=0.207moles[/tex]  of [tex]C_2H_5OH[/tex]

 Mass of [tex]C_2H_5OH=moles\times {\text {Molar mass}}=0.207moles\times 46.07g/mol=9.54g[/tex]

Volume of ethanol = [tex]\frac{\text {Mass of ethanol}}{\text {density of ethanol}}=\frac{9.54g}{0.789g/ml}=12.1ml[/tex]

12.1 ml of ethanol is needed to produce 18.2 g of [tex]CO_2[/tex]

Which yield comes from measurements obtained during a real experiment?

A) actual yield
B) theoretical yield
C) percent yield

Answers

Answer:

A) actual yield

Explanation:

Theoretical yield is the amount of product expected based on the stoichiomety.

Percent yield is the actual yield over the theoretical yield.

What is the mass in grams of 1.00 x 10^12 lead (Pb)
atoms?

Answers

Answer:

3.44 × 10⁻¹⁰ g Pb

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 1.00 × 10¹² atoms Pb

[Solve] grams Pb

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Pb - 207.2 g/mol

Step 3: Convert

[DA] Set up:                                                                                                     [tex]\displaystyle 1.00 \cdot 10^{12} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})(\frac{207.2 \ g \ Pb}{1 \ mol \ Pb})[/tex][DA] Multiply/Divide [Cancel out units]:                                                         [tex]\displaystyle 3.44072 \cdot 10^{-10} \ g \ Pb[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.44072 × 10⁻¹⁰ g Pb ≈ 3.44 × 10⁻¹⁰ g Pb

Answer:

[tex]\boxed {\boxed {\sf 3.44 *10^{-10} \ g \ Pb}}[/tex]

Explanation:

1. Atoms to Moles

Use Avogadro's Number to convert atoms to moles. This number: 6.022*10²³, tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of lead.

[tex]\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]

Multiply by the given number of atoms.

[tex]1.00 *10^{12} \ atoms \ Pb *\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]

Flip the fraction so the atoms of lead cancel.

[tex]1.00 *10^{12} \ atoms \ Pb *\frac {1 \ mol \ Pb}{6.022*10^{23} \ atoms \ Pb}[/tex]

[tex]1.00 *10^{12}*\frac {1 \ mol \ Pb}{6.022*10^{23}}[/tex]

[tex]\frac {1.00 *10^{12}\ mol \ Pb}{6.022*10^{23}} = 1.66057788*10^{-12} \ mol \ Pb[/tex]

2. Moles to Grams

Use the molar mass to convert moles to grams. This can be found on the Periodic Table. For lead it is 207.2 grams per mole.

[tex]\frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]

Multiply by the number of moles we calculated.

[tex]1.66057788*10^{-12} \ mol \ Pb* \frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]

[tex]1.66057788*10^{-12}* \frac {207.2 \ g\ Pb}{ 1 }[/tex]

[tex]1.66057788*10^{-12}* {207.2 \ g\ Pb}= 3.44071737*10^{-10} \ g \ Pb[/tex]

3. Round

The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, it is the hundredth place. The 0 in the thousandth place tells us to leave the 4.

[tex]3.44 *10^{-10} \ g \ Pb[/tex]

Which bonds form in the reaction shown in the diagram? 2 2H, + 0 H-H O=0 H-H → 2H 0 H-0-H H-OH A. The bonds between the two hydrogen atoms and between the two oxygen atoms B. The bonds between the two hydrogen atoms C. The bonds between the oxygen and hydrogen atoms D. The bonds between the two oxygen atoms​

Answers

The water molecule is formed by the covalent bonding between oxygen and hydrogen atoms. Therefore, option C is correct.

What is covalent bonding ?

Covalent bonding is a type of chemical bonding that involves the sharing of electrons between two atoms. In covalent bonding, the two atoms share a pair of electrons to fill their outermost electron shell and form a stable molecule.

This type of bonding usually occurs between non-metal atoms, which have a high electronegativity and tend to attract electrons strongly. In a covalent bond, the shared electrons are attracted to the positively charged nuclei of both atoms, creating a strong bond.

The strength of the bond depends on the number of shared electrons and the distance between the nuclei. Covalent bonds can be either polar or nonpolar, depending on the electronegativity difference between the two atoms.

In water the bond is formed between oxygen atom and two hydrogen atoms. Hence, C is correct.

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Chemical formula of copper (II) nitrate

Answers

It would be Cu(NO3)2. The NO3 has a negative charge. Copper has a positive 2. In order to have a stable compound, you would need 2 NO3s, which is why there is a 2 outside of the NO3. I hope this helps.

What is occurring with the velocity between points D and E?
A velocity is decreasing
B. velocity is increasing
C. velocity is constant
D. velocity is zero

Answers

Answer:

a

Explanation:

the line is going down

To determine the highest angle the pendulum will swing to after the impact, we can apply the principle of conservation of momentum. Initially, the total momentum is zero since the pendulum is at rest.

After the impact, the total momentum remains zero because the block and embedded projectile move together as a single system.First, let's convert the weight units to a common system. The 5-pound rod is approximately 2.27 kg, and the 10-pound wooden block is around 4.54 kg. The projectile's weight is 0.3 oz, which is about 0.0085 kg.The momentum before the impact is zero, so the momentum after the impact must also be zero. This can be expressed as:(2.27 kg + 4.54 kg + 0.0085 kg) * V_final = 0Solving for V_final gives us V_final ≈ 0 ft/s. Since the velocity is zero after the impact, the pendulum will momentarily stop at its highest point.Therefore, the highest angle the pendulum will swing to after the impact is 0 degrees, or it will come to rest at the vertical position.

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Which of the following a true statement about igneous rocks?

A: Igneous rocks are only formed under a lot of heat and pressure. Some igneous rocks are formed below the surface others in oceans.

B: The properties of igneous rocks depend on the location in which they are formed.

C: Wind and water erosion can create igneous rocks.​

Answers

Answer:

i think the answer is A....

Explanation:

Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface.

Consider the following reaction:

Fe3+(aq) + SCN-(aq) ↔︎ [Fe(SCN)]2-(aq)

1)Explain what is meant by the term dynamic equilibrium.

2) Write the equilibrium expression for the reaction.

3) The numerical value of Kc at 298K is about 1000 for the reaction. What does this tell you about the position of the equilibrium at 298K?

Answers

Answer: In 1860s, Norwegian scientists C. M. Guldberg and P. Waage noted a peculiar relationship between the amounts of reactants and products in an equilibrium. Today, we call this observation the law of mass action. It relates the amounts of reactants and products at equilibrium for a chemical reaction. For a general chemical reaction occurring in solution, aA + bB ⇄ cC + dD the equilibrium constant, also known as Keq, is defined by the following expression: Keq = [C]c/[D]d where [A] is the molar concentration of species A at equilibrium, and so forth. The coefficients a, b, c, and d in the chemical equation become exponents in the expression for Keq. The Keq is a characteristic numerical value for a given reaction at a given temperature. That is, each chemical reaction has its own characteristic Keq. The concentration of each reactant and product in a chemical reaction at equilibrium is related; the concentrations cannot be random values, but they depend on each other. The numerator of the expression for Keq has the concentrations of every product (however many products there are), while the denominator of the expression for Keq has the concentrations of every reactant, leading to the common products over reactants definition for the Keq. Let us consider a simple example. Suppose we have this equilibrium: A ⇄ B .There is one reactant, one product, and the coefficients on each are just 1. The Keq expression for this equilibrium is Keq = [B]/[A]. Exponents of 1 on each concentration are understood. Suppose the numerical value of Keq for this chemical reaction is 2.0. If [B] = 4.0 M, then [A] must equal 2.0 M so that the value of the fraction equals 2.0: Keq = [B]/[A] = 4.0/2.0 =2.0 .By convention, the units are understood to be M and are omitted from the Keq expression. Suppose [B] were 6.0 M. For the Keq value to remain constant (it is, after all, called the equilibrium constant), then [A] would have to be 3.0 M at equilibrium: Keq = [B]/[A] = 60/3.0= 2.0 .If [A] were not equal to 3.0 M, the reaction would not be at equilibrium, and a net reaction would occur until that ratio was indeed 2.0. At that point, the reaction is at equilibrium, and any net change would cease. However, that the forward and reverse reactions do not stop because chemical equilibrium is dynamic.

You dissolve 0.47 g of potassium chloride (KCl) in 700 ml of water.
What is the molarity of the solution?
(From the periodic table: 1 mol K = 39.10 g; 1 mol Cl = 35.453 g)
Enter the value rounded to three decimal places with no units
Will give BRAINLEst

Answers

Answer:

0.009

Explanation:

Molarity, a measure of molar concentration of a substance is calculated thus;

Molarity = number of moles ÷ volume

According to the provided information, mass of KCl = 0.47g, volume of water = 700ml

Using mole = mass/molar mass

Molar Mass of KCl = 39.10 + 35.453

= 74.553g/mol

Mole = 0.47/74.55

Mole = 0.0063mol

Volume of water = 700ml = 700/1000 = 0.7L

Molarity = 0.006/0.7

Molarity = 0.00857

The value of molarity rounded to three decimal places (3 d.p) = 0.009

Given the following chemical reaction equation:

3 Mg (s) + Al2O3 (s)------> 3 MgO (s) + 2 Al (s)
and 144g of MG and 150g of Al2O3 are reacted.

which chemical compound is the limiting reactant compound?

Answers

Answer:

Al₂O₃ is the limiting reactant

Explanation:

The limiting reagent or limiting reactant in a chemical reaction is a reactant that is totally used up when the chemical reaction is completed and subsequently, the reaction stops as no more products can be formed from the excess reactant.

Equation of the the reaction reaction is given below:

3 Mg (s) + Al₂O₃ (s) ----> 3 MgO (s) + 2 Al (s)

Mole ratio of reactants from the equation shows that 3 moles of magnesium metal is required to react with 1 mole of aluminum oxide.

Molar mass of magnesium metal, Mg = 24 g/mol

Molar mass of aluminum oxide, Al₂O₃ = (27 * 2 + 16 * 3) = 102 g/mol

from the equation of reaction,  (24 * 3 g) 72 g of Mg reacts with 102 g of Al₂O₃

Given masses of reactants:

144 g of Mg = 144/24 6 moles of Mg

150 g of Al₂O₃ = 1.47 moles of Al₂O₃

Mole ratio of Mg to Al₂O₃ = 6/1.47 = 4.08 : 1

Therefore, magnesium is excess reactant while Al₂O₃ is the limiting reactant

I just need my answers checked please be quick ​

Answers

Answer:

they are all right

Explanation:


Post-Lecture Assignment Chapter 06
Animation-Changes of State
< 1 of 23 >
When a solid is placed in a container and heat is applied, a phase change occurs. Watch the video and sort the parts of the curve based on whether the average energy of the molecules is changing, or is constant.
View Available Hint(s)
Reset Help
The liquid is heated at the boiling point
The solid is heated at the melting
point
The liquid is heated to reach the
boiling point
The solid is heated to reach the
melting point
Average molecule energy change
Average molecule energy constant
Submit

Answers

Answer:

Can you send an image of the question, please?

Explanation:

Given the decomposition of hydrogen peroxide, calculate the moles of oxygen gas produced from 4.20 mol of H2O2.
2H2O2(l)→2H2O(l)+O2(g)

Answers

Answer:

2.10 moles of O₂

Explanation:

2 H₂O₂ (l) → 2H₂O(l)  + O₂(g)

In this reaction we say, that 2 moles of hydrogen peroxide can decompose to 2 moles of water and 1 mol of oyxgen.

So ratio is 2:1, according to stoichiometry.

If we apply a rule of three;

2 moles of hydrogen peroxide can decompose to 1 mol of oxygen

Then 4.20 moles of hydrogen peroxide may produced (4.20 . 1)/2 =

2.10 moles of O₂

Can y’all help me with this question

Answers

Answer:

owa owa

Explanation:

owa owa owa owa owa ow


3. Calculate the energy in joules) of a photon with a wavelength of 3.66 X 104 hm (Infrared region) (Hint: Use Planck's equation)
104.3 x 10")
104.3 x 10-21,
1.043 X 1033
5.43 x 10 21

Answers

Answer:

5.43×10¯³² J

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.66×10⁴ hm

Energy (E) =?

Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:

1 hm = 100 m

Therefore,

3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm

3.66×10⁴ hm = 3.66×10⁶ m

Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:

Wavelength (λ) = 3.66×10⁶ m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3.66×10⁶ × f

Divide both side by 3.66×10⁶

f = 3×10⁸ / 3.66×10⁶

f = 81.97 Hz

Finally, we shall determine the energy of the photon. This can be obtained as follow:

Frequency (f) = 81.97 Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 81.97

E = 5.43×10¯³² J

Therefore, the energy of the photon is 5.43×10¯³² J

How many moles of F are in 8.25 grams of F?

Answers

Answer:

0.434 mol F

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TablesMoles

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 8.25 g F

[Solve] moles F

Step 2: Identify Conversions

[PT] Molar Mass of F - 19.00 g/mol

Step 3: Convert

[DA] Set up:                                                                                                      [tex]\displaystyle 8.25 \ g \ F(\frac{1 \ mol \ F}{19.00 \ g \ F})[/tex][DA] Multiply [Cancel out units]:                                                                    [tex]\displaystyle 0.434211 \ mol \ F[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.434211 mol F ≈ 0.434 mol F

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