What is the distance from Point A to Point B? Round your answer to the nearest tenth if necessary.

(Hint: sketch a right triangle and use the Pythagorean theorem.)

A coordinate is (4,6)
B coordinate is (5,-5)

The method "fibmemo" is a recursive method that calculates the nth Fibonacci number using the top-down strategy. To implement this method, you will need to create a recursive helper method that stores previously calculated fibonacci numbers using an array called "memo".

Here's how the helper method can be implemented:

private static long fibHelper(int n, long[] memo) {
 if (n == 0 || n == 1) {
   return n;
 } else if (memo[n] != 0) {
   return memo[n];
 } else {
   memo[n] = fibHelper(n-1, memo) + fibHelper(n-2, memo);
   return memo[n];
 }
}

In this method, we first check if n is equal to 0 or 1, in which case we return n itself. If the nth Fibonacci number has already been calculated and stored in the memo array, we return that value directly. Otherwise, we calculate the nth fibonacci number by recursively calling the helper method for (n-1) and (n-2), and add the results. We then store the calculated value in the memo array for future use.

Now we can use this helper method to implement the "fibmemo" method:

public static long fibmemo(int n) {
 long[] memo = new long[n+1];
 return fibHelper(n, memo);
}

In this method, we create an array called "memo" that can store previously calculated fibonacci numbers up to the nth fibonacci number. We then call the helper method with the input n and the memo array, which will recursively calculate the nth fibonacci number using the top-down strategy and return the result.

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Answer:

To yield more accurate results, we could increase the number of simulation runs, use more random numbers, or use a more sophisticated simulation method such as Monte Carlo simulation.

Step-by-step explanation:

a. To simulate the rental and location of a truck for a 20-week period, we can use the given transition matrix and the discrete random variable generator for each city. Starting with a truck in Broken Bow, we can generate random numbers using the table given and move the truck to the corresponding return city based on the probabilities in the transition matrix. The results of the simulation experiment are shown in the table below.

Week Return City Pickup City

Broken Bow r

1 Goodland Goodland

2 Goodland Goodland

3 Goodland Broken Bow

4 Amarillo Goodland

5 Amarillo Amarillo

6 Goodland Enid

7 Amarillo Goodland

8 Goodland Goodland

9 Goodland Topeka

10 Amarillo Goodland

11 Goodland Enid

12 Goodland Goodland

13 Amarillo Goodland

14 Goodland Goodland

15 Goodland Goodland

16 Goodland Enid

17 Topeka Goodland

18 Amarillo Goodland

19 Goodland Goodland

20 Goodland Goodland

b. From the simulation experiment, we can determine the percentage of time a truck will be returned in each city by counting the number of times the truck is returned to each city and dividing by the total number of returns. The results are shown in the table below.

Number of Returns % Returned City

Enid 0 0%

Topeka 1 5%

Broken Bow 15 75%

Goodland 3 15%

Amarillo 1 5%

Total 20 100%

c. To yield more accurate results, we could increase the number of simulation runs, use more random numbers, or use a more sophisticated simulation method such as Monte Carlo simulation.

Additionally, we could gather data on the actual rental and return patterns of the trucks and use that information to adjust the transition matrix and improve the accuracy of the simulation.

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The measures of the angles and the proofs are shown below

Circle 4

The angle at the centre is twice the angle at the circumference

So, we have

360 - ∠BOD = 2 * 110

Evaluate

∠BOD = 140

Circle 5

Angle in a semicircle is 90 degrees

So, we have

∠ABD + 19 = 90

∠ABD = 71

Angles in the same segment are equal

So, we have

∠ACB = 19

Circle 6

Angle in a semicircle is 90 degrees

So, we have

5y + y = 90

y = 15

So, we have

∠BAC = 5 * 15

∠BAC = 75

Circle 7

By corresponding angle theorem, we have

∠ABO = ∠CDO

By the sum of opposite internal angles in a triangle, we have

∠BOC = ∠BAO + ∠ABO

Substitute ∠ABO = ∠CDO

∠BOC = ∠BAO + ∠CDO --- proved

The angles at the edges are equal because they are corresponding angles of congruent isosceles triangles

Cyclic Quadrilateral

The opposite angles of cyclic quadrilaterals add up to 180 degrees

So, we have

180 - ∠x + 180 - ∠y = 180

Evaluate

∠x + ∠y = 180 --- proved

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Answer:

Decreasing by 10

Step-by-step explanation:

I'm pretty sure it's decreasing by 10s, so 301, 291, 281, 271, 261, 251, 241, 231, 221, 211, 201, 191, 181, 171, 161, 151, 141, 131, 121, 111, 101, 91

The x-intercept and the y-intercept of the function

1.(8, 6)

2. (4.5, 6)

We have,

1. f(x) = -3/4x + 6

2. f(x) = -4/3x + 6

So, to find x intercept put f(x)= 0

1. 0 = -3/4x + 6

-6 = -3/4x

x = 24/3

x= 8

2. 0= -4/3x + 6

-4/3x = -6

x= 18/4

x= 4.5

Now, to find y intercept put x = 0

1. f(x) = -3/4(0)+6 =

2. f(x) = -4/3(0) +6 = 6

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The original price of the hammock, when rounded to the nearest penny, can be found to be $ 102.67.

To determine the initial amount of the hammock, we must consider its price prior to the 25% sale that Ronald bought it for $77. Let us denote the original price as P. If we deduct 25% from the original price, then the new cost is equivalent to 75% of its total value (100% - 25% = 75%).

Thus, we can represent this calculation as:

Sales price = 0. 75 x P

77 = 0. 75P

P = 77 / 0. 75

P = $ 102. 67

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Answer:

v = (30 * b * c * sqrt(d))/sqrt(0.72)

Step-by-step explanation:

The minimum speed of the car when entering into the skid can be determined using the following expression:

v = (30 * b * c * sqrt(d))/sqrt(0.72)

where:

Note that the expression assumes that the car leaves four equally long skid marks, which is a common approximation used in accident reconstruction. Also, the expression is based on the formula for calculating speed from skid marks, which takes into account the drag factor of the road surface, the braking efficiency of the car, and the length of the skid marks.

The radius of the cylinder is 10 centimetres according to stated dimensions of the cylinder.

The volume of the cylinder is given by the formula-

Volume = πr²h, where r refers to radius of the circle. Keep the values in formula to find the value of radius of the cylinder

1600π = πr²×16

Cancelling π and 16 common on both sides of the equation.

r² = 100

r = ✓100

Taking square root on Right Hand Side of the equation to find the radius of the cylinder

r = 10 centimetres

Hence the radius is 10 centimetres.

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Answer: 17.2

Step-by-step explanation:

Mean means average, add all of the numbers and divide by how many there are.

mean = (11+17+21+14+23)/5

=17.2

A match of the items have been creating in the space below to fit in with the best decription that it should have as its definition

The list with the matched descriptions is as follows:

When something is bi, this means it has 2 sides to it

Quarterly indicates four

thrice or Tricycle has to do with wheels been three

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To implement the Boolean expression F(x,y,z) = xyz + (y′ + z) using a combinational circuit, we can use two AND gates and one OR gate.

To draw the combinational circuit that directly implements the Boolean expression F(x, y, z) = xyz + (y′ + z), follow these steps:
1. Identify the individual terms in the expression: xyz and (y′ + z).
2. Draw an AND gate for the term xyz:
  - Connect the input lines of the AND gate to x, y, and z.
3. Draw an OR gate for the term (y′ + z):
  - To obtain y′, connect an input line from y to a NOT gate.
  - Connect the output of the NOT gate and an input line from z to the input of the OR gate.
4. Combine the results from steps 2 and 3 with an OR gate:
  - Connect the outputs of the AND gate and the OR gate from steps 2 and 3 to the input lines of a final OR gate.
5. The output of the final OR gate is the function F(x, y, z).
In summary, the combinational circuit consists of 1 AND gate, 2 OR gates, and 1 NOT gate arranged as described above to directly implement the given Boolean expression.

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The direct method of Lyapunov is a technique used in the analysis of the stability of a dynamical system. It involves the use of a Lyapunov function to determine whether a system is stable or not.

A Lyapunov function is a scalar function V(x) that is defined on the state space of a dynamical system, where x is the state of the system. The function is chosen such that it is positive definite, i.e., V(x) > 0 for all x except possibly at the origin, where V(x) = 0. The time derivative of the Lyapunov function along the trajectories of the system, denoted by V'(x), is also chosen to be negative definite or negative semi-definite, i.e., V'(x) < 0 or V'(x) ≤ 0 for all x except possibly at the origin.

The direct method of Lyapunov uses this Lyapunov function to determine the stability of the system. If a Lyapunov function can be found that satisfies the above conditions, then the system is said to be stable or asymptotically stable, depending on whether V'(x) is negative definite or negative semi-definite, respectively. If a Lyapunov function cannot be found, then the stability of the system cannot be determined using this method.

In addition to determining stability, the direct method of Lyapunov can also be used to determine instability. If a Lyapunov function can be found that satisfies the above conditions, but with V'(x) positive definite or positive semi-definite instead of negative definite or negative semi-definite, respectively, then the system is unstable.

Overall, the direct method of Lyapunov provides a powerful tool for analyzing the stability of a wide range of dynamical systems, including linear and nonlinear systems, time-invariant and time-varying systems, and continuous and discrete-time systems.

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The integration of the expression is x⁴ ln (2x + 3) + C.

option B.

The integration of the expression is calculated as follows;

The given expression is written as;

∫ (4x³/(2x + 3) dx

So we can integrate the numerator as;

4x³ = (4x³⁺¹)/4 = x⁴

We can also integrate the denominator as;

1/(2x + 3) dx = ln (2x + 3)

After both integrations, we can add constant of integration, "C"

So the final integrand of the expression is written as;

∫ (4x³/(2x + 3) dx =  x⁴ ln (2x + 3) + C

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The coordinates of the image of the triangle RST following a dilation by a with the origin as the center of dilation and a scale factor of 4 are;

A. R'(4, 12), S'(12, 12), T'(8, 4)

A dilation transformation is a transformation in which the image dimensions are obtained by resizing the dimensions of the pre-image using a scale factor.

The vertices of the triangle RST are; R(1, 3), S(3, 3), and T(2, 1)

The coordinates of the image of the point (x, y) following a dilation by a scale factor of a about the origin is; (a·x, a·y)

Therefore, the coordinates of the dilated image of the triangle RST after a dilation with the origin as the center of dilation and a scale factor of 4 are;

R(1, 3) ⇒ R'(4 × 1, 4 × 3) = R'(4, 12)

S(3, 3) ⇒ S'(4 × 3, 4 × 3) = S'(12, 12)

T(2, 1) ⇒ T'(4 × 2, 4 × 1) = T'(8, 4)

The correct option is therefore;

A. R'(4, 12), S'(12, 12), T'(8, 4)

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Answer:

A = (93.5/2^(2n)) After each fold, the area of the paper is halved.

Step-by-step explanation:

When the paper is folded in half, the length and width of the paper are each halved, which means that the area of the paper is also halved. If we continue to fold the paper in half, the area will continue to be halved with each fold.

To write an exponential function to find the area of the paper after each fold, we can use the formula for the area of a rectangle, A = lw, where A is the area, l is the length, and w is the width. Since the length and width are both halved with each fold, we can represent this as:

A = (8.5/2^n)(11/2^n)

where n is the number of folds. To simplify this, we can combine the terms under the same exponent and get:

Answer:

A(n) = 93.5 / 2^(2n-1)

Step-by-step explanation:

Each time the paper is folded in half, its length and width are halved. Therefore, the area of the paper is also halved after each fold.

Let A₀ be the initial area of the paper, which is 8.5 inches by 11 inches, or 93.5 square inches (rounded to one decimal place). After the first fold, the area becomes:

A₁ = (8.5/2) x 11 = 46.75 square inches

After the second fold, the area becomes:

A₂ = (8.5/2) x (11/2) = 23.375 square inches

And so on.

Therefore, the exponential function to find the area of the paper after each fold is:

A(n) = 93.5 / 2^(2n-1)

The correct statement is,

⇒ Analyze the data using graphing and numerical methods.

We have to given that;

To find Presenting your findings best fits for the statistical process.

Now, If you are looking at the spread of your data, you have already designed a question and collected the data.

And, You are at the point where you are ready to analyze the data.

Thus, The correct statement is,

⇒ Analyze the data using graphing and numerical methods.

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The measure of angle A is 38 degrees by angle sum property

Given that ∠B is 40 degrees

∠AEB is 102 degrees

Now let us find ∠A

By angle sum property the sum of three angles is 180 degrees in triangle

AEB is triangle

40+102+ ∠A=180

142+∠A=180

∠A=180 - 142

∠A= 38 degrees

Hence, the measure of angle A is 38 degrees.

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To determine which interval contains the root of f(x) = 2x - x3 + 2, we need to examine the behavior of the function around the x-axis.

First, we can find the critical points by setting f(x) = 0: 0 = 2x - x3 + 2
Rearranging, we get: x3 - 2x + 2 = 0

This is a cubic equation, which can be difficult to solve exactly. However, we can use the Intermediate Value Theorem to determine whether there is a root in a given interval.

One critical point is x ≈ -1.7693. We can test whether there is a root in the interval (-∞, -1.7693) by evaluating f(x) at a point in the interval, such as x = -2:

f(-2) = 2(-2) - (-2)3 + 2 = -12

Since f(-2) is negative and f(x) is a continuous function, there must be at least one root in the interval (-∞, -1.7693).

Another critical point is x ≈ 1.7693. We can test whether there is a root in the interval (1.7693, ∞) by evaluating f(x) at a point in the interval, such as x = 2: f(2) = 2(2) - 23 + 2 = 0.

Since f(2) is zero and f(x) is a continuous function, there must be at least one root in the interval (1.7693, ∞).

Therefore, the intervals that contain the root of f(x) = 2x - x3 + 2 are (-∞, -1.7693) and (1.7693, ∞).
To determine which interval contains the root of the function f(x) = 2x - x^3 + 2, we can follow these steps:

Step 1: Identify the intervals of interest. For this question, the intervals are not specified, so we will assume the intervals are (-∞, 0) and (0, ∞).

Step 2: Check the value of f(x) at the endpoints of each interval. In our case, we will check f(0) for both intervals. f(0) = 2(0) - (0)^3 + 2 = 2.

Since f(0) > 0, we know that there is a root between the intervals (-∞, 0) and (0, ∞) if there's a change of sign between the intervals.

Step 3: Check the sign of f(x) within each interval. Pick a representative point from each interval and evaluate f(x) at that point.

For the interval (-∞, 0), let's pick x = -1:

f(-1) = 2(-1) - (-1)^3 + 2 = -1
For the interval (0, ∞), let's pick x = 1:
f(1) = 2(1) - (1)^3 + 2 = 3

Step 4: Determine which interval contains the root based on the change of sign.

The function f(x) changes its sign from negative to positive as we move from the interval (-∞, 0) to the interval (0, ∞). Therefore, the interval that contains the root of the function f(x) = 2x - x^3 + 2 is (-∞, 0).

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Answer:

Height of helicopter above ground = 13.63 feet

Step-by-step explanation:

See attached image to support explanation

B is the point vertically below where the helicopter is located

s is the distance from Sofie to B

d is the distance from Danika to B

We have
s + d = 100 ==> s = 100 -d

h is the height of the helicopter from the base

Both triangles are right triangles

For a right triangle,
tan x = Side opposite hypotenuse/Side adjacent to hypotenuse
where x is the angle between the side adjacent to the hypotenuse

Using this information for both triangles we get

[tex]\tan 10 = \dfrac{h}{s}\\or\\h = s ( \tan 10)\\\\\tan 31 = \dfrac{h}{d}\\or\\h = d (\tan31)\\\\[/tex]

Therefore
s (tan 10) = d ( tan 31)

But s = 100 -d:
(100-d) tan 10 = d ( tan 31)

100(tan 10) - d(tan 10) = d (tan 31)

Switch sides:
d (tan 31) = 100 (tan 10) - d( tan 10)

Add d (tan 10) to both sides:
d (tan 31) + d ·(tan 10) = 100(tan 10)

d(tan 31 + tan 10) = 100 (tan 10)

[tex]d = \dfrac{100(\tan 10)}{\tan 31 + \tan 10}[/tex]

Using a calculator we can compute right side as

[tex]\dfrac{100(\tan 10)}{\tan 31 + \tan 10} = 22.6878[/tex]

So
d = 22.6878

Plug this value of d into h = d sin 31 to get
h = d (tan 31)

h = 22.688 (0.6009)

h = 13.6322....

= 13.63 rounded to 2 decimal places

Height of helicopter above ground = 13.63 feet

There are several potential sources of probability in this study that could affect the results.

Selection bias could occur if the 249 individuals chosen for the study were not representative of the larger population of obese individuals. For example, if the study only recruited participants from a certain geographic area or demographic group, the results may not be generalizable to other populations.

Measurement bias could occur if the methods used to measure BMI were inaccurate or inconsistent. If the measurements were taken in a non-standardized way, or if the same person was not consistently measuring BMI throughout the study, the results may not be reliable.

Attrition bias could occur if participants dropped out of the study at different rates depending on whether they received the new drug or a placebo. For example, if participants who experienced negative side effects from the new drug were more likely to drop out, the results may overestimate the drug's effectiveness.

Reporting bias could occur if participants in the study provided inaccurate or incomplete information about their weight or BMI. For example, if participants underreported their weight or failed to record their weight on certain days, the results may not be accurate.

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The first four non-zero terms of the Taylor series expansion of f(x)=e^x sin x, centered at c=0, are: f(x) = x + x^2/2 + x^3/3! + ...

To find the Taylor series expansion of f(x)=e^x sin x, we need to first find the Taylor series expansions of e^x and sin x centered at c=0.

The Taylor series expansion of e^x centered at c=0 is:

e^x = 1 + x + (x^2)/2! + (x^3)/3! + ...

And the Taylor series expansion of sin x centered at c=0 is:

sin x = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ...

To find the Taylor series expansion of f(x)=e^x sin x, we need to multiply these two series together. We can do this using the "r series" method, where we take the product of the first r terms of each series and then add up all the resulting terms.

So the first term of the series for f(x) is simply the product of the first term of each series:

f(x) = e^0 * sin(0) = 0

The second term is the sum of the product of the second term of the e^x series and the first term of the sin x series, and the product of the first term of the e^x series and the second term of the sin x series:

f(x) = e^0 * sin(x) + e^x * sin(0) = x

The third term is the sum of the product of the third term of the e^x series and the first term of the sin x series, the product of the second term of the e^x series and the second term of the sin x series, and the product of the first term of the e^x series and the third term of the sin x series:

f(x) = e^0 * sin(x) + e^x * sin(0) + (x^2)/2! * sin(x) = x + x^2/2

The fourth term is the sum of the product of the fourth term of the e^x series and the first term of the sin x series, the product of the third term of the e^x series and the second term of the sin x series, the product of the second term of the e^x series and the third term of the sin x series, and the product of the first term of the e^x series and the fourth term of the sin x series:

f(x) = e^0 * sin(x) + e^x * sin(0) + (x^2)/2! * sin(x) + (x^3)/3! * sin(0) = x + x^2/2 + x^3/3!

So the first four non-zero terms of the Taylor series expansion of f(x)=e^x sin x, centered at c=0, are:

f(x) = x + x^2/2 + x^3/3! + ...

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To find the center and radius of the sphere whose equation is given by x²+y²+z²+4x−2z−8=0, follow these steps:

Step 1: Rewrite the given equation in the standard form of a sphere.
The standard form of a sphere's equation is (x-a)²+(y-b)²+(z-c)²=r², where (a, b, c) is the center and r is the radius.

Step 2: Complete the squares for the x and z terms.
(x²+4x)+(y²)+(z²-2z)=8
(x+2)²-4+(y²)+(z-1)²-1=8

Step 3: Move the constants to the other side of the equation.
(x+2)²+(y²)+(z-1)²=13

Now the equation is in standard form. We can identify the center and radius. Step 4: Identify the center and radius.
The center (a, b, c) = (-2, 0, 1), and the radius r = √13. So, the center of the sphere is (-2, 0, 1), and the radius is √13.

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We cannot provide a complete solution as the values of the angles of elevation are missing in the problem statement.

tan(theta) = h/d (where theta is the first angle of elevation)

tan(theta + delta) = h/(d-1500) (where delta is the change in angle of elevation from the first observation point)

We can rewrite these equations as:

h = d*tan(theta)

h = (d-1500)*tan(theta + delta)

Setting the right-hand sides equal to each other, we get:

d*tan(theta) = (d-1500)*tan(theta + delta)

Expanding the right-hand side using the tangent addition formula, we get:

tan(theta) = dtan(theta) - 1500tan(theta) + 1500tan(delta)

Simplifying and solving for h, we get:

h = 1500*tan(delta) / (tan(theta) - tan(theta+delta))

Now we just need to plug in the values given in the problem:

theta =

delta =

d =

Then we can solve for h.

Note: We cannot provide a complete solution as the values of the angles of elevation are missing in the problem statement.

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The expected number of smokers in a random sample of 150 students from this university is 15.

To calculate the expected number of smokers in a random sample of 150 students at a university where 10% of students smoke, you simply multiply the total number of students in the sample by the percentage of students who smoke:
Expected number of smokers = Total number of students x Percentage of smokers
= 150 students x 10%
= 150 x 0.10
= 15
So, if we know that 10% of students smoke at this university, and we have a random sample of 150 students, we can calculate the expected number of smokers as follows:

Expected number of smokers = 150 x 0.10 = 15

Therefore, we can expect that there will be approximately 15 smokers in a random sample of 150 students from this university.


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The probability that a randomly selected person spent more than $23 is approximately 0.4332 or 43.32%.

To find the probability that a randomly selected person spent more than $23, we need to use the standard normal distribution formula:

Z = (X - μ) / σ

where X is the amount spent on a restaurant meal, μ is the mean amount spent, σ is the standard deviation, and Z is the corresponding standard normal random variable.

Substituting the given values, we have:

Z = (23 - 22) / 6
Z = 0.1667

Using a standard normal distribution table or calculator, we can find the probability that Z is greater than 0.1667, which is:

P(Z > 0.1667) = 0.4332

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In order to illustrate the position of a table lamp on a table, we can identify the table lamp as P and the table as a flat surface.

From the image attached, we select two edges of the table that  tends to intersect at a right angle to serve as the OX and OY axis.

Then one need to Determine the length 'a' cm from the lamp to the vertical line of reference OY. Determine the value of 'b' cm, which is the vertical distance between point P (lamp) and the OX axis.

Therefore, The table lamp P can be located using the coordinates of  (a,b).

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The coordinate of the triangle after the dilation is R'(4, 8), S (4,4). T(4, 8)

From the question, we have the following parameters that can be used in our computation:

R(1, 2), S (1,1). T(1, 2)

Scale factor = 4

The coordinate of the triangle after the dilation is calculated as

Image' = triangle * Scale factor

Substitute the known values in the above equation, so, we have the following representation

R(1, 2), S (1,1). T(1, 2) * 4

Evaluate

R'(4, 8), S (4,4). T(4, 8)

Hence, the image is R'(4, 8), S (4,4). T(4, 8)

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The coterminal angle is 330°, which lies in Quadrant fourth, with a reference angle of 258 degrees.

We have 588 ° between 0° ≤θ<360

Coterminal angle in [0, 360°) range is 330°, located in the fourth quadrant.

Then for the reference angle will be

588 -330= 258

Thus, the reference angle is 258°

Therefore, we can conclude that  coterminal angle is 330°, which lies in Quadrant fourth, with a reference angle of 258 degrees.

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The probability of flipping heads 6 times in a row with this weighted coin is approximately 0.0273, or 2.73%.

Since the coin is weighted such that heads come up twice as often as tails, let's assign probabilities to each outcome. We can represent this as P(H) = 2/3 (probability of heads) and P(T) = 1/3 (probability of tails).

Now, you want to find the probability of flipping heads 6 times in a row. In this case, we can use the multiplication rule of probability, which states that the probability of multiple independent events occurring is equal to the product of their individual probabilities.

For your scenario, the probability of getting 6 heads in a row is:

P(H₁ and H₂ and H₃ and H₄ and H₅ and H₆) = P(H₁) × P(H₂) × P(H₃) × P(H₄) × P(H₅) × P(H₆)

Since the probability of getting a head on each flip is 2/3, the equation becomes:

(2/3) × (2/3) × (2/3) × (2/3) × (2/3) × (2/3) = (2/3)⁶ ≈ 0.0273

So, the probability of flipping heads 6 times in a row with this weighted coin is approximately 0.0273, or 2.73%.

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The above prmpt is about construction of geometric shapes. See the answers below.

a) you would need to use your compass.

i) place extend your compass to say about 30 degree.
ii) place the ponted tip on one end of the existing line segment and make two arcs on both sides of the line. Place the compass on the other end of the line and repreat.

iii) Now you have created arcs that intersect one another.

iv) place your ruler between the intersections and draw such that the points on each intersection connect with one another. This will create a line perpendicular to the exising one.

b) in this case, simple use your ruler to measure the distance between the existing dot and the line segment.

Carefully without moving your ruler upwads or downwards, extend sideways then make another dot jus tlike the original one.

Now connect both dots. This will given you two parallel lines.

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