What is the difference in
momentum between an 87.2 kg
football player running 2.87 m/s and
a 0.0520 kg bullet moving 789 m/s?

What Is The Difference Inmomentum Between An 87.2 Kgfootball Player Running 2.87 M/s Anda 0.0520 Kg Bullet

Answers

Answer 1
Answer:

209.236 kg · m/s

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Physics

Momentum

Momentum Formula: P = mv

P is momentum (in kg · m/s)m is mass (in kg)v is velocity (in m/s)Explanation:

Step 1: Define

m₁ = 87.2 kg

v₁ = 2.87 m/s

m₂ = 0.0520 kg

v₂ = 789 m/s

Step 2: Find Momentums

Football Player

Substitute [MF]:                    P = (87.2 kg)(2.87 m/s)Multiply:                                P = 250.264 kg · m/s

Bullet

Substitute [MF]:                    P = (0.0520 kg)(789 m/s)Multiply:                                P = 41.028 kg · m/s

Step 3: Find difference

Define equation:                    P₁ - P₂Substitute:                              250.264 kg · m/s - 41.028 kg · m/sSubtract:                                 209.236 kg · m/s
Answer 2

Answer:

209.236

Explanation:

Order of Operations: PEMDAS

"Please excuse my dear Aunt Sally"

Parentheses, exponents, multiplication, division, addition and subtraction

First use p=mv

Player:(plug in the data)

= 87.2*2.87

= 250.264

Bullet : (do the same)

Then subtract Bullet-Player =209.236


Related Questions

PLEASE The weight of a girl  is  600 N and the area of her one foot is        50 cm². What will be the pressure exerted by her on theground?       

Answers

Answer:

pressure=force/area

p=600/50

p=12

so 12Nm^-1

Why should a person warm up before physical activity?

Answers

Answer:

don't wanna pull anything

Explanation:

A good warm-up before a workout dilates your blood vessels, ensuring that your muscles are well supplied with oxygen. It also raises your muscles' temperature for optimal flexibility and efficiency. By slowly raising your heart rate, the warm-up also helps minimize stress on your heart.

Answer:

Here you go!

Explanation:

A good warm-up before a workout dilates your blood vessels, ensuring that your muscles are well supplied with oxygen. It also raises your muscles' temperature for optimal flexibility and efficiency. By slowly raising your heart rate, the warm-up also helps minimize stress on your heart. “Stretching allows for greater range of motion and eases the stress on the joints and tendons, which could potentially prevent injury. Warming up, such as low-heart rate cardio, prepares the circulatory and respiratory system for the upcoming ‘age- and type-appropriate target heart rate’ exercising, whether it’s endurance or sprint type of activities.” The cool-down is just as critical.  It keeps the blood flowing throughout the body. Stopping suddenly can cause light-headedness because your heart rate and blood pressure drop rapidly. Before you exercise, think about warming up your muscles like you would warm up your car. It increases the temperature and flexibility of your muscles, and helps you be more efficient and safer during your workout.  A warm-up before moderate- or vigorous-intensity aerobic activity allows a gradual increase in heart rate and breathing at the start of the activity.

Tips:

*Warm up for 5 to 10 minutes. The more intense the activity, the longer the warm-up.

*Do whatever activity you plan on doing (running, walking, cycling, etc.) at a slower pace (jog, walk slowly).

*Use your entire body. For many people, walking on a treadmill and doing some modified bent-knee push-ups will suffice.

2. A 50.0 kg shell was fired from a cannon at earth's surface to a
maximum height of 400. m.
a. What is the potential energy at maximum height?
b. It then fell to a height of 100. m. What was the loss of PE as
it fell?

Answers

Answer: a) 196000 Joules

b) 147000 Joules

Explanation:

a. Potential energy is the energy possessed by an object by virtue of its position.

[tex]P.E=m\times g\times h[/tex]

m= mass of object = 50.0 kg

g = acceleration due to gravity = [tex]9.8ms^{-2} [/tex]

h = height of an object = 400 m

Putting in the values we get:

[tex] P.E=50kg\times 9.8ms^{-2}\times 400m=196000kgm^2s^{-2}=196000Joules[/tex]     [tex](1kgm^2s^{-2}=1Joule )[/tex]

Thus the potential energy at maximum height is 196000Joules.

b. [tex] P.E=50kg\times 9.8ms^{-2}\times 100m=49000kgm^2s^{-2}=49000Joules[/tex]     [tex](1kgm^2s^{-2}=1Joule )[/tex]

Thus loss in P.E = (196000Joules-49000Joules) = 147000 Joules

A satellite moves at a constant speed in a circular orbit about the Earth. Which pair of statements about momentum and kinetic energy are correct.

Answers

Answer:

The momentum and the kinetic energy remains constant.

Explanation:

A uniform circular motion is defined as the motion of a body which moves in a constant speed or at the same speed during the motion.

In the context, it is given that a satellite is moving around the earth in a circular orbit at a constant speed. The satellite has certain momentum as well as energy.

We can conclude that the kinetic energy and the momentum of the satellite remains constant as the momentum and kinetic energy depends on the speed of an object And here the speed of the satellite is constant, so the moment as well as the kinetic energy of the satellite remains constant while moving in a circular path.

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