what is the concentration of a chemical in an oil spill in ppb if 0.060 mg of it is found in 4600 kg of soil?

Answers

Answer 1

The concentration of an chemical in an oil spill in ppb is 0.013 ppb (approx).

What is concentration?

concentration is the abundance of a constituent divided by the total volume to the  mixture. Several by the  types of mathematical description can be the  distinguished: mass of the  concentration, molar concentration, number and  concentration, and volume concentration.

Calculate the concentration in ppb by multiplying to the  ratio of the mass of solute to  mass of solution by 1 billion or 10 ^9

So here the answer can be calculated by

(10^ 9)(6×10 ^-8)/4600

(Here 0.060 mg = 6 × 10 ^-8 kh)

=  6/460

= 0.013 ppb (approx)

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Related Questions

what magnitude of current is required to produce 1.4 kg of sodium metal in one hour? express your answer in amperes to two significant figures.

Answers

The magnitude of the current required to produce 1.4 kg of sodium metal in one hour is 1398.38 Amps

Weight of Sodium = 1.4 kg = 1400 g

The molar mass of Sodium = 23 u

Moles of Sodium = 1400/23 = 52.174

No. of atoms of copper = 52.174 * 6.023 x[tex]10^{23}[/tex] = 3.14 x [tex]10^{25}[/tex]

Each copper requires a 1e charge,

So total charge = 1.602 x[tex]10^{-19}[/tex] * 3.14 x [tex]10^{25}[/tex]= 5034180.52 C

I = total charge/time

Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The current is frequently represented by the capital letter I. The standard unit is the ampere, represented by the letter A.

So I = 5034180.52/3600 = 1398.38 Amps

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A 60⁢kg board that is 6 m m long is placed at the edge of a platform, with 4m of its length extending over the edge. The board is held in place by blocks of masses M1M1 and M2M2 placed with their centers of mass on either end. If M2=30kg M2=30kg , what is the minimum value of M1 needed to keep the board from falling off the platform?
30kg
50kg
60kg
70kg
90kg

Answers

The minimum value of M1 to keep a board from falling off the platform is 90 kg.

The mass (M1) placed on the left side edge of the board

the mass of the board = 60 kg

the length of the board = 6 m

If the mass on the right side = 30 kg, and the length of the board L1 = 2m

Then, the length L2 which extend over the edge = 4m

Consider the center of gravity in the board that lies at the length of the board midpoint.

Then, the distance (D) of the gravity center from the platform end = 3 - 2

= 1

The moment when the platform end, the mass (M1) placed on the left side edge of the board can be computed as:

M1= 60kg+120kg/2

M1=180kg/2

M1=90kg

Therefore, The minimum value M1 needed to keep the board from falling off the platform is 90 kg.

Mass is a quantitative measure of inertia, a fundamental property of matter.

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what is the potential energy u of the toy when the spring is compressed 3.2 cm from its equilibrium position?

Answers

Total energy in compressing a spring is [tex]kx^{2}/2[/tex].

When we compress or extend a stretched spring, we experience a force equal to that applied by us in the opposite direction.When a spring deviates from its mean position, it tends to restore its equilibrium by exerting a force equal and opposite to the external force. We have seen the application of spring force in bicycle carriers and launching devices where the energy gained by disturbing the equilibrium of the spring is utilized as its potential energy and converted to other forms.

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An electric iron consumes energy at the rate of 420 W when heating is at the maximum rate and 180 W when heating is at the minimum rate. The applied voltage is 220 V. What is the current in each case?

Answers

when heating is at the minimum rate. The applied voltage is 220 V. The current in each case is 271.60 (approx)

P = VI   V is voltage and I is current

then,

I = P/V

when heating is at maximum

current:

I = 420W/220V

=1.9(approx)

resistance:

R = V/I

= 220V/1.9A

=115.78(approx)

when heating in minimum

current:

I = P/V

= 180W/220V

= 0.81 (approx)

resistance:

R = V/I

=220V/0.81A

=271.60 (approx)

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Calculate the total mass of the protons and electrons in 19 9f. Use 1. 007825 amu as the mass of 11h (mass of a proton and an electron).

Answers

We can conclude that total mass of protons and electrons in  is  9.07043 u.

What is Atomic mass ?

Atomic mass means the sum of total number of protons and neutrons present in an atom.

When an atom is neutral then number of protons equal the number of electrons.

Mass of a proton equals to 1.007276 u, mass of neutron equals to 1.008664 u.

For example, in a  atom there are total 9 protons and number of neutrons is 19 - 9 = 10.

Since, it is a neutral atom so number of electrons will also be 9.

So, total mass will be calculated as follows.

                 Total mass = 9 (mass of electron + mass of proton)

                                     = 9 (1.007825 u)

                                     = 9.07043 u

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You use j of energy to move a 2.0 N object. How far did you move it?

Answers

The distance the 2.0 N object will move, given that 35 J of energy is used to move it is 17.5 m

How do I determine the distance the object will move?

Work done is defined as the product of force and the distance moved in the direction of the force. Mathematically, it is expressed as:

Work done (Wd) = force (F) × distance (d)

Using the above formula, we can detertmine the distance the object will move as illustrated below:

Workdone (Wd) = 35 JForce (F) = 2.0 NDistance moved (d) = ?

Work done (Wd) = force (F) × distance (d)

35 = 2 × distance moved

Divide both sides by 2

Distance moved = 35 / 2

Distance moved = 17.5 m

Therefore, we can conclude from the calculation made above that the distance moved is 17.5 m

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Complete question:

You use 35 J of energy to move a 2.0 N object. How far did you move it?

Please hurry

Part A: A force of 8 N is exerted on a box with a mass of 2 kg. What is the acceleration of the
box?

Part B:If the box accelerates from rest to a velocity of 4 m/s, what is the impulse?

Answers

hope this helps solve your question

what is the z -component of the electric field at a depth δ beneath the origin along the negative z -axis? express your answer in terms of some or all of the variables σ , r , δ , and the electric constant ϵ0 .

Answers

In this problem we have spherical symmetry, so we can apply Gauss theorem to find the magnitude of the electric field:

∫ E(r) . dr = q / ε₀

where the term on the left is the flux of the electric field through the gaussian surface, and q is the charge contained in the surface.

Here we are analyzing the field at a distance , so outside the solid ball. If we take a gaussian sphere with radius r, we can rewrite the equation above as:

E(r) . 4πr² = q/ε₀  (1)

where 4πr² is the surface of the sphere.

The charge contained in the sphere, q, is equal to the charge density  times the volume of the solid ball, 4/3πr³ₐ:

q = ρ (4/3πr³ₐ)  (2)

Combining (1) and (2), we find

E(r) . 4πr² = (4/3ρπr³ₐ) / (3ε₀)

E(r) = ρπr³ₐ / 3ε₀r²

And we see that the electric field strength is inversely proportional to the square of the distance, r.

B) Now we are inside the solid ball: . By taking a gaussian sphere with radius r, the Gauss theorem becomes

E(r) . 4πr² = q / ε₀ (1)

But this time, the charge q is only the charge inside the gaussian sphere of radius r, so

q = ρ(4/3πr³) (2)

Combining (1) and (2), we find

E(r) . 4πr² = 4ρπr³ / 3ε₀

E(r) = ρr / 3ε₀

And we see that this time the electric field strength is proportional to r.

C) E(0)=0.

limr→∞E(r)=0.

The maximum electric field occurs when r=rb.

From part A) and B), we observed that

- The electric field inside the solid ball (r <r ₐ) is

ρr / 3ε₀ (1)

so it increases linearly with r

- The electric field outside the solid ball ( r > rₐ) is

E(r) = ρrₐ³ / 3ε₀r²  (2)

so it decreases quadratically with r

--> This implies that:

1) At r=0, the electric field is 0, because if we substitute r=0 inside eq.(1), we find E(0)=0

2) For r→∞, the electric field tends to zero as well, because according to eq.(2), the electric field strength decreases with the distance r

3) The maximum electric field occur for , i.e. on the surface of the solid ball: in fact, for  the electric field increases with distance, while for  the field decreases with distance, so the maximum value of the field is for .

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: A solid ball of radius rb has a uniform charge density ρ.

Part A What is the magnitude of the electric field E(r) at a distance r>rb from the center of the ball? Express your answer in terms of ρ, rb, r, and ϵ0.

Part B What is the magnitude of the electric field E(r) at a distance r Express your answer in terms of ρ, r, rb, and ϵ0.

Part CLet E(r) represent the electric field due to the charged ball throughout all of space. Which of the following statements about the electric field are true?

Check all that apply.

E(0)=0.

E(rb)=0.

limr→∞E(r)=0.

The maximum electric field occurs when r=0.

The maximum electric field occurs when r=rb.

The maximum electric field occurs as r→∞.]

a point mass is rotation about a rotation axis you increase its distance from that axis by a factor of two by what factor does its moement ofd inertia about that axis increase

Answers

When we increase the distance by two, the moment of inertia increases by a factor of four.

A measure of an object's resistance to changes in its rotating motion, the moment of inertia (commonly abbreviated as "I") is used in physics. It measures the amount of mass disposed about a rotational axis. The equivalent of mass in linear motion is the moment of inertia in rotational motion.

The idea of a moment of inertia is essential to rotational dynamics and is applied in many branches of mechanics, engineering, and physics. It is essential for understanding how spinning things such as wheels, gears, flywheels, and heavenly bodies like planets move.

The moment of inertia is given by:
I = mr²

Here, mass (m) and distance (d).

If we increase the distance from r to 2r. The new moment of inertial is:
I = m(2r)²

I = 4mr²

Hence, when we increase the distance by two, the moment of inertia increases by a factor of four.

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Mass (kg) Weight (N) 0.05 0.075 0.100 0.125 0.150 0.175 0.200 0.225 0.250 0.275 0.300 Displacement (Ay) 15 cm 23cm 30cm 40cm 48cm 55cm 63cm 71cm 80cm 90cm 97cm 1. Calculate the weight for each mass and fill in the middle column. Show the work for one of these calculations to receive credit. (5 points)

Answers

Here, we need to calculate weight.

Weight is given as the product of mass and gravity. This weight over here can also be denoted by force and it is said to be the force exerted by the bodies on the Earth.

If we take the gravity to be 10 m/s²,

then the weight for each given mass will be,

weight of 0.05 kg = 0.05*10 = 0.5 N

weight of 0.075 kg = 0.075 * 10 = 0.75 N

weight of 0.100 kg = 0.100 * 10 = 1 N

weight of 0.125 kg = 0.125 * 10 = 1.25 N

weight of 0.150 kg =0.150 * 10 = 1.5 N

weight of 0.175 kg = 0.175 * 10 = 1.75 N

weight of 0.200 kg = 0.200 * 10 = 2 N

weight of 0.225 kg = 0.225 * 10 = 2.25 N

weight of 0.250 kg = 0.250 * 10 = 2.5 N

weight of 0.275 kg = 0.275 * 10 = 2.75 N

weight of 0.300 kg = 0.300 * 10 = 3 N

Therefore, through this we got to know that the weight of the body is also the force exerted by the body on the Earth.

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Cations are always _____ than the parent atom and anions are always _____ than the parent atom.

Answers

Cations are always smaller than the parent atom and anions are always larger than the parent atom.

What are cations and anions?

Cations are positively charged ions i.e. one that would be attracted to the cathode in electrolysis while anions are negatively charged ions.

When a balanced atom loses one or more electrons, it will become a positively charged cation but it becomes negatively charged when it accepts one or more electrons.

Cations are always smaller than their parent atoms because they have lesser electrons, while their nuclear charge remains the same. On the other hand, anions are always larger because they have more electrons than their parent atoms.

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what minimum speed must the small sphere have in order to come within 5.00 cm of the surface of the large sphere?

Answers

The minimum speed must the small sphere have is v = 145.56  m/s

What is law of conservation of energy?

According to the rule of conservation of energy, energy cannot be generated or destroyed; it can only be transformed from one type of energy to another. This indicates that unless energy is added from outside, a system always has the same quantity of energy.

According to the given question,

Let the speed given to small charge q = v

Initially there is only Kinetic Energy present in the system , and potential energy is zero. The initial KE given to q is all transformed to Potential energy  at distance r = 9.00 + 5.00 = 14.00 cm  or 0.14 m from Q where q comes to rest due to the repelling forces.

Therefore, Using Energy Conservation -

PE = (qkQ)/r

KE = 1/2mv^2

PE = KE

1 / 2 * m * [tex]v^2[/tex] = Kq*Q/r

1 / 2 * 6  *  [tex]10^-5[/tex] *  [tex]v^2[/tex] = 8.9 * [tex]10^9[/tex] * 5 * [tex]10^-6[/tex] * 2* [tex]10^-6[/tex]  / 0.14

v = [tex]\sqrt{(0.63571 * 10^5)/3)} m/s[/tex]

v = 145.56 m/s

Minimum speed must the small sphere have, v = 145.56 m/s

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why can you assume that the Mechanical energy is equal to the Initial gravitational energy

Answers

The Mechanical energy is equal to the Initial gravitational energy as mechanical energy is stored in the object as gravitational potential energy.

What is law of conservation of energy?

Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another.

An isolated system's total energy is constant regardless of the types of energy present. The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that:

The total energy of the system is conserved in a closed system, also known as an isolated system.

Therefore, in a closed system like the universe, if energy is lost in one area, energy must be gained in a different area of the system by an equal amount. There is no known instance of the conservation of energy being broken, despite the fact that it cannot be proven.

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What can a transistor do in order to fulfill its function in a circuit? check all that apply.

Answers

A transistor is used to amplify or switch (rectify) electrical signals or power.

A transistor is an electronic component used in a circuit to control a large amount of current or voltage with a small amount of voltage or current. Smaller in size, the transistor could easily be manufactured cheaply in large quantities. They had various operational advantages.A transistor is a type of a semiconductor device that can be used to both conduct and insulate electric current or voltage.Transistors can be easily damaged when electrical and thermal events arise. For example, electrostatic discharge in handling.Transistors are affected by cosmic rays and radiation.

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consider an electron for which n 4, 3, and m 3. calculate the numerical value of (a) the orbital angular momentum and (b) the z component of the orbital angular momentum.

Answers

The L operates on [tex]\psi_3^3[/tex] eigenvalue will be equal to [tex]\sqrt{12}.[/tex]

z component of angular momentum is operates on [tex]\psi_3^3[/tex] gives [tex]L_z=3[/tex]

As per the data given in the question,

Quantum numbers of Electron n=4, l=3, and m=3.

Here, we need to find

(a) orbital angular momentum L and

(b) z component of orbital angular momentum [tex]\left(L_z\right)[/tex].

(a)

If orbital angular momentum (L) operates on spherical harmonic wave function of electron it gives an eigenvalue.

Then, we can write it as:

[tex]L^2 \psi_l^m=l(l+1) \hbar^2 \psi_l^m \\\\L \psi_l^m=\sqrt{l(l+1)} \hbar \psi_l^m[/tex]

Where, l is orbital quantum number and [tex]\hbar[/tex] is the reduced plank's constant.

We have l=3 and m=3

So,

[tex]& L \psi_3^3=\sqrt{3(3+1)} \hbar \psi_3^3 \\& L \psi_3^3=\sqrt{3(4)} \hbar \psi_3^3 \\& L \psi_3^3=\sqrt{12} \hbar \psi_3^3 \\& L=\sqrt{12} \hbar[/tex]

Therefore, the L operates on [tex]\psi_3^3[/tex] eigenvalue will be equal to [tex]\sqrt{12}.[/tex]

(b)

If z component of orbital angular momentum is operates on [tex]\psi_1^m[/tex], it give eigenvalue as follows,

[tex]L_z \psi_l^m=m_z \hbar \psi_1^m[/tex]

Here, [tex]m_z[/tex] is the magnetic quantum number.

[tex]L_z \psi_3^3=3 \hbar \psi_3^3 \\L_z=3 \hbar[/tex]

Therefore, if z component of angular momentum is operates on [tex]\psi_3^3[/tex] gives [tex]L_z=3[/tex]

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The numerical value of the orbital angular momentum is 1.8265719672742281e-34 J s, and the numerical value of the z component of the orbital angular momentum is 1.5818577255e-34 J s

The orbital angular momentum of an electron is given by the formula:

L = √l(l + 1) (h/2π)

where l is the orbital quantum number.

In this case, l = 3, so the orbital angular momentum is:

L = √3(3 + 1) (h/2π) = √12 (h/2π) = 1.8265719672742281e-34 J s

The z component of the orbital angular momentum is given by the formula:

Lz = m(h/2π)

where m is the magnetic quantum number.

In this case, m = 3, so the z component of the orbital angular momentum is:

Lz = 3(h/2π) = 1.5818577255e-34 J s

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a solid cylinder with a mass of 5 kg and a radius of 30 cm is rolling on a flat surface. the cylinder rolls with a speed of 2 m/s. what its kinetic energy?

Answers

The kinetic energy of the cylinder rolling is 10J

Rolling on a flat surface is a solid cylinder with a mass of 5 kg and a radius of 30 cm. 2 m/s is the rolling speed of the cylinder.

Due to frictional forces, when you slide an object over a surface (like a book over a table), it usually slows down quickly.

The frictional force acting provides the torque necessary for the object to begin rolling by causing it to change its angular momentum.

A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion.

The type of motion could be vibration, rotation about an axis, translation (or motion along a path from one place to another), or any combination of these.

[tex]K.E=mv^2/2[/tex]

=[5 x 2 x 2]/2

=10 J

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two capacitors of 4 μf and 8 μf are connected in parallel. what is the equivalent capacitance of this system?

Answers

The equivalent capacitance of this system is 12 micro F.

Let

C1 = 4 micro F

C2 = 8 micro F

C_parallel = C1 + C2

= 4 + 8

= 12 micro F

What is capacitance?

Capacitance is the ability of a component or circuit to collect and store energy in the form of electrical charge.

Capacitors are energy storage devices of various sizes and shapes. They consist of two sheets of conductive material (usually thin metals) sandwiched between insulators made of ceramic, foil, glass, or other material, or even air.

Insulators, also called dielectrics, increase the charging capacity of capacitors. Capacitors are sometimes called capacitors in the automotive, marine and aerospace industries.

The inner plate is connected to the two outer terminals. The outer terminal can be long and thin and resemble a small metal antenna or leg. These terminals can be plugged into a circuit.

Therefore, the equivalent capacitance of this system is 12.

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46. the sled is pulled up a higher hill that is less steep than the original hill described before question 44. how does the speed of the sled at the bottom of the hill (after it has slid down) compare to that of the sled at the bottom of the original hill?

Answers

Both hills' lowest speeds for the sled are the same.

Why would someone use a sled?

Sleds—also known as sleighs—are wintertime vehicles that are often pulled across ice or snow by either horses or dogs. The travois and the sidecar, which were its predecessors, are said to have been the earliest human-powered vehicles.

What is the difference between a sled and a sleigh?

An open-topped, often medium- to large-sized sleigh is used to transport people or cargo. Reindeer, dogs, or horses are frequently used as the drivers. While the name "sled" is still used generally in American parlance, it frequently refers to a smaller, frequently recreational, equipment.

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which term best describes the shape of jupiter's orbit around the sun?

Answers

Answer:

Explanation:

Kepler's First Law Describes the Shape of an Orbit

The orbit of a planet around the Sun (or of a satellite around a planet) is not a perfect circle. It is an ellipse—a “flattened” circle. The Sun (or the center of the planet) occupies one focus of the ellipse.

A book weighing 10 kg is preparing to fall off the desk from a 1 meter height. The book's
gravitational potential energy is 980 Joules.
O True
O False

Answers

Answer:

False

Explanation:

gravitational potential energy = mgh

10*10*1 = 100 joules

at what speed do a bicycle and its rider, with a combined mass of 100 kg , have the same momentum as a 1800 kg car traveling at 4.8 m/s ?

Answers

Answer:

Explanation:

Given:

m₁ = 100 kg

m₂ = 1800 kg

V₂ = 4.8 m/s

____________

V₁ - ?

According to the condition of the problem, the  momentum  are equal:

m₁·V₁ = m₂·V₂

Speed:

V₁ = m₂·V₂ / m₁ = 1800·4.8 / 100 ≈ 86 m/s

a ball is thrown upward with an initial velocity of 64 feet per second at an initial height of 80 feet. find the positio

Answers

The position of the object thrown upward with an initial velocity of 64 feet per second at an initial height of 80 feet from the ground after 10 seconds from the ground is 709.38 m

According to equation of motion,

s = u t + 1 / 2 a t²

s = Displacement

u = Initial velocity

t = Time

a = Acceleration

u = 64 ft / s

u = 19.5 m / s

t = 10 s

s = ( 19.5 * 10 ) + ( 1 / 2 * 9.8 * 10² )

s = 195 + 490

s = 685 m

Total distance from the ground,

d = h + s

h = 80 ft = 24.38 m

d = 24.38 + 685

d = 709.38 m

The final position of the object from the ground is 709.38 m

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While roller-skating, Granny collides with her tiny grandson Ambrose who is at rest. Ignoring …
a. Granny catches him and they both move together.
b. he and Granny make a bouncing collision, each going in opposite directions.

Answers

Momentum is conserved when two moving objects of equal masses collide while traveling in the same direction. The impact between cars 1 and 2 causes car 2 to accelerate.

According to the rule of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost. Collisions between two objects naturally fall under Newton's third law of motion. When two objects collide, forces of equal magnitude and opposite direction are applied to each object. These forces frequently result in one object gaining momentum and speeding up while the other object slows down.

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hree uniform spheres fig. p13.45. (a) what are the mag- nitude and direction of the force on a 0.0150 kg particle placed at p? (b) if the spheres are in deep outer space and a 0.0150

Answers

a) the magnitude of the force on particle is 9.7 x 10⁻¹² N and direction is 45° counter clockwise.

b) if spheres are in outer space of 0.0150, then velocity will be 3 x 10⁻⁵ km/s

We know

Force = G (m₁m₂/d²)

(a) F(net) = F₁ + F₂ + F₃

         G (mm(p)/d²) + G (mm(p)/d²) + 2G (mm(p)/2d²)

|F(net)| = G[ mm(p) / d² ](√2 + 1)

          = [6.67 x 10⁻¹¹ x 1 x (0.015) / (0.5)² ] (√2 + 1) = 9.7 x 10⁻¹² N

The magnitude of the force is 9.7 x 10⁻¹² N.

Direction 45° counter clockwise

(b) Initial velocity U(p) = √2Gm(2+√2/d - 2/150)

      = √2 x 6.67 x 10⁻¹¹(2 + √2 / 0.5 - 2/150)

      = 3 x 10⁻⁵ m/s

Therefore, the velocity at which it moves is 3 x 10⁻⁵ km/s.

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sunlight just outside earth's atmosphere has an intensity of 1.40 kw/m2. (a) calculate em for sunlight, assuming it to be a plane wave.

Answers

Electromagnetic waves for sunlight is  966.48  V/m

a) We know that the intensity of light

                 I = (1/2)ε0cEm2

From the above equation we can write

                Em = √(2I / ε0c)

                      = √2 * 1.24 x 103 / 8.85 x 10-12 * 3 x108

                      = 966.48  V/m

When an electric field and a magnetic field vibrate together, electromagnetic waves, or EM waves, are produced. Thus, magnetic and electric fields oscillate to form electromagnetic waves (EM waves). When an electric field and a magnetic field interact, electromagnetic waves are produced. It follows that they are referred to as "electromagnetic" waves. An electromagnetic wave's electric and magnetic fields are parallel to one another and form a right angle. In addition, they are parallel to the EM wave's direction.

In vacuum, the speed of electromagnetic waves is constant at 3.00 x 108 ms-1. Neither the electric nor magnetic fields can deflect them. On the other hand, they can exhibit diffraction or interference.

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an automobile sounds its horn while passing an observer at 25.5 m/s. the actual horn frequency is 405 hz. assume the speed of sound is 345 m/s. find its frequency heard by the observer while the car is approaching.

Answers

The frequency heard by the observer while the car is approacing 437.3 Hz.

What is doppler effect?

A wave's frequency changes in response to an observer moving in respect to the wave source, which is known as the Doppler effect or Doppler shift. The change in pitch that happens as an automobile approaches and drives away from a spectator while sounding its horn is a common way to demonstrate doppler shift.

By using Doppler's Formula:

fo = v+vo/v+vs x fs

where,

fo = observer frequency of sound

v= speed of sound waves

vo= observer velocity

vs= source velocity

fs= actual frequency of sound waves

It is given that,

fs= 405Hz

vs= 25.5 m/s

v= 345 m/s

fo= 0 m/s

Observer to source = Positive

Source to observer = Negative

fo = v+vo/v+vs x fs  

fo = 345/ 345 - 25.5× 405

fo = 437.3 Hz

Hence, The frequency heard by the observer is 437.3 Hz.

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The frequency heard by the observer while the car is approacing 437.3 Hz.

What is doppler effect?

A wave's frequency changes in response to an observer moving in respect to the wave source, which is known as the Doppler effect or Doppler shift. The change in pitch that happens as an automobile approaches and drives away from a spectator while sounding its horn is a common way to demonstrate doppler shift.

By using Doppler's Formula:

fo = v+vo/v+vs x fs

where,

fo = observer frequency of sound

v= speed of sound waves

vo= observer velocity

vs= source velocity

fs= actual frequency of sound waves

It is given that,

fs= 405Hz

vs= 25.5 m/s

v= 345 m/s

fo= 0 m/s

Observer to source = Positive

Source to observer = Negative

fo = v+vo/v+vs x fs  

fo = 345/ 345 - 25.5× 405

fo = 437.3 Hz

Hence, The frequency heard by the observer is 437.3 Hz.

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what method would astronomers use to find the distance to a galaxy so far away that individual stars are impossible to make out (resolve)?

Answers

The method would astronomers use to find the distance to a galaxy so far away that individual stars are impossible to make out (resolve) is finding the redshift .

What is meant by finding redshift ?

A manifestation of the Doppler Effect is redshift. The sound or light waves that are released by an object as it moves away from us are stretched out, which lowers their pitch and causes them to migrate towards the red end of the electromagnetic spectrum, where light has a longer wavelength.

An important topic for astronomers is "red shift." The term can be taken literally; when the light's wavelength is stretched, the light is perceived as having "shifted" toward the red portion of the spectrum. When a source of sound moves in relation to an observer, sound waves experience a similar phenomenon.

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A lab technician uses laser light with a wavelength of 640 nm to test a diffraction grating. When the grating is 40.8 cm from the screen, the first-order maxima appear 6.00 cm from the center of the pattern.

Answers

A lab technician uses laser light with a wavelength of 640 nm to evaluate a diffraction grating, and this particular grating has 195.31 lines per millimeter.

Its wavelength is 640 nm.

L=40.8 cm The distance between the grating and the screen

The first dazzling fringe is six centimeters away from the centre of the order for laser light. According to the deduced results from Young's experiment, which tie the order of bright fringes to the central order,

With the approach of laser light is small-angle approximation, y = m(wavelength)(L)/d and d = m()(L)/y

Using the value d= 1*640*10^-9*0.48/0.06m = 5.120*10^-9 as a starting point

The line density is 1/d = 1/5.120*10^-9, or 195.31 lines per millimeter.

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A gas is taken through the cyclic process described in the figure. (The x axis is marked in increments of 2.5 m3.;) P (kPa) V (m3) (a) Find the net energy transferred to the system by heat during one complete cycle. (b) If the cycle is reversed-that is, the process follows the path ACBA-what is the net energy input per cycle by heat?

Answers

The correct solutions are -

(a) The net energy transferred to the system by heat during one complete cycle is 15 kJ

(b) The net energy input per cycle by heat is -15 kJ

The net energy transferred to the system is equal to work done. The work done will be calculated by the calculating the area enclosed in the figure.

The area = 1/2 × (8 - 2) × 5

Performing multiplication and division on Right Hand Side of the equation

Work done = 1/2 × 6 × 5

Work done = 3 × 5

Work done = 15 kJ

On reversing the cycle, the net energy input per cycle be heat will be -15kJ.

Hence, work done is 15 kj and net energy input is -15kJ.

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The complete question is attached in the figure.

what is the longest wavelength of light (in nm) for which all three metals will emit photoelectrons?

Answers

The 520 nm wavelength is the longest at which a metal will emit an electron.

The definitions of wavelength and frequency

The wavelength, which is also the distance between two wave crests and troughs, is the measurement of wave length. In cycles per second (Hz), the term "frequency" refers to the number of vibrations that cross a specific area in a second (Hertz). This article talks about the relationship between wavelength and frequency.

The wavelength is what.

The length of a waveform signal that is propagating in space or over a wire is measured by the separation between identical points (adjacent crests) in the adjacent cycles. This length is often stated in meters (m), centimeters (cm), or millimeters (mm) in wireless systems (mm).

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