What is the best way to organize desert several several million different types of organisms on earth

Answers

Answer 1

Answer:

The desert should be divided into different types based on its properties. The organisms living in specific type of desert should be named accordingly.

Explanation:

There are usually five major types of desert in the world. Tropical, rainy, semi arid desert, coastal desert and dry desert. There are many different types of organisms living in these deserts. The biodiversity has made it difficult for the humans to analyse and identify the millions of different types. The best way is to organize and name the organisms that live in specific types of deserts.


Related Questions

After heating the solution, you decant the liquid and wash the remaining solid with distilled water. What you are removing by this washing?

Answers

Answer:

The solvent

Explanation:

After the solid is recoverd by decanting the liquid, some solvent particles may still adhere to the solid.

In order to remove the solvent that may have adhered to the solid completely , the solid is washed before it is now dried.

In order to remove the remaining liquid present the solid material.

We are washing the solid in order to remove the liquid particles that is attached to the solid material with the help of water. Water is a universal solvent that dissolve large number of solutes in it.

Water removes the liquid from the solid by attaching with that liquid or dissolving in it so that's why we use water for washing a solid in order to remove the impurities from the solid material in which it is placed.

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Problem:
[Ar]4s2
Identify the period (p) , group (g) and valence electrons block of the element

Answers

Answer:

it is Calcium (Ca)

4th period, 2nd group, 2 valence electrons

Which of the following reactions will proceed as drawn below? (Yes or No)

Answers

Answer:

i wish i could help but t know either so i wish you luck for an answer once again truly sorry don'

Explanation:

i am sorry but i do not know :(

g A 0.4395 g sample of aluminum reacts according to our experiment to produce alum. 5.1629 g of dried alum crystals are recovered. What is the percent yield of the experiment?

Answers

Answer:

92.75%

Explanation:

The overall chemical equation for the reaction in the preparation of alum from the aluminium can be expressed as:

[tex]\mathtt{2Al + 2KOH + 4H_2SO_4 +2H_2O \to 2KAl(SO_4)_2 2H_2O +3H_2}[/tex]

From above; we will see that 2 moles of Aluminium react with sulphuric acid and water to produce 2 moles o aluminium alum.

Therefore, the theoretical yield can be determined as:

[tex]=0.4395 \ g Al \times \dfrac{1 \ mol \ Al}{27 \ g Al }\times \dfrac{2 \ mol \ KAl(SO_4)_2}{2 \ mol \ Al}\times \dfrac{294.23 \ KAl(SO_4)_2}{1 \ mol \ KAl(SO_4)_2}[/tex]

= 4.789g of [tex]KAl(SO_4)_2[/tex]

To find the percent yield, we need to divide the actual yield by the theoretical yield and then multiply it with 100.

percent yield = ( mass of alum(g)/theoretical yield(g) ) × 100

percent yield = ( 4.789g / 5.1629g ) × 100%

percent yield = 0.9275 × 100%

percent yield = 92.75%

Thus, the percent yield of the experiment 92.75%

Which of the following is NOT an example of deposition?
sand dune
river delta
cave crystal
valley
This science btw

Answers

Answer:

Cave Crystal

Explanation:

I believe it's cave crystal because sand dunes, river deltas, and valleys are all examples of deposition.

Need help with 8 plssss

Answers

Answer:

c,a,b,d

Explanation:

Someone plz hello me ASAP it would be appreciated on question 2 and 3 btw

Answers

Answer:

2 should be potential energy and 3 should be A

Explanation:

Both should be A. Hope it helps.

A 25.00-mL aliquot of a nitric acid solution of unknown concentration is pipetted into a 125-mL Erlenmeyer flask and 2 drops of phenolphthalein are added. The above sodium hydroxide solution (the titrant) is used to titrate the nitric acid solution (the analyte). If 12.75 mL of the titrant is dispensed from a burette in causing a color change of the phenolphthalein, what is the molar concentration of the nitric acid solution? (Show all steps for calculating the answer.)
Answer: 0.0611 M HNO3​

Answers

Answer:

0.0611M of HNO3

Explanation:

The concentration of the NaOH solution must be 0.1198M

The reaction of NaOH with HNO3 is:

NaOH + HNO3 → NaNO3 + H2O

1 mole of NaOH reacts per mole of HNO3.

That means the moles of NaOH used in the titration are equal to moles of HNO3.

Moles HNO3:

12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.

In 25.00mL = 0.025L -The volume of the aliquot-:

0.00153 moles HNO3 / 0.025L =

0.0611M of HNO3

The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this problem. Part A What minimum frequency of light is required to ionize boron

Answers

Answer:

The frequency is  [tex]f =  2,01 * 10^{15} \  Hz  [/tex]

Explanation:

From the question we are told that

   The energy required to ionize boron is [tex]E_b  =  801 KJ/mol[/tex]

Generally the ionization energy of boron pre atom is mathematically represented as

     [tex]E_a  =  \frac{E_b}{N_A}[/tex]

Here  [tex]N_A[/tex] is the Avogadro's constant with value [tex]N_A  =  6.022*10^{23}[/tex]

So

      [tex]E_a  =  \frac{801}{6.022*10^{23}}[/tex]

=>     [tex]E_a  =  1.330 *10^{-18} \  J/atom [/tex]

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

       [tex]E =  hf  =  E_a[/tex]

=>     [tex]  hf  =  E_a[/tex]

Here h is the Planks constant with value [tex]h = 6.626 *10^{-34}[/tex]

So

       [tex]f =  \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}[/tex]

=>      [tex]f =  2,01 * 10^{15} \  Hz  [/tex]

Is nuclear fission exothermic or endothermic? Explain your answer.

Answers

Answer:

Exothermic

Explanation:

Nuclear fission means splitting, so there is a lot of energy being released.

20 POINTS PLEASE ANSWER ASAP!!!!

Why is calcium (Ca) in group 2, period 4 on the periodic table?

A Calcium, like all group 2 elements, is nonreactive and a gas at room temperature.

B Calcium, like all period 4 elements, is nonreactive and a gas at room temperature,

C Calcium, like all group 2 elements, is reactive and a solid at room temperature.
D. Calcium, like all period 4 elements, is reactive and a solid at room temperature.​

Answers

C
the period of Ca just indicates the number of shells it has and the group shows the electrons in the outermost shell which infact affects its chemical properties. Group 2 element are all solids abs very reactive

Calcium (Ca) is in group 2 and period 4 on the periodic table be because Calcium has 2 valence electrons and 4 electron shell. Thus, calcium is a metal like all other group 2 element.

The correct answer to the question is Option C. Calcium, like all group 2 elements, is reactive and a solid at room temperature.

Calcium is a group 2 element majorly because it has 2 valence electrons. It is also in period 4 because it has 4 electron shells.

Being a group 2 element, calcium is a solid at room temperature and also reactive. All elements in the group 2 are metals.

There are other elements in period 4 which are not solid. For example krypton is an element in period 4 and it is a gas and not reactive.

From the above information, we can conclude that the correct answer to the question is:

Option C. Calcium, like all group 2 elements, is reactive and a solid at room temperature.

See attached image

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It has been hypothesized that a chemical known as BW prevents colds. To test this hypothesis, 20,000 volunteers were divided into four groups. Each volunteer took a white pill every morning for one year. The contents of the pill taken by the members of each group are shown in the chart below. What is the independent variable in this experiment? *


1. % Developing Colds

2. Number of Volunteers

3. Grams of sugar

4. Grams of BW

Answers

Grams of BW

i think thats irtu9rgirg

Independent variable in an investigation is the variable is does not depends on any other variable and on which we can have the control. Hence, the grams of BW is the independent variable here.

What is independent variables?

In an experiment the parameters which changes by control or depending on other changes are called variables. There are two kinds variables namely dependant and independent variables.

The dependant variables are those variable which depends upon other variables and whose changes are studying with respect to certain parameters.

Independent variables does not depends on other variable and can be controlled by the researcher. Here, we are studying the % of developing cold with respect to the amounts of BW. The changing variable is BW amount on which the percentage of cold depends.

Therefore, the independent variable is grams of BW and dependant variable is % development of cold.

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A gaseous mixture contains 441.0 Torr H2(g), 387.3 Torr N2(g), and 74.5 Torr Ar(g). Calculate the mole fraction, ????, of each of these gases.
????H2=
????N2=
????Ar=

Answers

Answer:

XH₂ = 0.4885

XN₂ = 0.4290

XAr = 0.0825

Explanation:

Step 1: Given data

Partial pressure of H₂ (pH₂): 441.0 TorrPartial pressure of N₂ (pN₂): 387.3 TorrPartial pressure of Ar (pAr): 74.5 Torr

Step 2: Calculate the total pressure (P)

The total pressure is equal to the sum of the partial pressures of all the gases.

P = pH₂ + pN₂ + pAr = 441.0 Torr + 387.3 Torr + 74.5 Torr = 902.8 Torr

Step 3: Calculate the mole fraction (X) of each gas

We will use the following expression.

Xi = pi / P

where,

Xi: mole fraction of the gas i

pi: partial pressure of the gas i

P: total pressure

XH₂ = pH₂ / P = 441.0 Torr / 902.8 Torr = 0.4885

XN₂ = pN₂ / P = 387.3 Torr / 902.8 Torr = 0.4290

XAr = pAr / P = 74.5 Torr / 902.8 Torr = 0.0825

Question 14 (1 point)
Calculate the molarity of a solution made by dissolving 15.25 g lithium chloride (Lici)
in 250 mL of solution
61 M LICI
2
1.4 M LICI
5
0.36 M LICI
18
0.061 M Lici
0.0014 M LICI

Answers

Answer:

Molarity = 1.4 M

Explanation:

Given data:

Mass of LiCl = 15.25 g

Volume of solution = 250 mL (250/1000 = 0.25 L)

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles of LiCl.

Number of moles = mass/molar mass

Number of moles = 15.25 g/ 42.39 g/mol

Number of moles = 0.36 mol

Molarity:

Molarity = 0.36 mol / 0.25 L

Molarity = 1.4 M           (M= mol/L)

Which step of mitosis involves the nucleus spitting and nuclear membranes forming around each new nucleus??

Answers

Answer:

telophase

Explanation:

Enter your answer in the provided box. A sample of an unknown gas effuses in 11.1 min. An equal volume of H2 in the same apparatus under the same conditions effuses in 2.42 min. What is the molar mass of the unknown gas

Answers

Answer: The molar mass of the unknown gas  is 9 g/mol

Explanation:

From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

[tex]\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}} [/tex]

[tex]rate=\frac{volume}{time} [/tex]

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

[tex]\frac{t_B}{t_A}=\sqrt{\frac{M_B}{M_A}}[/tex]

Putting the values in the formula:

[tex]\frac{2.42min}{11.1min}=\sqrt{\frac{M_{H_2}}{M_A}} [/tex]

[tex]\frac{2.42min}{11.1min}=\sqrt{\frac{2}{M_A}} [/tex]

Squaring both sides:

[tex]\frac{2}{M_A}=0.218[/tex]

[tex]M_A=9g/mol[/tex]

The molar mass of the unknown gas  is 9 g/mol

A car travels for 0.5 hours and goes 25 miles. What is the car's speed? (Remember sad + t)

Answers

Answer:

s = 22.352 m/s

Explanation:

Given data:

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

Solution:

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

miles to meter:

25 mi × 1609 m/ 1 mi = 40233.6 m

Formula:

s =  d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s

Suppose you produce 0.0451 g of N 2 gas with a volume of 0.0413 L and a pressure of 0.991 atm at 298 K. Based on the experimental data, what is the value of the gas constant R ?

Answers

Answer:

R = 0.096 L•atm•mol-1•K-1

Explanation:

According to the ideal gas law:

Pv=nRT

P = pressure
V = volume
n = # of moles
R = ?
T = temperature

Steps:

n = 0.451/289 =0.00156055

R = (0.991)x(0.0451)/(0.00156055)x(298)

R = 0.0961073

Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, value of the gas constant R is 0.0821LatmK⁻¹ when volume is 0.0413 L.

What is ideal gas equation?

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of nitrogen gas = 0.991 atm

V= volume of nitrogen gas =0.0413 L

n =number of moles of nitrogen gas = given mass ÷Molar mass

                                                          =0.0451 g ÷28

                                                          =0.0016mol

T =temperature of nitrogen gas =298 K

R = Gas constant =?

0.991 atm×0.0413 L=0.0016×R×298 K

R=0.0821LatmK⁻¹

Therefore, value of the gas constant R is 0.0821LatmK⁻¹.

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Question 5 of 5
Which two phrases describe the nature of an electromagnetic force?
O A. Acts only when objects touch each other
B. Produced by interactions between magnetic objects
O c. Not a fundamental force of nature
O D. Produced by interactions between electrically charged objects

Answers

Answer:

I think it's A and D

Explanation:

I'm not sure if it's right

Answer:

The answer is B and D

Explanation:

trust fr

An object is moving at a speed of 6 inches every 4.5 days. Express this speed in yards per year. Round your answer to the nearest tenth.

Answers

i added .. i got 10.5

The definition of average speed and unit reductions allows to find the result for the speed of the object is:

The velocity is:   v = 13.5 [tex]\frac{yard}{year}[/tex]

Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.

Average velocity is defined as the change in position between the interval time

       v = [tex]\frac{\Delta x}{\Delta t}[/tex]

Where v is the velocity, Δx and Δt the change in position and time, respectively.

The system of units is a system that allows the exchange of data and values ​​with precision and without errors, the most used system in the world is the international system of measurements (SI), another system also used is the English system, where the basic units are the foot and the second.

They indicate the displacement in the form of a 6-inch in a time of 4.5 days. Let's look for speed.

    v = [tex]\frac{6 \ inch}{4.5 \ day }[/tex]    

    v = 1.3333 inch/days

They ask that I know this speed in yards per year, let's reduce the units.

   1 yard = 36 in

   1 year = 365 days

Let's reduce.

 

   v = [tex]1.33333 (\frac{inch}{day}) \ (\frac{1 yard}{36 inch}) \ ( \frac{365 day }{1 year} )[/tex]  

   v = 13.52 yard / year

The result is requested with a nearest tenth.

   v = 13.5 yard / year

In conclusion using the definition of average speed and unit reductions we can find the result for the speed of the object is:

The veloicity is:  v = 13.5 [tex]\frac{yard}{year}[/tex]  

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In the ionic compound KCL, which ion is the cation, and which is the anion? PLEASE HELP

Answers

Answer:

Potassium chloride, KCl , is an ionic compound formed by the electrostatic force of attraction that holds the potassium cations and the chlorine anions together

Explanation:

A certain first-order reaction has a rate constant of 2.10×10−2 s−1 at 19 ∘C. What is the value of k at 58 ∘C if Ea = 82.0 kJ/mol ?

Answers

Answer:

K₂ = 1.12s⁻¹

Explanation:

Based on Arrhenius equation:

ln K₂/K₁ = -Ea/R (1/T₂ - 1/T₁)

Where K is rate constant,

R is gas constant (8.314J/molK),

T is absolute temperature (In K) Of 1, initial state and 2, final state.

ln K₂/K₁ = -Ea/R (1/T₂ - 1/T₁)

ln K₂/2.10x10⁻²s⁻¹ = -82000J/mol/8.314J/molK (1/(273.15 + 58) - 1/(273.15 + 19))

ln K₂ / 2.10x10⁻²s⁻¹ = 3.976

K₂ / 2.10x10⁻²s⁻¹ = 53.3

K₂ = 1.12s⁻¹

The degree of unsaturation, or index of hydrogen deficiency, is the number of pi bonds plus rings in a molecule. Specify the degree of unsaturation (index of hydrogen deficiency) of the following formulas:
(a) C5H6
(b) C10H6Cl2
(c) C4H3NO

Answers

Explanation:

The degree of unsaturation is given as;

Degree of unsaturation = (2C + 2 + N - H - X) / 2

(a) C5H6

Using the formular above;

Degree of unsaturation = [ 2(5) + 2 - 6] / 2

Degree of unsaturation = [ 12 - 6 ] / 2 = 3

(b) C10H6Cl2

Using the formular above;

Degree of unsaturation = [ 2(10) + 2 - 6 -2 ] / 2

Degree of unsaturation = [ 22 - 8 ] / 2 = 7

(c) C4H3NO

Using the formular above;

Degree of unsaturation = [ 2(4) + 2 - 3 -1 ] / 2

Degree of unsaturation = [ 10 - 4 ] / 2 = 3

Note: Oxygen is ignored because its presence has no effect on the degree of unsaturation.

which of the following determines an object’s ability to float in water?

a. how much the object weighs
b. what the mass of the object is
c. how dense the object is
d. the volume of the object

Answers

Density of the object! :)
A. because it object is weighs

Question: Can a penny dropped from a building kill a pedestrian below?


Hypothesis:


Controls:


Independent variable:


Dependent variable:


Conclusion:

Answers

Answer:

Hypothesis: IF a penny is dropped from a building, THEN it would kill a pedestrian below

Controls: Same building, Same distance

Independent variable: Penny

Dependent variable: Pedestrian's death

Conclusion: The hypothesis is rejected

Explanation:

- The hypothesis is a testable explanation to an observed problem or asked question. Based on the cientific question in this question, a possible hypothesis will be: IF a penny is dropped from a building, THEN it would kill a pedestrian below

- Independent variable is the variable that is changed or manipulated in an experiment. In this case, the PENNY is the independent variable

- Dependent variable is the variable that responds to the change made to the independent variable. It is the measured variable. In this case, the dependent variable is the DEATH OF PEDESTRIANS.

- Controls are those variables that is kept constant or unchanged throughout the experiment. The controls in this experiment are: Same building, Same distance of throw etc.

- The conclusion is whether the hypothesis is accepted or not depending on the result of the experiment conducted. In this case, the hypothesis will be rejected if the penny doesn't kill a pedestrian

The molar mass of gallium (Ga) is 69.72 g/mol.
Calculate the number of atoms in a 27.2 mg sample of Ga.
Write your answer in scientific notation using three significant figures.
atoms Ga

Answers

Answer:

2.35 x 10²⁰ atoms Ga

Explanation:

After converting from mg to g, use the molar mass as the unit converter to convert to moles. Then using Avogadro's number, 6.022 x 10²³ convert from moles to atoms of Ga.

[tex]27.2mgGa*\frac{1g}{1000mg} *\frac{1 mol Ga}{69.72gGa} *\frac{6.022*10^2^3 atoms Ga}{1 molGa} = 2.349 * 10^2^0 atoms Ga[/tex]

Then round to 3 significant figures = 2.35 x 10²⁰ atoms Ga.

The number of atoms in 27.2 mg sample of Ga is 2.35 × 10²⁰ atoms

Stoichiometry

From the question, we are to calculate the number of atoms in a 27.2 mg sample of Ga.

First, we will determine the number of moles of Ga present

Using the formula,

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass} [/tex]

Mass = 27.2 mg = 0.0272 g

Molar mass = 69.72 g/mol

Then,

[tex]Number\ of\ moles \ of\ Ga = \frac{0.0272}{69.72} [/tex]

[tex]Number\ of\ moles \ of\ Ga = [/tex] 0.000390132 moles

Now, for the number of atoms present

From the formula

Number of atoms = Number of moles × Avogadro's constant

Then,

Number of Ga atoms = 0.000390132 × 6.022×10²³

Number of Ga atoms = 2.35 × 10²⁰ atoms

Hence, the number of atoms in 27.2 mg sample of Ga is 2.35 × 10²⁰ atoms

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A major component of gasoline is octane (C8H18). When octane is burned in air, it chemically reacts with oxygen gas (O2) to produce carbon dioxide CO2 and water H2O. What mass of carbon dioxide is produced by the reaction of 7.58 g of octane? Please explain the answer to me like I'm five, I want to understand but the content makes no sense.

Answers

Answer:

Mass = 23.232 g

Explanation:

Given data:

Mass of C₈H₁₈ = 7.58 g

Mass of CO₂ produced = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25O₂      →     16CO₂ + 18H₂O

Number of moles of octane:

Number of  moles =  mass/molar mass

Number of moles = 7.58 g/ 114.23 g/mol

Number of moles = 0.066 mol

Now we will compare the moles of CO₂ with octane from balance chemical equation.

                  C₈H₁₈            :           CO₂

                       2              :              16

                 0.066             :           16/2×0.066 = 0.528

Mass of CO₂ produced:

Mass = number of moles × molar mass

Mass = 0.528 mol × 44 g/mol

Mass = 23.232 g

Please help me . I attached a picture down below . I need a answer as soon as possible

Answers

Answer:

I can't see the picture.. Can you try attaching it again?

Explanation:

A gas has a volume of 300 mL and a pressure of 2 atm. What volume will the gas occupy when the pressure is
increased to 7 atm (total)?

Answers

Answer:

The answer is 85.71 mL

Explanation:

The new volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

We have

[tex]V_2 = \frac{300 \times 2}{7} = \frac{600}{7} \\ = 85.714285...[/tex]

We have the final answer as

85.71 mL

Hope this helps you

Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abundance of 48%. Find average atomic mass of this element and express your

Answers

Answer:

x = 33.52 amu

Explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

[tex]x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=\dfrac{52}{100}\times 34+\dfrac{48}{100}\times 33\\\\x=0.52\times 34+0.48\times 33\\\\x=33.52\ \text{amu}[/tex]

So, the average atomic mass of this element is 33.52 amu.

Other Questions
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