What is the best estimate for the value of the expression?
[34/8 - 16/3] -14/9
O -3
O -2 1/2
O 7
O 7 1/2

Answer:

the answer is 42

Step-by-step explanation:

12-6+(14-8)^2

12-6(6)^2

12-6+36

=42

Answer:

the answer is -1 3/4

Step-by-step explanation:

Answer:

84,43,675 - Eighty Four Lakh Forty Three Thousand Six Hundred Seventy Five.

Step-by-step explanation:

Answer:

times -6

Explanation... 2 x 10-6 x -6=56

                      6 x 10-4=56      

Hope this helps

Answer:

Perimeter of the given triangle = [tex]\frac{7x+38}{(x+8)(x+5)}[/tex] units

Step-by-step explanation:

Perimeter of a polygon = Sum of the measures of all sides of the polygon

From the picture attached,

Perimeter of the given isosceles triangle = Measures of two equal sides + remaining side

P = [tex]2(\frac{3}{x+8})+\frac{x}{x+5}[/tex]

  = [tex]\frac{6}{(x+8)}+\frac{x}{(x+5)}[/tex]

  = [tex]\frac{6(x+5)+(x+8)}{(x+8)(x+5)}[/tex]

  = [tex]\frac{6x+30+x+8}{(x+8)(x+5)}[/tex]

  = [tex]\frac{7x+38}{(x+8)(x+5)}[/tex] units

Therefore, perimeter of the given triangle is [tex]\frac{7x+38}{(x+8)(x+5)}[/tex] units

Answer:

x< 9

Step-by-step explanation:

I'm not sure if it's right but I think it is .

Answer: 3,4,5,6,52,72,86,105

Step-by-step explanation: when solving the range you find the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

x = # of hours the bike was rented.

$40 = $12 + $7x

Subtract $12 from both sides.

$28 = $7x

Divide both sides by $7

4 = x

Sandy rented the bike for 4 hours.

Answer:

the answer is A

Step-by-step explanation:

those who want to save money and will only use product for a few years

Answer:

those who want to save money  an will use the product for only a few years

Step-by-step explanation:

i took a test on edge 2020!!!

Answer:

w = -4

Step-by-step explanation:

w - 2 + 2w = 6 + 5w

Add 2 to both sides.

w + 2w = 8 + 5w

Subtract w from each side.

2w = 8 + 4w

Subtract 4w from each side.

-2w = 8

Divide.

w = -4

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                    →    A + B = π - C

                                                    →    A + C = π - B

Use the Cofunction Identities:   sin (π - A) = sin A

                                                    sin (A - π/2) = cos A

                                                    cos (π/2 - A) = - sin A

Use the Power Reducing Identity:  sin ² A - sin² B = sin (A + B) · sin (A - B)

Use the Sum to Product Identity:

                                               sin A - sin B = 2 [cos (A + B)/2] · [sin (A - B)/2]

Proof LHS → RHS:

LHS:                                   sin² A - sin² B - sin² C

                                       = (sin² A - sin² B) - sin² C

Power Reducing:           sin (A + B) · sin (A - B) - sin² C

Given:                             sin (π - C) · sin (A - B) - sin² C

Cofunction:                    sin C · sin (A - B) - sin² C

Factor:                            sin C [sin (A - B) - sin C]

[tex]\text{Sum to Product:}\qquad \sin C\bigg[2\cos \bigg(\dfrac{(A-B)+C}{2}\bigg)\cdot \sin \bigg(\dfrac{(A-B)-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{(A+C)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(B+C)}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad \qquad 2\sin C\bigg[\cos \bigg(\dfrac{(\pi - B)-B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-(\pi - A)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi -2B}{2}\bigg)\cdot \sin \bigg(\dfrac{2A-\pi}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =2\sin C\bigg[\cos \bigg(\dfrac{\pi}{2} -B}\bigg)\cdot \sin \bigg(A-\dfrac{\pi}{2}\bigg)\bigg][/tex]

Cofunction:             2 sin C (-sin B) · (cos A)

                           = -2 sin C · sin B · cos A

                           = -2 cos A · sin B · sin C

LHS = RHS:   -2 cos A · sin B · sin C = -2 cos A · sin B · sin C  [tex]\checkmark[/tex]

Answer:

-6300

Step-by-step explanation:

I just plugged it into my calculator, Google's works just fine :)

Answer:

1

Step-by-step explanation:

Answer:

Last Option: (-∞, 4) U (4, ∞)

Step-by-step explanation:

Domain is the set of x-values that can be inputted into function f(x).

We see that our x-values span all numbers except x = -4. Therefore, it is not included in our domain:

(-∞, 4) U (4, ∞)

Answer:

4,000 is the integer representing the final balance of the bank account

Step-by-step explanation:

Here, we are told that Shiavni had a total of $9,000 in her bank account at the start of the week of which she spent $5,000 out of it on an antique clock.

Now, we want to know the integer that represents the amount which is the final balance of the bank account.

Mathematically, when we talk of an integer, we are simply referring to a whole number, be it negative or positive.

Thus, the integer is the case is the difference in what she had at the beginning of the week minus the cost of the clock

That would be; $9,000 -$5000 = $4,000

Answer:

No

Step-by-step explanation:

It is not, because we can only add the terms that contain x of the same order.

For x to be grouped with x 2 resulting in x 3 the terms would have to be multiplying

In this case they are grouped

x * x 2 = x 3

In this case they are not grouped

x + x 2 = x + x 2

Answer:

270°

Step-by-step explanation:

[tex]m\widehat{BC} = 360\degree - (146\degree + 90\degree) \\

m\widehat{BC} = 360\degree -236\degree \\

m\widehat{BC} = 124\degree \\\\

m\widehat{ABC} =m\widehat {AB} + m\widehat {BC} \\

m\widehat{ABC} =146\degree + 124\degree \\

\huge \red {\boxed {m\widehat{ABC} =270\degree}} \\

[/tex]

Answer:

area of square = l² = n²

Step-by-step explanation:

Answer:

[tex]A=n^{2}[/tex]

Step-by-step explanation:

Find area of a square

Area of square = length x width

Since a square's has the same length on all sides, we can square both sides.

Area of square = [tex]length^{2}[/tex]

If length = n

Then,

[tex]A=n^{2}[/tex]

The pH of solution A decreases, and the pH of solution B decreases.

Answer:

0.20<n<0.25

Step-by-step explanation:

0.20<n<0.25

Answer:

[tex]C = 180 - 3a[/tex]

Step-by-step explanation:

Given

[tex]A = a[/tex]

[tex]B = 2a[/tex]

Required

[tex]Find\ C[/tex]

Since, ABC is a triangle, we have:

[tex]A + B + C = 180[/tex]

Substitute values for A and C

[tex]a + 2a + C = 180[/tex]

[tex]3a + C = 180[/tex]

Subtract 3a from both sides

[tex]C = 180 - 3a[/tex]

Answer:

180°-3α

Step-by-step explanation:

If you forgot to put the degree sign on 180, that's why you got it wrong!

Answer:

If you are solving the equation for x :

3x + 3y = 180

3x = -3y + 180

x = -y + 60 or x = 60 - y

If you are solving the equation for y:

3x + 3y = 180

3y = -3x + 180

y = -x + 60 or y = 60 - x

Answer:

x=[tex]-\frac{1+2i\sqrt{31} }{5}[/tex]

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

−25=  [tex]\frac{1}{2}[/tex]  (10x−2)+3x

−25=([tex]\frac{1}{2}[/tex])(10x)+( [tex]\frac{1}{2}[/tex] )(−2)+3x(Distribute)

−25=5x+−1+3x

−25=(5x+3x)+(−1)(Combine Like Terms)

−25=8x+−1

−25=8x−1

Step 2: Flip the equation.

8x−1=−25

Step 3: Add 1 to both sides.

8x−1+1=−25+1

8x=−24

Step 4: Divide both sides by 8.

8x  ÷ 8   =   −24  ÷ 8

Answer:

x>-2

Step-by-step explanation:

first you subtract 10 from both sides to find x

10-3x-10<16-10

-3x<6

now here you divide both sides by -3

-3x/-3<6/-3

BUT since you are dividing by a negative number the sign will have to flip

so the answer will be

x>-2

Answer:

entire orchestra I'm gonna say

Answer:

A.) -2<y<3 is the range of the graph

Answer:

C

Step-by-step explanation:

Range refers to the y-values of a function. The line begins at y = -2 and ends at y = 3. Thus, the range is -2 to 3, C.

Answer:

Step-by-step explanation:

Collinear points A, B, and C and point B being midpoint of AC means:

AB = BC

12x - 398  =  22

   + 398      + 398

 12x = 420

  ÷12    ÷12  

    x = 35

Answer:

Q1:

[tex]-5\sqrt{27c^2}[/tex]

[tex]-5\sqrt{27}\sqrt{c^2}[/tex]

[tex]-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}[/tex]

[tex]-5\times3\sqrt{3}\sqrt{c^2}[/tex]

[tex]-5\times3\sqrt{3}c[/tex]

[tex]-15\sqrt{3}c[/tex]

Q2:

[tex]5\sqrt{72}-3\sqrt{32}[/tex]

[tex]5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}[/tex]

[tex]5\times6\sqrt{2}-3\times4\sqrt{2}[/tex]

[tex]30\sqrt{2}-12\sqrt{2}[/tex]

[tex]18\sqrt{2}[/tex]

Q3:

[tex]\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}[/tex]

[tex]\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}[/tex]

[tex]6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}[/tex]

[tex]16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}[/tex]

Q4:

[tex]\sqrt{15n^2}\sqrt{10n^3}[/tex]

[tex]\sqrt{15}n\sqrt{10n^3}[/tex]

[tex]\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}[/tex]

[tex]\sqrt{15}\sqrt{10}n^2\sqrt{n}[/tex]

[tex]\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}[/tex]

[tex]5\sqrt{3}\sqrt{2}n^2\sqrt{n}[/tex]

[tex]5\sqrt{6}n^2\sqrt{n}[/tex]

Q5:

[tex]\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}[/tex]

[tex]\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}[/tex]

Cancel off [tex]\sqrt{x}[/tex]:

[tex]\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}[/tex]

Cancel off [tex]y:[/tex]

[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}[/tex]

Cancel off [tex]\sqrt{y} :[/tex]

[tex]\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}[/tex]

Multiply [tex]\sqrt{5}[/tex] on the numerator and denominator:

[tex]\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}[/tex]

[tex]\frac{\sqrt{15}\sqrt{x}}{20}[/tex]

sorry i pushed add answer