What is the area of the square?

Answer:

The constant of  proportionality is 7.87.

Step-by-step explanation:

The relation between x and y is given by the equation :

y = 7.87x

y is directly proportional to x i.e.

y ∝ x

To remove the constant of proportionality, a constant 7.87 is inserted. Hence, the constant of  proportionality is 7.87.

Answer:

follow me please and give thanks

Answer: 360>5.5+36.41d

Step-by-step explanation:

Answer:

(x + y) (6 x - 9 y + 2)

6 x^2 - 3 x y + 2 x - 9 y^2 + 2 y

1\/24 (12 x - 3 y + 2)^2 + 1\/24 (-225 y^2 + 60 y - 4)

Step-by-step explanation:

its one of these 3 answers

Answer:

56

Step-by-step explanation:

Hope this helps

Answer:

56

Step-by-step explanation:

56×1=56

Answer:

X= -10

Step-by-step explanation:

Answer:

A. c = kn

Step-by-step explanation:

The cost c varies directly as the numbers n of pencils

This means that c is a multiplication of a constant by n, which is the number of pencils. So the equation for the cost is given by:

[tex]c = kn[/tex]

In which k is the constant of proportionality, that is, the cost of each pencil. So the correct answer is given by option A.

Answer:

8x + 245

Step-by-step explanation:

8(x + 30) + 5

8x + 240 +5

8x + 245

good luck, i hope this helps :)

Answer:

Step-by-step explanation:

x-5(x-1) = x- (2x-3)​

x  + x *(-5) + (-1) * (-5) = x +  2x*(-1) + (-3)*(-1) {use distributive property}

x - 5x + 5 = x - 2x +3   {Combine like terms}

    -4x + 5 = - x +3           {Add 'x' to both sides}

-4x + 5 + x  = -x + x + 3

       -3x + 5 = 3           {subtract 5 from both sides}

            -3x = 3 - 5

            -3x = -2           {Divide both sides by (-3)}

              x = -2/-3

               x = 2/3

Answer:

624

Step-by-step explanation:

I hope it helps i did the test  btw <3

Answer:

624

Step-by-step explanation:

I also did that same exact test. K12 right? That is what I go to. Anyway that answer is correct. Your welcome!

Answer:

honestly I don't know the answer

Answer:

3x2+15x=18

Step 1: Subtract 18 from both sides.

3x2+15x−18=18−18

3x2+15x−18=0

Step 2: Factor left side of equation.

3(x−1)(x+6)=0

Step 3: Set factors equal to 0.

x−1=0 or x+6=0

x=1 or x=−6

Answer:

A

I worked them out myself so if their wrong uh please don't get mad I tried my best.

Step-by-step explanation:

3x (2) + 15x = 18                               3x (2) + 15x = 18

6x + 15x = 18                                     6x + 15x = 18  

-6x + -6x = 18                                            -18     -18

--------------------------                             ------------------------

0 + 9x = 18                                            6x + -3 = 0

   ------  -------                                         -3 +  -3

      18  18                                           --------------------

          x = 2                                              -3 + 0

                                                                    X = -3

Answer:

The proof is done in the step-by-step explanation below.

Step-by-step explanation:

We are given the following identity:

[tex]\frac{\sin{A}\tan{A}}{1-\cos{A}}[/tex]

And we have to show that this is equals to:

[tex]1 + \sec{A}[/tex]

Multiplying numerator and denominator by the conjugate of the denominator:

[tex]\frac{\sin{A}\tan{A}}{1-\cos{A}} \times \frac{1+\cos{A}}{1+\cos{A}}[/tex]

[tex]\frac{\sin{A}\tan{A}(1+\cos{A})}{1 - \cos^2{A}}[/tex]

We use these following identities:

[tex]\sin^2{A} + \cos^2{A} = 1[/tex]

So

[tex]1 - \cos^2{A} = \sin^2{A}[/tex]

Also:

[tex]\tan{A} = \frac{\sin{A}}{\cos{A}}[/tex]

Then

[tex]\frac{\sin{A}\sin{A}(1+\cos{A})}{\cos{A}\sin^2{A}}[/tex]

[tex]\frac{\sin^2{A}(1+\cos{A})}{\cos{A}\sin^2{A}}[/tex]

[tex]\frac{1 + \cos{A}}{\cos{A}}[/tex]

[tex]\frac{1}{\cos{A}} + \frac{\cos{A}}{\cos{A}}[/tex]

[tex]\frac{1}{\cos{A}} + 1[/tex]

Since:

[tex]\sec{A} = \frac{1}{\cos{A}}[/tex]

We have that:

[tex]1 + \sec{A}[/tex]

Thus, the proof is done.

Answer:

Good luck Dude

Step-by-step explanation:

Answer

I think A or c

Step-by-step explanation:

Your answer to this would be A, The table and equation of the same slope.

To find this, just divide Y by X. For ex, this could look something like 12 divided 4, 15 divided by 5, or 18 divided by 6.

To figure this out too, you can plug in the X and Y components into the equation to see if it checks out.

If you need any further help, please do not hesitate to ask or message me!!

Answer

there will be 6 on all three pages

Step-by-step explanation:

divide 18 by 3

Answer:

the correct answer is the last one to the right side

Answer:

Equation :

f(x) = ³√x+2

See image.

I hope the image helps.

Answer:

The estimated size of the population in 10 days is of 1372 mosquitos.

Step-by-step explanation:

Population after t days:

The population after t days is given by:

[tex]P(t) = P(0)e^{rt}[/tex]

In which P(0) is the initial population and r is the growth rate, as a decimal.

P(0)=574.

So

[tex]P(t) = 574e^{rt}[/tex]

P'(0)=50

[tex]P^{\prime}(t) = 574re^{rt}[/tex]

Since P'(0)=50

[tex]574r = 50[/tex]

[tex]r = \frac{50}{574}[/tex]

[tex]r = 0.0871[/tex]

So

[tex]P(t) = 574e^{0.0871t}[/tex]

Estimate the size of the population in 10 days

This is P(10).

[tex]P(10) = 574e^{0.0871*10} = 1372[/tex]

The estimated size of the population in 10 days is of 1372 mosquitos.

The size of the population of mosquito follows an exponential model.

The size of the population in 10 days is 1370

The given parameters are:

[tex]\mathbf{P(0) = 574}[/tex]

[tex]\mathbf{P'(0) = 50}[/tex]

An exponential function is represented as:

[tex]\mathbf{P(t) = P(0) \times e^r^t}[/tex]

So, we have:

[tex]\mathbf{P(t) = 574 \times e^r^t}[/tex]

Differentiate

[tex]\mathbf{P'(t) = 574r}[/tex]

Substitute 0 for t

[tex]\mathbf{P'(0) = 574r}[/tex]

Substitute [tex]\mathbf{P'(0) = 50}[/tex]

[tex]\mathbf{50 = 574r}[/tex]

Divide both sides by 574

[tex]\mathbf{0.087 = r}[/tex]

So, we have:

[tex]\mathbf{r = 0.087 }[/tex]

The function becomes

[tex]\mathbf{P(t) = 574 \times e^r^t}[/tex]

[tex]\mathbf{P(t) = 574 \times e^{0.087t}}[/tex]

In 10 days, t = 10.

So, we have:

[tex]\mathbf{P(10) = 574 \times e^{0.087 \times 10}}[/tex]

[tex]\mathbf{P(10) = 574 \times e^{0.87}}[/tex]

Solve

[tex]\mathbf{P(10) = 1370}[/tex]

Hence, the size of the population in 10 days is 1370

Read more about exponential functions at:

https://brainly.com/question/11487261

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

[tex]2 \sqrt{13} [/tex]

that is your answer

Answer:

5m•5m•5m

Step-by-step explanation:

so you  multiply the factor by itself as many times as the exponent says so if the factor is 5m you would multiply it by the exponent which in this case is 3

5m.5m.5m and 125m³  is the equivalent expressions of the expression (5m)³.

An expression is combination of variables, numbers and operators.

The given expression is (5m)³

We have to find the equivalent expression of (5m)³

Equivalent expressions are expressions that work the same even though they look different

(5m)³ can be written as 5m.5m.5m

The value of five cube is one hundred twenty five.

125m³

Hence, 5m.5m.5m and 125m³  is the equivalent expressions of the expression (5m)³.

To learn more on Expressions click:

https://brainly.com/question/14083225

#SPJ2

Answer:

1.-179

2.68

3. 11

4. 25

5. -734

Answer:

x=5.6  y=4.8

Step-by-step explanation:

Answer:

The scores within one standard deviation of the mean are: 77, 79, 80, 83, 87, 88

Step-by-step explanation:

The mean of the data is 83 and the standard deviation is 6.5, find scores within 1 standard deviation of the mean:

Between

83 - 6.5 = 76.5

83 + 6.5 = 89.5

So:

The scores within one standard deviation of the mean are: 77, 79, 80, 83, 87, 88

Answer:

See Explanation

Step-by-step explanation:

Given

The given side lengths are not clear enough:

So, I will give a general explanation.

From the question, we understand WXYZ is dilated to produce W'X'Y'Z

This implies that the sides of WYZY is multiplied by the scale factor (k) to give W'X'Y'Z'

i.e.

[tex]ZW *k =Z'W'[/tex]

Divide both sides by k to get side length ZW

[tex]ZW = \frac{Z'W'}{k}[/tex]

Assume that:

[tex]k = 4[/tex] and

[tex]Z'W' = 28[/tex]

[tex]ZW = \frac{Z'W'}{k}[/tex]

[tex]ZW = \frac{28}{4}[/tex]

[tex]ZW = 7[/tex]

Apply these steps and you will get your answer