the answer is 80
you take 9 x 8 and get 72 then you just add 8 to it and get 80.
1 point
A 40-acre farm yields 600 bushels of wheat. At the same rate, how much
wheat would a 75-acre farm yield?
no. of bushels yield at 40 acre farm=600
no of bushels yield at 1 acre farm=15
no. of bushels yield at 75 acre farm=15×75
=1125
PLEASE HELP ME !!!!!!!!
Verify that parallelogram ABCD with vertices A(-5, -1), B(-9, 6), C(-1, 5), and D(3, is a rhombus by showing that it is a parallelogram with perpendicular diagonals.
multiplication of the gradients of the two diagonals is equals to -1 if they are perpendicular
Is 13:15 and 30:26 a pair of equivalent ratios and why?
Given:
The two ratios are 13:15 and 30:26.
To find:
Whether the given ratios are equivalent or not.
Solution:
Two ratios are equivalent if the values of the ratio are equal after simplification.
[tex]13:15=\dfrac{13}{15}[/tex]
And,
[tex]30:26=\dfrac{30}{26}[/tex]
[tex]30:26=\dfrac{15}{13}[/tex]
[tex]30:26=15:13[/tex]
The first ratio is 13:15 and the value of second ratio after simplification is 15:13 both ratios are different, so,
[tex]\dfrac{13}{15}\neq \dfrac{30}{26}[/tex]
Therefore, the required answer is "No", the given ratios are not a pair of equivalent ratios.
how do you describe the graph of |x| < 12 brainly
Answer:
Describe the two functions f(x) and g(x) , using the terms increasing, decreasing, maxima and minima. The graph of f(x) is periodic.
Answer:
Step-by-step explanation:
Use the diagram below to find x and each missing angle.
What is the area of the fire pit? (Use 3.14 for pi.)
Answer:
[tex]Area = 65.94[/tex]
Step-by-step explanation:
I will assume that the shaded region is the fire pit
Given
[tex]R = 5[/tex]
[tex]r = 2[/tex]
Required
Determine the area of the fire pit
First, calculate the area of the big circle.
[tex]A_2 = \pi R^2[/tex]
Area of the small is:
[tex]A_1 = \pi r^2[/tex]
The area of the pit is:
[tex]Area = A_2 - A_1[/tex]
[tex]Area = \pi R^2 - \pi r^2[/tex]
[tex]Area = \pi (R^2 - r^2)[/tex]
[tex]Area = 3.14 (5^2 - 2^2)[/tex]
[tex]Area = 3.14 (25 - 4)[/tex]
[tex]Area = 3.14 * 21[/tex]
[tex]Area = 65.94[/tex]
Find the measure of S
Answer:
151°
Step-by-step explanation:
Pentagons interior angles are always 540°. So to solve, you must put
540= (5x+2)+(10x-3)+(8x-19)+(7x-11)+(13x-31). After solving this you will get x=14 and you can now substitute x in for measure s.
13(14) -31
182 - 31
measure of s = 151°
Answer: 151
Step-by-step explanation:
Step-by-step explanation:Pentagons interior angles are always 540°.
So to solve, you must put 540= (5x+2)+(10x-3)+(8x-19)+(7x-11)+(13x-31).
After solving this you will get x=14 and you can now substitute x in for measure s.
13(14) -31182 - 31
measure of s = 151°
The safety officers of a mining company take an SRS of 500500500 employees and finds that 15\, percent of the sampled employees wear contact lenses. The safety officers may take several more samples like this. Suppose it is really 12\, percent of the approximately 34{,}00034,00034, comma, 000 employees in the company who wear contact lenses. What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses
Answer:
The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
12% of the employees wear contact lenses.
This means that [tex]p = 0.12[/tex]
Samples of 500:
This means that [tex]n = 500[/tex]
What are the mean and standard deviation of the sampling distribution of the proportion of employees who wear contact lenses?
Mean:
[tex]\mu = p = 0.12[/tex]
Standard deviation:
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.12*0.88}{500}} = 0.0145[/tex]
The mean of the sampling distribution of the proportion of employees who wear contact lenses is 0.12 and the standard deviation is 0.0145.
Find the length of the side and I’ll give brainlyist
Answer:
the answer is about 7.5
Step-by-step explanation:
hope this helps
tell me if you want me to explain it
Doughnuts are sold in bag and cartons. A bag holds 4 doughnuts and a carton holds 10 doughnuts. Tome buys b bags of doughnuts and c cartons of doughnuts. He buys a total of t doughnuts. Write down the formula for t in terms of b and c
Answer:
[tex]t = 4b + 10c[/tex]
Step-by-step explanation:
Given
1 bag = 4 doughnuts
1 carton = 10 doughnuts
Required
Determine the amount of doughnuts in b bags and c cartons
If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts
If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts
So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:
i.e.
[tex]t = 4b + 10c[/tex]
The probability of an event occurring is 0.61. Which of the options below show the probability of an event that is less likely to occur? Select all that apply.
Water is leaking out of an inverted conical tank at a rate of 12,500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate (in cm3/min) at which water is being pumped into the tank. (Round your answer to the nearest integer.)
Answer:
12500cm x3= 37500
6x3=18
37500+18=37518
If there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain ,how many boxes of labels remain?
Answer:
Rounded to the nearest integer, there are 32 boxes of labels left.
Step-by-step explanation:
Since there are 125 boxes of prescription bottle labels at the beginning of inventory cycle, and 25 3/4 remain, we can determine how many boxes of labels remain through the following mathematical operations:
3/4 = 0.75
100 = 125
25.75 = X
25.75 x 125/100 = X
3218.75 / 100 = X
32.1875 = X
Thus, rounded to the nearest integer, there are 32 boxes of labels left.
Evaluate the expression: 16.2 x 2 + 1/2 x 8.5 x 12
Answer:
83.4
Step-by-step explanation:
16.2 x 2
=
32.4 +
1/2 x 8.5 x 12
=
51 + 32.4 = 83.4
Hope this helps!
I need help with this also
Answer:
Part A: $336.4
Part B:279.2645625
Step-by-step explanation:
$320+5.125% tax = 336.4
Part B:$279.2645625-5.125% tax = 279.2645625 bucks.
Thank you and good luck cheating
Find the value of 0.7 x 0.08
Answer:
0.056
Step-by-step explanation:
I used my calculator, not much work to show :)
Answer:
The answer for 0.7 x 0.08 is 0.056.
Explantion:
I am smart like that.
I am built different.
Ms.Gallegos burns 236 calories
What is 23x56÷67-68?
Hurry plz
Me give brainliest
Thanks in advance
Answer:
-48.4328358209
Step-by-step explanation:
hope this helps!!!
Answer:
If you meant 68-67 then it would be 1288
But if you meant 67-68 it is -1288
(I really hope this isn't hard to understand).
Find the distance between (-5,6)and (3,2).
Answer:
[tex]\displaystyle d = 4\sqrt{5}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Point (-5, 6) → x₁ = -5, y₁ = 6
Point (3, 2) → x₂ = 3, y₂ = 2
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formulas]: [tex]\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}[/tex][Distance] [√Radical] (Parenthesis) Add/Subtract: [tex]\displaystyle d = \sqrt{(8)^2+(-4)^2}[/tex][Distance] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{64+16}[/tex][Distance] [√Radical] Add: [tex]\displaystyle d = \sqrt{80}[/tex][Distance] [√Radical] Simplify: [tex]\displaystyle d = 4\sqrt{5}[/tex]A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover, softcover, and plastic (for infants). At the beginning of January, the central computer showed the following books in stock.
Hard Soft Plastic
San Francisco 1,000 2,000 6,000
Los Angeles 1,000 6,000 2,000
Its sales in January were as follows: 600 hardcover books, 1,200 softcover books, and 1,900 plastic books sold in San Francisco, and 300 hardcover, 200 softcover, and 400 plastic books sold in Los Angeles. The bookstore chain actually maintained the same sales figures for the first 6 months of the year. Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 600 hardcover, 600 softcover, and 600 plastic books to Los Angeles.
(a) Use matrix operations to determine the total sales over the 6 months, broken down by store and type of book.
Hard Soft Plastic
San Francisco
Los Angeles
(b) Use matrix operations to determine the inventory in each store at the end of June.
Hard Soft Plastic
San Francisco
Los Angeles
Answer:
a. Sales from January to June: Matrix B6
Hard Soft Plastic
San Francisco 3,600 7,200 11,400
Los Angeles 1,800 1,200 2,400
b) Ending Inventory: Matrix D:
Hard Soft Plastic
San Francisco 400 3,200 3,000
Los Angeles 2,800 8,400 3,200
Step-by-step explanation:
a) Data and Calculations:
Stock on January 1: Matrix A
Hard Soft Plastic
San Francisco 1,000 2,000 6,000
Los Angeles 1,000 6,000 2,000
Sales in January: Matrix B
Hard Soft Plastic
San Francisco 600 1,200 1,900
Los Angeles 300 200 400
Restocking: Matrix C
Hard Soft Plastic
San Francisco 500 1,400 1,400
Los Angeles 600 600 600
Total Sales over the first 6 months =
Matrix B * 6 = Matrix B6
Sales in January: Matrix B
Hard Soft Plastic
San Francisco 600 1,200 1,900
Los Angeles 300 200 400
* 6
=
Sales from January to June: Matrix B6
Hard Soft Plastic
San Francisco 3,600 7,200 11,400
Los Angeles 1,800 1,200 2,400
Matrix C6 = Matrix C * 6
=
Restocking: Matrix C6
Hard Soft Plastic
San Francisco 3,000 8,400 8,400
Los Angeles 3,600 3,600 3,600
Inventory at the end of June =
Matrix A + Matrix C6 - Matrix B6
= Matrix D
Stock on January 1: Matrix A
Hard Soft Plastic
San Francisco 1,000 2,000 6,000
Los Angeles 1,000 6,000 2,000
+
Restocking: Matrix C6
Hard Soft Plastic
San Francisco 3,000 8,400 8,400
Los Angeles 3,600 3,600 3,600
-
Sales from January to June: Matrix B6
Hard Soft Plastic
San Francisco 3,600 7,200 11,400
Los Angeles 1,800 1,200 2,400
Ending Inventory: Matrix D:
Hard Soft Plastic
San Francisco 400 3,200 3,000
Los Angeles 2,800 8,400 3,200
f(x) = 2x² + 4x - 5
g(x) = 6x3 – 2x2 + 3
Find (f – g)(x).
A. (f – g)(x) = –6x3 + 4x2 + 4x – 2
B. (f - g)(x) = 6x + 4x – 2
C. (f - g)(x) b= 6x? – 4x² - 4x + 8
D. (f - g)(x) = –6x2 + 4x2 + 4x – 8
The required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8
Given the following functions
f(x) = 2x² + 4x - 5
g(x) = 6x³ – 2x² + 3
In order to get the required function (f-g)(x), we will have to take the difference of the function as shown:
(f – g)(x) = f(x) - g(x)
Substitute the given parameters into the expression
(f – g)(x) = 2x² + 4x - 5 - (6x³ – 2x² + 3)
Expand
(f – g)(x) = 2x² + 4x - 5 - 6x³ + 2x² - 3
Collect the like terms
(f – g)(x) = 2x²+2x²- 6x³ + 4x -5 -3
(f – g)(x) = - 6x³+ 4x² + 4x -5 -3
(f – g)(x) = - 6x³+ 4x² + 4x - 8
Hence the required difference in the expression (f – g)(x) is - 6x³+ 4x² + 4x - 8
Learn more here: https://brainly.com/question/17431959
Solve the equation: p2 - 4p + 4 = 0.
Perfect square trinomial
[tex] \boxed{ a^2 \pm 2ab+b^2 = (a \pm b)^2 } [/tex]
Using the perfect square trinomial
[tex] p^2 - 4p + 4 = 0 [/tex]
[tex] p^2 - 2(2p) + (2)^2 = 0 [/tex]
[tex] (p-2)^2 = 0 [/tex]
[tex] (p-2) = 0 [/tex]
[tex] p = 2 [/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\bold{p^2-4p+4=0}[/tex]
[tex]\text{FACTOR the LEFT side of your equation}\\\bold{(p-2)(p-2)=0}[/tex]
[tex]\text{SET each of your FACTORS TO EQUAL to 0}\\\bold{p-2=0\ or\ p-2=0}[/tex]
[tex]\text{SIMPLIFY the equations\ above and you will have your answer}[/tex]
[tex]\boxed{\boxed{\bold{Answer: \large\text{\bf{p = 2}}}}}\huge\checkmark[/tex]
[tex]\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Please show how to do
Answer:
Slope = -3.5
Step-by-step explanation:
Find the slope using any two given pair of values. Let's use (6, -21) and (12, -42).
Slope = ∆y/∆x
Slope = (-42 -(-21)) / (12 - 6)
Slope = -21/6
Slope = -3.5
What is the solution to the equation Sqrt 2x+6-Sqrt x+4 = 1?
Answer:
its 5
Step-by-step explanation:
Which of the following expression is equivalent to 6^-7?
Answer:
B
Step-by-step explanation:
Pls answer ASAP it’s due tomorrow
Answer:
729
Step-by-step explanation:
Simplify the expression 1 + 4.25n + 3/2p -3 + (-2p) + 5/4n
Answer:
5.5n -2 -0.5p
Step-by-step explanation:
Make Everything to either decimals or fractions.
then simplify as shown
In ΔDEF, the measure of ∠F=90°, the measure of ∠E=41°, and FD = 79 feet. Find the length of DE to the nearest tenth of a foot.
Answer:
120.4ft
Step-by-step explanation:
Find the diagram in the attachment.
The triangle shown is a right angled triangle with the side DE as the hypotenuse, EF is adjacent side while DF is the opposite side.
To get DE, we will use the SOH CAH TOA trigonometry identity
Using CAH which is defined as:
Cos(theta) = Adjacent/Hypotenuse
Cos 79°= 23/Hypotenuse
Hypotenuse = 23/cos79°
Hypotenuse = 23/0.191
Hypotenuse = 120.4feet
DE = 120.4feet (to nearest tenth)
The sum of 3 and
twice the number n