what is one and three hundred twenty-four thousand in decimal

Answer:

f(-3) = 9

Step-by-step explanation:

Step 1: Define

f(-3) = x = -3

f(x) = x²

Step 2: Substitute and Evaluate

f(-3) = (-3)²

f(-3) = 9

Answer:

233

Step-by-step explanation:

Step-by-step explanation:

43+[(96/8=12)×5]-42

=43+60-42

=103-42

=61

Answer:

6⁴

Step-by-step explanation:

We see that we are multiply 4 6's together. That means we can simply just raise 6 to the 4th power as we are multiplying 6 x 6 x 6 x 6.

Hey there!

[tex]6*6*6*6 \text { as a power}[/tex]

If you want to find this number to be written as a power, you will need to see how many times the number is being multiplied by 6.

[tex]6(1)*6(2)*6(3)*6(4)\\\text {It was multiplied 4 times}[/tex]

Since it was multiplied by 4 times, you will write it as:

[tex]6^4(ANSWER)[/tex]

Hope this helps!

[tex]\text {-TestedHyperr}[/tex]

Answer:

she would run 6.4 miles in 48 min

Step-by-step explanation:

hope it helps

Answer:

Yes it is.

Step-by-step explanation:

-(5/12) = -*5/12 = -5/12

5/-12 = -5/12

Best of Luck!

Answer:

The answer for the first one is 1 and the second answer is 12i.

Step-by-step explanation:

The value of the given imaginary number i¹² will be 1 thus option (A) is correct.

A complex number is the sum of a real number and an imaginary number.

The idea of a complex number has come by solving a quadratic equation that has root as negative under root.

If we solve x² + 1 = 0 ⇒ x = √(-1) which is called as iota(i).

The value of iota(i) is given as i = √(-1).

By the law of indices,

i¹² = (i²)⁶

⇒ (-1)⁶

Since the even exponents of a negative number give positive output thus  (-1)⁶ = 1.

Thus, i¹² = 1

Hence "The value of the given imaginary number i¹² will be 1".

To learn more about complex numbers,

brainly.com/question/10251853

#SPJ2

Answer:

1:00 PM

Step-by-step explanation:

1500 hours is 3 PM. 3-2 = 1 So that would be 1 o'clock PM.

Answer:

36 units^2

Step-by-step explanation:

The area of a triangle is 1/2*base*height. Knowing this is just 2 triangles means you solve for 1 triangle, then multiply that by 2

Answer:

[tex]A=36\text{ units}^2[/tex]

Step-by-step explanation:

The area of a rhombus is given by the formula:

[tex]A=\frac{d_1\cdot d_2}{2}[/tex]

Namely, it is half of one diagonal multiplied by the other diagonal.

So, to find the area, we just need to find the length of AC and BD, multiply them together, and then divide by 2.

To find their lengths, we can use the distance formula. The distance formula is:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

So, let's find the lengths of each diagonal:

AC:

Point A is (-1,0) and Point C is (-1,-6). Let (-1,0) be (x₁, y₁) and let (-1,-6) be (x₂, y₂). Substitute this into our formula:

[tex]d=\sqrt{(-1-(-1))^2+(-6-0)^2[/tex]

Simplify:

[tex]d=\sqrt{(-1+1)^2+(-6-0)^2[/tex]

Add or subtract:

[tex]d=\sqrt{(0)^2+(-6)^2[/tex]

Square:

[tex]d=\sqrt{36}[/tex]

Take the square root:

[tex]d=6[/tex]

So, the length of diagonal AC is 6.

BD:

Point B is at (5,-3) and Point D is at (-7,-3). Let (5,-3) be (x₁, y₁) and let (-7,-3) be (x₂, y₂). Substitute this into our formula:

[tex]d=\sqrt{(-7-5)^2+(-3-(-3))^2[/tex]

Simplify:

[tex]d=\sqrt{(-7-5)^2+(-3+3)^2[/tex]

Add or subtract:

[tex]d=\sqrt{(-12)^2+(0)^2[/tex]

Square:

[tex]d=\sqrt{144}[/tex]

Take the square root:

[tex]d=12[/tex]

So, our second diagonal is 12 units long.

Now, to find the area, substitute 6 and 12 into our formula. So:

[tex]A=\frac{d_1\cdot d_2}{2}[/tex]

Substitute 6 for d₁ and 12 for d₂. So:

[tex]A=\frac{(6)(12)}{2}[/tex]

Multiply:

[tex]A=\frac{72}{2}[/tex]

Divide:

[tex]A=36\text{ units}^2[/tex]

So, the area of the rhombus is 36 squared units.

And we're done!

Notes:

Of course, instead of using the distance formula, you can also just count :)

Answer:

b

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer: 8/15

Step-by-step explanation: find the LCD which is 15 in this case,  then multiply 1/3 by 5/5 which equals 5/15. then multiply 1/5 by 3/3 which equals 3/15 then add them together =8/15

Answer:

.75

Step-by-step explanation:

12/16 = 75/100

100/4 = 25

16/4 = 4

3 x 4 = 12

3 x 4 = 75

12/16 = 3/4

75/100 = 3/4

Hopefully this helps you

pls mark brainlest

Answer: 13.71

Step-by-step explanation:

20+6+17+10+19+15+9=96

96/7=13.71

Answer:

1. See Explanation for Sample Space

2. [tex]P(10) = \frac{1}{12}[/tex]

3. [tex]P(6) = \frac{5}{36}[/tex]

Step-by-step explanation:

Given

Roll of Two die

Solving (1): The Sample Space

Represent the first dice with S1 and the second with S2

[tex]S_1 = \{1,2,3,4,5,6\}[/tex]

[tex]S_2 = \{1,2,3,4,5,6\}[/tex]

The sample space of both die is:

[tex]S = (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)[/tex][tex](4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(55,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}\}[/tex]

Solving (2): Probability of Sum being 10

First, we need to add the outcome of each roll in (1) above:

[tex]S = \{2,3,4,5,6,7, 3,4,5,6,7,8, 4,5,6,7,8,9, 5,6,7,8,9,10, 6,7,8,9,10,11 7,8,9,10,11,12\}[/tex][tex]n(S) = 36[/tex]

[tex]n(10) = 3[/tex]

The required probability is:

[tex]P(10)= \frac{3}{36}[/tex]

[tex]P(10) = \frac{1}{12}[/tex]

Solving (3): Probability of Sum being 6

[tex]n(S) = 36[/tex]

[tex]n(6) = 5[/tex]

The required probability is:

[tex]P(6) = \frac{5}{36}[/tex]

Answer:

198 degrees

Step-by-step explanation:

Such a shape is called a 20-gon, such shapes have an interior angle of 162. Hence, the exterior angle = 360 (Complete angle) - 162 (The interior anlge) = 198 degrees, Hope my answer helps you, Thank you, and please add me as brainliest! Thanks

Answer:

Step-by-step explanation:

Such a shape is called a 20-gon, such shapes have an interior angle of 162. Hence, the exterior angle = 360 (Complete angle) - 162 (The interior anlge) = 198 degrees, Hope my answer helps you, Thank you, and please add me as brainliest! Thanks and Godbless

Answer:

h(2)= 8

Step-by-step explanation:

h(2) = 2^2 +2(2)

4 + 4

h(2)=8

Answer:

Third quadrant

Step-by-step explanation:

Answer:

Quadrant III

Step-by-step explanation:

(-13, -12) is located in quadrant III because both the x values and y values are negative in the ordered pair, therefore they will be graphed on the part of the coordinate plane where the x and y values are also both negative simultaneously.

I included a photo so it is easier to visualize.

Answer:

[tex]B(x_2,y_2)= (20,12)[/tex]

Step-by-step explanation:

Given

[tex]A = (0,0)[/tex]

[tex]Ratio; m : n = 1 : 3[/tex]

[tex]Point\ at\ 1 : 3 = (5,3)[/tex]

Required

Coordinates of B

This question will be answered using line ratio formula;

[tex](x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})[/tex]

In this case:

[tex](x,y) = (5,3)[/tex]

[tex](x_1,y_1) = (0,0)[/tex]

[tex]m : n = 1 : 3[/tex]

Solving for [tex](x_2,y_2)[/tex]

[tex](x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})[/tex] becomes

[tex](5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})[/tex]

[tex](5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})[/tex]

[tex](5,3) = (\frac{x_2}{4},\frac{y_2}{4})[/tex]

Comparing the right hand side to the left;

[tex]\frac{x_2}{4} = 5[/tex] -- (1)

[tex]\frac{y_2}{4} = 3[/tex] -- (2)

Solving (1)

[tex]x_2 = 5 * 4[/tex]

[tex]x_2 = 20[/tex]

Solving (2)

[tex]y_2 = 3 * 4[/tex]

[tex]y_2 = 12[/tex]

Hence;

[tex]B(x_2,y_2)= (20,12)[/tex]

Answer:

the answer is 6

Step-by-step explanation:

hope this helps!!!

Answer:

18

Step-by-step explanation:

6 × 4 + 2 ÷ 2 - 7

24 + 1 - 7

25 - 7

= 18

thanks

Answer:

16

Step-by-step explanation:

The mean of a group of values is calculated as

mean = [tex]\frac{sum}{count}[/tex]

Given 5 numbers with a mean of 12, then

[tex]\frac{sum}{5}[/tex] = 12 ( multiply both sides by 5 )

sum = 60

let the number removed be x , then

[tex]\frac{60-x}{4}[/tex] = 11 ( multiply both sides by 4 )

60 - x = 44 ( subtract 60 from both sides )

- x = - 16 ( multiply both sides by - 1 )

x = 16

The number removed was 16

Answer:

-20

Explanation:

(11 + 1) - 6 · 8 + 16

11 + 1 = 12

12 - 6 · 8 + 16

6 · 8 = 48

12 - 48 + 16

= -20

Answer:

24,840,000

Step-by-step explanation:

The number in the ten thousands place is 3.  The number to the right of it is 7.  Since 7 ≥ 5, we round up the 3 to a 4.

24,837,618 ≈ 24,840,000

Answer:

please put the full question

I think the question is incorrect please repeat again.....

Answer: 512/9 and 6,144/81

Step-by-step explanation:

The sequence is:

18, 24, 32, 128/3, ...

Now, is easy to see that it is not an arithmetic sequence, so we can jump to see if this is a geometric sequence.

To see this, we must see at the quotient of two consecutive numbers in the sequence, and that quotient must be the same for any pair of consecutive elements.

24/18 = 1.33...

32/24 = 1.33...

(128/3)/32 = 1.33....

The quotient is constant, then this is a geometric sequence.

Then we can write the n-th term as:

Aₙ = Aₙ₋₁*1.33...

And we first should write 1.33 in a way that is easier to use:

1.33... = 1 + 0.33...

The left side can be writen as:

0.33... = 0.33...*(10/10) = (3.3.../10)

Now we can subtract the initial number:

(3.33..../10) - 0.33... = 3/10 = 0.33...*(9/10)

0.33... = (3*10)/(9*10) = 30/90 = 3/9

then we have:

1.33... = (1 + 3/9) = (9/9 + 3/9) = (12/9)

Then the two next terms are:

(128/3)*(12/9) = 128*4/9 = (512/9)

And the next term is:

(512/9)*(12/9) = (6,144/81)

Then the first six terms are:

18, 24, 32, 128/3, 512/9, 6,144/81

Answer:

see below

Step-by-step explanation:

Given:

Binomial 7 - 25f

Answer:

The area of the surface over R is [tex]\mathbf{ 2 \sqrt{17} + \dfrac{1}{2} \ In ( \sqrt{17} +4)}[/tex]

Step-by-step explanation:

From this study,

The surface area of f(x,y) is expressed by:

[tex]A = \iint_R \sqrt{1 +f^2_x+f^2_y}} \ dA[/tex]

where

[tex]0 \leq x \leq 2 \ and \ 0 \leq y \leq 2[/tex]

Given that:

f(x,y) = 9 - x²

Thus, [tex]f_x = -2x[/tex] and   [tex]f_y = 0[/tex]

However, the area becomes:

[tex]A = \iint_R \sqrt{1+(-2x)^2+0^2} \ dxdy[/tex]

[tex]A = \iint_R \sqrt{1+4x^2} \ dxdy[/tex]

From above, replacing x with [tex]\dfrac{1}{2} \ tan \ u[/tex]

then [tex]dx = \dfrac{1}{2} sec^2 \ udu[/tex]

∴

[tex]\sqrt{1 + 4x^2 } \ dA= \dfrac{1}{2} \iint \sqrt{1 + 4u^2 } \ sec^2 \ udu[/tex]

[tex]\sqrt{1 + 4x^2 } \ dA= \dfrac{1}{2} \iint sec^2 \ udu[/tex]

[tex]\sqrt{1 + 4x^2 } \ dA= \dfrac{1}{2} ( \sqrt{4x^2 + 1x} + \dfrac{1}{2} In \sqrt{4x^2 + 1}+2x)[/tex]

Hence;

[tex]\mathsf{A = \int \limits ^2_0 \begin {bmatrix} \dfrac{1}{2}(\sqrt{4x^2 +1 x}+ \dfrac{1}{2} In ( \sqrt{4x^2+1}+2x \end {bmatrix}^2_0 \ dy}[/tex]

[tex]\mathbf{A = 2 \sqrt{17} + \dfrac{1}{2} \ In ( \sqrt{17} +4)}[/tex]

Therefore, the area of the surface over R is [tex]\mathbf{ 2 \sqrt{17} + \dfrac{1}{2} \ In ( \sqrt{17} +4)}[/tex]