B1:B4 is a search table or a lookup value
Answer:
lookup value
Explanation:
(1) Prompt the user to enter a string of their choosing. Output the string.
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself.
(2) Complete the GetNumOfCharacters() function, which returns the number of characters in the user's string. Use a for loop in this function for practice. (2 pts)
(3) In main(), call the GetNumOfCharacters() function and then output the returned result. (1 pt) (4) Implement the OutputWithoutWhitespace() function. OutputWithoutWhitespace() outputs the string's characters except for whitespace (spaces, tabs). Note: A tab is '\t'. Call the OutputWithoutWhitespace() function in main(). (2 pts)
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself. Number of characters: 46 String with no whitespace: The only thing we have to fear is fear itself.
Answer:
See solution below
See comments for explanations
Explanation:
import java.util.*;
class Main {
public static void main(String[] args) {
//PrompT the User to enter a String
System.out.println("Enter a sentence or phrase: ");
//Receiving the string entered with the Scanner Object
Scanner input = new Scanner (System.in);
String string_input = input.nextLine();
//Print out string entered by user
System.out.println("You entered: "+string_input);
//Call the first method (GetNumOfCharacters)
System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));
//Call the second method (OutputWithoutWhitespace)
System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));
}
//Create the method GetNumOfCharacters
public static int GetNumOfCharacters (String word) {
//Variable to hold number of characters
int noOfCharactersCount = 0;
//Use a for loop to iterate the entire string
for(int i = 0; i< word.length(); i++){
//Increase th number of characters each time
noOfCharactersCount++;
}
return noOfCharactersCount;
}
//Creating the OutputWithoutWhitespace() method
//This method will remove all tabs and spaces from the original string
public static String OutputWithoutWhitespace(String word){
//Use the replaceAll all method of strings to replace all whitespaces
String stringWithoutWhiteSpace = word.replaceAll(" ","");
return stringWithoutWhiteSpace;
}
}
the language is Java! please help
public class Drive {
int miles;
int gas;
String carType;
public String getGas(){
return Integer.toBinaryString(gas);
}
public Drive(String driveCarType){
carType = driveCarType;
}
public static void main(String [] args){
System.out.println("Hello World!");
}
}
I'm pretty new to Java myself, but I think this is what you wanted. I hope this helps!
Write a program that reads in 10 numbers from the user and stores them in a 1D array of size 10. Then, write BubbleSort to sort that array – continuously pushing the largest elements to the right side
Answer:
The solution is provided in the explanation section.
Detailed explanation is provided using comments within the code
Explanation:
import java.util.*;
public class Main {
//The Bubble sort method
public static void bb_Sort(int[] arr) {
int n = 10; //Length of array
int temp = 0; // create a temporal variable
for(int i=0; i < n; i++){
for(int j=1; j < (n-i); j++){
if(arr[j-1] > arr[j]){
// The bubble sort algorithm swaps elements
temp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = temp;
}
}
}
}
public static void main(String[] args) {
//declaring the array of integers
int [] array = new int[10];
//Prompt user to add elements into the array
Scanner in = new Scanner(System.in);
//Use for loop to receive all 10 elements
for(int i = 0; i<array.length; i++){
System.out.println("Enter the next array Element");
array[i] = in.nextInt();
}
//Print the array elements before bubble sort
System.out.println("The Array before bubble sort");
System.out.println(Arrays.toString(array));
//Call bubble sort method
bb_Sort(array);
System.out.println("Array After Bubble Sort");
System.out.println(Arrays.toString(array));
}
}