Answer:
A person's skin color, hair color, dimples, freckles, and blood type are all examples of genetic variations that can occur in a human population.
Explanation:
3. How many grams of aluminum can be heated from 90°C to 120°C if 500 J of heat energy are applied?
(c = 0.900 J/g °C)
We are given:
Initial Temperature = 90°c
Final Temperature = 120°c
Heat applied(ΔH) = 500 Joules
Specific heat(c) = 0.9 Joules / g°C
Mass of Aluminium(m) = ?
Change in temperature:
ΔT = Final temp. - Inital Temp.
ΔT = 120 - 90
ΔT = 30°c
Calculating the mass:
We know the formula:
ΔH = mcΔT
replacing the values:
500 = m(0.9)(30)
500 = m(27)
m = 500/27
m = 18.52 grams
What are the reactants and products of a redox reaction, neutralization reactions, and precipitation reactions?
Answer:
Precipitation reactions are ones in which at least one of the reactants is in the aqueous phase (i.e., dissolved in water), and a solid forms on the product side which was not present on the reactant side. If all the reactants are solid, then a solid product forming should not be called a precipitate. To be called a precipitate, an insoluble product must form from within solution, either from a solid and solute interacting, or from an interaction strictly between solutes.
Explanation:
Please help
Apply your knowledge and understanding of equilibrium constant in solving the following problems:
The equilibrium constant Kc for the reaction below is 170 at 500 K.
Determine whether the reaction mixture is at equilibrium when the concentrations of the components at this temperature are as follows:
[N2]=1.50
[H2]=1.00
[NH3]=8.00
If it is not at equilibrium, state and explain in which direction the reaction will proceed.Multi Line Text.
2()+32() ⇄ 23()
Answer:
The reaction will proceed to the right to attain the equilibrium.
Explanation:
Step 1: Write the balanced equation
2 N₂(g) + 3 H₂(g) = 2 NH₃(g)
Step 2: Calculate the reaction quotient
The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.
Qc = [NH₃]² / [N₂]² × [H₂]³
Qc = 8.00² / 1.50² × 1.00³ = 28.4
Since Qc ≠ Kc, the reaction is not at equilibrium.
Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.
Balanced equation: K2S(aq) + BaCl2(aq) =
Answer:
K2S(aq) + BaCl2(aq) = 2KCl(aq) + BaS(s)
In the image attached, it is explained how the solution is balanced.
The number of atoms of any element in the given chemical formula is the number that is written on the foot of the symbol of that element. The balanced equation is
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)
What is Balanced equation?Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side.
The unbalanced equation is
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]KCl(aq) + BaS(s)
The number of atoms of K on reactant side is 2 while on product side it is 1, so to balance K we need to multiply KCl by 2
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]2KCl(aq) + BaS(s)
The atoms of sulfur on reactant and product side is 1, so it is balanced.
The atoms of Ba on reactant and product side is 1, so it is balanced.
The atoms of Cl on reactant and product side is 2, so it is balanced.
Therefore the balanced equation is
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)
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Question 3 of 20 :
Select the best answer for the question.
3. The atomic number of niobium (Nb) is 41. What's the electron configuration for Nb?
O A. [Ar] 3s 4p?
O B. [Kr] 5s? 5p
O C. [Kr] 4d45s
O D. (Ne) 4d
Answer:
[Kr] 4d4 5s1
Explanation:
Niobium is a chemical element with atomic number 41 which means there are 41 protons and 41 electrons in the atomic structure. The chemical symbol for Niobium is Nb. Neutron Number and Mass Number of Niobium Mass numbers of typical isotopes of Niobium are 93.
Name of Element : Niobium
Atomic Weight : 92.9
Atomic Number : 41
Group : Transition Elements
Electron Configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d3
Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
(a) SO3
(b) N2O (N is central)
(c) CH2C12
Solution :
a). [tex]$SO_3$[/tex]
This compound is known as sulfur trioxide.
The molecular shape of sulfur trioxide is trigonal planer.
And the bond angle is 120°.
b). [tex]$N_2O$[/tex]
This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.
It is linear in shape.
The bond angle between them is 180°.
c). [tex]$CH_2Cl_{2}$[/tex]
This compound is known as the Dichloromethane.
The molecular shape of the compound is tetrahedral.
The bond angles is 120°
At the start of a reaction, there are 0.0249 mol N2,
3.21 x 10-2 mol H2, and 6.42 x 10-4 mol NH3 in a
3.50 L reaction vessel at 375°C. If the equilibrium constant, K, for the reaction:
N2(g) + 3H2(g)= 2NH3(g)
is 1.2 at this temperature, decide whether the system is at equilibrium or not. If it is not, predict in which direction, the net reaction will proceed.
Answer:
Explanation:
The reaction is given as:
[tex]N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}[/tex]
The reaction quotient is:
[tex]Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]
From the given information:
TO find each entity in the reaction quotient, we have:
[tex][NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}[/tex]
[tex][N_2] = \dfrac{0.024 }{3.5}[/tex]
[tex][N_2] = 0.006857[/tex]
[tex][H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}[/tex]
[tex][H_2] = 9.17 \times 10^{-3}[/tex]
∴
[tex]Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135[/tex]
However; given that:
[tex]K_c = 1.2[/tex]
By relating [tex]Q_c \ \ and \ \ K_c[/tex], we will realize that [tex]Q_c \ \ < \ \ K_c[/tex]
The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.
What is the Ksp expression for the dissociation of calcium oxalate?Immersive Reader
(4 Points)
Ksp=[Ca⁺²] x [C₂O₄⁻²]
Ksp=[Ca⁺²]² x [C₂O₄⁻²]
Ksp=[Ca⁺²]⁴ x [C₂O₄⁻²]
Ksp=[Ca⁺²] x [C₂O₄⁻²]²
Answer:
Ksp = [Ca⁺²] × [C₂O₄⁻²]
Explanation:
Step 1: Write the balanced reaction for the dissociation of calcium oxalate
CaC₂O₄(s) ⇄ Ca⁺²(aq) + C₂O₄⁻²(aq)
Step 2: Write the expression for the solubility product constant (Ksp) of calcium oxalate
The solubility product constant is the equilibrium constant for the dissociation reaction, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids nor pure liquids because their activities are 1.
Ksp = [Ca⁺²] × [C₂O₄⁻²]
When elements chemically combine with each other, what do they Form? A. electrons, B. compounds, C. atoms
Answer:
B
Explanation:
When two distinct elements are chemically combined—i.e., chemical bonds form between their atoms—the result is called a chemical compound. Most elements on Earth bond with other elements to form chemical compounds, such as sodium (Na) and Chloride (Cl), which combine to form table salt (NaCl).
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how to solve x² in differential
Answer:
x² = mutiphy by them self
Explanation:
Steven placed an ice cream scoop under hot water before scooping ice cream. Which describes how the ice cream scoop was affected
Answer: Okay so i don't know how i can explain this but.. OK so Steven placed an ice cream scoop right? and put it under hot water so i would say it would make the ice cream scoop hot? and then using it to scoop the ice cream i could say it would be a melting affection i think
Explanation:
im am so sorry pls forgive me is i am wrong i tried my best so at least give me a like for effort.. i hope u have a great day :)
A balloon can be inflated with 4.23 Liters of O2gas at STP. How much will the balloon weigh in grams?
Answer: 6.04 g
Explanation: In STP conditions, amoint of substance
n = V / Vm = 4.23 l / 22.41 l/mol = 0.188755 mol
Molar mass M(O2) = 32 g/mol and
mass m = nM
How many moles of a gas sample are in a 5.0 L container at 205 K and 340 kPa?
(The gas constant is
L kPa
8.31
mol K
)
Round your answer to one decimal place and enter the number only with no units.
Your Answer:
Answer
Answer:
1.0 mole
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 5 L
Temperature (T) = 205 K
Pressure (P) = 340 KPa
Gas constant (R) = 8.31 KPa.L/Kmol
Number of mole (n) =?
Using the ideal gas equation, the number of mole of the gas in the container can be obtained as follow:
PV = nRT
340 × 5 = n × 8.31 × 205
1700 = n × 1703.55
Divide both side by 1703.55
n = 1700 / 1703.55
n = 1.0 mole
Thus, the number of mole of the gas in the container is 1.0 mole
For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.
a. Mg(OH)2
b. CaSO3
c. BaCrO4
d. CaS
1. copper (II) sulfide
2. zinc hydroxide
Answer:
1 - Salts required that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - [tex]CaSO_3[/tex] (Option b) ,[tex]BaCrO_4[/tex] (Option c) and [tex]CaS[/tex] (Option d)
2 - Salts that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - [tex]Mg(OH)_2[/tex] (Option a)
Explanation:
[tex]K_s_p[/tex] values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.
[tex]CuS[/tex] {copper (II)sulfide} dissociates with ions in ratio 1:1 .Because the salts [tex]CaSO_3[/tex] , [tex]BaCrO_4[/tex] and [tex]CaS[/tex] have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.
[tex]K_s_p[/tex] Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.
2. [tex]Zn(OH)_2[/tex] dissociates into ions in ratio 1:2 .
Because the ions in the salt [tex]Mg(OH)_2[/tex] are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.
Hence , Salt 1 is matched with options b , c , d.
Salt 2 is matched with option a.
what is the photo above showing
How many grams of sodium chloride are in 100 mL of 1.25 M sodium chloride?
Answer:
7.3125grams
Explanation:
Molarity is the measure of the molar concentration of a solution. It can be calculated using the formula as follows:
Molarity = number of moles (n) ÷ volume (V)
Based on the information given,
Molarity = 1.25 M
Volume = 100 mL = 100/1000 = 0.1 L
Molarity = n/V
1.25 = n/0.1
n = 1.25 × 0.1
n = 0.125mol
Using the below formula to calculate the mass of NaCl;
mole = mass/molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
0.125 = mass/58.5
mass = 0.125 × 58.5
mass = 7.3125 grams
Is vinegar acidic, alkaline or neutral?
Answer:
Substances over 7 are categorized as basic, with 7 being the neutral point. Water has a pH level of 7. Substances with pH levels under 7 are categorized as acidic. Vinegar is acidic.
Explanation:
You can change it a little if you want. Hope this helps!
Vinegar is acidic. The only vinegar that has alkaline is apple cider vinegar, but all types of vinegar are acidic.
Which of the following
describes the zone of the
ocean where no light reaches?
A. up to 200 meter depth and includes
photosynthetic plants, sea anemones,
sponges, crabs, and clams
B. the "twilight zone" between 200-1000
meters deep and includes whales and octopi
and little life
C. permanent darkness below 1000 meters
with bioluminescent bacteria, bottom
feeders, and angler fish
Answer:
Bathypelagic
54% of the ocean lies in the Bathypelagic (aphotic) zone into which no light penetrates. This is also called the midnight zone and the deep ocean. Due to the complete lack of sunlight, photosynthesis cannot occur and the only light source is bioluminescence.
Explanation:
The small surface zone that has light is the photic zone. The entire rest of the ocean does not have light and is the aphotic zone.
Permanent darkness below 1000 meters with bioluminescent bacteria, bottom feeders, and angler fish is where no light reaches.
What is Darkness?This is referred to the state of being dark as a result of absence of light in the area.
The light ray penetration decreases with increase in depth thereby making areas below 1000 meters dark with bioluminescent bacteria, bottom feeders, and angler fish which is why option C was chosen.
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