What is an equation of the line that passes through the point (7,-7) and is perpendicular to the line x-2y=2x−2y=2?

Answers

Answer 1

Answer:

y=−2x+7

Step-by-step explanation:

The other moron doesn't understand simple math.

Answer 2

An equation of the line that passes through the point (7,-7) and is perpendicular to the line x - 2y = 2 will be  2x + y = 0.

What is Slope of Line ?

We have the given line x - 2y = 2 which is in form ax + by = c As we know that slope of line ax + by = c will be -(a/b).

Therefore For given line x -2y = 2 value of a will be 1 and value of b will be -2. Therefor Slope of given line will be -(a/b) = -(1/-2) = 1/2.

Now As we know that slope of two lines which are perpendicular to each other has product of there slopes as negative of unity that is -1.

Let the slope of line which we have to find be m also we have slope of given line as 1/2.

∴ m(1/2) = -1

∴ (m/2) = -1

∴ m = -1(2)

∴ m = -2.

Now as we know that line passes through the point given as (7,-7) and has slope m = -2.

Therefore equation of a line passing through a point (x₁, y₁) and have slope m will be given as

  y - y₁ = m(x - x₁)

∴ y - (-7) = -2(x - 7)

∴ y + 7 = -2x -(-7)

∴ 2x + y = 7 - 7

∴ 2x + y = 0

For more details about slope of line visit the link below

https://brainly.com/question/16949303

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