Frictional force is the force that causes an object to slow down when it touches another object. Thus, the correct option is C.
What is Frictional force?Frictional force of an object is the force which is generated by the two surfaces which generate due to their contact and slide against each other. A few factors which affect the frictional force are that these forces are mainly affected by the surface texture of the object and the amount of force impelling them together.
Frictional force is mainly of four types which include static friction, sliding friction, rolling friction, and the fluid friction. The frictional force can be given by the formula: F = μN, where μ is a constant.
Therefore, the correct option is C.
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Different satellites orbit the earth with a vast range of altitudes, from just a couple hundred km, all the way to tens of thousands of km above the surface. The international space station (ISS) is in a low earth orbit, just 400km above the surface (you can see it with the naked eye at sunset and sunrise as a bright, moving dot). At this altitude, the acceleration due to gravity has a value of 8.69m/s Assuming that the radius of the earth is 6400km).
1. What is the speed of the ISS? Express your answer to three significant figures and include the appropriate units.
2. What is the orbital period (T) of the ISS in minutes?
Answer:
a) v = 7.69 10³ m / s, b) T = 92.6 min
Explanation:
a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity
a = v² / r
v = [tex]\sqrt{a r}[/tex]
the distance to the ISS is
r = R_earth + d
r = 6400 10³ + 400 10³
r = 6800 10³ m
we calculate
v = [tex]\sqrt{8.69 \ 6800 \ 10^3}[/tex]Ra (8.69 6800 103)
v = [tex]\sqrt{59.09 \ 10^6}[/tex]
v = 7.687 10³ m / s
the result with the correct significant figures
v = 7.69 10³ m / s
b) The speed of the ISS is constant, so we can use the uniform motion relationships
v = d / t
if distance is the orbit distance
d = 2π r
time is called period
v = 2π r / T
T = 2π r / v
let's calculate
T = 2π 6800 10³ /7,687 10³
T = 5.558 10³ s
let's reduce the period to minutes
T = 5.558 10³ s (1 min / 60s)
T = 9.26 10¹ min
T = 92.6 min
what did classical physics predict would happen to the light given of by an object as its tempurtare increased
Answer:
The energy of the light would increase from visible light into the ultraviolet range.
Explanation:
blah blah blah, blah blah BLAH
Plzz answer this question correctly
Answer:
B
Explanation:
F= m×a
450N = 1.5kg × a
450/1.5 = a
a=300m/s²
IM NOT SURE THO
How do I fix my task bar thing
Answer:
go to settings and find what your looking for
Explanation:
An electrically charged point particle with a mass of 1.41 x 10-6 kg is launched horizontally into a uniform electric field with a magnitude of 686 N/C. The particle's initial velocity is 5.39 m/s, directed eastward, and the external electric field is also directed eastward. A short time after being launched, the particle is 9.89 x 10-3 m below and 0.151 m east of its initial position. Determine the net charge carried by the particle, including the algebraic sign ( or -).
Answer:
the net charge carried by the particle is -2.35 × 10⁻⁷ C
Explanation:
Given that;
mass m = 1.41 × 10⁻⁶ kg
Magnitude E = 686 N/C
v = 5.93 m/s
A short time after being launched, the particle is 9.89 x 10-3 m below and 0.151 m east of its initial position
consider vertical;
u =0, y = 9.89 × 10⁻³ m, g = a = 9.8 m/s²
Now, from the second equation of motion;
s = ut + 1/2 × at²
so, y = ut + 1/2 × at²
we substitute
9.89 × 10⁻³ = 0×t + (1/2 × 9.8 × t²)
9.89 × 10⁻³ = 4.9t²
t² = 9.89 × 10⁻³ / 4.9
t² = 0.0201836
t = √0.00201836
t = 0.0449 s
Consider horizontal;
u = 5.93 m/s, a = (qE/m) m/s, t = 0.0449 s, x = 0.151 m
also, from the second equation of motion;
s = ut + 1/2 × at²
so
x = ut + 1/2 × (qE/m) × t²
we substitute
0.151 = (5.93 × 0.0449) + (1/2 × ((q×686)/1.41 × 10⁻⁶) × (0.0449 )²
0.151 = 0.266257 + 0.69149143q / 1.41 × 10⁻⁶
0.151 - 0.266257 = 0.69149143q / 1.41 × 10⁻⁶
-0.115257 = 0.69149143q / 1.41 × 10⁻⁶
-0.115257 × 1.41 × 10⁻⁶ = 0.69149143q
0.69149143q = -1.6251237 × 10⁻⁷
q = -1.6251237 × 10⁻⁷ / 0.69149143
q = -2.35 × 10⁻⁷ C
Therefore, the net charge carried by the particle is -2.35 × 10⁻⁷ C
In a hydraulic press, a force of 200 N is applied to master piston of area of 25cm-2. If the press is designed to produce a force of 5000N, determine
a:the area of the slave piston
b:the radius of the slave piston
Answer:
[tex]625\ \text{cm}^2[/tex]
[tex]14.1\ \text{cm}[/tex]
Explanation:
[tex]F_1[/tex] = Force applied to master piston = 200 N
[tex]F_2[/tex] = Force applied to slave piston = 5000 N
[tex]A_1[/tex] = Area of master piston = [tex]25\ \text{cm}^2[/tex]
[tex]A_2[/tex] = Area of slave piston
r = Radius of slave piston
From Pascal's law we have
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow A_2=\dfrac{F_2}{F_1}A_1\\\Rightarrow A_2=\dfrac{5000}{200}\times 25\\\Rightarrow A_2=625\ \text{cm}^2[/tex]
The area of the slave piston is [tex]625\ \text{cm}^2[/tex]
Area of the slave piston is given by
[tex]A_2=\pi r^2\\\Rightarrow r=\sqrt{\dfrac{A_2}{\pi}}\\\Rightarrow r=\sqrt{\dfrac{625}{\pi}}\\\Rightarrow r=14.1\ \text{cm}[/tex]
The radius of the slave piston is [tex]14.1\ \text{cm}[/tex].
pls help i’ll give brainliest
Explanation:
option A is the correct answer of this question .
plz mark my answer as brainlist if you find it useful.☺️
An objects motion changes
Answer:
uh finish the question please lol.
What distance will a car cover while uniformly accelerating from 12 m/s to 26 m/s in 14 seconds?
Answer:
266 m
Explanation:
For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. The electric field inside is zero. The entire conductor is at the same potential. Any excess charge is uniformly spread throughout the volume of the conductor.
Answer:
The entire conductor is at the same potential.
The electric field inside is zero.
Explanation:
For a conductor in electrostatic equilibrium, the properties are:
The electric field inside is zero.The entire conductor is at the same potential. What is electrical conductor?A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors.
It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads).
Instead, all that is required of the charged particle is a small amount of nudging from its neighbor, who in turn will nudging its neighbor, and so on, until a particle gets nudged into the consumer, so supplying it with power.
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Can anyone help me with the Wet Lab Guide - Coulomb's Law report? I'm really having trouble with it. I have attached the worksheet
Answer:
Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.
Explanation:
Which of the models most accurately represents the structure of DNA?
A
B.
G
Answer:
It's A.
Explanation:
DNA is a double helix.
Model which accurately displays structure of DNA is model A as DNA is a double helical structure.
What is DNA?
DNA is a hereditary material which is present in human beings as well as all other living organisms. Every cell which is present in an organism's body has DNA which is the same. Most of the DNA is situated in the cell's nucleus and small amount of it can be found in the cell's mitochondria as well.
Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.
DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule and a phosphate group. A base, phosphate sugar are together called as nucleotides.
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If my candle has a brightness of 15 candela from a distance of 2 meter. What would the brightness be at a distance of 6 meters?
Answer:
5 candela
Explanation:
Let the candle brightness be B
Let the distance be d
The candle brightness is inversely proportional to the distance
B α 1/d
B = k/d
If my candle has a brightness of 15 candela from a distance of 2 meter, then;
15 = k/2
k = 30
To get the brightness when the distance is 6m;
B = k/d
B = 30/6
B = 5 candela
Hence the brightness will be 5 candela
1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of the electric force? The constant k = 9 x 109 N-m2/C2
Solution:
Answer:
F = 36 N
Explanation:
Given that,
Charge, q₁ = +8 μC
Charge, q₂ = -5 μC
The distance between the charges, r = 10 cm = 0.1 m
We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]
So, the magnitude of the electrostatic force is 36 N.
A 0.85 N force exists between a 7.1 * 10 ^ - 6 * C charge 5.4 m away. What is the magnitude of the second charge ? Please show work
Answer:
Explanation:
Force between charge is given by the following expression
F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .
Putting the given values ,
.85 = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²
Q₂ = .85 x 5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )
= .38788 x 10⁻³ C .
= 387.88 x 10⁻⁶ C .
a transformer with an input emf of 240volts and output of 960volts has 720 turns in the secondary coil. what is the number of coil in the primary coil?
Answer:
180 turns
Explanation:
Given data
Vi= 240 volts
Vo= 960volts
Ns= 720 turns
Required
The amount of Primary turns Np
The expression relating voltage and turns in a transformer is given as
Np/Ns= Vi/Vo
substitute
Np/720= 240/960
cross multiply
720*240= Np*960
172800= Np*960
Np= 172800/960
Np= 180
Hence the primary turns is 180 turns
A 800-w iron is left on the ironing board with the base exposed to the air. About 85 percent of the heat generated by iron dissipate through its base with surface area of 0.15 ft2 . Calculate the amount of heat the iron dissipates in 2 hours, the heat flux on the surface of iron and total cost of electricity wasted in 2 hours if unit cost of electricity to be $0.11kwh.
Answer:
ΔQ = 4896 KJ
Heat Flux = 57407.55 W/m²
Cost = $ 0.176
Explanation:
The amount of heat dissipated in two hours can be given as:
[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]
where,
P = Power of Iron = 800 W
t = time taken = 2 hrs
η = Conversion efficiency = 85% = 0.85
[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]
ΔQ = 4896 KJ
Now, for heat flux:
[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]
Heat Flux = 57407.55 W/m²
Now, for total heat energy in KWhr in two hours:
[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]
Now, for the cost:
[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]
Cost = $ 0.176
Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance ddd is
|F|=K|QQ′|d2|F|=K|QQ′|d2,
where K=14πϵ0K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q1q1q_1 = -11.5 nCnC , is located at x1x1x_1 = -1.675 mm ; the second charge, q2q2q_2 = 40.0 nCnC , is at the origin (x=0.0000)(x=0.0000).
What is the force exerted by these two charges on a third charge q3q3q_3 = 48.0 nCnC placed between q1q1q_1 and q2q2q_2 at x3x3x_3 = -1.215 mm ?
Your answer may be positive or negative, depending on the direction of the force.
Express your answer numerically in newtons to three significant figures.
Answer:
F_total = -65.5 N
Explanation:
Coulomb's law is
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2
In this exercise the force on the charge q3 is asked, for this we use that the force is a vector
F_total = F₁₃ + F₂₃
let's look for every force
F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]
it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m
the distance is
r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]
r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]
r₁₃ = 1.175 10⁻³ m
we calculate
F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]
F₁₃ = 3.598 N
as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right
we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0
F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]
r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]
r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103
r₂₃ = 0.5 10⁻³ m
F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]
F₂₃ = 6.912 10¹ N
F₂₃ = 69.12 N
as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left
the total force is
F = total = 3.598 - 69.12
F_total = -65.5 N
the negative sign indicates that the force is to the left
Determine the maximum volume in gallons [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of feet [ft] so the total pressure at the bottom of the container will not exceed pound-force per square inch [psi]. Assume the height of the tank is sufficient to store the amount of olive oil required, and the surface pressure is 1 atmosphere [atm]. The specific gravity of olive oil is 0.86.
This question is incomplete, the complete question is;
Determine the maximum volume in gallons [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of 3feet [ft] so the total pressure at the bottom of the container will not exceed 26 pound-force per square inch [psi]. Assume the height of the tank is sufficient to store the amount of olive oil required, and the surface pressure is 1 atmosphere [atm]. The specific gravity of olive oil is 0.86.
Answer:
A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo
Explanation:
Given the data in the question;
Using SI units
Diameter = 3 ft = 3 × 0.3048 = 0.9144 m
pressure at bottom Pb = 26 psi = 26 × 6.89476 × 1000 = 179263.76 pascal
surface pressure Ps = 1 atm = 1 × 101325 = 101325 pascal
specific gravity = 0.86
we know that; density of water = 1000 kg/m³
so, density of oil P = density of water × specific gravity
= 1000 × 0.86 = 860 kg/m³
pressure at depth can be related to pressure at surface;
Pb = Ps + Pgh
acc. due gravity g = 9.81 m/s²
we substitute
179263.76 = 101325 + ( 860 × 9.81 × h)
8436.6h = 179263.76 - 101325
8436.6h = 77938.76
h = 77938.76 / 8436.6
h = 9.238 m
Now;
Volume of the cylinder = π/4 × D² × h
we substitute
Volume of the cylinder = π/4 × ( 0.9144 )² × 9.238
Volume of the cylinder = 6.0665 m³
we know that; 1 m³ = 264.172 gal
so; Volume of the cylinder = 6.0665 × 264.172 gal
Volume of the cylinder = 1602.6 gallons
Therefore, A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo
True or False
A curved line indicates a constant velocity
Answer:
false this is correct answer of this question
At what rate is thermal energy being generated in the 2R-resistor when = 12 V and R = 3.0 ?
a. 12 W
b. 24 W
c. 6.0 W
d. 3.0 W
e. 1.5 W
If there's nothing else connected to the battery except the 3-ohm resistor, then the question is defective and the correct answer is not on the list.
With 12v connected across the resistor, the current through the resistor is
I = (E/R) = (12/3) = 4 Amperes.
The power generated inside a resistor is
P = (E x I) = (12v) x (4 A) = 48 watts
What does the following figure illustrate?
^
+
Answer:
Intterferance
Explanation:
I took the test
A team of scientists is researching the best way to use tides to produce energy. One team includes environmental
scientists.
Which other branch of Earth science would these scientists most likely represent?
-geology
-astronomy
-meteorology
-oceanography
Answer:
agree with above answer
Why are rocks made of limestone usually an indication that an area was previously covered by ocean water
Answer:
what's the question? I don't understand
Answer:
Limestone can from form shell fragments of sea creatures
Explanation:
g Light is a traveling wave! The oscillations are oscillations of electric fields. The electric fields oscillate in the y-direction while the light travels in the x direction, so we can create a wave equation Ey(x,t); Ey is the y-component of the electric field, x is position in meters, and t is time in seconds. Consider light with a wave length of 550 nanometers, a wave speed of 3.00 x 108 m/s , and an amplitude of 10 V/m (volts/meters). Construct the traveling wave equation for this light if at t = 0 seconds, the light is at its maximum positive value and is traveling in the negative x-direction. Your equation, Ey(x,t) , should only have the variables x and t (i.e. calculate the values of the relevant traveling wave quantities to three sig figures and use those in the equation you are constructing, do not use the symbols in your final answer).
Answer:
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Explanation:
The general equation of a traveling wave on the x-axis is
[tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)
the amplitude of the wave is E₀ = 10 V / m
the wave number is
k = 2π /λ
indicate the value of λ = 550 nm = 550 10⁻⁹ m
we substitute
k = 2π / 550 10⁻⁹
k = 1.15 10⁻¹¹ m⁻¹
angular velocity is related to frequency
w = 2πf
the speed of light is related to the wavelength and frequency
c = λ f
f = c /λ
we substitute
w = [tex]2\pi \frac{c}\lambda }[/tex]
w = 2π 3 10⁸/550 10⁻⁹
w = 3.427 10¹⁵ rad / s
we substitute in the electric field equation
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth
Ey (0,0) = 10
which corresponds to its maximum positive value, therefore this is the expression of the traveling wave
Bearing in mind that a sound reflects off an object if the object is larger than the wavelength of the sound, calculate the wavelength of a sound in the air for a sound in the middle of the human hearing range. Then calculate the wavelength for a sound in the middle of the bat hearing range. If you had to use echolocation to detect an insect, which sound has an advantage
Answer:
mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters
Explanation:
The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz
let's use the relationship between wave speed, wavelength and frequency
v = λ f
λ= v / f
λ = 343/10000
λ = 3.43 10⁻² m
the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range
f = (100 10³ + 25 10³) / 2
f = 62.5 10³ Hz
λ = 343 / 62.5 10³
λ = 5.5 10⁻³ m
Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.
The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters
Czocharalski process
Answer:
The Czochralski method, also Czochralski technique or Czochralski process, is a method of crystal growth used to obtain single crystals of semiconductors, metals, salts and synthetic gemstones
Explanation:
hope it helps:)
if a particle with a charge of +4.3 C is attracted to another particle by a force of 6.5 N, what is the strength of the electric field at this location?
Answer: 1.5 N/C
Explanation:
The equation is derived from Coulomb's Law, but is not exactly Coulomb's Law:
F = qE
q is the test charge
E is the electrical field produced by the source charge
F is the force in Newtons
In this problem, we were given the value of the test charge q, and the force acting on it due to the electric field from the source charge.
E = F/q
E = 6.5N/4.3C
E = 1.5 N/C
A device that has the capacity to receive and store electrical energy is a(n)
.
Answer:
Yes, capacitor is the correct answer
Explanation:
What is the mechanical advantage of a 8 m ramp that rises 2 m to a stage?
Answer:
Mechanical advantage = 4
Explanation:
Given the following data;
Distance of effort, de = 8m
Distance of ramp, dr = 2m
To find the mechanical advantage;
Mechanical advantage = de/dr
Substituting into the equation, we have;
Mechanical advantage = 8/2
Mechanical advantage = 4