What is a dominant trait and a recessive trait

Answers

Answer 1

Answer:

Dominant traits are always expressed when the connected allele is dominant, even if only one copy exists. Recessive traits are expressed only if both the connected alleles are recessive.

Explanation:

Freckles, cleft chin and dimples are all examples of a dominant trait.

Answer 2
Examples are freckles

Related Questions

Please help :)
It’s a science thing for 7th grade

Answers

Answer: The first question is chemical The second one is Physical

Explanation:

is copper an elementary substance or a compound?

Answers

Elementary substance

Colin decided to investigate soil erosion by water. He measured rates of erosion on
model hills made of soil, rock, and sand. Which of the following was the test
(independent) variable?

Answers

Answer:

i just had a test on this with 2 attempts and got it wrong on both but i do know that the answer is not...

the steepness of the models hillside

or

the rate of erosion on the hills

so the answer is either...

the amount of water sprayed on the hills

or

the type of material used to construct the model hills

but i think its the amount of water sprayed on the hills...i hope i helped a lil ;)

Explanation:

What is the pH of an aqueous solution that has a hydroxide ion concentration of 1.0 x 10^-5 M?​

Answers

Answer:

pH = 9

Explanation:

pOH = -log[OH-] = -log(1.0 x10^-5) = 5

pOH + pH = 14

pH = 14 - 5 = 9

Which of the following have London dispersion forces?
a. methane
b. carbon tetrachloride
c. bromine trifluoride
d. all of the above

Answers

It’s think it’s A I’m sorry if I’m wrong

NH₄⁺(aq)+NO₃⁻(aq) → NH₄NO₃(s)
How much energy is released when 3 moles of NH₄+ react?

1) -25.69 kJ
2) -51.38 kJ
3) -77.07 kJ
4) -102.76 kJ

Answers

I think the answer is number 3

4. A girl walked for 30 minutes. She noticed that she traveled farther in the first 15 minutes of
her walk than in the second 15 minutes,
What can she conclude about her walk?
A she walked over many hills
B
her average speed was faster during the first part of her walk
C. she walked in two different directions
D. she was walking at a constant speed

Answers

i think it’s B.
because her speed was faster in the first part of her walk

helllllppppppp pleaseeeeeee​

Answers

Just look it up :) hope this helps

is it true or false?

Answers

Answer:

The rainforest is teeming with animals and insects, so you would hear  humming. Frogs and birds make some of the loudest rainforest sounds.

howler monkeys, are the loudest so i think that its false cause lost of animals are there but some can be quiet

Height
O
Genetic
O Environmental
O Both

Answers

Answer:

its both because your hight can change if u do exercises

Hope it helped.

19) Which one of the following statements describes a chemical property of hydrogen gas?
A) Hydrogen gas has a density of 0.00009 g/cm’ at STP.
B) Hydrogen gas burns in air.
C) Hydrogen gas has a boiling point of 20. K at standard pressure.
D) Hydrogen gas is colorless.

Answers

b) hydrogen gas burns in air.

explanation: the rest are physical properties.

El etanol combustiona con el oxigeno produciendo dióxido de carbono gaseoso y agua: En un proceso se hacen reaccionar 450.2 g de dioxígeno con 998. 2 g de etanol . a) ¿Cuál de los reactivos es el limitante? b) Calcule la masa de dióxido de carbono que se formará c) ¿ Cuanto del reactivo en exceso quedará sin reaccionar?

Answers

Answer:

uh oh stinky uh oh stinky

Which body system includes the lungs?m​

Answers

Answer: The respiratory system

Explanation: It includes the nose, mouth, throat, voice box, windpipe, and lungs. Air enters the respiratory system through the nose or the mouth.

A beaker contains a sample of water with a mass of 325 grams. The water in the beaker
is boiled and weighed again after it cools. The new mass of the water is 305 grams. In
this example of the conservation of matter in physical changes,
A. the mass is less after it cools because water has less mass as a gas.
B. the mass of the water was 305 grams and the mass of the water vapor was 20 grams.
C. the process of boiling destroyed 20 grams of the water and left 305 grams of water.
D. the heat energy created by boiling water makes up the rest of the mass.

Answers

Answer: a

Explanation:

Bc I just did it and yeah

how many moles of solute are present in a 2 L of a 25M potassium nitrate solution
a. 0.5 moles
b. 2 moles
c. 50 moles
d. 25 moles

I NEED THIS ANSWER ASAP, im taking the quiz right now and i need HELPPP

Answers

Answer:

50 moles

Explanation:

took the quiz

object with a mass of 30 kg is observed to accelerate at the rate of 4 m/s2. Calculate the force required

Answers

this answer is 2kg good luck

PLEASE HELP WITH CHEM !! Calculate the [OH-] of each of the following solutions given the [H+]. AND Classify each of the solutions in the question above as either acid, base, or neutral. AND FIND THE PH

Answers

pH, pOH, [H+], and [OH-] are all interrelated. For simplicity, we assume that we're working with aqueous solutions at 25 °C.

The following mathematical relations are relevant here:

pH = -log[H⁺]pOH = -log[OH⁻][H⁺] = 10^-pH[OH⁻] = 10^-pOHpH + pOH = 14[H⁺] × [OH⁻] = 10^-14

A pH of 7 is neutral; a pH less than 7 is acidic; and a pH greater than 7 is basic.

---

We are given four solutions of varying [H⁺], and we want to find the pH and the [OH⁻]. The pH will tell us whether the solution is neutral, an acid, or a base.

Finding the [OH⁻]

Using the relationship [H⁺] × [OH⁻] = 10^-14, we can calculate the [OH⁻] of each solution by dividing 10^-14 by the given [H⁺]:

[OH⁻] = 10^-14/(3.3 × 10^-5) = 3.0 × 10^-10

[OH⁻] = 10^-14/(4.0 × 10^-8) = 2.5 × 10^-7

[OH⁻] = 10^-14/(7.2 × 10^-11) = 1.4 × 10^-4

[OH⁻] = 10^-14/(8.2 × 10^-4) = 1.2 × 10^-11

Note: While not indicated here, the units for [H⁺] and [OH⁻] are moles/liter (M).

Finding the pH

To find the pH of each solution, we take the negative logarithm of the [H⁺] with base 10, i.e., pH = -log₁₀[H⁺]:

pH = -log(3.3 × 10^-5) = 4.48

pH = -log(4.0 × 10^-8) = 7.40

pH = -log(7.2 × 10^-11) = 10.14

pH = -log(8.2 × 10^-4) = 3.09

Note that, for significant figures involving logarithms, the number of decimal places should equal the number of significant figures in the argument of our logarithm (the argument is what we're taking the -log of). Since we're taking the -log of quantities given to two significant figures, our corresponding pH values are given to two decimal places.

Acid, Base, or Neutral?

As mentioned above, a pH = 7 is neutral, a pH < 7 is acidic, and a pH > 7 is basic.

4.48 < 7, so the first solution is an acid.

7.40 > 7, so the second solution is a base.

10.14 > 7, so the third solution is a base.

3.09 < 7, so the fourth solution is an acid.

Calcium carbonate decomposes into
calcium oxide and carbon dioxide.
The mass of calcium carbonate that
decomposes is 57 g. At the end of
the experiment, the mass of the
products were only 45 g. What can
we conclude from this information?

Answers

Answer:

The mass of carbon dioxide formed is 12g.

During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the excess reagent are left over after the reaction is complete. 2SO2()+O2()⟶2SO3()

Answers

Answer: 16.32 g of [tex]O_2[/tex] as excess reagent are left.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol[/tex]

[tex]\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol[/tex]

[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)[/tex]  

According to stoichiometry :

2 moles of [tex]SO_2[/tex] require = 1 mole of [tex]O_2[/tex]

Thus 0.34 moles of [tex]SO_2[/tex] will require=[tex]\frac{1}{2}\times 0.34=0.17moles[/tex]  of [tex]O_2[/tex]

Thus [tex]SO_2[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.

Moles of [tex]O_2[/tex] left = (0.68-0.17) mol = 0.51 mol

Mass of [tex]O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g[/tex]

Thus 16.32 g of [tex]O_2[/tex] as excess reagent are left.

Which is an example of a chemical change?
A. heating a block of ice to form liquid water
B. heating a tungsten wire until it glows brightly
C. adding sugar crystals to water to form a clear, colorless liquid
D. passing an electric current through water to form hydrogen and oxygen

Answers

Answer:

D. passing an electric current through water to form hydrogen and oxygen

Explanation:

only one that's not just a physical change.

Name
12. A chemist places a piece of solid magnesium in an aqueous solution of copper (II)
sulfate and notices a reaction. Pieces of solid copper dropped out of the solution as a
precipitate and magnesium sulfate was formed.
a) Give a balanced formula equation (with state symbols) for this reaction (3 marks)

Answers

Answer:

Explanation: Mg(s) + CuSO4 (aq) -> Cu(s) + MgSO4 (aq)

Can someone please help me with the right answer? I only have one more attempt :(

Answers

The decomposition of a solid to yield a gaseous product would involve an increase in entropy. So, the fourth answer choice would be correct.

A water solution containing an unknown quantity of a

nonelectrolyte solute is found to have a freezing point of

–0.23°C. What is the molal concentration of the solution?​

Answers

Answer:

The molal concentration of the solution is approximately 0.124 molal

Explanation:

The given parameters are;

The reduced freezing point of the water = -0.23°C

For freezing point depression of a solution, we have;

[tex]\Delta T_f[/tex] = [tex]K_f[/tex]· b·i

Where;

[tex]\Delta T_f[/tex] = The freezing point depression

[tex]K_f[/tex] = Cyroscopic constant (The freezing-point depression constant) = 1.86° Cm⁻¹ for water

b = The molality of the solution

i = van't Hoff factor = 1

Therefore;

[tex]\Delta T_f[/tex] = [tex]T^{\circ}_f - T_f[/tex]

Where;

[tex]T^{\circ}_f[/tex] = The freezing point of pure water = 0°C

[tex]T_f[/tex] = The freezing point of the solution = -0.23°C

∴ [tex]\Delta T_f[/tex] = [tex]T^{\circ}_f - T_f[/tex] = 0°C - (-0.23°C) = 0.23 °C

From, [tex]\Delta T_f[/tex] = [tex]K_f[/tex]· b·i, we have;

0.23°C = 1.86°C/m × b × 1

∴ b  = (0.23°C/1.86°C/m) ≈ 0.124 molal

Therefore, the molal concentration of the solution, b ≈ 0.124 molal.

HELP!! 30 POINTS!!!! What does the energy graph look like for this reaction??
C3H8+5O2 -> 3CO2+4H2O

I have the data, I just need to know how to make the graph, please!!

total enthalpy of reactants= -103.85
total enthalpy of products= =-2147.81
=-2043.96 kJ/mol exothermic reaction

Answers

=2043.96 kJ/mol exothermic reaction

Answer:

Bottle Nose Dolphin ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

Lunar Eclipse. Choose ALL that apply

Question 1 options:

Earth casts its shadow on the moon


The moon turns dark


Light from the sun is blocked


Earth is directly between the moon and sun

Question 2 (0.5 points)
Solar Eclipse: Choose ALL that apply

Question 2 options:

The Earth is directly between the moon and sun


Earth casts a shadow on the moon


Moon moves between the sun and Earth


The moon blocks out the light of the sun and casts a shadow onto the Earth

Answers

In this exercise we have to use the knowledge of lunar eclipse to identify the alternatives that correspond to this effect, as follows:

Light from the sun is blockedEarth is directly between the moon and sun

What is lunar eclipse?

A lunar eclipse happens when the Earth is between the Moon and the Sun, at times when they are aligned. Depending on the position of the Moon, it is total, partial or penumbral. Different stages of a lunar eclipse on a full moon night.

Now,  use the knowledge of solar eclipse to identify the alternatives that correspond to this effect, as follows:

Moon moves between the sun and EarthThe moon blocks out the light of the sun and casts a shadow onto the Earth

What is the definition of solar eclipse?

Solar eclipse is an astronomical phenomenon that occurs when the Moon is positioned between the Earth and the Sun, hiding the light emitted by the star towards the planet.

See more about eclipse at brainly.com/question/25105283

Covert 50oC to k
(I’ll mark you as brainlister)

Answers

Answer:

323 K

Explanation:

To convert Celcius to kelvin first you need to remember this equation:

C + 273 = K (K = kelvin and C = celsius)

Next, you substitute with what you have given:

50 + 273 = K

Solve the equation by adding 50 and 273

k = 323

1. When _____
are added or removed from an atom, _____
is formed

Answers

Answer:

1.) protons or electrons 2.) ion

Explanation:

Sulfuric acid reacts with aluminum hydroxide by double replacement producing aluminum sulfate and water Write chemical reaction. If 30 g of sulfuric acid reacts with 25 g of aluminum hydroxide, identify the limiting reactant?

Answers

Answer: [tex]H_2SO_4[/tex] is the limiting reagent.

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation is:

[tex]3H_2SO_4(aq)+2Al(OH)_3(aq)\rightarrow Al_2(SO_4)_3(aq)+6H_2O(l)[/tex]

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} H_2SO_4 =\frac{30g}{98g/mol}=0.31moles[/tex]

[tex]\text{Moles of} Al(OH)_3=\frac{25g}{78g/mol}=0.32moles[/tex]  

According to stoichiometry :

3 moles of [tex]H_2SO_4[/tex] require = 2 moles of [tex]Al(OH)_3[/tex]

Thus 0.31 moles of [tex]H_2SO_4[/tex] will require=[tex]\frac{2}{3}\times 0.31=0.21moles[/tex]  of [tex]Al(OH)_3[/tex]

Thus [tex]H_2SO_4[/tex] is the limiting reagent as it limits the formation of product and [tex]Al(OH)_3[/tex] is the excess reagent.

Determine from the balanced chemical reaction if
the derived mole ratio is correct or incorrect.
2FeBr3 + 3Na2S → Fe2S3 + 6NaBr
2 moles FeBra
3 moles Na2S

Answers

Answer:

Correct

Explanation:

According to the balanced chemical reaction, 2 mol FeBr3 are consumed for every 3 mol Na2S consumed.

A balanced equation obey the law of conservation of mass. The coefficients are the numbers which are added to balance the chemical equation. Here the given mole ratio is correct.

What is a balanced equation?

An equation in which the number of atoms of reactants and products on both sides of the equation are balanced is defined as the balanced chemical equation. The coefficients which are added in front of the formula of each component represents the number of the species.

A molar ratio denotes the ratio between the amounts in moles of any two compounds involved in a balanced chemical reaction. By comparing the coefficient of each component, the mole ratio can be determined.

Here for the given reaction, for every 3 moles of Na₂S consumption 2 moles of FeBr₃ is also consumed. So the molar ratio of Na₂S to FeBr₃ is 2/3. Molar ratios are used as the conversion factors between products and reactants in many chemistry problems.

To know more about mole ratio, visit;

https://brainly.com/question/29095152

#SPJ7

Can someone double check my work? (Ideal Gas Law Equation)
I am solving for the amount of moles in two gases.
For one, it was 4.75mL at 0.5C (273.65K) and 1.2atm.
n=(1.2*4.75)/(0.0821/273.65)=(5.7/22.456)=0.25361653 moles
For the other gas, it was 4.6mL at 0.5C and 1.2atm.
n=(1.2*4.6)/(0.0821/273.65)=(5.52/22.456)=0.24581403 moles
Please double check these for any errors in math or whatever. Thank you.

Answers

I did not see any errors, i may be wrong but what i can see is that it is correct

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