What is a common factor of 12x 2 − 5x − 3 and 6x 2 − x − 1 ?

Answer:

Rotation

Step-by-step explanation:

If you were to translate it, it wouldn't match up because it needs to be turned around. translation just involves moving the shape without rotating it. a dilation means that you're changing the size, and you're not supposed to do that for this problem. a reflection means that if you were to fold in between these two shapes, they would match up. They Don't in this case so that won't work. A rotation is the only way to get it so that all of the areas match up.

Answer:

d= bv + r

Treat it like you would a normal equation. Multiply by b and add r to isolate d.

Answer:

i think its 9, i dont exactly know

Step-by-step explanation:

Answer:

18x+12

Step-by-step explanation:

5x+14+13x-2

combine Like terms:

5x+13x

14-2

18x+12

Answer:

The answer is 18x+12.

I think after 14 there should equal sign if you want to know what x equals to.

Given :

The Dobson exit is halfway between the Mt. Airy exit and the Elkin exit. If the Elkin exit is located at (-5,-2) and the Dobson exit is located at (-1,4).

To Find :

How far is it from the Elkin exit to the Mt. Airy exit.

Solution :

E(-5,-2) , D(-1 ,4 ) .

It is also given that Dobson exit is halfway between the Mt. Airy exit and the Elkin exit.

Let , location of Elkin exit is A(h,k) .

So , point D in terms of A and E is given by :

[tex](\dfrac{h-5}{2},\dfrac{k-2}{2})[/tex] .

Comparing it with given D :

[tex]\dfrac{h-5}{2}=-1\\\\h=3[/tex] [tex]\dfrac{k-2}{2}=4\\\\k=10[/tex]

Therefore , the location of Mt. Airy exit is ( 3, 10 ) .

Distance between Elkin exit to the Mt. Airy exit.

[tex]D=\sqrt{(5-3)^2+(-2-10)^2}\\\\D=12.17\ units[/tex]

Therefore , distance between Elkin exit to the Mt. Airy exit is 12.17 units .

Hence ,this is the required solution .

The value of x will be equal to -1 when the value of h(x) is -2.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that  h(x) = -3x – 5, and the value h(x) = -2. The value of x will be calculated as below:-

h(x) = -3x – 5,

-2=-3x -5

3=-3x

x=-1

Therefore, the value of x will be equal to -1 when the value of h(x) is -2.

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Answer:

5544 cm²

Step-by-step explanation:

Radius of circle = r

Circumference = 2πr

2πr = 264

22/7*r = 132

r = 132*7/22

 = 42 cm

Area = πr²

        = 22/7*42*42

        = 5544 cm²

Answer:

16

Step-by-step explanation:

Step-by-step explanation:

M=9 so m+n becomes 9+n.

N=7 so 9+n becomes 9+7.

9+7=16

Answer:

Step-by-step explanation:

[tex]7\cdot \:3\\\mathrm{Multiply\:the\:numbers:}\:7\cdot \:3=21\\=21\\[/tex]

Answer:

21

Step-by-step explanation:

Answer:

z=-[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Answer:

I'm pretty sure y=mx+b is standard form, unless I'm reading the question wrong.

Step-by-step explanation:

Step-by-step explanation:

y = -4(x+6)(x-8)

= -4[x²-2x-48]

= -4x²+8x+192

Answer:

The number is 76

Step-by-step explanation:

I think it is 128.77 cm. Because it has the most numbers, and it is presice.

Answer:

.

Step-by-step explanation:

[tex]\text{Hi there! :]}[/tex]

[tex]\large\boxed{y = 8}[/tex]

[tex]3y + 8 = 1/2y + 28\\\\\text{Subtract 8 from both sides:}\\\\3y + 8 - 8 = 1/2y + 28 - 8\\\\3y = 1/2y + 20\\\\\text{Subtract 1/2y from both sides:}\\\\3y - 1/2y = 1/2y - 1/2y+ 20\\ \\\text{Convert 3y to 6/2y to make subtracting easier:}\\5/2y = 20\\\\\text{Divide both sides by 5/2 (Multiply by reciprocal, or 2/5):}\\\\\\5/2y * 2/5 = 20 * 2/ 5\\\\y = 8[/tex]

The answer is D.

Turning fractions into decimals will help you eliminate answers!!

How I got D:

-2 3/4 can be turned into -2.75 by dividing 3/4.

-2 3/4 is the smallest number out of all of them so it has to be first.

-2.67 is the second smallest value.

3/5 is .60 making it the third smallest value.

4 is the second largest value.

17/4 is 4.25, which is the largest.

A is not correct because -3/5 is not the smallest number.

B Is not correct because the largest number is 17/4.

C is not correct because -2.67 is not the smallest number.

Answer:

[tex](\frac{7}{2} ,\frac{29}{4} )[/tex]

Step-by-step explanation:

Answer:

no

Step-by-step explanation:

Answer:

total money=rupees 50

3/5 of 50= rupees 30

money he spent = rupees 30

money he's left with =50-30=20

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Answer:

Step-by-step explanation:

like u told me social studis

<3

Answer: Train 2 is traveling 4 miles per hour faster than train 1.

Step-by-step explanation:

Answer:

Train 2 is traveling 4 miles per hour faster than train 1.

Step-by-step explanation

:)))))

Answer:

250

Step-by-step explanation:

Answer:

63

Step-by-step explanation:

∫₂⁴ f(x) g"(x) dx

Integrate by parts.

If u = f(x), then du = f'(x) dx.

If dv = g"(x) dx, then v = g'(x).

∫ u dv = uv − ∫ v du

= f(x) g'(x) − ∫ g'(x) f'(x) dx

f'(x) is constant at 3, so:

= f(x) g'(x) − ∫ 3 g'(x) dx

= f(x) g'(x) − 3 g(x)

Evaluate from x=2 to x=4.

[f(4) g'(4) − 3 g(4)] − [f(2) g'(2) − 3 g(2)]

[(13) (7) − 3 (9)] − [(7) (1) − 3 (2)]

64 − 1

63

The required value of [tex]\int\limits^4_2 {f(x)g"(x)} \, dx (1)[/tex] is 63.

Given that,

The table above gives selected values of twice-differentiable functions f and g,

The first two derivatives of g. If f′ (x) = 3 for all values of x.

We have to determine,

What is the value of [tex]\int\limits^4_2 {f(x)g"(x)} \, dx (1)[/tex].

According to the question,

To obtain the value of given function, integrating the function,

[tex]= \int\limits^4_2 {f(x)g"(x)} \, dx (1)[/tex]

Integrating by using by-parts.

[tex]= \int\limits^4_2 {f(x)g"(x)} \, dx (1)\\\\if\ u = f(x), \ then \ du = f'(x)dx\\\\if \ dv = g"(x)dx, \ then \ v = g'(x)\\\\[/tex]

Then,

[tex]\int u\ dv = uv\ - \ \int v \ du\\\\= f(x) \ g'(x) - \int g'(x) f'(x) \ dx\\[/tex]

if f'(x) is constant at 3,

Then,

[tex]= f(x) g'(x) - \int g'(x)\dx\\\\= f(x) g'(x) -3g(x)[/tex]

Substitute from x = 2 to x = 4 then evaluate,

[tex]= [f(4)\ g'(4) - 3 \ g (4)]- [f(2)\ g'(2) - 3 \ g (2)]\\\\= [(13).(7) - 3.(9)] - [7.(1)- 3.(2)]\\\\= [91-27} - {7-6}\\\\= 64-1\\\\= 63[/tex]

Hence, The required value of [tex]\int\limits^4_2 {f(x)g"(x)} \, dx (1)[/tex] is 63.

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Answer:

Step-by-step explanation:

Begin at the end. By this I mean to start at the end of that expression and work your way backwards to the beginning. "The difference of t and 8" looks like this: t - 8. "2/3 of" means we are multiplying (the word "of" means to multiply): 2/3(t - 8) is your algebraic translation of that expression.

The required mathematical expression of a statement is 2 / 3 (t - 8 ).

Given that,
To transform the statement into the mathematical form,
2/3 of the difference between a number t and 8

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

Here,
given statement,
2/3 of the difference between a number t and 8
implies,
The difference between t and 8 is,
= t - 8
Now the difference is 2/3, now the statement become,
= 2 / 3 (t - 8 )
above equation is the required mathematical expression.

Thus, the required mathematical expression of a statement is 2 / 3 (t - 8 ).

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