At the end of the reaction, an aqueous solution of sodium bisulfite is added to the reaction mixture. The sodium bisulfite destroys the remaining bromine. Also, the fact that the sodium bisulfite is in water helps to further separate the reaction solvent from the product because the solvent is very soluble in water. What is the most important intermolecular force that allows the solvent to dissolve in wate?
Answer:
Polarity.
Explanation:
The most important intermolecular force to allow a solvent to dissolve in water is polarity. This is because water is a polar substance and there is a chemical law that states that there is only solubility between substances of equal polarity. Thus, water is only able to dissolve a polar substance, just like it. In this case, we can say that the equal polarity between the two solvents is the most important for one to be able to dissolve the other.
The formation of tert-butanol is described by the following chemical equation: Suppose a two-step mechanism is proposed for this reaction, beginning with this elementary reaction: Suppose also that the second step of the mechanism should be bimolecular. Suggest a reasonable second step. That is, write the balanced chemical equation of a bimolecular elementary reaction that would complete the proposed mechanism.
Answer:
(CH3)3C^+ + OH^- --------> (CH3)3COH
Explanation:
This reaction has to do with SN1 reaction of alkyl halides. Here tert-butanol is formed from tert-butyl bromide.
The first step in the reaction is the formation of a carbocation. This is a unimolecular reaction. The rate of reaction depends on the concentration of the alkyl halide. This is a slow step and thus the rate determining step in the mechanism.
(CH3)3CBr -------> (CH3)3C^+ + Br^-
The second step is a fast step and it completes the reaction mechanism. It is a bimolecular reaction as follows;
(CH3)3C^+ + OH^- --------> (CH3)3COH
For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
Answer:
The pH of the buffer is 3.90
Explanation:
The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:
pH = pKa + log [A-] / [HA]
Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.
To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:
CH3COO- + HCl → CH3COOH + Cl-
The moles of CH3COO- are its initial moles - the moles of HCl added
And moles of CH3COOH are its initial moles + moles HCl added
Moles CH3COO-:
Initial moles = 0.100L * (0.010mol / L) = 0.00100moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.000500 moles
Moles CH3COOH:
Initial moles = 0.100L * (0.040mol / L) = 0.00400moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.003500 moles
pH is:
pH = 4.75 + log [0.000500] / [0.00350]
pH = 3.90
The pH of the buffer is 3.90
The pH of the buffer after addition of 10.0 mL of 50.0mM HCl is 3.90
What is the Henderson-Hasselbach equation?The Henderson-Hasselbach equation is given as:
pH = pKa + log [A-] / [HA]where
pKa of acetic acid (4.75), [A-] is moles of the conjugate base[HA] the moles of thw weak acid.How to determine the moles of CH3COO- and CH3COOHThe formula for calculating number of moles is:
Moles = concentration × volumeThe equation of the reaction is given below:
CH3COO- + HCl → CH3COOH + Cl-
moles of CH3COO- = initial moles - moles of HCl added
moles of CH3COOH = initial moles + moles HCl added
Moles CH3COO-
Molarity = 0.010 M
volume = 100 mL = 0.100 L
Initial moles = 0.100 L * 0.010 M = 0.001 moles
Moles HCl = 0.010L * 0.050 M= 0.0005 moles
Moles CH3COO- = 0.001 - 0.0005 moles
Moles of CH3COO- = 0.000500 moles
Moles CH3COOH:
Molarity = 0.040 M
volume = 100 mL = 0.100 L
Initial moles = 0.100L * (0.040mol / L) = 0.00400moles
Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles
Moles CH3COO- = 0.004 - 0.0005 moles
Moles CH3COO- = 0.003500 moles
Substituting the calculated values:
pH = 4.75 + log [0.000500] / [0.00350]
pH = 3.90
Therefore, the pH of the buffer after addition of the 10.0 mL 50.0mmHg HCL is 3.90
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A cook grabs the handle of the frying pan and their hand gets very warm. The cook's hand gets very warm because of?
a. conduction
b.radiation
c.convetion
According to the Bohr model of the atom, which particles are allowed to exist in any one of a number of energy levels?
Answer: the line-emission spectrum of an atom is caused by the energies released when electrons. releases energy of only certain values.
An electric circuit has an expected current of 80 amps An electrician measures the current in the circuit at 120 amps. Which
statement provides a possible explanation for this observation?
There is not enough voltage in the circuit.
The circuit has an extra resistor
A resistor in the circuit is broken
There is not enough electrical energy in the circuit.
It is common to mix polar solvents (e.g., acetone) with non-polar solvents (e.g., hexane) to obtain an eluting solvent of intermediate polarity. Would it be appropriate to use a water-DMSO mixture
Answer:
No, it is not appropriate to mix water and DMSO
Explanation:
We have to realize that DMSO is a highly polar solvent and water is a highly polar solvent. The question explicitly says that our target is to produce a solvent of intermediate polarity.
We can only do this by mixing a polar and a nonpolar solvent. We have been given the example of the mixture of acetone/hexane which is quite a perfect mixture.
Thus, it is inappropriate to mix DMSO and water.
The water-DMSO mixture has a high polarity and is not appropriate for intermediate polarity solution.
The interactions between solute-solvent result in the solubility and the polarity of the solution. The polar and non-polar solvents result in intermediate polarity of the solution.
What is the polarity of Water-DMSO solute?The water and DMSO both are highly polar in nature. The addition of polar DMSO to polar water results in the dipole-dipole interaction between the molecules.
The interactions result in the solubility of the solute with solvent. However, the polarity of the solution will be high as both the molecules gave synergistic mixture polarity to the solution.
Thus, to obtain the solution of intermediate polarity, water-DMSO mixture is not appropriate.
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1. Give examples of a catalyst and the reaction it catalyses.
1
Answer:
Explanation:
Iron Haber process = (making ammonia)
Vanadium (V) oxide = Contact process (a stage in making sulfuric acid)
Manganese dioxide = Decomposition of hydrogen peroxide (produces water and oxygen)
ch4(g) + h2o(g) 3h2(g) + co(g) enthalpy of formation of CH4
Answer:
Kc=[[CO][H2]3[CH4][H2O]
3.90=(0.30)(0.10)3[CH4]×0.02
[CH4]=0.023.90×0.30×(0.10)3=5.85×10−2 M
Thus, the concentration of methane in the mixture is 5.85×10−2 M.
This group of fungi forms spores in a round structure on the end of a hyphae
Answer:
Is zygote fungi an option??
Answer:
zygote fungi
Explanation:
i got the answer right
Calculate the [H+]
and pH of a 0.000295 M
butanoic acid solution. Keep in mind that the a
of butanoic acid is 1.52×10-5
[H⁺]=6.696 x 10⁻⁵
pH = 4.174
Further explanationGiven
The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution
Required
the [H+] and pH
Solution
Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids
For weak acid :
[tex]\tt [H^+]=\sqrt{Ka.M}[/tex]
Input the value :
[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴
[H⁺]=6.696 x 10⁻⁵
pH = - log [H⁺]
pH = - log 6.696 x 10⁻⁵
pH = 5 - log 6.696
pH = 4.174
After two half-lives, how much of the original material has decayed? 25 percent 50 percent 75 percent 100 percent
The original material has decayed 75%
Further explanationGiven
two half-life
Required
The decayed sample
Solution
General formulas used in decay:
[tex]\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}[/tex]
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t = 2 x t 1/2
Input the value :
[tex]\tt \dfrac{Nt}{No}=\dfrac{1}{2}^2=\dfrac{1}{4}=25\%[/tex]
The amount of Nt = 25% No
Which of the following does not describe a chemical property?
A. Gasoline burns.
B. Gold does not react with oxygen.
C. Bleach is poisonous when swallowed.
D. Lead is more dense than gold.
The one that does not describe a chemical property is bleach is poisonous when swallowed. The correct options are C.
What are chemical properties?Chemical properties are those properties that show the reactivity of an element. These chemical properties are pH, chemical stability, reactivity, radioactive decay, flammability, toxicity, etc.
Gasoline is a chemical compound, its burning will be a chemical property because it shows how it reacts when it comes in contact with another chemical.
Gold is a pure element, its reactivity tendency is a chemical property, and it is not reactive with oxygen. Density is also a property of an element. And lead is denser than gold, which will show a chemical property.
Thus, the correct options are C. Bleach is poisonous when swallowed.
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What is the percent oxygen in Rb2Cr2O7
Answer:
28.9452
Explanation:
Answer:
28.9452%
Explanation:
Rb-44.1781
Cr-26.8767
O-28.9452
From where do the placenta and umbilical cord develop?
Answer:
it develops from the womb
Answer:
outer cells of the blastocyst
Explanation:
on edg:)
When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.40 °C less than the freezi point of pure X. Calculate the mass of iron(III) nitrate (Fe(NO3)3 that must be dissolved in the same mass of X to produce the same depression in freezing point.
Answer:
21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.
Explanation:
Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.
Formula is: ΔT = Kf . m . i
Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:
ΔT = Freezing point of pure solvent - Freezing point of solution.
This data is known → 6.40°C
m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles
m = 0.351 mol / 0.5kg = 0.702 m
As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:
6.40°C = Kf . 0.702 m . 1
6.40°C /0.702m = 9.11 °C/m.
Let's go to the next question.
ΔT is the same → 6.40°C
But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ → 1Fe³⁺ + 3NO₃⁻
For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4
Let's replace data: 6.40°C = 9.11 °C/m . m . 4
6.40°C / (9.11 m/°C . 4) = 0.176 m
This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.
Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol
Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g
Can somebody PLEASE tell me the empirical formula for br2o6
Answer:
BrO3
Explanation:
The empirical formula is the smallest whole-number ratio, you find the greatest common factor (which is 2, in this case), then divide the subscripts by it.
So:
Br2 / 2 = Br1
O6 / 2 = O3
A geochemist in the field takes a 25.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 26.° C, and caps the sample carefully. Back in the lab, the geochemist first dilutes the sample with distilled water to 350. mL. Then he filters it and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 3.00 g.1) Using only the information above, can you calculate the solubility of X in water at 26 degrees Celsius.? Yes or No2) If yes than calculate the solubility of X. Round your answer to 3 significant digits
Answer:
Yes we can calculate the solubility
The solubility of the mineral is 120 g/L
Explanation:
We have the information that the sample taken originally from the rock pool is 25.0 mL
So,
25.0 mL of the sample contained 3.000 g of the sample
10000mL of the sample now contains 1000 * 3.000/25 = 120 g
This means that 120 g of the sample dissolves in 1000mL or 1L of solution.
Therefore, the solubility of the mineral is 120 g/L
What is the theoretical yield of SO3 produced by 8.96 g of S?
Answer: Theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles[/tex]
The balanced chemical equation is:
[tex]2S+3O_2\rightarrow 2SO_3[/tex]
According to stoichiometry :
2 moles of [tex]S[/tex] produce = 3 moles of [tex]SO_3[/tex]
Thus 0.28 moles of [tex]S[/tex] will produce=[tex]\frac{3}{2}\times 0.28=0.42moles[/tex] of [tex]SO_3[/tex]
Mass of [tex]SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g[/tex]
Thus theoretical yield of [tex]SO_3[/tex] produced by 8.96 g of S is 33.6 g
A
regulation
NBA
basketball
has
a
surface
area
of 283 square inches
.
What
is
the
surface
area
of
this
basketball
in Square Centimeters
?
Answer:
1.83 × 10³ cm²
Explanation:
Step 1: Given data
Surface area of a NBA basketball (A): 283 in²
Step 2: Convert "A" from square inches to square centimeters
In order to convert "A" from in² to cm², we need a conversion factor. In this case, we will use the conversion factor 1 in = 2.54 cm. Since "in" is raised to the power of 2, we will have to raise the conversion factor to the power of 2 as well.
283 in² × (2.54cm/1 in)² = 1.83 × 10³ cm²
Indicate the type of solute-solvent interaction that should be most important in each of the following solutions.a. LiCl in waterb. NF3 in acetonitrile (CH3CN)c. CCl4 in benzene (C6H6)d. methylamine (CH3NH2) in watere. Dispersion forcesf. Dipole-dipole forcesg. Ion-dipole forcesh. Hydrogen bonding
Explanation:
a. LiCl is an ionic molecule whereas water is a polar molecule with net dipole moment in it. There LiCl in water would have an ion-dipole force of interaction.
b. Both NF3 and CH3CN have dipole moment in them, since both are polar molecule. Hence, there would be dipole-dipole interaction.
c. Here both CCl4 and benzene are non polar molecules therefore, they have London dispersion force of interaction.
d. In methylamine and water both have hydrogen bonding in them. The nitrogen of CH3NH2 forms hydrogen bond with water.
The type of interactions in the following solutions are:
LiCl in water - Ion-dipole force[tex]\rm NF_3[/tex] in acetonitrile - Dipole-dipole force[tex]\rm CCl_4[/tex] in benzene - London Dispersion forceMethylamine in water - Hydrogen bondingIn a solution, the dissolution of solute molecules is driven by the interactions between the solute and solvent molecules.
Which interaction is present in solutions?The solute solvent interaction is based on the nature of the molecules. The interactions in the following solutions are:
LiCl in waterThe water is polar solvent and LiCl is an ionic molecule. The interaction between the molecules will be Ion-dipole force.
[tex]\rm NF_3[/tex] in acetonitrileThe acetronitrile and [tex]\rm NF_3[/tex] both are polar molecules. The force present in the interactions is Dipole-dipole force.
[tex]\rm CCl_4[/tex] in benzeneThe benzene and [tex]\rm CCl_4[/tex] both are nonpolar molecules. The type of interaction present in the solution is London Dispersion force.
Methylamine in waterThe water is a polar solvent, and Methylamine is an organic compound. The interaction in the solution is hydrogen bonding.
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What is a property of a moving object that makes it hard to stop?
How is a magnetic field produced?
O when an electromagnetic field interacts with a magnet
O when a current runs through a conductor
O when an object has an electric charge
O when electrons move through a circuit
Answer:
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. ... Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.
Answer: when an electromagnetic field interacts with a magnet
Explanation:
A gas sample of 5 moles, has a volume of 95 L. How many moles of the same gas should I add to obtain a volume of 133 L at the same temperature and pressure.
Over an interval of 2.0 s the average rate of change of the concentration of C was measured to be 0.0540 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 2.000 M
Answer:
Explanation:
the average rate of change of the concentration =
( initial concentration - final concentration ) / time
Initial concentration = 2.000 M
the average rate of change of the concentration = .0540 M/s
time = 2 s
Putting the values
.0540 = (2.000 - X ) / 2
0.108 = 2.000 - X
X = 1.892 M .
Final concentration = 1.892 M .
Observation of balloon rub with cloth?
Answer:
When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.
How are acids and alkalis
similar?
Answer:h
Explanation:
Answer:
Acids and alkalis both contain ions. Acids contain lots of hydrogen ions, which have the symbol H+. Alkalis contain lots of hydroxide ions, symbol OH-. Water is neutral because the number of hydrogen ions is equal to the number of hydroxide ions.
Draw a mechanism for the reaction of methanol with sodium amide. In the box to the left, draw any necessary curved arrows. Show the products of the reaction in the box to the right. Include any nonzero formal charges and all lone pairs of electrons. Finally, check the box to indicate which side of the reaction is favored at equilibrium.
Answer:
See explanation
Explanation:
When sodamide reacts with methanol, the following equilibrium is set up;
CH3OH(aq) + NH2-(aq) ⇄ CH3O-(aq) + NH3(aq)
In the reaction, the sodamide acts as a base that abstracts a proton from methanol to yield the conjugate base of methanol which is the methoxide ion.
The forward reaction is favoured at equilibrium.
Phosphate, PO43−, is a polyatomic ion that can combine with any cation to form an ionic compound.
Identify all the formulas below that correctly represent phosphate compounds.
Select one or more:
Combined with lithium:
Li3PO4
Combined with iron(III):
Fe3(PO4)3
Combined with iron(III):
FePO4
Combined with copper(I):
Cu3PO4
Combined with copper(I):
(Cu)3PO4
Combined with magnesium:
Mg3(PO4)2
Combined with magnesium:
Mg2(PO4)3
Combined with lithium:
Li2PO4
Answer:
Li3PO4 - correct
FePO4 - correct
Cu3PO4 - correct
Mg3(PO4)2 - correct
Explanation:
In order to answer this question we must be conversant with the idea of valency as well as the idea of writing formula of ionic substances.
Lithium has a valency of 1 while PO4^3- has a valency of 3 so the correct formula of lithium phosphate must be Li3PO4 after the exchange of valencies.
Iron III has a valency of 3 while the phosphate ion also has a valency of 3 so the subscripts cancel out and iron III phosphate is FePO4.
Copper I ion has a valency of 1 and the phosphate ion has a valency of 3. When they exchange valencies, the formula of the compound is Cu3PO4.
Magnesium has a valency of 2 while the phosphate ion has a valency of 3. The exchange of valency gives us the formula Mg3(PO4)2.
Change of a liquid to a solid