Answer:
the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.
Explanation:
In the figure, if the tension in string 1 is 34 N (40 degrees to the left) and the tension in string 2 is 24 N ( to the right) what is the mass of the object shown?
Answer:
3.7 kg
Explanation:
Start off by drawing and labeling a free-body diagram for the object. I have attached an image that I drew that shows all of the relevant forces acting on the object.
On the free-body diagram, we have the tension forces (T₁ and T₂), their x and y components, and the weight force (w).
We want to start off by finding the angle theta (Θ) so that we can use this angle when using Newton's Second Law later on in the problem to calculate the mass of the object.
We can find the angle Θ by using the fact that there are no unbalanced horizontal forces acting on the object, so the net force is zero.
This means that T₁ sin(40) is equal to T₂ sin(Θ). Set them equal to each other in an equation and solve for the angle Θ. We are given the tension forces: T₁ = 34 N and T₂ = 24 N.
T₁ sin(40) = T₂ sin(Θ)34 * sin(40) = 24 * sin(Θ)Evaluate 34 * sin(40) and divide it by 24 to isolate sin(Θ).
0.9106157804 = sin(Θ)Take the inverse sine of both sides of the equation.
Θ = sin⁻¹(0.9106157804) Θ = 65.59058699°Now that we have the angle Θ, we can use this to set up an equation involving mass using Newton's Second Law.
We know that there is a weight force directed downwards on the object, and this weight force is equal to mg (mass · gravitational acceleration).
There are two forces acting upwards on the object: the x-components of the two tension forces.
Using the fact that the object is not moving vertically, we know that the net force must equal 0 (since F = ma and acceleration = 0 m/s², therefore F = 0 N).
The sum of the forces in the y-direction will be equal to 0. Setting the upwards direction to be positive and the downwards direction to be negative, we can write this equation:
∑Fᵧ = T₁ cos(40) + T₂ cos(65.59058699) - mg = 0Add mg (weight force) to both sides of the equation.
T₁ cos(40) + T₂ cos(65.59058699) = mgSubstitute 34 for T₁ and 24 for T₂.
34 * cos(40) + 24 * cos(65.59058699) = mgThe gravitational acceleration on Earth is 9.8 m/s². Substitute this value into the equation and solve for m, the mass of the object.
34 * cos(40) + 24 * cos(65.59058699) = m(9.8)Evaluate the left side of the equation.
35.96360799 = 9.8mDivide both sides of the equation by 9.8.
m = 3.669755918Round this to two significant figures since the problem gives us the tension forces to two sig figs.
m ≈ 3.7 kgThe mass of the object shown is around 3.7 kg.
Answer:
3.7 kg
Explanation:
Start off by drawing and labeling a free-body diagram for the object. I have attached an image that I drew that shows all of the relevant forces acting on the object.
On the free-body diagram, we have the tension forces (T₁ and T₂), their x and y components, and the weight force (w).
We want to start off by finding the angle theta (Θ) so that we can use this angle when using Newton's Second Law later on in the problem to calculate the mass of the object.
We can find the angle Θ by using the fact that there are no unbalanced horizontal forces acting on the object, so the net force is zero.
This means that T₁ sin(40) is equal to T₂ sin(Θ). Set them equal to each other in an equation and solve for the angle Θ. We are given the tension forces: T₁ = 34 N and T₂ = 24 N.
T₁ sin(40) = T₂ sin(Θ)
34 * sin(40) = 24 * sin(Θ)
Evaluate 34 * sin(40) and divide it by 24 to isolate sin(Θ).
0.9106157804 = sin(Θ)
Take the inverse sine of both sides of the equation.
Θ = sin⁻¹(0.9106157804)
Θ = 65.59058699°
Now that we have the angle Θ, we can use this to set up an equation involving mass using Newton's Second Law.
We know that there is a weight force directed downwards on the object, and this weight force is equal to mg (mass · gravitational acceleration).
There are two forces acting upwards on the object: the x-components of the two tension forces.
Using the fact that the object is not moving vertically, we know that the net force must equal 0 (since F = ma and acceleration = 0 m/s², therefore F = 0 N).
The sum of the forces in the y-direction will be equal to 0. Setting the upwards direction to be positive and the downwards direction to be negative, we can write this equation:
∑Fᵧ = T₁ cos(40) + T₂ cos(65.59058699) - mg = 0
Add mg (weight force) to both sides of the equation.
T₁ cos(40) + T₂ cos(65.59058699) = mg
Substitute 34 for T₁ and 24 for T₂.
34 * cos(40) + 24 * cos(65.59058699) = mg
The gravitational acceleration on Earth is 9.8 m/s². Substitute this value into the equation and solve for m, the mass of the object.
34 * cos(40) + 24 * cos(65.59058699) = m(9.8)
Evaluate the left side of the equation.
35.96360799 = 9.8m
Divide both sides of the equation by 9.8.
m = 3.669755918
Round this to two significant figures since the problem gives us the tension forces to two sig figs.
m ≈ 3.7 kg
The mass of the object shown is around 3.7 kg.
A 40N force is applied to a spring constant of 100 N/m how far can this spring be compressed by the force
Answer:
Extension, e = 0.4 meters
Explanation:
Given the following data;
Force = 40N
Spring constant, k = 100N/m
To find the extension;
Force = spring constant * extension
Substituting into the equation, we have
40 = 100 * extension
Extension, e = 40/100
Extension, e = 0.4 meters
Therefore, the spring can be compressed by the force over a distance of 0.4 meters.
uses of convace, convex mirror
Answer:
The concave mirror is a converging mirror so that it is used for many purposes, It is used as a torch to reflect the light, It is used in the aircraft landing at the airports to guide the aeroplanes, It is used in shaving to get an enlarged and erect image of the face.
Explanation:
How do you calculate the magnitude of the resultant force of two
forces acting on an object in the same direction?
Answer:
Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force.
To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force. A force of 5 N acts to the right, and a force of 3 N act to the left. Calculate the resultant force.
What type of relationship exists between the rams?
Answer:
The relationship the exist between the rams is a mild one.
Explanation:
Please help me I give good points
A 6.0 kg box is at rest on a table. The static friction coefficient 1, between the box and table is 0.40, and
the kinetic friction coefficient us is 0.20. Then, a 23 N horizontal force is applied to the box.
What is the best estimate of the magnitude of the box's acceleration?
Round the answer (if non-zero) to two significant digits.
Choose 1 answer:
Answer:
B. 1.1 m/s²
good luck, i hope this helps :)
what is electrical energy ?
Explanation:
Electrical energy is energy derived from electric potential energy or kinetic energy. When used loosely, electrical energy refers to energy that has been converted from electric potential energy.
HOPE THIS HELPS YOU
Answer:
Hi!
Explanation:
Its kinetec energy moving by electric charges.
Mr. Draper asks his class to design a system of gears, strings, and pulleys that will allow him to pull back the classroom's curtains simply by turning a crank at his desk. The system must be built within the following constraints:
It must be made only out of metal gears, metal pulleys, string, and one crank.
It must be strong enough to move the curtains.
It cannot be in the way of students or their desks.
It must take no more than one day to build.
The final design will use which type of energy to perform work on the curtains?
A.
kinetic energy
B.
elastic potential energy
C.
thermal energy
D.
gravitational potential energy
Answer:
Its A
Explanation:Your using motion to crank which is kinetic energy
A sixth grader moves down the hall at 1.2 m/s. When he sees a bunch of eighth graders coming, he
begins to run. After 3.2 s, he is moving at 3,6 m/s. What is his acceleration?
Answer:
0.75m/s^2
Explanation:
3.6-1.2=2.4 m/s (Change in velocity)
2.4/3.2=0.75 m/s/s or m/s^2
The principal ran a marathon, 26.2 miles in 3 hours. This is an example of.....
A-speed
B-velocity
C-acceleration
True or false, the hardest working muscle in the body is the gluteus Maximus?
Answer:heart
The hardest working muscle is the heart. It pumps out 2 ounces (71 grams) of blood at every heartbeat. Daily the heart pumps at least 2,500 gallons (9,450 liters) of blood. The heart has the ability to beat over 3 billion times in a person's life.
Explanation:hope this helps
A race car takes 4.3 hours to teavel 500 miles. What is the average speed of the race car?
Answer:
speed = distance/time
Therfore,
speed = 500/4.3
= 116.27 ~ 116.3
So, the speed of the car is 116.3 mile/h
Hope it helps!
What is the definition of major plates?
Answer:
The outer shell of the earth, the lithosphere
Explanation:
The seven major plates are the African plate, Antarctic plate, Eurasian plate, Indo-Australian plate, North American plate, Pacific plate and South American plate.
A wave has a wavelength of 0.02m and period of 8.0*10^-2 seconds. calculate it's speed. (showing working)
Answer:
[tex]v = 0.25m/s[/tex]
Explanation:
Given
[tex]\lambda = 0.02m[/tex] --- Wavelength
[tex]T = 8.0 * 10^{-2}s[/tex] --- Period
Required
Determine the velocity of the wave
This is calculated using:
[tex]v = \frac{\lambda}{T}[/tex]
[tex]v = \frac{0.02m}{8.0*10^{-2}s}[/tex]
[tex]v = \frac{0.02m}{8.0*0.01s}[/tex]
[tex]v = \frac{0.02m}{0.08s}[/tex]
[tex]v = 0.25m/s[/tex]
Hence, the velocity is 0.25m/s
A bowling ball is rolling at a velocity of 56 km/h with a momentum of 130 kg-m/s. What is its
mass?
+
Answer:
Explanation:
Momentum
You have a series circuit powered by a 9V battery. If you double the amount of
resistance, what happens to the current?
Please answer fast!!!
which of the following is an example of unbalanced force?
1. A chair leaning on a wall
2. A stroller being pushed
3. A ball on the grass
4. A book sitting on a table
Answer:1. A chair leaning on a wall
Explanation:
How much work is performed when a 50 kg crate is pushed 15 m with a force of 20 N?
Answer:
300 jules
Explanation:
Everything is made up of blank and all matter is made of blank. There are three basic parts of atom: protons,neutrons, and blank. The blank and blank are located in the center of the atom; this area is called the blank. The electrons are found orbiting around the nucleus in an area we call the blank. They are organized into levels within the electron cloud, and the outermost level is referred to as the blank level.
a horizontal applied force of magnitude 25 N acts on a block sliding on a horizontal surface. The force of friction between the block and the surface has magnitude 8 N. If the direction of the applied force is reversed which of the following is true?
A. the magnitude of the velocity of the block will remain constant.
B. the magnitude of the acceleration of the block decreases
C. The magnitude of the net force on the block increases as compared to before.
D. the magnitude of the net force on the block will remain the same as before
' A ' and ' D ' are both correct statements.
A bullet is shot from a rifle with a velocity of 720 m/s. What is the velocity of the bullet in km/h.
Answer:
2592 km/h
Explanation:
Given that a bullet is shot from a rifle with a velocity of 720 m/s. What is the velocity of the bullet in km/h.
The velocity = 720 m/s
Solution
To convert metres per second to kilometer per hour, you will multiply by 3600 and divide by 1000
720 × 3600/1000
720 × 3.6
72 × 36
2592 km/h
Therefore, the velocity of the bullet in kilometer per hour is 2592 km/h
what is linear magnification
Answer:
Linear magnification refers to the ratio of image length to object length measured in planes that are perpendicular to the optical axis. A negative value of linear magnification denotes an inverted image.
Explanation:
Answer:
i hope it help
Explanation:
stay happy and safe
A car engine produces a force of 2000N while moving a distance of 200m in a time of 10s. What is the power developed by the engine
Electromagnetic waves from the sun reach the earth even though the space between us and the sun. Sound waves emitted by the sun cannot reach the earth. Explain why this difference?
Answer:
em waves do so because they require no medium to travel...space =vacuum)))
while sound waves that are longitudinal waves...require medium to travel......so in space it has vacuum.....it can't travel..
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! What is the fundamental frequency of a mandolin string that is 42.0 cm long when the speed of waves of the string is 329 m/s? with working outs
Answer:
f = V/λ = 329/0.42 = 783 Hz
:)
______ images are obtained when the plane mirror are kept parallel to the each other
.infinite.
&
also
.virtual.
How long would it take for a car to travel 22km if it has an average speed of 55 km/hr
Distance = (speed) x (time)
Time = (distance) / (speed)
Time = (22 km) / (55 km/hr)
Time = (22/55) (hr)
Time = 0.4 hour (that's 24 minutes)
________ 8. The pH of a solution is a measure of the concentration of H+ ions in it. TRUE OR FALSE
Answer:
False.
Explanation:
Potential of Hydrogen is the full form of PH.
Potential of Hydrogen tells about the acidity or basicity of the solution.
The pH of a solution is a measure of the concentration of hydrogen ions [tex](H+)[/tex] ions and hydroxide ions [tex](OH-)[/tex] in a solution.
So, the given statement is false.
Esteban pulls a 62 kg sled trough the snow. On the back of the sled is his 50 kg sack of fishing equipment. The between the sled and the snow is 0.07 and the between the sled and the sack is 0.1. While pulling, the fishing rod sticking out of his sack catches a tree branch, but Esteban doesn't notice and keeps walking. What force does Esteban need to exert to keep the sled moving with a constant velocity while the sack is pulled back across it?
Answer:
F = 144 N
Explanation:
For this exercise we will use Neqwton's second law. Let's fix a reference system with the x-axis in the direction of the sled, let's write the forces for each part
Sack, let's use subscript 1
Y axis
N₁-W₁ = 0
N₁ + W₁ = m₁ g
X axis
fr₁ = m a₁
the expression for the friction force is
fr = μ₁ N₁
we substitute
μ₁ m₁ g = m a₁
Sled, subscript 2
Y axis
N₂ - W₁ -W₂ = 0
N₂ = W₁ + W₂
N₂ = (m₁ + m₂) g
X axis
F - fr₁ -fr₂ = m a₂
the expression for the deroce force is
fr = μ N
we substitute
F - μ₁ m₁g - μ₂ (m₁ + m₂) g = m a₂
as it indicates that the velocity is constant the acceleration of the sled is zero (a₂ = 0)
F = μ₁ m₁g + μ₂ (m₁ + m₂) g
F = g (m₁ (μ₁ + μ₂) + μ₂ m₂)
let's calculate
F = 9.8 (50 (0.07 + 0.1) + 62 0.1)
F = 144 N
Which of the following planets is home to the largest volcano in our
solar system?
A. Earth
B. Mercury
C. Mars
D. Uranus