What is 5 percent of 300

Answer: 33

Step-by-step explanation: When a tangent and radius intersect (as in the diagram) they will always be perpendicular. And using the Triangle Sum Theorem that all angles add up to 180 when get that m<BCA must be 33 degrees.

Answer:

shhdhd

Step-by-step explanation:

Oh wow great marks

Answer:

B. f (4) = 4 · [tex]20^{3}[/tex]

Step-by-step explanation:

I did the quiz too

Step-by-step explanation:

The given figure can be broken into three parts i.e. a triangle, and two rectangles as shown in the figure.

The base and height of triangle is 15 and 7 in. respectively

For II shape, length and width are 8 and 2 in. respectively

For III shape, length and width are 10 and 9 in. respectively.

Answer:e

Step-by-step explanation:

-(5/3)=-5/3

180...................

Answer:

answer: 85

Step-by-step explanation:

These add up to 360 and

85 + 85 + 95 + 95 = 360 so 85 is the answer.

Hope that helps!

Answer:

x=13

Step-by-step explanation:

18-5=13. You have to subtract 5 from 5 itself and then 18.

Answer:

The first one- 24, The second one-B

Step-by-step explanation:

The first one-Top corner=110, 110+46=156, 180-156=24

The other one-I have no clue how to explain it

Answer:

true

true

false

Answer:

r=s+5

Step-by-step explanation:

So, letsgo over what we know:

The regular price is r

The sale price is s

Now lets compare the difference between r and s:

10r = 5s

20r = 15s

30r = 25s

What is the difference between the r and s value in each situration?

Well, from what I can see, r is always 5 more than s.

This can be writen as:

r = s+5\

So this is our equation, for if you plug in any number for s, you will get an accurate r value.

For instance, if you say s is 25:

r=25+5

=

r=30

This looks just like the 30r=25s in the table above.

So:

r=s+5

Hope this helps! :)

Answer:

Pedro pagó $448

Step-by-step explanation:

Sea P el precio inicial de un objeto.

Si aplicamos un descuento del X%, entonces el nuevo precio del objeto es:

NP = P*(1 - X%/100%)

y lo que estamos ahorrando es:

P - NP

En este caso, primero tenemos un descuento del 30%, entonces:

NP = P*(1 - 30%/100%) = P*(1 - 0.3)

Luego tenemos otro descuento, esta vez del 20%, entonces:

NP' = NP*(1 - 20%/100%) = P*(1 - 0.3)*(1 - 20%/100%) = P*(1 - 0.3)*(1 - 0.2)

Lo que Pedro ahorra es igual a $352

entonces:

P - NP' = $352

P -  P*(1 - 0.3)*(1 - 0.2) = $352

P*(1 - (1 - 0.3)*(1 - 0.2)) = $352

P*(1 - 0.56) = $352

P = $352/(1 - 0.56) = $800

Esto significa que el precio original era $800.

Y lo que pedro pago esta dado por la ecuación:

NP' = P*(1 - 0.2)*(1 - 0.3) = $800*(1 - 0.2)*(1 - 0.3) = $448.

Answer:

The only true statement is:

"∠3 + ∠4 = ∠1 + ∠2"

Step-by-step explanation:

When we have two lines intersect each other, there are 4 angles generated in the intersection.

Two vertical angles are angles whose only "contact point" is the intersection itself. The vertical angles are supplementary only if the two lines are perpendicular.

While a linear pair are two angles that are separated by one of the lines, and linear pairs are always supplementary.

Now let's look at the image and see which statements are true and which ones aren't.

"∠2 and ∠3 form a linear pair"

If we look at the image, we can see that ∠2 and ∠3 are not separated by one of the lines, ∠2 and ∠3 are vertical angles, then this statement is false.

"∠1 and ∠4 are supplementary angles"

Two angles are supplementary if the sum of the measures is equal to 180°, such that, as stated before, a linear pair of angles are supplementary angles.

In the case of ∠1 and ∠4, we can see that these angles are vertical angles, and we also can see that the lines are not perpendicular, then angles ∠1 and ∠4 are not supplementary.

"∠2 and ∠3 = 180°"

This is the same as saying that "∠2 and ∠3 are supplementary"

By the exact same reasoning than in the previous statement, we can find that this one is false.

"∠3 + ∠4 = ∠1 + ∠2"

We know that ∠1 and ∠2 are a linear pair, then ∠1 and ∠2 are supplementary angles, then:

∠1 + ∠2 = 180°

And we know that ∠3 and ∠4 also are a linear pair, and then also are supplementary angles, then we also have:

∠3 + ∠4 = 180°

Then is true that:

∠3 + ∠4 = ∠1 + ∠2

This statement is true.

"∠2 and ∠4 are vertical angles"

We can see that ∠2 and ∠4 are separated by one of the lines, then these angles form a linear pair.

The statement is false.

Answer:

[tex]area \: = side \times side \\ area = 20 \times 20 \\ area = 400 \: {cm}^{2} [/tex]

Answer:

400cm^2

Sides are 20cm long Area for square is a squared since all the lides are of equal length you can just choose one side.

20squared id 400

20 x 20 = 400cm squared

Answer:

12.327X + 452.084

45206.327

Step-by-step explanation:

The linear regression model obtained by fitting the data using technology is :

ŷ = 12.327X + 452.084

Where, 12.327 = slope ; 452.084 = Intercept ; X = appraised value ; y = Area

The estimated error variance which is the degree of variation between the actual and predicted value.

Error variance = ΣSSE /n-2

n = sample size = 15

ΣSSE = 587682.2638

Error variance = 587682.2638/13

Error variance = 45206.327

Answer:

y = - 3

Step-by-step explanation:

[tex]y = \frac{1}{4}x[/tex]

y = 0.25 · x

y = 0.25 · - 12

y = - 3

answer

the answer is is is option a 200

Answer:

What type of line the picture represent

Answer: It’s B.

Step-by-step explanation: Got it on edge

Answer:

Answer: It’s B.

Got it on edge

Step-by-step explanation:

Got it right on edge

Answer:

a. dS(t)/dt + [7S(t)/(300 - 5t)] = 1.2 with S(0) = 0.8

b. S(t) =   [tex]\frac{120e^{\frac{7t}{100} } }{7}[/tex]  -  16.34[tex]e^{-\frac{7t}{100}[/tex]

Step-by-step explanation:

a. Write an initial value problem for S(t), the amount of salt in the tank at time t. Do not solve the equation!!

The net mass flow rate of salt dS(t)/dt = mass flow in - mass flow out

mass flow in = concentration of flow in × flow rate in = 0.6 lb/gal × 2 gal/min = 1.2 lb/min

Let S(t) be the mass of salt in the tank at time, t. The concentration of salt in the tank at time, t, C(t) = S(t)/volume of tank at time t ,V

V = V₀ + (r - r')t where V₀ = initial volume of water in tank = 300 gal, r = volume flow rate in = 2 gal/min, r'= volume flow rate out = 7 gal/min and t = time

So, V = V₀ + (r - r')t

V = 300 + (2 - 7)t

V = 300 - 5t

So, C(t) = S(t)/V = S(t)/(300 - 5t) lb/gal

Now, mass flow rate out = concentration in tank × volume flow rate out = S(t)/(300 - 5t) lb/gal × 7 gal/min = 7S(t)/(300 - 5t) lb/min

So, dS(t)/dt = mass flow in - mass flow out

dS(t)/dt = 1.2 lb/min - 7S(t)/(300 - 5t) lb

dS(t)/dt = 1.2 - 7S(t)/(300 - 5t)

So, our differential equation is

dS(t)/dt + [7S(t)/(300 - 5t)] = 1.2 with S(0) = 0.8 since we initially have 0.8 lb of salt

b. Write an expression in terms of S for the amount of salt in the tank when the tank is one-quarter full.

When the tank is one-quarter full, V = volume of tank/4 = 400 gallons/4 = 100 gallons

We now solve our differential equation

dS(t)/dt + 7S(t)/100 = 1.2

Using the integrating factor method, I.F = [tex]e^{\int\limits{\frac{7}{100} \, dt } =[/tex]  [tex]e^{\frac{7t}{100} }[/tex]

[tex]e^{\frac{7t}{100}[/tex]dS(t)/dt +

d[[tex]e^{\frac{7t}{100}[/tex]S(t)]/dt = 1.2

d[[tex]e^{\frac{7t}{100}[/tex]S(t)] = [1.2

integrating both sides, we have

∫d[[tex]e^{\frac{7t}{100}[/tex]S(t)] = ∫[1.2

Let u = 7t/100. So, du/dt = 7/100 and dt = 100du/7

∫[1.2[tex]e^{\frac{7t}{100}[/tex]]dt = ∫[1.2 × 100[tex]e^{u}[/tex]]du/7 = (120/7)∫

[tex]e^{\frac{7t}{100}[/tex]S(t) =  [tex]\frac{120e^{\frac{7t}{100} } }{7}[/tex] + C

S(t) =   [tex]\frac{120e^{\frac{7t}{100} } }{7}[/tex] ÷ [tex]e^{\frac{7t}{100}[/tex]  +  [tex]e^{-\frac{7t}{100}[/tex]

S(t) =   [tex]\frac{120e^{\frac{7t}{100} } }{7}[/tex]  +  C[tex]e^{-\frac{7t}{100}[/tex]

From our initial condition, S(0) = 0.8. So,

S(0) =   [tex]\frac{120e^{\frac{7(0)}{100} } }{7}[/tex]  +  C[tex]e^{-\frac{7(0)}{100}[/tex]

S(0) =   [tex]\frac{120e^{\frac{0}{100} } }{7}[/tex]  +  C[tex]e^{-\frac{0}{100}[/tex]

S(0) =   [tex]\frac{120e^{0}}{7}[/tex]  +  C[tex]e^{0}[/tex]

0.8 =   [tex]\frac{120}{7}[/tex]   +  C

C = 0.8 - 120/7

C = 0.8 - 17.14

C = - 16.34

So,

S(t) =   [tex]\frac{120e^{\frac{7t}{100} } }{7}[/tex]  -  16.34[tex]e^{-\frac{7t}{100}[/tex]

Answer:

B= 43

Step-by-step explanation:

B=19+(6)(4)

B=19+24

B=43

Answer:

here are the cordinates you need to mark :

Step-by-step explanation:

(1,15) : 1x,15y

(2,20) : 2x,20y

(3,35) : 3x,35y

(4,45) : 4x,45y

(5,70) : 5x,70y

Hope this helps :)

Answer:

Hello! if Chris garden is a square shape then the answer is 40 7/10 in fraction form or 40.7 in decimal form

Answer:

cgtcdtxcgv gg ok

Step-by-step explanation:

Answer:

[tex](a)\ (-7,-3)\ \&\ (7,-3)[/tex]

Step-by-step explanation:

Given

Options a, b and c

Required

Points that are reflections across y-axis

The rule of reflection across the y-axis is:

[tex](x,y) \to (-x,y)[/tex]

Testing the given options:

[tex](a)\ (-7,-3)\ \&\ (7,-3)[/tex]

Rule: [tex](x,y) \to (-x,y)[/tex]

[tex](-7,-3) \to (-(-7),-3)[/tex]

[tex](-7,-3) \to (7,-3)[/tex]

This is true, because the actual reflection equals the given reflection

[tex](b)\ (-5,4)\ \&\ (5,-4)[/tex]

Rule: [tex](x,y) \to (-x,y)[/tex]

[tex](-5,4) \to (-(-5),4)[/tex]

[tex](-5,4) \to (5,4)[/tex]

This is not true, because the actual reflection does not equal to the given reflection

[tex](c)\ (1,-8)\ \&\ (1,8)[/tex]

Rule: [tex](x,y) \to (-x,y)[/tex]

[tex](1,-8) \to (-1,-8)[/tex]

This is not true, because the actual reflection does not equal to the given reflection

Hence

[tex](a)\ (-7,-3)\ \&\ (7,-3)[/tex] is a reflection of each other across y axis

Answer:

I am almost postive it is B, D, E

Answer:

slope: 4

Y-intercept: -7

Step-by-step explanation:

you would have to solve for y so you subtract the 7 on both sides. then it is in slope-intercept form which is y=mx+b where m is slope and b is the y-intercept. the slope would be 4 and the y-intercept would be -7

Answer:

explain please

Step-by-step explanation:

Answer:

nose nada

Step-by-step explanation:

:c