Answer:
A. The rate constant decreases
Explanation:
i took the quiz on a pex and it was correct
For many purposes we can treat butane as an ideal gas at temperatures above its boiling point of . Suppose the pressure on a sample of butane gas at is cut in half. Is it possible to change the temperature of the butane at the same time such that the volume of the gas doesn't change? yes no If you answered yes, calculate the new temperature of the gas. Round your answer to the nearest °C.
Answer:
A. Yes
B. The new temperature of the gas is -116 °C
Note: The question is incomplete. The complete question is given below :
For many purposes we can treat butane C H10) as an ideal gas at temperatures above its boiling point of - 1. °C. Suppose the pressure on a 500 mL sample of butane gas at 41.0°C is cut in half. Iyes Is it possible to change the temperature of the butane at the same time such that the volume of the gas doesn't change? yes no If you answered yes, calculate the new temperature of the gas. Round your answer to the nearest °C.
Explanation:
A. According to the pressure law of gases,for a fixed mass of gas the pressure of a gas is directly proportional to its Kelvin temperature once the volume is kept constant. This means that a change in temperature can bring about a change in pressurein a gas at constant volume.
B. From the pressure law of gasese: P1/T1 = P2/T2
Where initial pressure = P1, final pressure = P2
Initial temperature = T1, final temperature = T2
For the butane gas;
P1 = P
P2 = P/2
T1 = 41°C = (273 + 41 ) K = 314 K
T2 = ?
From the equation, T2 = T1 × P2 / P1
T2 = 314 × P/2 /P
T2 = 157 K
T2 = (157 - 273) °C = -116 °C
Therefore, the new temperature of the gas is -116 °C
In this experiment, you will need to prepare 250.0 mL of 0.100 M KCl(aq) solution. Determine the mass in grams of potassium chloride required to prepare this solution. Type your numerical answer (no units) in the box below. Even though the number of significant figures is limited to three by the inputs, please report your answer to four significant figures.
Answer: The mass in grams of potassium chloride required to prepare this solution is 1.862 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
moles of [tex]KCl[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{74.5g/mol}[/tex]
Now put all the given values in the formula of molality, we get
[tex]0.100=\frac{x\times 1000}{74.5g/mol\times 250.0ml}[/tex]
[tex]x=1.862g[/tex]
Therefore, the mass in grams of potassium chloride required to prepare this solution is 1.862 grams
Which of the following solutions is the most dilute.
a. 0.32 M
b. 1.5 M
c. 2.5 mol / L
d. 0.23 mol / L
e. 0.23 mol / L
Answer:
d and e
Explanation:
We have 5 solutions with different molar concentrations, that is, the quotient between the number of moles of solute and the liters of solution. This can be expressed as mol/L or M. The most dilute would be the one having the less number of moles of solute per liters of solution, that is, solution d or e, which have the same concentration. If we order them from the most diluted to the most concentrated, we get:
d = e < a < b < c
A gas has a volume of 6.00 liters at a temperature of 300 K and a pressure of 1.00 atm what is the volume of the gas in liters at a temperature of 600 K and a pressure of 3.00 atm
Answer:
V₂ = 4.00 L
Explanation:
Given that:
Volume (v1) = 6.00 L
Temperature (T1) = 300 K
Pressure (P1) = 1.00 atm
VOlume (V2) = unknown???
Temperature (T2) = 600 K
Pressure (P2) = 3.00 atm
Using combined gas law equation:
[tex]\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}[/tex]
[tex]\dfrac{1 \times 6}{300} = \dfrac{3 \times V_2}{600}[/tex]
[tex]\dfrac{1}{50} = \dfrac{1 \times V_2}{200}[/tex]
200 = 50V₂
V₂ = 200/50
V₂ = 4.00 L
For the following reaction conditions select the correct statement regarding the reaction below.
OH Cl OTs OTs N TsCl W X Y Z N
a. W is the correct product.
b. X is the correct product.
c. Y is the correct product.
d. Z is the correct product since pyridine acts as a nucleophile.
e. Both X and Y are both formed in this reaction as a racemic mixture
Answer:
B
Explanation:
The appropriate diagram of the question is shown in the first image attached below.
From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.
So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.
Thus, X is the appropriate and the correct product.
A sample of ideal gas at room temperature occupies a volume of 10.0 L at a pressure of 302 torr. If the pressure changes to 1510 torr
with no change in the temperature or moles of gas, what is the new volume, V2?
Explanation:
boyles law; P1V1=P2V2
302×10=1510×V2
V2=2L
Suppose you have a solution that might contain any or all of the following cations: Cu 2, Ag , Ba 2, and Mn2 . The addition of HBr causes a precipitate to form. After the precipitate is filtered off, H2SO4 is added to the supernate, and another precipitate forms. This precipitate is filtered off, and a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed. Which ions are present in each of the precipitates
Answer:
Ag⁺, Ba²⁺,
Explanation:
We can solve this question using the solubility rules:
When an Halide as Br- is added to a solution, the ions that can be precipitate are Ag⁺, Hg₂²⁺ and Pb²⁺.
That means the first ion present is Ag⁺
When sulfates, SO₄²⁻ are added, the ions that precipitates are: Ag⁺, Ca²⁺, Sr²⁺, Ba²⁺, Hg₂²⁺ and Pb²⁺
The second ion present is Ba²⁺
Hydroxides of Cu²⁺ and Mn²⁺ are insolubles but as no precipitate are formed when the solution is strongly alkaline those ions are not present.
How much ammonia would it take to neutralize 5ml of apple cider and 5ml of white vinegar if the ammonia had a molarity of 0.25?
Answer:
[tex]m_{NH_3}=0.0213gNH_3[/tex]
Explanation:
Hello there!
In this case, since it is known that the reaction between ammonia and acetic acid is:
[tex]CH_3COOH+NH_3\rightarrow CH_3COONH_4[/tex]
It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:
[tex]M_{acid}V_{acid}=M_{base}V_{base}\\\\[/tex]
In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:
[tex]m_{NH_3}=0.005L*0.25\frac{molNH_3}{L}*\frac{17.04gNH_3}{1molNH_3}\\\\m_{NH_3}=0.0213gNH_3[/tex]
Regards!
Which of the following is an example
of a chemical property?
A. Iron has a tendency to rust.
B. The boiling point of water is 100°C.
C. Salt will dissolve in water.
D. Chlorine does not conduct
electricity
Answer:
Examples of chemical properties include flammability, toxicity, acidity, reactivity (many types), and heat of combustion.
8. Calculate (H^+), (OH^-), pOH and the pH for a 0.00024 M solution of calcium hydroxide. Must show work!
Answer:
1. [H⁺] = 2.0×10¯¹¹ M
2. [OH¯] = 4.8×10¯⁴ M
3. pOH = 3.3
4. pH = 10.7
Explanation:
From the question given above, the following data were obtained obtained:
Molarity of Ca(OH)₂ = 0.00024 M
We'll begin by calculating the concentration of the hydroxide ion [OH¯]. This can be obtained as follow:
Ca(OH)₂ (aq) —> Ca²⁺ + 2OH¯
From the balanced equation above,
1 mole of Ca(OH)₂ produced 2 moles of OH¯.
Therefore, 0.00024 M Ca(OH)₂ will produce = 2 × 0.00024 = 4.8×10¯⁴ M OH¯
Thus, the concentration of the hydroxide ion [OH¯] is 4.8×10¯⁴ M
Next, we shall determine the pOH of the solution. This can be obtained as follow:
Concentration of the hydroxide ion [OH¯] = 4.8×10¯⁴ M
pOH =?
pOH = –Log [OH¯]
pOH = –Log 4.8×10¯⁴
pOH = 3.3
Next, we shall determine the pH of the solution. This can be obtained as follow:
pOH = 3.3
pH =?
pH + pOH = 14
pH + 3.3 = 14
Collect like terms
pH = 14 – 3.3
pH = 10.7
Finally, we shall determine the concentration of hydrogen ion [H⁺]. This can be obtained as follow:
pH = 10.7
Concentration of hydrogen ion [H⁺] =?
pH = –Log [H⁺]
10.7 = –Log [H⁺]
Divide both side by –1
–10.7 = Log [H⁺]
Take the antilog of –10.7
[H⁺] = Antilog (–10.7)
[H⁺] = 2.0×10¯¹¹ M
SUMMARY:
1. [H⁺] = 2.0×10¯¹¹ M
2. [OH¯] = 4.8×10¯⁴ M
3. pOH = 3.3
4. pH = 10.7
A solution is prepared by mixing 2.50g of CaCl2 with 50.0g H2O, what is the mass percent of CaCl2?
A. 3.76%
B. 4.76%
C. 5.76%
D. 6.76%
Ar
Si
K
Al
An atom of which element in the table above has the highest
number of neutrons?
Answer: ar
Explanation:
Can someone please help me with this question.
Answer:
A-Sphalerite + Dioxygen+Zinc Oxide+Sulfur Trioxide
B-Sodium+Magnesium+Sodium iodide
Explanation:
Heyyy love good luck i may be wrong on letter B so if it is thats my bad but A should be correct :)
If you have a solution that is 15 percent by mass of KCl in benzene, what is the new boiling point?
Answer:
https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186
Explanation: Thats your answer
For each event stated below, indicate how the concentration of each species in the chemical equation will then change to reach equilibrium.
2CO(g) + O2(g) ⇌ 2CO2(g)
a. increasing the concentration of CO
b. decreasing the amount of O2
c. decreasing the the volume of the system
Answer:
See Explanation
Explanation:
When a constraint such as a change in temperature, concentration or pressure is imposed on a reaction system in equilibrium, the system will readjust itself in such a way as to annul the constraint. This readjustment occurs when the equilibrium position shifts towards the left or right in order to annul the constraint.
a. increasing the concentration of CO: When the concentration of CO is increased, the equilibrium position shifts to the right in order to annul the constraint. This means that more CO2 is produced in the system while the concentration of CO and O2 are decreased until equilibrium is reestablished.
b. decreasing the amount of O2: When the amount of O2 is decreased, the equilibrium position will shift to the left and more CO and O2 are produced while the concentration of CO2 decreases until equilibrium is reestablished.
c. decreasing the the volume of the system: When the volume of the system is decreased, the equilibrium position shifts towards the right hand side where there is less total volume. Hence the concentration of CO and O2 decreases while the concentration of CO2 increases.
Suppose that you must go into court and testify as to the level of X in the river water. Your lawyer is concerned that your analytical results are lower than they should be because you cannot extract with benzene (distribution Ratio K=4) all of X from your samples. Assume the concentration of X in the 1.00 L river water sample is 1.06 x 10-4 M.
a. How many extracts would be required to remove all but 1000 molecules of X from the sample with repeated 10.00 mL portions of extract?
b. How many extractions are required for a 99.99% chance of extraction of the last molecule remaining (0.01% chance of a single molecule left behind)
Answer:
The appropriate solution is:
(a) n ≈ 900
(b) n ≈ 1165
Explanation:
According to the question,
(a)
The final number of molecules throughout water will be:
= [tex](\frac{1000}{1000}\times 4\times 10 )^n[/tex]
where, n = number of extractions
Now,
The initial number of molecules will be:
= [tex]1.06\times 10^{-4}\times 6.023\times 10^{23}[/tex]
= [tex]6.387\times 10^{19}[/tex]
Final number of molecule,
⇒ [tex]1.566\times 10^{-16}=(\frac{1000}{1040} )^n[/tex]
[tex]n \approx 900[/tex]
(b)
Final molecules of X = left (0.01%)
hence,
⇒ [tex]initial = 6.384\times 10^{19}[/tex]
[tex]\frac{1}{6.384\times 10^{19}} =(\frac{1000}{1040} )^2[/tex]
[tex]n \approx 1165[/tex]
A scientist wants to investigate several problems. In which of the following situations is using a simulation LEAST suitable for solving a problem?
a. When a scientific study requires performing a large number of trials that need to be conducted very quickly
b. When the solution to the problem requires real-world data inputs that are continually measured at regular intervals.
c. When performing an experiment that would be too costly or dangerous to conduct in the real world
d. When it is considered acceptable to make simplifying assumptions when modeling a real-world object or phenomenon
Answer:
A
Explanation:
got from another website
The simulation which is least suitable to scientists for solving a problem is when performing an experiment that would be too costly or dangerous to conduct in the real world.
What is scientific approach?Scientific approach is an empirical method of acquiring knowledge and result. This method involved the careful observation of the problem, applying skepticism about the problem and giving cognitive assumptions also.
If a scientist wants to investigate several problems, then they will perform a large no. of trials at regular intervals to get the required result. But if performing of any experiment is dangerous to conduct in the real world then scientists will ignore to solve that problem.
Hence, option (C) is correct.
To know more about scientific approach, visit the below ink:
https://brainly.com/question/497944
8. Sulfur has a first ionization energy of 1000 kJ/mol. Photons of what frequency are required to ionize one mole of Sulfur?
Answer:
the frequency of photons [tex]v = 1.509\times10^{39}Hz[/tex]
Explanation:
Given: first ionization energy of 1000 kJ/mol.
No. of moles of sulfur = 1 mole
[tex]\Delta E_1 = 1000KJ/mol[/tex]
We know that plank's constant
[tex]h = 6.626\times10^{-34} Js[/tex]
Let the frequency of photons be ν
Also we know that ΔE = hν
this implies ν = ΔE/h
[tex]= \frac{10^6J}{6.626\times10^{-34} Js}[/tex]
[tex]v = 1.509\times10^{39}Hz[/tex]
Hence, the frequency of photons [tex]v = 1.509\times10^{39}Hz[/tex]
How many grams of water can be heated from 15.0 oC to 55oC using 4250.0 J.
Answer:
25.42 grams
Explanation:
The specific heat of water is 4.18 J/g •°C, so that means that it takes 4.18 joules of energy to raise one gram of water 1 °C.
Change in temp = 55 - 15 = 40°C
So we can calculate how much energy it would take to raise the temp of one gram of water by one degree using the following
(4.18 J/g•°C) * (40°C) * (1 gram) = 167.2 J
So if it takes 167.2 J of energy to raise on gram of water 40°C, we now we can calculate the amount of grams of water that can heated with 4250 J of energy
(4250 J) ÷ (167.2 J) = 25.42 grams of water can be heated from 15°C to 55°C
PLEASEEE HELP!!!! ILL MARK BRAINLESS FIRST PERSON!!!!!
Answer:
A. it should have a cell wall to give it structure
Why are fossil fuels considered nonrenewable resources?
Answer:
They are considered nonrenewable because they are prehistoric animals that has been extinct therefore can't be renew.
to find the mass in g of 3 moles Al .
Answer:
81 gm
Explanation:
The mass of 1 mole is 27 gSo, Mass of 3 moles of Aluminium would be 3 × 27 = 81 gm
Thus mass of 3 Moles of Aluminium is 81 gm.
balance the equation P + O2 → P4O10
Can someone give me an example of balancing equations with a solution that is simple?
Explanation:
[tex]H _{2}O _{2(aq)} →H _{2}O _{(l)} + O _{2}(g) \\ solution : 2 \: and\: 2[/tex]
The ionization potential of Be atom is more than expected because it has -
(a) half filled valence p orbitals
(b) fully filled valence s orbitals
(c) both a and b
Answer:
(b) fully filled valence s orbitals
Explanation:
Electron configuration of Be: 1s22s2
2s2 is fully filled
a warm air is rising as cooler air es in to take its place. what is the name for that?
Answer:
convection
hope this helps
have a good day :)
Explanation:
What is the Molar mass of zinc
Answer:
the molar mass of zinc is 65.38u or 65.38 grams(g).
mplete the following Charles' Law calculations. If the current temperature is 25 degrees C and you have a 2L balloon, identify the new volume of the balloon if you increase the temperature to 30 degrees C. Remember to change Celsius to Kelvin: K= C + 273.
Answer:
New volume = 2.03 L
Explanation:
Given that
Initial temperature, T₁ = 25°C = 298 K
Initial volume, V₁ = 2L
Final temperature, T₂ = 30°C = 303 K
We need to find the final volume. The mathematical form of Charle's law is given by :
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}[/tex]
Put all the values,
[tex]V_2=\dfrac{2\times 303}{298}\\\\V_2=2.03\ L[/tex]
so, the new volume is equal to 2.03 L.
in a hypothetical element ,two energy levels are separated by an energy of 282kj mol-1 . what wavelength of light (in nma) is evolved for an electron to change between these two levels?
Answer:
7.05 × 10⁻²² nm
Explanation:
Step 1: Given and required data
Energy evolved when a mole of electrons changes between the 2 levels (E): 282 kJPlanck's constant (h): 6.63 × 10⁻³⁴ J.sSpeed of light (c): 3.00 × 10⁸ m/sStep 2: Calculate the wavelength (λ) of the light evolved
We will use Planck-Einstein's relation.
E = h × c/λ
λ = h × c/E
λ = (6.63 × 10⁻³⁴ J.s) × (3.00 × 10⁸ m/s)/(282 × 10³ J) = 7.05 × 10⁻³¹ m
We will convert λ to nm using the conversion factor 1 m = 10⁹ nm.
7.05 × 10⁻³¹ m × 10⁹ nm/1 m = 7.05 × 10⁻²² nm
a transverse wave moves a medium at an abtuse angle to the wave , true or false ?
Answer:
True! A transverse wave does move a medium at an obtuse angle to the wave!!
Answer:
False
Explanation: