What gift is given from one generation to the next

Explanation:

Potential energy=MGH

100=3×10×H.

H=100/30

H=3.40m

Answer:

Hope this helps =)

Explanation:

The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.

Answer:

O C. Its particles vibrate slightly.

Explanation:

At absolute zero, atoms would occupy the lowest energy state.They move much less than at higher temperatures, but they still have small vibrations at absolute zero.

Answer:

The answer is B its particles have no kinetic energy

Explanation:

trust the big brain

Answer:

The same current flows through each resistor in series. Individual resistors in series do not get the total source voltage, but divide it. The total resistance in a series circuit is equal to the sum of the individual resistances: RN(series)=R1+R2+R3+…

Answer:

13.1 m/s

Explanation: Given that a pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere

The formula to use is :

W = sqrt ( L/g )

Where

L = 67m

g = 9.8m/s^2

A = 5m

Substitute all the parameters into the formula

W = sqrt ( 67 / 9.8 )

W = 2.6

To get the maximum velocity, we use the below formula.

V = wA

V = 2.6 × 5

V = 13.07 m/s

Therefore the maximum speed of the sphere is 13.1 m/s approximately.

Answer:

mmmm im going to say B but i’m not sure

Explanation:

Electromagnetic waves can travel through air and unlike ocean waves or sound waves they do not need physical molecules for like a medium to travel

Answer:

(a) I = 625 A

(b) I = 101 A    

Explanation:

The relationship between current, voltage and resistance can be given by Ohm's Law:

V = IR

where,

V = Voltage

I = Current

R = Resistance

(a)

Here,

V = 12.5 V

R = 0.02 Ω

Therefore,

[tex]12.5\ V = I(0.02\ \Omega)\\\\I = \frac{12.5\ V}{0.02\ \Omega}[/tex]

I = 625 A  

(b)

Here,

V = 10.1 V

R = 0.1 Ω

Therefore,

[tex]10.1\ V = I(0.1\ \Omega)\\\\I = \frac{10.1\ V}{0.1\ \Omega}[/tex]

I = 101 A    

Answer:

2

Explanation:

Answer:

stretching prior to an exercise is a great way to improve a range of motion, along with yoga and Pilates!

Answer:

A&B

Explanation:

Answer:

Chemical to mechanical(b) and Chemical to Thermal(a)

Answer:

force on the electron is upwards

Explanation:

The magnetic force is given by the relation

        F = q v x B

the bold indicates vectors, we can write the module of this expression

        F = q v  B sin θ

the direction of the force is given by the right hand rule.

If we have a positive charge, the flea points in the direction of velocity, in this case towards the inside of the page.

fingers extended in the direction of the magnetite field, in our case to the right and

the palm gives the direction of the force for a positive charge, for a negative charge it is in the opposite direction. The palm points downwards, so the force on the electron is upwards

Answer:

    vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = [tex]\sqrt{\frac{2GM}{R} }[/tex]

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( [tex]1+ \frac{\Delta M}{M}[/tex] )

            R ’= R + ΔR = R ( [tex]1 + \frac{\Delta R}{R}[/tex] )

we substitute

           vₐ = [tex]\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }[/tex]

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( [tex](1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )[/tex])

we make the product and keep the terms linear

        vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

The minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

The escape velocity is defined as the velocity required to send the object out of the gravitational influence of the earth.

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

    [tex]E_{mo} = K + U = \dfrac{1}{2} m v_c^2 - \dfrac{G Mm} { R}[/tex]

final point. At a very distant point

      [tex]E_{mf} = U = \dfrac{- G Mm }{ R_2}[/tex]

energy is conserved

         [tex]E{mo} = E{mf}[/tex]

          [tex]\dfrac{1}{2}m v_c^2 - \dfrac{G Mm} {R} = \dfrac{- G Mm }{ R_2}[/tex]

[tex]v_c^2 = 2 G M (\dfrac{1} {R} - \dfrac{ 1 }{R_2})[/tex]

if we consider the speed so that it reaches an infinite position R₂ = ∞

[tex]v_c = \sqrt{\dfrac{2GM}{R}[/tex]

now indicates that the mass and radius of the planet changes slightly

[tex]M ’= M + \Delta M = M(1+\dfrac{\Delta M}{M})[/tex]  

[tex]R ’= R + \Delta R = R (1+\dfrac{\Delta R}{R} )[/tex]

we substitute

   [tex]vₐ = \sqrt{\dfrac{2GM}{R} }\dfrac{\sqrt{1+\dfrac{\Delta M}{M}}} {\sqrt{1+\dfrac{\Delta R}{R}}}[/tex]

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

      [tex]v_a=v_c(1+\dfrac{1}{2}\dfrac{\Delta M}{M})(1-\dfrac{1}{2}\dfrac\Delta R}{R})[/tex]

Hence the minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

To know more about escape velocity follow

https://brainly.com/question/13726115

Answer: When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light. The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray.

Have a great day and stay safe !

Answer:

The Republican party was formed because they wanted??????

Explanation:

Answer: deceleration of [tex]1.904\ rad/s^2[/tex]

Explanation:

Given

Car is traveling at a speed of u=20 m/s

The diameter of the car is d=70 cm

It slows down to rest in 300 m

If the car rolls without slipping, then it must be experiencing pure rolling i.e. [tex]a=\alpha \cdot r[/tex]

Using the equation of motion

[tex]v^2-u^2=2as\\[/tex]

Insert [tex]v=0,u=20,s=300[/tex]

[tex]0-(20)^2=2\times a\times 300\\\\a=\dfrac{-400}{600}\\\\a=-\dfrac{2}{3}\ m/s^2[/tex]

Write acceleration as [tex]a=\alpha \cdot r[/tex]

[tex]-\dfrac{2}{3}=\alpha \times 0.35\\\\\alpha =-\dfrac{2}{1.05}\\\\\alpha =-1.904\ rad/s^2[/tex]

So, the car must be experiencing the deceleration of [tex]1.904\ rad/s^2[/tex].

The angular accelaration of a car traveling at 20.0 m/s on tires with a diameter of 70.0 cm, when car slows down to rest after traveling 300.0 m is 1.91 m/s

Angular acceleration: This can be defined as the rate of change of angular velocity. The s.i unit of angular acceleration is  rad/s²

In other to solve the problem above, we will use the formula for calculating angular acceleration

a = αr.............. Equation 1

Where a = acceleration of the car's tires, α = angular acceleration of the car's tires, r = radius of the car's tires

Therefore,

α = a/r................. Equation 2

But, we need to calculate a using the equations of motion

v² = u²+2as................ Equation 3

Where v = final velocity = 0 m/s (rest), u = initial velocity= 20m/s, s = distance = 300 m

Substitute these values into equation 3

0² = 20²+2(300²)a

-400 = 600a

a = -400/600

a = -0.67 m/s²

going back to equation 2,

Given: r = 70/2 = 35 cm = 0.35 m

Substitute this values into  equation 2,

α = -0.67/0.35

α = -1.91 rad/s²

Hence, the magnitude of the angular acceleration is 1.91 rad/s²

Learn more about angular acceleration here: https://brainly.com/question/20432894

Answer: creo que es A o D

Explanation:

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

To solve this, we must be knowing each and every concept related to lever.  Therefore,  due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of 3rd class. The correct option is option C.

A lever is a basic device that consists of a beam or stiff rod located at a set tight, or edge. It is used to apply force to a load and often offers a mechanical advantage.

A stiff object that can rotate about a spot on itself is called a lever. The three types of levers are categorized according to where the edge, weight, and effort are located. Due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of  3rd class.

Therefore,  the correct option is option C.

To learn more about lever, here:

https://brainly.com/question/2860526

#SPJ2

place's absolute location is its exact place on Earth, often given in terms of latitude and longitude. For example, the Empire State Building is located at 40.7 degrees north (latitude), 74 degrees west (longitude).

Place's absolute location is its exact place on Earth, often given in terms of latitude and longitude.

A point's longitude, which might refer to the east-west position of a point on the surface of the Earth or another celestial body, is a geographic coordinate. The Greek symbol lambda is used to represent the angular measurement, which is often given in degrees.

Latitude is a coordinate used in geography that describes a point's north-south location on the surface of the Earth or another celestial body. Latitude is measured as an angle, with 0° at the Equator and values ranging from -90° at the south pole to 90° at the north pole.

Place's absolute location is its exact place on Earth, often given in terms of latitude and longitude.

To learn more about longitude refer to the link:

brainly.com/question/28606059

 #SPJ2

Answer:

Explanation:

Some geologists favor convection currents in the mantle as the best explanation for plate tectonic movement. It is reasonable to assume that the heat radiated from the core creates convection currents in the mantle, and the mantle rocks begin to move plastically.

Answer:

It can travel in various wavelengths. brainliest?

Explanation:

The evidence that reveals about the light is that  It can travel in various wavelengths.

It is the wave property that should be blending of the wave related to the corners.

At the time when the wave is bending so it passed via the openings.

Also, the light diffracted via the small slits and it should be shown to arise in the water waves and the sound waves.

hence, the first option is correct.

Learn more about light here: https://brainly.com/question/26122702

Answer:

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium.

Explanation:

I hope this helped you

(Sorry If it didn't)

Answer:

Explanation:

Slit distance d = .25 x 10⁻³ m .

Distance of screen D = 60 x 10⁻² m

Distance between first and fifth minimum = 5.5 x 10⁻³ m .

There will be four bright fringes between first and 5 th minimum so

distance between them = 4 x λ D / d  where λ is the wavelength of light .

Substituting the values

4 x λ x 60 x 10⁻² m  /  .25 x 10⁻³ m = 5.5 x 10⁻³ m

4 x λ x 60 x 10⁻² m =  .25 x 10⁻³ m x  5.5 x 10⁻³ m = 1.375 x 10⁻⁶ m

λ = .005729 x 10⁻⁴

= 572.9 x 10⁻⁹ m

= 572.9 nm .

Answer:

[tex]\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}[/tex]

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=m \times a[/tex]

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

Substitute these values into the formula.

[tex]F= 8 \ kg * 1.6 \ m/s^2[/tex]

Multiply.

[tex]F= 12.8 \ kg*m/s^2[/tex]

Now,  use the force we just calculated to complete the second part of the problem. We use the same formula:

[tex]F= m \times a[/tex]

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

Substitute the values into the formula.

[tex]12.8 \ kg*m/s^2= 2 \ kg *a[/tex]

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}[/tex]

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}=a[/tex]

The units of kilograms cancel.

[tex]\frac {12.8}{2}\ m/s^2=a[/tex]

[tex]6.4 \ m/s^2=a[/tex]

The acceleration is 6.4 meters per square second.

Answer:

Negative electric charges

Answer:

one beta particle

Explanation:

Since the atomic number of 131_I_53 increases by one to 131_Xe_54, we have the release of a beta particle since only a beta particle can cause a change in atomic number without a change in mass number. Since a beta particle is one electron, ₋₁⁰e, our nuclear equation is

¹³¹I₅₃ → ¹³¹X₅₄ + ₋₁⁰e

The atomic and mass numbers on both sides are balanced

mass number 131 = 131 + 0 = 131

atomic number 53 = 54 - 1 = 53

Thus a beta particle is emitted

Answer:

Answer is option d

Explanation:

,Mark as brainlist