What forces are acting on the race car while it is in motion? (hint: there are 3
forces)

Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

Answer:

Option B is appropriate for this question

Answer:

the researcher say hi for us the best pa the best of us are going out to eat that I can get my money toward a little bit but the best of luck to be at work by then and we will see what the status

Answer:B

Explanation:

Answer:

1) true 2) true 3) true 4) true 5) false 6) false

Explanation:

Answer:

8 days

Explanation:

Answer:

The angle the boat must be pointed upstream is 69⁰

Explanation:

Check the image uploaded for the diagram;

Given;

speed of the boat on still water, = 4.6 km/h

speed of the boat on a river with current, = 1.8 km/h

The angle the boat must be pointed upstream is calculated as follows

[tex]tan(\theta) = \frac{4.6}{1.8} \\\\tan(\theta) = 2.556\\\\\theta = tan^{-1}(2.556)\\\\\theta = 68.63^0\\\\\theta = 69^0[/tex]

Answer:

As objects move around over time, the energy associated with them—e.g., kinetic, gravitational potential, heat—might change forms, but if energy is conserved, then the total will remain the same. Conservation of energy applies only to isolated systems.

thenks and pls mark me barinliestt :))

This question is incomplete, the complete question  is;

Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec

m = 0.2, γ = 1.6 and k = 4

Initial displacement is 1 and initial velocity is -2

x" + _____ x' ____x = 0

x(t) =

Answer:

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Explanation:

Given the data in the question ;

m = 0.2, γ = 1.6, k = 4

x(0) = 1, x'(0) = -2

Now, the differential equation that governs the motions of spring mass system is;

mx" + γx' + kx = 0

so we substitute

0.2x" + 1.6x' + 4x = 0

divide through by 0.2

x" + 8x' + 20x = 0

hence, characteristics equation will be;

m² + 8m + 20 = 0

we find m using; x = [ -b±√(b² - 4ac) ] / 2a

m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)

m = [ -8 ± √( 64 - 80 ) ] / 2

m = [ -8 ± √-16 ) ] / 2

m = ( -8 ± 4i ) / 2

m = -4 ± 2i

Hence, the general solution of the differential equation is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

From the initial conditions;

c₁ = 1, c₂ = 1

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Answer:

As long as there is rain, a rainbow is possible. Rain is possible on a sunny day, and is known as a sunshower.The rainbow can be observed in a sunny day if the water droplets are present in air and the sun rays pass through it reaches the eye of the observer. In this situation, the observer can see a rainbow.

or

If you happened to look up at the sky this past weekend, you might have noticed a rare and beautiful sight: iridescent rainbow clouds, but not a drop of rain in sight. This phenomenon is known, fittingly, as cloud iridescence or irisation. The effect is not unlike seeing a rainbow painted on the clouds.

Answer:

The number of particles in state E0 over the number of particles in state E1  will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart  means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1  will reduce.

Answer:

B

Explanation:

Answer:

D)parallel circuit

Explanation:

the components are placed parallel from eachother

Answer:

[tex]81:256[/tex].

Explanation:

Let [tex]T[/tex] denote the absolute temperature of this object.

Calculate the value of [tex]T[/tex] before and after heating:

[tex]T(\text{before}) = 27 + 273 = 300\; \rm K[/tex].

[tex]T(\text{after}) = 127 + 273 = 400\; \rm K[/tex].

By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to [tex]T^4[/tex].

Ratio between the absolute temperature of this object before and after heating:

[tex]\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}[/tex].

Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:

[tex]\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}[/tex].

Answer:

2 Joule

Explanation:

Work=force *dISPLACMENT

2N*1M

2 JOUL

Answer:

The FITT principles are an exercise prescription to help participants understand how long and how hard they should exercise. FITT is acronym that stands for Frequency, Intensity, Time, and Type. FITT can be applied to exercise in general or specific components of exercise.

Explanation:

Answer: [tex]8.54\times 10^{-5}\ s[/tex]

Explanation:

Given

The initial magnetic field is [tex]B=0.27\ T[/tex]

No of turns [tex]N=599\ \text{turns}[/tex]

Diameter of the solenoid [tex]d=9.29\ cm[/tex]

Induced EMF [tex]E=12.8\ kV[/tex]

Induced emf is the product of no of turns and rate of change of flux.

[tex]\Rightarrow E=-N\cdot \dfrac{\Delta \phi }{\Delta t}\\\\\Rightarrow E=-N\cdot \dfrac{\Delta (B\cdot A)}{\Delta t}\\\\\Rightarrow E=-NA\cdot \dfrac{\Delta B}{\Delta t}\\\\\text{Insert the values}\\\\\Rightarrow 12.8=-599\times \pi r^2\cdot \dfrac{(0-B)}{\Delta t}\\\\\Rightarrow \Delta t=\dfrac{599\times \pi \times (4.64\times 10^{-2})\times 0.27}{12.8\times 10^3} \\\\\Rightarrow \Delta t=854.71\times 10^{-7}\ s\\\\\text{Taking absolute value}\\\Rightarrow \Delta t=8.54\times 10^{-5}\ s[/tex]

Answer:

773.25 Hz

Explanation:

Concept : In an open organ pipe in fundamental mode of vibration

wave length of wave λ = 2L

where L  is length of  the pipe

frequency   = velocity of sound / λ

Given values: fundamental frequency = 288 Hz

fluid is air. velocity of sound = 340 m/s

⇒ 288 = 340/2L

⇒L = 59.02 cm

The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then,  frequency of note produced will also be changed .

We know that velocity of sound is inversely proportional to  square root of molar mass of gas

velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)

[tex]\frac{V_a}{V_{He}} = \sqrt{\frac{4}{28.8} } \\\frac{340}{V_{He}} =0.3725\\V_{He} =912.5 m/s[/tex]

Now, frequency  = velocity of sound / λ

= 912.75 / (2 x 0.5902)

= 773.25 Hz

Answer:

r = 6.6 x 10³ m = 6600 m

Explanation:

The potential at a distance from a charged sphere can be given as follows:

[tex]V = \frac{kq}{r}\\\\r = \frac{kq}{V}[/tex]

where,

r = distance = ?

k = Colomb Constant = 9 x 10⁹ Nm²/C²

q = charge on sphere = 3.3 C

V = potential = 4.5 MV = 4.5 x 10⁶ V

Therefore,

[tex]r = \frac{(9\ x\ 10^9\ Nm^2/C^2)(3.3\ C)}{4.5\ x\ 10^6\ V}[/tex]

r = 6.6 x 10³ m = 6600 m

Answer:

the frequency of the oscillation is 1.5 Hz

Explanation:

Given;

mass of the spring, m = 1500 kg

extention of the spring, x = 5 mm = 5 x 10⁻³ m

mass of the driver = 68 kg

The weight of the driver is calculated as;

F = mg

F = 68 x 9.8 = 666.4 N

The spring constant, k, is calculated as;

k = F/m

k = (666.4 N) / (5 x 10⁻³ m)

k = 133,280 N/m

The angular speed of the spring is calculated;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s[/tex]

The frequency of the oscillation is calculated as;

ω = 2πf

f = ω / 2π

f = (9.426) / (2π)

f = 1.5 Hz

Therefore, the frequency of the oscillation is 1.5 Hz

Answer:

C) the heat removed from the inside to the work done to remove the heat.

Explanation:

Refrigerator is a heat engine working in reverse direction . Heat from cold source is taken out , some work is done to remove them and total heat and work energy is thrown into outside surrounding .

If q heat is taken out and W is work done to get this heat out .

coefficient of performance ( COP ) = q / W .

Hence C ) is the right choice .

Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C

Substitute these values into equation 2

t = 4190×40(75-20)/3500

t = 9218000/3500

t = 2633.7 s

Answer:

The right solution is:

(a) 89.455 m/s

(b) 44.73 m/s

Explanation:

The given values are:

Mass,

m = 200 lbs

or,

   = [tex]\frac{200}{2.205} \ kg[/tex]

   = [tex]90.7 \ kg[/tex]

Air's density,

[tex]\delta = 1.225 \ kg/m^3[/tex]

Drag coefficient,

[tex]C_d=0.325[/tex]

When body is straight, area,

[tex]A_1=6 \ ft^2[/tex]

As we know,

Terminal velocity,

⇒  [tex]V_t=\sqrt{\frac{2W}{C_d \delta A} }[/tex]

or,

⇒      [tex]=\sqrt{\frac{2mg}{C_d \delta A} }[/tex]

At straight orientation,

⇒ [tex]V_t'=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558} }[/tex]

⇒      [tex]=\sqrt{\frac{1777.72}{0.223}}[/tex]

⇒      [tex]=89.455 \ m/s[/tex]

When belly flat,

⇒  [tex]V_t''=\sqrt{\frac{2\times 90.7\times 9.8}{0.325\times 1.225\times 0.558\times 4} }[/tex]

⇒        [tex]=\sqrt{\frac{1777.72}{0.889} }[/tex]

⇒        [tex]=44.73 \ m/s[/tex]

Answer:

40*C

Explanation:

Answer:

the observed frequency will reduce but the wavelength will increase

Explanation:

As we know

fo = fs (v/(v-vs))

fo = observed frequency

vs = velocity of source

As per this equation,  

When an observer moves away from the stationary source, the observed frequency reduces. Since the observer in the balloon is moving away from the source which itself is moving in opposite direction, the observed frequency will reduce.  

Since wavelength = V/fs . The source frequency is unchanged but the velocity is increasing as it is moving in downward direction. Hence, the wavelength will increase