What does the power source in a circuit provide?

the means to break a circuit
a path along which electricity can flow
static electricity
a steady flow of electrons

plsssssssssssssssssss answer plss not in a meen way but plssss anwer correctly

Answer:

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

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Answer:

GRAVITY:

In physics, gravity is the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.

Answer: Climate change poses to the tourism development in Fiji islands. It shows the adverse effects of the changing climate and the dangers pose by the tourism activities and also pose a major hazard for the local people in the region. It also deals with the dangerous carbon emissions and CO2 effect on the landscape, food, water, energy.

The pacific is the world`s largest ocean with a surface area of 175 million sq km and constitutes for 40% of the planet`s waters. Located in the tropical latitudes, it covers more than half the globe`s circumference. Temperature of the surface water in the western tropical regions is always more than 28 ÌŠC over a depth of several hundred meters. This makes up the world`s storage of thermal energy for exchange with atmosphere. Here the interaction between atmosphere and ocean is most extreme and influences the climate not only regionally but planet-wide. The nations of the pacific are obscured human settlements absorbed in this vast fluid universe. The ocean is the most important factor controlling the environment and life.

Answer:

R = 46,25 (Ω)

L = 0,07363 (H)

C = 2,7 *10⁻⁶ (F)

Explanation:

Statement problem does not specify if  160 (V) is peak voltage or RMS value. If 160 (V) is the peak value then for a sinusoidal wave,  RMS value is  V(rms) = 160 /√3

V(rms) =  92,49 (V)

In each branch: we have

V = I*Z         V = voltage through the impedance in (V) , I current in (A)

and Z impedance in Ω

Resistor case    Z = R  then V = 92,49 = 2 * R

R = 92,49/2       R = 46,25 (Ω)

Inductor case   |Z| = wL    Then Z = 2*π*f*L   V = 0,8 * |wl|

Inductor L in (H)       |wL| * 0,8 = 92,49   |wL| = 92,5/0,8    w = 2*π*f   2*3,14*250= 1570

1570*L = 92,49/0,8

L = 0,07363 (H)

In the case of the capacitor

|Z|  = 1/wc    = 1/1570*c

The current is 2 + 0,8 = 2,8          2,8 - 2,5 = 0,3 (A)

Again  V = I*Z        92,49 = 0,3 /1570*C

C = 0,3 / 1570*92,49

C = 2,7 *10⁻⁶ (F)

Answer:

D (not so sure, look in the explanation and judge yourself)

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards

Minimum force required = 0.25 x 34 x 9.81

= 83.385 N

So technically the force need to be greater than 83.385 so the answer should be d, not really sure if it should be b though really depends on the acceleration due to gravity.

Answer: 5 N

Explanation:

Given

Mass of box [tex]m=4\ kg[/tex]

acceleration of box [tex]a=2\ m/s^2[/tex]

Force applied by Manual [tex]F_m=8\ N[/tex]

Friction force [tex]f=5\ N[/tex]

The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]

Suppose [tex]F_c[/tex] is the force applied by Carlos

[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]

The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

The force is defined as the external effort applied on any object to move it or to restrict it.

Here following information is given in the question:

Mass of the box m=4 kg

The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]

The force applied by the Manual [tex]F_m=8\ N[/tex]

The frictional force is [tex]F_f=5\ N[/tex]

The net force on the body will be calculated by

[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]

The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:

[tex]F_m+F_c-F_f=F_{net}[/tex]

[tex]8+F_c-5=8[/tex]

[tex]F_c=5\ N[/tex]

Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

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Answer:

Explanation:

In an elliptical orbit , the angular momentum of the planet remains constant because velocity of planet makes a right angle to the direction to the star .

mvr = constant .

mv₁r₁ = mv₂r₂

v₁r₁ = v₂r₂

v₁ x 21 = 38 x 75

v₁ = 135.71 km/s .

Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.

Explanation: hope this helps!

Explanation:

it is played as a sequence of alternating strokes

The total energy is conserved within isolated system.

In an isolated system, there is no exchange of matter or energy with the surroundings. Therefore, the total energy within the system remains constant, meaning that energy is conserved within the system.

In contrast, in an open system, there can be an exchange of both matter and energy with the surroundings, so the total energy within the system is not necessarily conserved.

In a closed system, there can be an exchange of energy but not matter, so the total energy within the system is conserved as long as there is no work being done by or on the system. In a connected system, the term is not commonly used in the context of energy conservation.

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Answer:

0.34 m

Explanation:

From the question,

v = λf................ Equation 1

Where v = speed of sound, f = frequency, λ = Wave length

Make λ the subject of the equation

λ = v/f............... Equation 2

Given: v = 340 m/s, f = 500 Hz.

Substitute these values into equation 2

λ = 340/500

λ = 0.68 m

But,  the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length

Therefore,

λ/2 = 0.68/2

λ/2 = 0.34 m

Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m

Answer:

the answer is d the world  trade organization

Explanation:

Answer:

 y = 4.666 10⁻² m

Explanation:

The constructive interference experiment for the double slit

         d sin sin θ = m λ

Let's use trigonometry to find a sine relationship.

         Tan θ = y / L

          tan θ = sin θ/ cos θ

in these experiments the angles are very small

           tan θ = sin θ

           sin θ = y / L

            [tex]d \frac{y}{L}[/tex] = m λ

              y = [tex]\frac{ m \lambda \ L}{d}[/tex]

we replace the values

              y = 3  560 10⁻⁹ 3.0 / 0.108 10⁻³

              y = 4.666 10⁻² m

Answer:

I THINK it's A but I'm not completely sure

Answer:

Man will not slide down

Explanation:

Given:

Coefficient of static friction = 0.25

Angle = 13°

Computation:

Man will slide down if

tan13° > Coefficient of static friction

Tan 13 = 0.23

So,

0.23 < 0.25

So,

Man will not slide down

Answer:

the speed of the ball just after the collision is 1.5 m/s.

Explanation:

Given;

mass of the ball, m₁ = 1.6 kg

initial velocity of the ball, u₁ = 0

mass of the block, m₂ = 0.8 kg

initial velocity of the block, u₂ = 0

final velocity of the block, v₂ = 3 m/s

let the final velocity of the ball after collision = v₁

Apply the principle of conservation of linear momentum for elastic collision;

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

1.6 x 0   +    0.8 x 0       =   1.6 x v₁     +  0.8 x 3

0 = 1.6v₁  + 2.4

-1.6v₁ = 2.4

v₁  = -2.4 / 1.6

v₁ = - 1.5 m/s

v₁ = 1.5 m/s (in opposite direction of the block)

Therefore, the speed of the ball just after the collision is 1.5 m/s.

Answer:

(a) The reduced pressure is 0.2711 MPa

The reduced temperature is 2.54 K

(b) The initial volume of the piston is approximately 0.806 m³

(c) The mass of CO₂ is approximately 16.9884 kg

(d) The work done, W is approximately 388.023 kJ

(e) The heat transfer is approximately -2,650.1904 kJ

Explanation:

The initial temperature of the piston-cylinder, T₁ = 500°C = 773.15 K

The initial pressure of the gas, P₁ = 2 MPa

The final temperature of the gas, T₂ = 350°C

The final volume of the gas = 1 m³

(a) For an isobaric process, we have;

The reduced pressure,

[tex]P_r = \dfrac{P}{P_c}[/tex]

The critical pressure of carbon dioxide, [tex]P_c[/tex] = 7.3773 MPa

[tex]P_r = \dfrac{2 \, MPa}{7.3773 \, MPa} \approx 0.2711 \, MPa[/tex]

The reduced pressure, [tex]P_r[/tex] = 0.2711 MPa

The critical temperature, [tex]T_c[/tex] = 304.13 K

The reduced temperature, [tex]T_r[/tex], is given by the following formula;

[tex]T_r = \dfrac{T}{T_c}[/tex]

Therefore, [tex]T_r[/tex] = (773.15 K)/(304.13 K) = 2.54216947 K

The reduced temperature, [tex]T_r[/tex] ≈ 2.54 K

(b) The initial volume of the piston, V₁ = (V₂/T₂) × T₁

∴ V₁ = (1 m³/773.15) × 623.15 = 0.80598848865 m³  ≈ 0.806 m³

The initial volume of the piston, V₁ ≈ 0.806 m³

(c) The number of moles of CO₂ in the cylinder, 'n', is given according to the following formula;

n = P·V/(T·R)

The universal gas constant, n = (2 × 10⁶Pa × 1 m³)/(623.15 K × 8.3145 J/(mol·K)) ≈ 386.0124 moles

The mass of CO₂ ≈ 386.0124 moles × 44.01 g/mol = 16.9884 kg

(d) The work done, W = P·([tex]V_f - V_i[/tex])

W = 2 × 10⁶ × (1 - 0.80598848865) = 388023.0227

The work done, W ≈ 388.023 kJ

(e) The heat transfer dQ = m·[tex]c_p[/tex] ×(T₂ - T₁)

[tex]c_p[/tex] for CO₂ ≈ 1.04 kJ/(kg·K)

∴ dQ = 16.9884 × 1.04 × (350 - 500) = -2,650.1904 kJ

Therefore, the heat transfer = dQ = -2,650.1904 kJ

Answer:

Explanation:

For Doppler effect in radar the formula is as follows

Δf = f₀ x 2v /c

Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .

Δf  = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .

2460 =  1.0525 x 10¹⁰ x 2 v / 3 x 10⁸

2460 = 105.25 x 2 v / 3

v = 2460 x 3 / (105.25 x 2 )

v = 35 .06 m /s .

(b)

Since the observed frequency is less , the source is moving away from the observer .

option (2) is correct .

Answer:

b) N = 560 N, c)  fr = 138.56 N, d)  μ = 0.247

Explanation:

a) In the attachment we can see the free body diagram of the system

b) Let's write Newton's second law on the y-axis

              N + T_y -W = 0

              N = W -T_y

let's use trigonometry for tension

             sin θ = T_y / T

             cos θ = Tₓ / T

             T_y = T sin θ

             Tₓ = T cos θ

we substitute

              N = W - T sin 30

we calculate

              N = 640 - 160 sin 30

              N = 560 N

c) as the system goes at constant speed the acceleration is zero

X axis

              Tₓ - fr = 0

               Tₓ = fr

we substitute and calculate

              fr = 160 cos 30

              fr = 138.56 N

d) the friction force has the formula

             fr = μ N

             μ = fr / N

we calculate

             μ = 138.56 / 560

             μ = 0.247

Answer:

increases

Explanation:

due to less speed

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

[tex]Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J[/tex]

or

Q = 282,000 J

So, the required heat is 282,000 J .

Answer:

1 : b  2: d

Explanation:

Answer:

40m/s

Explanation:

Id say its the last option of the fourth option

Explanation:

Answer:  

1:increase the number of coils, increase the strength of the magnet

2:increase the speed of the magnet

3: increasing the time used to power up an electromagnet

Explanation:

1). Increasing the number of turns of wire in the coil – By increasing the amount of individual conductors cutting through the magnetic field, the amount of induced emf produced will be the sum of all the individual loops of the coil, so if there are 20 turns in the coil there will be 20 times more induced emf than in one piece of wire.

2). Increasing the speed of the relative motion between the coil and the magnet – If the same coil of wire passed through the same magnetic field but its speed or velocity is increased, the wire will cut the lines of flux at a faster rate so more induced emf would be produced.

3). Increasing the strength of the magnetic field – If the same coil of wire is moved at the same speed through a stronger magnetic field, there will be more emf produced because there are more lines of force to cut.

a metal spike in an airport runway

A metal spike in an airport runway  is NOT a way to stay safe from static electricity. Hence option C is correct.

Electricity is a collection of physical phenomena related with the presence and motion of matter having an electric charge. Both electricity and magnetism are connected to the phenomena of electromagnetic, as defined by Maxwell's equations. Lightning, static electricity, electric heating, electric discharges, and other frequent occurrences are all connected to electricity.

An electric field is created when either a positive or negative electric charge is present. The movement of electric charges results in an electric current and a magnetic field. In most applications, a force of magnitude determined by Coulomb's law operates on a charge. Volts are commonly used to measure electric potential.

Hence option C is correct.

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Answer:

Velocity = 12 m/s

Explanation:

Given the following data;

Wavelength = 6 meters

Period = 0.5 seconds. This is due to the fact that the student is moving his hand up and down twice each second.

To find the velocity;

Velocity = wavelength * frequency

But, frequency = 1/period

Frequency = 1/0.5

Frequency = 2

Substituting the values into the velocity formula, we have;

Velocity = 6 * 2

Velocity = 12 m/s

Therefore, the velocity of the wave is 12 meters per seconds.

Answer:

It is A. Light blue

_____________

Hope this helps!

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Answer:

a) [tex] E_{p} = 0 [/tex]

[tex] E_{k} = 168.7 J [/tex]

[tex] E_{m} = 168.7 J [/tex]

b) [tex] E_{p} = 73.6 J [/tex]

[tex] E_{k} = 95.8 J [/tex]

[tex] E_{m} = 169.4 J [/tex]

c) [tex] E_{p} = 169.2 J [/tex]

[tex] E_{k} = 0 [/tex]

[tex] E_{m} = 169.2 J [/tex]

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

[tex] E_{p} = mgh = 0 [/tex]

The kinetic energy is:

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]

Now, to find the kinetic energy we need to calculate the speed at 5 m:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]

[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]

c) At its maximum height:

[tex] v_{f}[/tex]: is the final speed = 0

[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]

Now, the potential, kinetic and mechanical energies are:

[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]

[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]

I hope it helps you!    

Answer:

A)2.811 × 10^-12 F

B)4.09V

Explanation:

(a) What is the capacitance?

Capacitance of coaxial cylinder can be determined using below expresion

C= (2π ε0 L)/ Ln[ rb/ra]

Where

ε0= permittivity of free space= 8.85×10^−12 Fm^-1

L= length of each cylinder =13.0 cm= 13×10^-2m

rb= radius of outer cylinder= 7.20 mm= 7.20×10^-3m

ra=radius of inner cylinder=0.550 mm= 0.550×10^-3 m

If we substitute the values we have,

C= (2π ε0 L)/ Ln[ rb/ra]

C= ( 2 × π × 8.85×10^−12 ×13×10^-2) / Ln[

7.20×10^-3/0.550×10^-3]

C=( 7.2288×10^-12 )/2.5729

C=2.811 × 10^-12 F

B) (b) What applied potential difference is necessary to produce these charges on the cylinders?

Vba= Q/C

Where Vba=potential difference

Q= charge on each = 11.5 pC. = 11.5×10^-12

C= capacitance= 2.811 × 10^-12 F

If we substitute the values we have

Vba=(11.5×10^-12)/2.811 × 10^-12

= 4.09V

Answer:

true , true, and I'm not sure about the last one!

Explanation: